Which statements about energy are true?
1.Energy is found only in moving objects.
2.Energy is never created.
3.Energy can move matter.
4.Energy is the same as force.
5.Energy is never destroyed

Answers

Answer 1

Answer:

Energy is found only in moving objects : False

Energy is never created : True

Energy can move matter : True

Energy is the same as force : False

Energy is never destroyed : True

Explanation:

Plato

Answer 2

Energy can neither be created nor be destroyed. Energy is generated by both moving and stationary objects but in different forms. Energy can move matter. Hence, options 2, 3 and 5 are correct.

What is energy conservation ?

According to the law of conservation of energy, energy can neither be created nor be destroyed. However, it can be transformed from one state to the other. For example electrical energy can be converted to light energy.

Energy is generated in both stationary and moving object. The energy for a particle gained by its motion is called its kinetic energy. The energy stored on an object at rest is called potential energy.

Energy can move matter as well. The energy used to displace an object is called work done on the object. The unit of energy and work done  is joule. Therefore, options 2, 3 and 5 are correct.

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Related Questions

[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?​

Answers

Answer: is  13

Explanation:

write any three rules two keep in in mind while using SI units​

Answers

Answer:

Rules and conventions for writing SI units and their symbols

The units named after scientists are not written with a capital initial letter. ...

The symbols of the units named after scientist should be written by a capital letter. ...

Small letters are used as symbols for units not derived from a proper name

Explanation:

Hope this helps u

Crown me as brainliest:)

Answer:

when temperature is expressed in Kelvin,the degree sign is omitted.

only accepted symbols should be used.

some space is always to be left between the number and the symbol of the unit and also between the symbols for compound units such as force,momentum, etc.

What is the weight of a 328N emperor penguin?

Answers

Answer:

Weight = 3217.68

Explanation:

N times Gravity = weight

Gravity= 9.81

The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.

What is Weight ?

Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -

W = m x g

where -

[m] is the mass of object

[g] is acceleration due to gravity

Given is the mass of an emperor penguin as 328 Kg.

We can write -

Mass [m] = 328 kg

Acceleration due to gravity [g] = 9.8 m/s²

Therefore, the weight of the emperor penguin will be

W[P] = m x g = 328 x 9.8 = 3214.4 Newtons

Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons

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A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-kilometer radius of its warehouse. What was the magnitude of its average acceleration?
A. 1.2 x 10^−2 m/s^2
B. 5.3 x 10^−1 m/s^2
C. 7.3 x 10^−1m/s^2
D. 4.4 x 10^1 m/s^2

Answers

I think it is letter A

The heat loss from a boiler is to be held at a maximum of 900Btu/h ft2 of wall area. What thickness of asbestos (k= 0.10 Btu/h ft ℉) is required if the inner and outer surfaces of the insulation are to be 1600 and 500℉, respectively? Now if a 3-in.-thick layer of kaolin brick (k= 0.07 Btu/h ft ℉) is added to the outside of the asbestos, what heat flux will be result if the outside surface of the kaolin is 250℉? What will be the temperature at the interface between the asbestos and kaolin for this condition?

Answers

Answer:

a. 0.122 ft b. -70 Btu/h ft² c. 633.33 °F

Explanation:

a. Since the rate of heat loss dQ/dt = kAΔT/d where k = thermal conductivity, A = area, ΔT = temperature gradient and d = thickness of insulation.

Now [dQ/dt]/A = kΔT/d

Given that [dQ/dt]/A = rate of heat loss per unit area = -900Btu/h ft², k = 0.10 Btu/h ft ℉(for asbestos), ΔT = T₂ - T₁ = 500 °F - 1600 °F = -1100 °F. We need to find the thickness of asbestos, d. So,

d = kΔT/[dQ/dt]/A

d = 0.10 Btu/h ft ℉ × -1100 °F/-900Btu/h ft²

d = 0.122 ft

b. If the 3 in thick Kaolin is added to the outside of the asbestos, and the outside temperature of the asbestos is 250℉, the heat loss due to the Kaolin is thus

