what is an equation of the line that is parallel to y=-5x+6 and passes through the point (-4,-1)​

Answers

Answer 1

Answer:

y= -5x - 21

Step-by-step explanation:

parallel lines have the same slope, so you know the slope.

you need to use the point slope formula y-y1=m(x-x1)

with this equation, this looks like y - -1 =- 5(x - -4)

double negatives are positives, so to keep this easier on the eyes, let's make it y + 1= -5(x + 4)

distribute the -5. you should get y + 1 = -5x - 20

subtract 1 to move it from the left side to the right and you get your answer!

y = -5x - 21


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In triangle ABC, AB measures 25 cm and AC measures 35 cm. The inequality < s < represents the possible third side length of the triangle, s, in centimeters. The inequality < p < represents the possible values for the perimeter, p, of the triangle, in centimeters.

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Answer:

The inequality 10 < s < 60 represents the possible third side length of the triangle, s in centimeters.

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Step-by-step explanation:

Firsts one The lower number has to be the difference between the bigger number and smaller number. In this case 35 - 25 = 10 and the s < 60 has to be the sum of both numbers.

Second one. I'm assuming it's just the sum of the two numbers to the first answer, and the second number is just the second number from the previous one, but multiplied by 2. Sorry that I couldn't go into too much detail about this one

The inequality that represents the possible third side length

[tex]10cm<s<60cm[/tex]

The inequality that represents the possible values for the perimeter

[tex]70cm<P<120cm[/tex]

Given :

In triangle ABC, AB measures 25 cm and AC measures 35 cm.

For any triangle , we know that the sum of measures of two sides is greater than the third side

Let 's' be the third side length

[tex]25+35>s\\60>s\\\\Also , s+25>35\\s>35-25\\s>10\\Inequality\; is \;\\10<s<60[/tex]

Now we find the perimeter when s=10

Perimeter = sum of all the sides

[tex]s=10\\P=25+35+10=70\\s=60\\P=25+35+60=120[/tex]

[tex]70<P<120[/tex]

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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If the font is too small, it says x^8 all over top 256y^20 as one big fraction.

========================================================

Work Shown:

[tex]\left(\frac{5x^3}{20xy^5}\right)^4\\\\\\\left(\frac{x^2}{4y^5}\right)^4\\\\\\\frac{\left(x^2\right)^4}{(4^1)^4\left(y^5\right)^4}\\\\\\\frac{x^{2*4}}{4^{1*4}y^{5*4}}\\\\\\\frac{x^{8}}{4^{4}y^{20}}\\\\\\\frac{x^{8}}{256y^{20}}\\\\\\[/tex]

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.

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