Waste dairy whey is used to grow Kluyveromyces fragilis yeast in a continuous culture system operated at 30C and 1 atm pressure. Medium containing 4% w/w lactose (C12H22O11) and 0. 15% w/w NH3 flows into a specially designed aerated bioreactor at a rate of 200 kg h21. The reactor is compartmentalised to facilitate gravity settling of the yeast; a suspension containing concentrated cells is drawn off continuously from the bottom of the reactor at a rate of 40 kg h21, while an aqueous waste stream containing 0. 5 kg cells per 100 kg leaves from the top. All of the lactose provided is utilised by the culture. The biomass yield from lactose is known from preliminary experiments to be 0. 25 g g21. The composition of the K. Fragilis biomass is determined by elemental analysis to be CH1. 63O0. 54N0. 16 1 7. 5% ash.


Required:

a. What is the RQ for this culture?

b. It is proposed to supply the reactor with air at a maximum flow rate of 305 litres min21. Will this provide sufficient oxygen? If not, what minimum level of oxygen enrichment of the air is needed if the total gas flow rate is 305 litres min21?

c. What is the concentration of residual NH3 in the aqueous waste stream?

d. What is the concentration of cells in the cell concentrate?

6.15 grams of carbon dioxide is form when 8.94 g of oxygen is completely react.

Mass of any substance will be calculated from moles as :

n = W/M, where

W = required mass

M = molar mass

Given combustion reaction is:

CH₄ + 2O₂ → CO₂ + 2H₂O

Given mass of O₂ = 8.94 g

Molar mass of O₂ = 32.00 g/mole

Moles of O₂ = 8.94 / 32 = 0.279 mole

From the stoichiometry of the reaction, it is clear that:

2 moles of O₂ = produce 1 mole of CO₂

0.279 moles of O₂ = produce 1/2×0.279 = 0.139 moles of CO₂

Molar mass of CO₂ = 44 g/mole

Required mass of CO₂ will be calculated as:

W = n × M

W = 0.139 × 44 = 6.15 grams

Hence, option (2) is correct i.e. 6.15 grams.

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Answer:

Option 2/ B. 6.15 grams on edge.

Explanation:

S/o to the person above me, got it because of them.

Answer:

Oxygen is one of the most abundant elements on Earth. Oxygen accounts for 20.9% of the atmosphere, 45% of the Earth's crust (as oxide minerals) and also accounts for almost all of the mass of water on Earth (89%). It is found in a huge number of natural minerals including sulfates, phosphates, carbonates and oxides.

Explanation:

Hope this helps

Answer: not sure on actual answer, but heres a answer on a similar question with just different quantities.

Explanation: just minus the terms i got and u should be okay

Explanation:

use the diagram above to understand it

Answer:

Explanation:

i) Red as Methyl orange shows red color in acidic medium and hyrdochloric acid is acidic.

ii) In 10cm^3 of 0.100 mole/dm^3 of hydrochloric acid, there are:

10/1000*0.1 = 1.00x10^(-3) moles of hydrochloric acid were used.

Answer:

Water is the answer

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Answer:

Alchemy is based on mystic view of reality whereas chemistry is based on experiments, observations and facts.

Answer:

1.) Cu(NO₃)₂ + 2 NaOH --> Cu(OH)₂ + 2 NaNO₃

2.) CuO + 2 HCl --> H₂O +  CuCl₂

Explanation:

Both of these reactions are substitution/double displacement reactions. The base reaction looks like this: AX + BY --> AY + BX. In other words, the negative ion of the first molecule bonds to the positive ion of the second molecule, and vice versa.

The products of the first equation are:

Cu(NO₃)₂ + NaOH --> Cu(OH)₂ + NaNO₃

The OH⁻ and the NO₃⁺ are polyatomic ions, meaning they stay together in these types of reactions. When determining the products, make sure to take note of the charges on the ions because subscripts may be necessary to balance them out.

Now you need to balance the coefficients. When balancing equations, begin with an element that is not present in more than one molecule on either side (ex. the oxygen is in two molecules on the reactant side). Keep in mind that the subscripts should be multiplied by the coefficients when determining the number of some elements.

The balanced first equation is:

Cu(NO₃)₂ + 2 NaOH --> Cu(OH)₂ + 2 NaNO₃

The process for the second equation is nearly identical to the first. The balanced second equation is:

CuO + 2 HCl --> H₂O +  CuCl₂

Answer:

Energy is first released then arbsorbed the eventually it dissappears

Explanation:

Answer:

that's not good

Explanation:

microbes???? not good for a sewage system

Answer

changing from liquid to gas

Explanation

changing from liquid to gas

Explanation:

magnet will attract iron.

salt and water is left behind

The amount of heat required to purify the Al is 25.94 * 10^3 J

The term heat capacity refers to the amount of heat required to raise the temperature of a substance by 1K. The aluminum was heated from 298 K to 933 K then it melted.