[dQ/dt]/A = k'ΔT'/d'

k' = 0.07 Btu/h ft ℉(for Kaolin), ΔT' = T₂ - T₁ = 250 °F - 500 °F = -250 °F and d' = 3 in = 3/12 ft = 0.25 ft

[dQ/dt]/A = 0.07 Btu/h ft ℉ × -250 °F/0.25 ft

[dQ/dt]/A  = -70 Btu/h ft²

c. To find the temperature at the interface, the total heat flux equals the individual heat loss from the asbestos and kaolin. So

[dQ/dt]/A = k(T₂ - T₁)/d + k'(T₃ - T₂)/d' where  [dQ/dt]/A = -900Btu/h ft², k = 0.10 Btu/h ft ℉(for asbestos), k' = 0.07 Btu/h ft ℉(for Kaolin), T₁ = 1600 °F, T₂ = unknown and T₃ = 250℉.

Substituting these values into the equation, we have

-900Btu/h ft² = 0.10 Btu/h ft ℉(T₂ - 1600 °F)/0.122 ft + 0.07 Btu/h ft ℉(250℉ - T₂)/0.25 ft

-900Btu/h ft² = 0.82 Btu/h ft ℉(T₂ - 1600 °F) + 0.28Btu/h ft ℉(250℉ - T₂)

-900 °F = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82T₂  - 1312°F + 70 °F - 0.28T₂

collecting like terms, we have

-900 °F + 1312°F - 70 °F = 0.82T₂   - 0.28T₂

342 °F = 0.54T₂

Dividing both sides by 0.54, we have

T₂ = 342 °F/0.54

T₂ = 633.33 °F

The thickness of asbestos required is 0.122 ft.

The heat flux will be -70 Btu/h ft²

And the temperature of the interface is 633.33 °F.  

(i) the rate of heat loss :

dQ/dt = kAΔT/d

where k = thermal conductivity, A = area, ΔT = temperature gradient, and

d = thickness of insulation.

[dQ/dt]/A = kΔT/d

Given that [dQ/dt]/A = rate of heat loss per unit area = -900Btu/h ft²,

k = 0.10 Btu/h ft ℉,

ΔT = 500 °F - 1600 °F = -1100 °F

We have to find the thickness of asbestos that is d.

d = kΔT/[dQ/dt]/A

d = 0.10 Btu/h ft ℉ × -1100 °F/-900Btu/h ft²

d = 0.122 ft is the thickness required.

(ii) a 3-in thick Kaolin is added to the outside of the asbestos

outside temperature of the asbestos is 250℉,

the heat loss due to the Kaolin is:

[dQ/dt]/A = k'ΔT'/d'

k' = 0.07 Btu/h ft ℉(for Kaolin), ΔT' = T₂ - T₁ = 250 °F - 500 °F = -250 °F and d' = 3 in = 3/12 ft = 0.25 ft

[dQ/dt]/A = 0.07 Btu/h ft ℉ × -250 °F/0.25 ft

[dQ/dt]/A  = -70 Btu/h ft²

(iii) temperature at the interface

the total heat flux :

[dQ/dt]/A = k(T₂ - T₁)/d + k'(T₃ - T₂)/d'

where  [dQ/dt]/A = -900 Btu/h ft²,

k = 0.10 Btu/h ft ℉  (for asbestos),

k' = 0.07 Btu/h ft ℉  (for Kaolin),

T₁ = 1600 °F and T₃ = 250℉.

