A foot contains 12 inches 5 inches is what fraction of a foot ​

Answer:

Can't see problem 1

2. C.

3. A.

4. C.

Step-by-step explanation:

Hope this helps!

answer I need a picture please

The graph given below is the rational function y = 1/(x + 1).

Option C is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

In the case of the function y = 1/(x + 1), the numerator is a constant function, which means that the function has a horizontal asymptote at y = 0.

The denominator, x + 1, is a linear function, which means that the function has a vertical asymptote at x = -1.

Therefore, the graph of the function will have a shape that is similar to a hyperbola.

Thus,

The graph given below is the rational function y = 1/(x + 1).

Learn more about functions here:

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#SPJ5

Answer:

622.08

Step-by-step explanation:

576 × (0.080 ÷ 1)

576 × 1.08

622.08

Answer:

622.08

Step-by-step explanation:

hope it helps you

Answer:

Step-by-step explanation:

Question 1:

Question 2:

Question 3:

Can't solve this sorry. :(

Answer:

Part 1) The ratio of buttons in package A to package B is 7:12

Part 2) For every 1 button in package C, there are 5 in package D.

Part 3) The ratio of buttons in package A to the total number of buttons is 1:5

Step-by-step explanation:

Part 1.

To find the ratio of buttons in package A to package B, we first have to identify how many buttons are in each package.

Package A: 35

Package B: 60

One way we can find the ratio of 35 to 60 is to find a common factor between the two numbers.

Well, both 35 and 60 have a common factor of 5.

Now we divide both numbers by 5 to simplify

35 / 5 = 7

60 / 5 = 12

Now we have the ratio of 7:12

It cannot be simplified anymore since 7 and 12 have no common factors

Part 2.

To find the answer to this, we have to find the ratio of buttons in package C to package D.

Package C: 10 buttons

Package D: 50 buttons

Now we find a common factor between the two numbers

The greatest factor is 10

Now we divide both numbers by 10 to simplify

10 / 10 = 1

50 / 10 = 5

So, our ratio is 1:5

That means for every 1 button in package C, there are 5 in package D.

Part 3.

To find this ratio, we have to identify the number of buttons for both sides.

Package A: 35

All Packages: 60 + 10 + 50 + 20 + 35 = 175

So, let's find the greatest common factor between 175 and 35

Well, the greatest common factor is 35, since 35 is a factor of 175

35 / 35 = 1

175 / 35 = 5

The ratio of buttons in package A to the total number of buttons is 1:5

Step-by-step explanation:

Componets of a vector are

[tex]x = r \cos(x) [/tex]

[tex]y =r \sin(x) [/tex]

The vector of F1 has a angle of 30 and radius of 30 n so the component are

[tex]x = 30( \cos(30) ) = {15 \sqrt{3} }[/tex]

[tex]y = 30 \sin(30) = 15[/tex]

F2 is a 90 degree so

[tex]x = 20 \cos(90) = 0[/tex]

[tex]y = 20\sin(90) = 20[/tex]

F3 is a 240 degree so we have

[tex]x = 35( \cos(240) ) = - 17.5[/tex]

[tex]y = 35 \sin(240) = - 17.5 \sqrt{3} [/tex]

F4 is 310 angle so we have

[tex]x = 40 \cos(310) = - 21.01[/tex]

[tex]y = 40 \sin(310) = 34.04[/tex]

how many lines are perpendicular to AB?

Hello!

1

middle!

Answer:

A. 1

Step-by-step explanation:

since the perpendicular line has to be at a 90 degree angle of AB and there is only one line which is at a 90 degree angle at AB.

The integral distributes over the sum:

[tex]\displaystyle \int \left(4x^{\frac34} + 2x^{\frac34} + 4x^{\frac12} + 2x + 2\right) \, dx \\\\\\ = \int 4x^{\frac34} \, dx + \int 2x^{\frac34} \, dx + \int 4x^{\frac12} \, dx + \int 2x \, dx + \int 2 \, dx[/tex]

Then just integrate each term using the power rule; if n ≠ -1, then

[tex]\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C[/tex]

Then your integral is simply

[tex]\displaystyle \int \left(4x^{\frac34} + 2x^{\frac34} + 4x^{\frac12} + 2x + 2\right) \, dx \\\\\\ = \frac{4x^{\frac34+1}}{\frac34+1} + \frac{2x^{\frac34+1}}{\frac34+1} + \frac{4x^{\frac12+1}}{\frac12+1} + \frac{2x^2}2 + \frac{2x^1}1 + C \\\\\\ = \frac{16}7 x^{\frac74} + \frac87 x^{\frac74} + \frac83 x^{\frac32} + x^2 + 2x + C \\\\\\ = \boxed{\frac{24}7 x^{\frac74} + \frac83 x^{\frac32} + x^2 + 2x + C}[/tex]

Answer:

6

Step-by-step explanation:

Just multiply both the top and bottom by 6 you get 18/24 from 3/4

Answer:

90 apples

Step-by-step explanation:

1st class did 1/3, 1/3 of 60 is 20, 60-20 is 40, 40 into 2.25 or 2 1/4 = 90 because 40 x 2 = 80 and 1/4 of 40 is 10, 10+80 = 90, so the second class needs 90 apples

Answer:

90 apples

Step-by-step explanation:

First, we need to find 1/3 of the total number of pies, which is the number of pies the first class made. To do this, we divide 60 by 3 (or multiply 60 by 1/3):

60 ÷ 3 = 20

This means the first class made 20 pies and that the second class has to make 40 pies (60 - 20 = 40)

1 pie needs 2 1/4 apples

To find how many apples the second class will need, we must multiply 40 (the number of pies) • 2 1/4 (the number of apples needed for 1 pie)

40 • 2 1/4 = 90

This means 90 apples are needed for the second class to make the remaining pies

Hey there!