The total heat required is;

H = ncdT + nL

H = (1 * 24 * (933 - 298)) + (1 * 10.7 * 10^3)

H = 15.24 * 10^3  J + 10.7 * 10^3 J

H = 25.94 * 10^3 J

Learn more about heat capacity: https://brainly.com/question/1453843

Answer:

6 Energy levels

Explanation:

First Energy Level: 2

Second Energy Level: 8

Third Energy Level: 18

Fourth Energy Level: 25

Fifth Energy Level: 8

Sixth Energy Level: 2

Hope this helps.

Answer:

Humans :)

Explanation:

Humans have killed so many species of wolves, deer, tigers, lions and bears oh my!

In the food chain, we, humans are at the top because of this

After boiling the mixture of iron salt, water

iron, and salt it will remain and water will be evaporated

Answer:

hydrogen bond exists between nucleotides

Answer:

phosphodiester

Explanation:

Noncovalent hydrogen bonds connect the nucleotides that make up each DNA strand. Individual hydrogen bonds are weaker than covalent bonds like phosphodiester bonds. But they are so numerous that they strongly connect the two DNA polymers.

I hope this helps you

:)

The ionization potential of Ba(OH)2 was found to be 8±1 eV, with a value of 6±1 eV for the monohydroxide.

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log(2.4\times 10^{-6})[/tex]

[tex]\\ \rm\Rrightarrow pH=-log2.4-log10^{-6}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.38+6[/tex]

[tex]\\ \rm\Rrightarrow pH=5.62[/tex]

Answer:

B, E

Explanation:

Edge

Answer:

1. LR: Cl2,      ER: Al                2. LR: CHCl3

Explanation:

1. Find g/moles of Al and Cl2

g/moles of Al: 0.74 and Cl2 is 0.42

We can find the limiting reactant by take those number divided by 2 and 3

0.74 divided by 2 = 0.37

0.42 divided by 3 = 0.14 so 0.14 is the least -> that going to be the limiting reactant. (Cl2)

Now we know Al is a excess reactant.

2. That equation is already balanced and it's already give us 0.36 mole of chlorine, now we just need to find the mole of chloroform ( CHCl3 )

To do that we need to find the molar mass of CHCl3 which is 119.0 g/moles

then take 25 grams ÷ by 119g/moles we will get: 0.21 mole of CHCl3 that's mean CHCl3 is a limiting reactant.

Answer:

Percent composition = mass of element in the compound/mass of compound × 100

In this case, the mass of the compound is its molar mass.

Percent Composition of N in CO(NH2)2 (urea)

Molar mass CO(NH2)2 = 60.056 g/mol

Mass of N = 2×14.007 g/mol = 28.014 g/mol

%N: 28.014 g/mol/60.056 g/mol × 100 = 46.646%

Percent Composition of N in NH4NO3 (ammonium nitrate)

Molar mass of NH4NO3 = 80.044g/mol

Mass of N = 2×14.007 = 28.014 g/mol

%N: 28.014 g/mol/80.044 g/mol × 100 = 34.998%

Hope this helps, please let me know If I'm wrong.

Answer:

breathing

Explanation:

Your welcome lol

hope this helps :) pls give brainliest

Answer:

SEE BELOW

Explanation:

The act or process of breathing i.e the inhaling of oxygen and the exhaling of carbon dioxide. The process in which cells use oxygen to break down sugar and obtain energy which is used for various purposes.

Answer:

C3H8

Explanation:

1 1.5mol

2 0.75mol

3 0.667mol

Questions 1.2

1 16.7mol

2 8.3×10−3mol

Questions 1.3

1 9

2 11

3 12

4 24

5 22

Questions 1.4

1 a) 151.9

b) 162.1

c) 60.0

d) 132.1

e) 388.8

2 a) 0.5mol

b) 2.5mol

c) 0.6mol

d) 2.0mol

e) 0.38mol

3 a) 180.6g

b) 44.46g

Questions 1.5

1 Mr = 277.9 moles of oxygen = 11

2 Mr = 474.3 moles of oxygen = 20

Questions 1.6

1 Cu2S

2 C3H8

3 CaFe2O4

Questions 1.7

1 a) 2H2 + O2 → 2H2O

b) I2 + 3Cl2 → 2ICl3

c) NaOH + Al(OH)3 → NaAlO2 + 2H2O

d) 2H2S + SO2 → 3S + 2H2O

e) 4NH3 + 3O2 → 2N2 + 6H2O

2 a) MgCO3 → MgO + CO2

b) Pb(s) + 2AgNO3(aq) → Pb(NO3)2(aq) + 2Ag(s)

c) Na2O(s) + H2O(l) → 2NaOH(aq)

d) 2FeCl2 + Cl2 → 2FeCl3

e) Fe2(SO4)3 + 6NaOH → 2Fe(OH)3 + 3Na2SO4

Questions 1.8

1 17.0g

2 60.7g

3 51.1%

Questions 1.9

1 1.2dm3

2 Volume of SO2 = 50cm3; mass of sulfur = 0.20g

Questions 1.10

1 a) 2.67moldm−3

b) 0.025moldm−3

c) 0.833moldm−3

2 a) 0.75mol

b) 0.044mol

c) 0.010mol

Answer:

1.76g of N

Explanation:

5.04g x 1mol/16mol x 2mol/5mol x 14.01g/1mol = 1.76g

Answer:

28.9

Explanation:

4.5+24.4

= 28.9

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