Consider the reaction


2 NO2 (g) <=> N2O4

If the equilibrium concentration of both NO2 and N2O4 are 0.2 M, what is the value of Kc?


A. 0.2

B. 0.3

C. 0.225

D. 5.0

E. 2.5

Please help.

Answer:

Due its storing and holding ability.

Explanation:

It matter that the material from which the vat is made is metal because this vat is used for storing and holding liquids. Vat is a large container or tank that is used for storing or holding liquids in industrial sector. This vat is made of metal which increases its strength and durability. If the vat is made of wood or plastic so it can't hold huge amount of liquid or chemical due to its weak material so that's why it matters that the substance from which the vat is made is metal or not.

Answer:

I'm pretty sure a lot of them are melting because of global warming

Answer: Energy = 10000J - 2000J = 8000J

Therefore, the energy is dissipated the skier moves down to the slope is 8000J

Explanation:

Answer:

Your answer will be C. 1/32

Answer:

C. 1/32

Explanation:

Answer:

1.25 mL/s

Explanation:

Your are told that 25.0 mL of H2 was produced 20 seconds. This is equal to rate 25/20 = 1.25 mL/s

When a reaction progresses, the reactant concentration gradually decreases and the product concentration gradually increases. Here the rate of the reaction is 1.25 mL/s.

The rate of a chemical reaction is defined as the rate of decrease of concentration of a reactant or the rate of increase of concentration of a product. The rate of the reaction is usually expressed in units mol L⁻¹s⁻¹. The rate of the reaction are affected by several factors like concentration of the reactants, temperature, etc.

An equation which expresses the experimentally observed rate of a reaction in terms of the molar concentration of the reactants which determine the rate of the reaction is called rate equation.

Here it is seen that 25.0 mL of H2 was produced 20 seconds. So the rate is given as:

Rate = 25/20 = 1.25 mL/s

Thus the rate of the reaction is 1.25 mL/s.

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Answer: The final temperature of the system will be [tex]13.14^0C[/tex]

Explanation:

[tex]heat_{absorbed}=heat_{released}[/tex]

As we know that,  

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex]         .................(1)

where,

q = heat absorbed or released

[tex]m_1[/tex] = mass of steam = 25 g

[tex]m_2[/tex] = mass of water = 0.2384 kg = 238.4 g   (1kg=1000g)

[tex]T_{final}[/tex] = final temperature = ?

[tex]T_1[/tex] = temperature of steam = [tex]116^oC[/tex]

[tex]T_2[/tex] = temperature of water = [tex]8^oC[/tex]

[tex]c_1[/tex] = specific heat of steam = [tex]1.996J/g^0C[/tex]

[tex]c_2[/tex] = specific heat of water= [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)][/tex]

[tex]T_{final}=13.14^0C[/tex]

Therefore, the final temperature of the system will be [tex]13.14^0C[/tex]

Answer:

Now, the molar solubility of lead(II) phosphate in water is said to be equal to 6.2⋅10−12mol L−1 . This means that in one liter of water, presumably at room temperature, you can only hope to dissolve 6.2⋅10−12 moles of lead(II) phosphate.

Explanation:

Hope this helps!!

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

Answer:

The white stuff we know as sugar is sucrose, a molecule composed of 12 atoms of carbon, 22 atoms of hydrogen, and 11 atoms of oxygen (C12H22O11). Like all compounds made from these three elements, sugar is a carbohydrate

Answer:

55mL

Explanation:

44g / 0.8g/mL = 55mL

yes use the masses of an element below calculate the mass of it 8.70 mole of each 3M

Answer:

carbon electrode: delocalised electrons

molten mixture....: aluminium oxide ions

metal wire: Metal atoms

The free moving charged particles in the following substances are as follows;

Graphite, an allotrope of carbon has Delocalized (free-moving) electrons and these electrons serve to enable conductivity.

Although, cryolite is a bad conductor of electricity, when Molten Aluminium oxide and cryolite is used, the free moving Aluminium ions enable conductivity.

In metal wires, conductivity is solely the responsibility of metal ions.

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Answer:

the answer is A

Explanation:

Hopefully u get the answer right

Answer:

A

Explanation:

give me thanks not stars

Answer:

There is no picture but the one that is in motion in the picture has kinetic energy.

Explanation:

Kinetic energy is the energy of motion.

hope this helped!

Answer:

607.9616 grams

Explanation:

Hope this helped!!

Answer:

This is polar

Explanation:

If the arrows are of different lengths, and if they do not balance each other, the molecule is polar.

If the arrangement is asymmetrical, the molecule is polar.

Hope this helped!!!

Answer:

Endothermic

Explanation:

An endothermic reaction is one in which energy is absorbed while an exothermic reaction is one in which energy is given out(evolved).

If we look at the reaction as written; 3C(graphite) + 3H2(g) + 88kcal -------> C3H8(g), we will notice that;

i) 88kcal of energy had to be absorbed for the reaction to occur

ii) The enthalpy change for the reaction is positive.

Since energy must be taken in to drive the forward reaction, then the reaction is endothermic as written.

The expected outcome of carrying out this step as planned is :

B. The resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

The expected outcome of carrying out this step as planned is the resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

pH may be a degree of how acidic/basic water is.

The run goes from - 14, with 7 being unbiased. pHs of less than 7 demonstrate causticity, while a pH of more noteworthy than 7 demonstrates a base.

pH is truly a degree of the relative amount of free hydrogen and hydroxyl particles within the water

Thus, the correct answer is B.

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Answer:

Expof HCl are required to produce 7.50 moles of ZnCl2? 6. Copper ... When 9.34 g of zinc react with excess hydrochloric acid how many grams of zinc chloride will.lanation:

Answer: it should be 80g

Explanation:

Answer:

combustion is fast and destructive it also involves a lot of movement of the atoms where erosion is a slow process that does not involve a lot of energy

Answer:

1.05 atm

It should be 1 atm = 760 mm; therefore, 798 mm x (1 atm/760) = about 1.05 atm.

The value of pressure in atm that would be equal to 798 mmHg is 1.05 atmospheric.

Pressure is a physical quantity or a kind of force which is perpendicularly applied on the surface area of any object so that force is equally distributed on that surface.

Pressure will be maesured by various unit and have relation with one another.

As we know that, 1 atm = 760 mmHg

Or 1 mmHg = 1/760atm

Given quantity of pressure is 798 mmHg and we calculate this quantity by multiply this value by 1/760 and we get,

798 mmHg = 798mmHg × 1/760atm/mmHg = 1.05 atm

Hence required value of pressure is 1.05 atm.

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Answer:

7.The answer is 2.13 because if u add 3.23 and 4.51 and the answer is 7.74 and u add 2.13 to get 9.87. 3.23 + 4.51 + 2.13 is 9.87

Explanation:

Answer: A heat energy of 50160 joules are required to heat 15 grams of ice from [tex]-200^{o}C[/tex] to [tex]1400^{o}C[/tex].

Explanation:

Given : mass of ice = 15 g

Convert grams into kg as follows,

[tex]1 g = 0.001 kg\\15 g = 15 g \times \frac{0.001 kg}{1 g}\\= 0.015 kg[/tex]

Initial temperature = [tex]-200^{o}C[/tex]

Final temperature = [tex]1400^{o}C[/tex]

Formula used to calculate the amount of heat energy is as follows.

[tex]q = m \times C \times (T_{2} - T_{1})[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat of substance (ice here has C = [tex]2090 J/kg ^{o}C[/tex])

[tex]T_{1}[/tex] = initial temperature

[tex]T_{2}[/tex] = final temperature

Substitute the values into above formula as follows.

[tex]q = m \times C \times (T_{2} - T_{1})\\= 0.015 kg \times 2090 J/kg^{o}C \times [1400 - (-200)]^{o}C\\= 50160 J[/tex]

Thus, we can conclude that 50160 joules are required to heat 15 grams of ice from [tex]-200^{o}C[/tex] to [tex]1400^{o}C[/tex].

Answer: CH4 + 1,5 O2 ⇒ CO + 2 H2O, then multiply numbers by 2

Explanation:

Answer:

1.44 g

Explanation:

The problem gives you the molarity and volume of the target solution, so right from the start you know that you can use that information to determine the number of moles of hydrochloric acid that it must contain.

So, molarity measures a solution's concentration in terms of how many moles of solute, which in your case is hydrochloric acid, you get per liter of solution.

A

0.158 M

hydrochloric acid solution contains

0.158

moles of hydrochloric acid for very liter of solution. Since you're dealing with

250 mL

, the equivalent of

1

4

th

of a liter, your solution will contain

250

mL

⋅

1

L

10

3

mL

⋅

0.158 moles HCl

1

L

=

0.0395 moles HCl

Now that you know how many moles of hydrochloric acid are needed to prepare your solution, use the compound's molar mass to convert this to grams

0.0395

moles HCl

⋅

36.46 g

1

mole HCl

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

1.44 g

a

a

∣

∣

−−−−−−−−−−

Explanation:

Please  brainliest.

Answer:

[tex][C_6H_{12}O_6][/tex]

Explanation:

Hello there!

In this case, since the concept of solution concentration is majorly used in terms of moles per liters of solution or molarity (M), it is also possible to represent this chemical unit by using squared brackets, [ ].

In such a way, when focused on the concentration of glucose, C6H12O6, we can use:

[tex][C_6H_{12}O_6][/tex]

Best regards!

Answer:

3

Explanation:

3 is the answer is did this a little while ago

Answer: This is a typical acid/base equilibrium problem, that involves the use of logarithms.

Explanation:We assume that both nitric acid and hydrochloric acid dissociate to give stoichiometric

H

3

O

+

.

Moles of nitric acid:

26.0

×

10

−

3

⋅

L

×

8.00

⋅

m

o

l

⋅

L

−

1

=

0.208

⋅

m

o

l

H

N

O

3

(

a

q

)

.

And, moles of hydrochloric acid:

88.0

×

10

−

3

⋅

L

×

5.00

⋅

m

o

l

⋅

L

−

1

=

0.440

⋅

m

o

l

H

C

l

(

a

q

)

.

This molar quantity is diluted to

1.00

L

. Concentration in moles/Litre =

(

0.208

+

0.440

)

⋅

m

o

l

1

L

=

0.648

⋅

m

o

l

⋅

L

−

1

.

Now we know that water undergoes autoprotolysis:

H

2

O

(

l

)

⇌

H

+

+

O

H

−

. This is another equilibrium reaction, and the ion product

[

H

+

]

[

O

H

−

]

=

K

w

. This constant,

K

w

=

10

−

14

at

298

K

.

So

[

H

+

]

=

0.648

⋅

m

o

l

⋅

L

−

1

;

[

O

H

−

]

=

K

w

[

H

+

]

=

10

−

14

0.648

=

?

?

p

H

=

−

log

10

[

H

+

]

=

−

log

10

(

0.648

)

=

?

?

Alternatively, we know further that

p

H

+

p

O

H

=

14

. Once you have

p

H

,

p

O

H

is easy to find. Take the antilogarithm of this to get

[

O

H

−

]

.

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