-900 = 0.10(T₂ - 1600 °F)/0.122 + 0.07(250℉ - T₂)/0.25

-900 = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82T₂  - 1312°F + 70 °F - 0.28T₂

-900 °F + 1312°F - 70 °F = 0.82T₂   - 0.28T₂

342 °F = 0.54T₂

Dividing both sides by 0.54, we have

T₂ = 342 °F/0.54

T₂ = 633.33 °F

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A 8 g of iron shot is added to a graduated cylinder containing 46 mL of water. The water level rises to the 49 mL mark, from this information, calculate the density of iron

Answers

Answer:

The answer is 2.67 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass of iron = 8 g

volume = final volume of water - initial volume of water

volume = 49 - 46 = 3 mL

We have

[tex]density = \frac{8}{3} \\ = 2.666666...[/tex]

We have the final answer as

2.67 g/mL

Hope this helps you

a spring balance used to weigh candy is built with a spring the spring stretches 3.00 cm when a 15 n weight is placed in the pan. when the weight is replaced with 3 kg of candy, what distance will the spring stretch?
a.7.0 b.4.5 c.3.8 d.5.9

Answers

Answer: 5.9cm

Explanation:

15N/3cm=5

Convert 3kg to N (29.42N)

Use the 5 from earlier to divide 29.42/5=5.884

Round to 5.9

5.9cm is the answer

(I don’t know if I solved this the correct way but I got it right. 5.9 is the correct answer)

Give me an example of heterogeneous mixture

Answers

Answer:

oil and water

Explanation:

if your mass is 72kg your textbooks in Madison has 3.7 kg and you and your textbook are separated by a distance of 0.33 M what is the gravitational force between you and your textbook

Answers

Answer:

1.63 X 10^-7N

Explanation:

How does changing the force affect the sound?

Answers

Answer:

From a sound standpoint, higher tracking force reduces all other things being equal which might reduce the top end a bit and increase bass.

What's the time it takes a car to attain the speed of 30 m/s when accelerating from rest at 2 m/s (squared)
A- 15 s
B- 2 s
C- 60 s
D- 30 s
E- none

Answers

The answer is A - 15s

who has a iphone (age range 15-19 )

Answers

Hi friend! I have an iPhone. why do you ask????

The anther and filament are parts of a flower's:

stamen

petal

pistil

stigma

Answers

A the stamen :)). haha yea smert

energy
Potential energy + Kinetic energy
OA) Heat
OB) Chemical
Electrical
OD) Mechanical

Answers

i think the answer may be D- mechanical
The answer is OD) Mechanical

Jack took up the job of a front desk staff at a reputed hotel. He will be interacting with various customers and employees from different parts of the world. What should his manager do to help Jack adapt to a diverse workplace? The manager is quite impressed with Jack. He wants to encourage Jack to actively listen and explore all solutions. He also wants to train Jack to avoid using I-statements and encourage him to participate in programs that teach him more about his own ethnic group. In addition, the manager wants to help Jack to understand the customs of other cultures.

Answers

Answer:

a. He wants to encourage Jack to actively listen and explore all solutions.

d. the manager wants to help Jack to understand the customs of other cultures.

Explanation:

As a front desk staff of the hotet, jack has to learn to activel listen, and explore all solutions available within his reach when deali with customers.

Because he is the first point of contact in the hotel as the front desk officer, this means he would get to interact with people of diverse cultures, customs e.t.c. Jack needs to learn and understand this cultures.


A ninja applies a force of 1250-N to a piece of 4-inch solid oak with his fist. What is the size of
the force applied to the fist by the piece of oak?

Answers

Answer:

The force is 1250-N

Explanation:

Generally according to Newtons third law , which states that for every action there is an equal and opposite reaction

 Now considering the question, the action here is the force applied by the ninja while the reaction is the force applied by the oak and from Newton law both of these action are equal but opposite to each other.

Hence the force applied by the the piece of oak on the fist is 1250 N

What happens to particle spacing when temperature increase, What we call this process?

Answers

Answer:

The atoms start vibrating really fast, making the space between them larger. It's an increase in Kinetic Energy.

Pregunta 2
George took his puppy to a dog park and unleashed her once they entered the gate. The puppy accelerated Northward, from rest, to 15 meters per second in 10
seconds. What was China's displacement in this time interval?

Answers

it was the time interval and the chinas displacement

How does an object become negatively charged

Answers

Explanation:

When insulating materials rub against each other, they may become electrically charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged. The material that loses electrons is left with a positive charge.

A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the acceleration

Answers

Answer:

a = 0.50 m/s²

v = 6.0 m/s

Explanation:

Step 1: Given data

Initial velocity (u): 0 m/s (rest)Displacement of the marble (s): 36 mTime elapsed (t): 12.0 sFinal velocity (v): ?Acceleration (a): ?

Step 2: Calculate the acceleration

We will use the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 × 12.0 s + 1/2 × a × (12.0 s)²

36 m = a × 72.0 s²

a = 0.50 m/s²

Step 3: Calculate the final velocity

We will use the following suvat equation.

v = u + a × t

v = 0 + 0.50 m/s² × 12.0 s

v = 6.0 m/s

A force of 6.0 N is applied horizontally to a 3.0 kg crate initially at rest on a horizontal frictionless surface. After the crate is pushed for 1.5 seconds, it has a gelocity of 3.0 m/s. Does this support Newton’s second law of motion, that force equals mass times acceleration?

Answers

Your answer to your question is 6.9 m/s

What state of matter has the highest energy? Lowest?

Answers

Answer:

The highest state of matter in energy is gas. The lowest is solid.

Explanation:

The reason why is because gas is the highest conductor of electricity (which is why we have lightning). However, solids don't conduct electricity very well.

Which of the following is an example of a properly written testable hypothesis? *

A people should taste this new health food and see whether it makes them stronger

B When dog owners don't feed their puppies Brand A food, the puppies do not grow properly

C If Frederico had added the leaves to the compost pile last year, he wouldn't have to organic fertilizer

D if it is dark, then an owl will find a mouse by the sound the mouse makes​

Answers

Answer:

D. if it is dark, then an owl will find a mouse by the sound the mouse makes

non examples of kinetic energy

Answers

Answer:

Anything that isn't moving

Which action describes the first step in both scientific investigation and technological design?

researching how solar panels work
identifying a need for a solar panel
communicating to the team that solar panels are easy to install
designing a solution by sketching a prototype for a solar panel

Answers

Answer:

The best answer would be D

Explanation:

This would be best because if you sketch about an object or thing you are making it can help you better picture what you are making or someone else therefore the answer is D

Answer:

Answer is D fs

Explanation:

*designing a solution by sketching a prototype for a solar panel*

Two children fight over a toy. One pulls with a force of 8N to the right. The other pulls with
a force of 6N to the left. What is the strength and direction of the net force on the toy?

Answers

Answer: To the right

Explanation:

8n is more strength then 6n periodt pooh ✨

When two children fight over a toy. One pulls with a force of 8N to the right. The other pulls with a force of 6N to the left then the net force on the toy would be 2 N to the right.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem, two children fight over a toy. One pulls with a force of 8N to the right. The other pulls with a force of 6N to the left.

Net force = 8 - 6

                = 2 Newtons

Thus, the net force of the toy comes out to be 2 Newtons.

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The speed of an object undergoing constant acceleration increases from 8.0 m/s to 12.0 m/s in 10.0 seconds. How far does the object travel during the
10.0 seconds?
4 m
100 m
800 m
10 m

Answers

Answer:

is the question finnished

Explanation:

I need help because I don’t understand that question

Answers

I think you multiple both of them, give me a second and I’ll figure it out!

Using the graphs on your notes, how are wavelength and frequency related to sound waves? Make sure to use proper terminology in your response.

Answers

The higher the frequency of sound waves the shorter their wavelength. This presumes that sound waves in air have almost a constant speed of around 330 m/s

What was the instantaneous speed of Bear A at 5 seconds in meters/min? (No unit conversions necessary, no units required for answer).

Answers

Answer:

Answer: The answer is 40.

Explanation: There is a typo, they mean 5 minutes. Five minutes is the line between zero and 10, and the dot matches up at 5 and 200. 200 divided by 5= 40.

(i got this answer from: https://brainly.com/question/18253554)

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