(3 * 2)^2

= (3 + 3)^2

= 6^2

= 6 * 6

= 6 + 6 + 6 + 6 + 6 + 6

= 12 + 12 + 12

= 24 + 12

= 36

Therefore, your answer is: 36

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

(3 × 2)² = 36

Step-by-step explanation:

Given expression,

→ (3 × 2)²

Evaluating the expression,

→ (3 × 2)²

→ (6)²

→ 36

Hence, the answer is 36.

Answer:

9a(9b-10)

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

the gcf of 48 and 54 is 6,the gcf of 60 is 60.

Answer:

To find : The error in the solution and what additional step needs to be completed?

Solution : The mistake is the step 3 and additional step need to be added after it.

Step 1 - \log x -\log_5 3 = 2\log_5 3logx−log

5

3=2log

5

3

Step 2 - \log x = 3\log_5 3logx=3log

5

3

Step 3 - \log x =\log_5 3^3logx=log

5

3

3

Step 4 - \log x=\log_5 27logx=log

5

27

Applying change base rule of logarithmic, \log_b a=\frac{\log a}{\log b}log

b

a=

logb

loga

Step 5 - \log x=\frac{\log 27}{\log 5}logx=

log5

log27

Step 6 - \log x=\frac{1.431}{0.698}logx=

0.698

1.431

Step 7 - \log x=2.050logx=2.050

Step 8 - x=10^{2.050}x=10

2.050

Step 9 - x=112.20x=112.20

From step 4 to 9 is the required steps.

Step-by-step explanation:

Permutation is "How many ways can you arrange 'r' from a set of 'n' if the order matters?"

For #7, it would be "how many ways can you pick 2 things out of 6 things when the order matters?"

The steps for this is in the picture.

For #9, you would do the same as #7 and just add -4 to your final answer

Answer: 2x7=14

Step-by-step explanation:

There are only three numbers that go with each equation, all you have to do is eliminate the ones that don't match.

Answer:

(2,7)

Step-by-step explanation:

Plug in 2 for x for f(x)

[tex]4(2) - 1 = 7[/tex]

So the answer will be (2,7)

Answer:

b 18÷3=6

Step-by-step explanation:

The fact family contains 3,6and 18

since 3×6=18,18÷6=3and 6×3=18

∴ you need to look for numbers that contain 3,6and18. when you find the number make sure to check that they are not in the question, if it is not in the question then that is your answer.

hope it helps

Answer:

Frequency means the number of times the value occurs in the data set.

Therefore, to determine the frequency of height 63, count the number of times "63" occurs in the data set.  From inspection of the data set, we can see that there are five "63"s so the frequency of 63 is 5.

Height   Frequency

63                5

64                1

65                6

66                2

67                3

68                3

69                4

70                0

71                 2

72                4        

Total          30

Answer:

pattern B

Step-by-step explanation:

just took the test

Answer:

[tex]\tt \angle QTS=1/2(m\:\widehat {sQ}-m\:\widehat{RP}[/tex]

[tex]\tt =1/2(154^{o}-80^{o})[/tex]

[tex]\tt =1/2(74^{o})[/tex]

[tex]\boxed{\tt m\angle QTS=37^{o}}[/tex]

~

[tex]\tt m\angle GKI=1/2(m\:\widehat{GI}+m\widehat{JH})[/tex]

[tex]\tt 55=1/2(76+m\:\widehat{JH})[/tex]

[tex]\tt 55(2)=76+m\: \widehat{JH}[/tex]

[tex]\tt 110+76=m\:\widehat{JH}[/tex]

[tex]\boxed{\tt m\:\widehat{JH}=34^{o}}[/tex]

~

Out of the 40 prizes, 15 prizes were for Kazoos and 35 prizes were for whistle

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the diagram, the ratio is represented, hence:

Number of Kazoos = (3/8) * 40 = 15

Number of whistles = (5/8) * 40 = 35

Out of the 40 prizes, 15 prizes were for Kazoos and 35 prizes were for whistle

Find out more on equation at: https://brainly.com/question/2972832

The differentiation using the chain rule gives:

[tex]\frac{d(g(f(x)))}{dt} = g'(f(x))*f'(x) = \frac{1}{(kx)}*k = \frac{1}{x}[/tex]

Remember that:

[tex]ln(x) = \int\limits {\frac{1}{x} } \, dx[/tex]

Now, we want to derivate ln(kx) where k is a constant, the problem tells us to use the chain rule, so we define two functions:

Then we have:

g(f(x))

Remember that the chain rule says that:

[tex]\frac{d(g(f(x)))}{dt} = g'(f(x))*f'(x)[/tex]

In this case:

Then:

[tex]\frac{d(g(f(x)))}{dt} = g'(f(x))*f'(x) = \frac{1}{(kx)}*k = \frac{1}{x}[/tex]

If you want to learn more about the chain rule, you can read:

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Answer:

let the vertices on either side of the 0 be A and B

then let the vertex opposite of O be C

First, angle ACB will be equal to 90° as it is the angle that lies on the same arc as the diameter. From there you can find angle y with angle A+ angle B+ Angle C=180°

then you can find the angle complementary to x with the same formula then you can subtract that angle with 90° to get x.Step-by-step explanation:

Answer:

8/12 and higher. To ensure an accurate answer, are there other fractions to compare "7/12" to?

Step-by-step explanation:

Answer:

4p

Step-by-step explanation:

you dont have to put multiplication sign when you multiply by variables this is honestly a pretty easy question

Answer:

U just said a random thing

Step-by-step explanation: