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Answer:

17 is the total perimeter of the shape on the perimeter grid

yes they are similar, one is 3/4ths of the other for all dimensions if you match it up right

Answer:

40%

Step-by-step explanation:

Given,

Here,

Percentage of girls=256/640×100%

= 40%

Answer:

[tex](x+3)^{2} +(y+5)^{2} =16[/tex]

Step-by-step explanation:

the general equation of a circle is

[tex](x-h)^{2} + (y-k)^{2} =r^{2}[/tex]

with (h,k) being the centre of the circle and r the radius

Answer: 20.4

Step-by-step explanation: U = 74°

Cos 74 = x/74

x = 74 * Cos 74

x = 20.39716433 or 20.4

Answer:

[tex] \: [/tex]

Step-by-step explanation:

A rectangle is a parallelogram with equal angles and the diagonals of a rectangle are of equal length.

[tex] \: [/tex]

Therefore,

[tex]\\ { \longrightarrow \qquad{ \sf{ \pmb {DF = EG}}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \sf{ \pmb {7x - 3 = 5x + 9}}}} \: \: \\ \\[/tex]

Subtracting 5x from both sides we get :

[tex] \\ { \longrightarrow \qquad{ \sf{ \pmb {7x - 5x - 3 = 5x - 5x + 9}}}} \: \: \\ \\[/tex]

[tex] { \longrightarrow \qquad{ \sf{ \pmb {2x - 3 = 9}}}} \: \: \\ \\[/tex]

Adding 3 to both sides we get :

[tex] \\ { \longrightarrow \qquad{ \sf{ \pmb {2x - 3 + 3 = 9 + 3}}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \sf{ \pmb {2x = 12}}}} \: \: \\ \\[/tex]

Dividing 2 from both sides we get :

[tex]\\ { \longrightarrow \qquad{ \sf{ \pmb { \frac{2x}{2} = \frac{12}{2} }}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \frak{ \pmb {x = 6}}}} \: \: \\ \\[/tex]

Therefore,

Answer :

⠀

Explanation :

⠀

[tex] \longrightarrow \sf \qquad {x}^{2} + 10x = 39[/tex]

⠀

We can write it as,

[tex] \longrightarrow \sf \qquad {x}^{2} + 10x - 39 = 0[/tex]

⠀

We have to find the two numbers a and b such that,

[tex] \longrightarrow \sf \qquad a + b = 10[/tex]

[tex] \longrightarrow \sf \qquad a b = 39[/tex]

⠀

Obviously, the two numbers are 3 and 13.

[tex] \longrightarrow \sf \qquad {x}^{2} - 3x + 13x - 39 = 0[/tex]

[tex]\longrightarrow \sf \qquad {x}(x - 3)+ 13(x - 3) = 0[/tex]

[tex]\longrightarrow \sf \qquad ({x}+ 13)(x - 3) = 0[/tex]

⠀

Whether, the value of x :

[tex]\longrightarrow \sf \qquad {x}+ 13 = 0[/tex]

[tex]\longrightarrow \pmb{\bf \qquad {x} = - 13}[/tex]

⠀

Whether, the value of x :

[tex]\longrightarrow \sf \qquad {x} - 3 = 0[/tex]

[tex]{\longrightarrow { \pmb{\bf \qquad {x} = 3}}}[/tex]

⠀

So,

The solutions of the given equations are given by equating the

variables to gives;

First part;

The given functions are;

y = -3·x² + 24·x + 3, and y = -4·x² + 25·x + 15

When the balloons collided, we have;

The height are equal, which gives;

y = y

-3·x² + 24·x + 3 = -4·x² + 25·x + 15

-3·x² + 24·x + 3 - (-4·x² + 25·x + 15) = x² - x - 12 = 0

Which gives;

x² - x - 12 = (x - 4) × (x + 3) = 0

x = 4, and x = -3

The time at which the balloon collide at the highest point is therefore;

Second part;

The given system of equations are;

x - y = 6

y = x² - 6

y = x - 6

Which gives;

x - 6 = x² - 6

x = x²

Which gives;

x = 0 or x = 1

Similarly, we have;

x = y + 6

Which gives;

y = (y + 6)² - 6

y² + 11·y + 30 = 0

(y + 5)·(y + 6) = 0

Which gives;

y = -5, or y = -6

When y = -5, we have; x = -5 + 6 = 1

The solution are therefore;

Third part;

The equations are; y = x + 7 and y = x² - 3·x + 7

At the solution, the u-values are equal, which gives;

y = y

x + 7 = x² - 3·x + 7

x² - 3·x + 7 - (x + 7) = 0

x² - 4·x = 0

x·(x - 4) = 0

x = 4, or x = 0

When x = 4, y = 4 + 7 = 11

When x = 0, y = 0 + 7 = 7

The solutions are located at points;

Fourth part;

Given that the point of intersection of the line and the quadratic function

is the point (2, 0), we have;

On the linear function, when y = 0, x = 2

The possible linear function functions is therefore;

x + y = 2

From the quadratic function that accompanies the above linear function, we have;

y = x² + 3·x + 2

When x = 0, y = 0² + 3×0 + 2 = 2

Therefore;

Learn more about the solutions of equations here:

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Answer:

im sorry i dont know what is the history

Answer:

Step-by-step explanation:

Known:

Given:

To find:

Brian's group ⇒ 1 garage in 12 hours ( [tex]\frac{1garage}{12hours}[/tex])

Sequoia's group ⇒ 1 garage in 16 hours ([tex]\frac{1garage}{16hours\\}[/tex])

To make it easier to calculate the time it would take if they worked together, we will write this expression:

[tex]\frac{1}{12} +\frac{1}{16} =\frac{4}{48} +\frac{3}{48} =\frac{7}{48} \\[/tex]

From this fraction we see that for 7 garages they would need 48 hours. . To calculate how much time they would need for

1 garage, we will further simplify the fraction.

Solving the worked together is would need

6.86 hours for one garage.

Answer:

Step-by-step explanation:

I need a graph. but from what you're telling me they are both 90 degrees

6. [tex]4(-8a-5b+3) = -32a-20b+12 = 12-32a-20b\\[/tex]

8. [tex]12(x+3y-6z) = 12x+36y-72z[/tex]

Hope that helped!

Answer:

area = 697.5 ft²

Step-by-step explanation:

Think of an outer large rectangle minus a smaller upper rectangle.

area = LW - lw

area = (45 ft)(20 ft) - (45 ft - 10 ft - 8 ft)(7.5 ft)

area = 900 ft² - (27 ft)(7.5 ft)

area = 900 ft² - 202.5 ft²

area = 697.5 ft²

Step-by-step explanation:

Let the measure of the third angle of the triangle be x.

As we know that,

Therefore,

[tex] \sf \longrightarrow {\angle{A}\ +\ \angle{B}\ +\ \angle{C}\ =\ 180^{\circ}} [/tex]

[tex] \sf \longrightarrow {85^{\circ}\ +\ 23^{\circ}\ +\ x\ =\ 180^{\circ}} [/tex]

[tex] \sf \longrightarrow {108^{\circ}\ +\ x\ =\ 180^{\circ}} [/tex]

[tex] \sf \longrightarrow {x\ =\ 180^{\circ}\ -\ 108^{\circ}} [/tex]

[tex] \bf \longrightarrow {\underline{x\ =\ 72^{\circ}}}\ \bigstar [/tex]

∴ Hence, the measure of the third angle of the triangle is 72°.

I think the answer is A sorry if it's wrong

answer

False

the x and y of Y=x+7 is x=-7 and y=7 not 100% sure pls someone recheck

Answer:

No real zeros for the function.

Explanation:

solve:

[tex]\sf y=(x-20)^2 +5[/tex]

so when f(y) = 0

[tex]\hookrightarrow \sf (x-20)^2 +5 = 0[/tex]

[tex]\hookrightarrow \sf (x-20)^2 = -5[/tex]

[tex]\hookrightarrow \sf (x-20) = \sqrt{-5}[/tex]

[tex]\hookrightarrow \sf x = \pm \sqrt{-5} +20[/tex]

[tex]\hookrightarrow \sf x = \sqrt{-5} +20, \ \sf x = -\sqrt{-5} +20[/tex]

check:

[tex]\hookrightarrow f \sf (\sqrt{-5} +20) = Not \ applicable[/tex], [tex]f \sf (-\sqrt{-5} +20) = Not \ applicable[/tex]

Answer:

No real zeros.

Step-by-step explanation:

Given... y = [tex](x-20)^{2} +5[/tex]

Since above equation has no real real value, there are no zeros.

But complex zeros are:

         [tex](x-20)^{2} +5=0[/tex]

          [tex](x-20)^{2} =-5[/tex]

I was late so mark the person above me Brainliest!

Answer:

answer is 266

Step-by-step explanation:

80% of 355 is 280

4% of 355 is 14

280-14=266

Answer:

she can take six round trips before her warning light turns on

Answer: The fixed amount Geet earns for each television is $60.

Step-by-step explanation: Geet sells televisions. He earns a fixed amount for each television and an additional $ 30 if the buyer gets an extended warranty. If Geet sells 17 televisions with extended​ warranties, he earns $ 1,530.Now, to find the fixed amount Geet earns for each television.Let the cost of fixed amount be .Number of television = 17.He earns total = $1,530.He earns additional amount = $30.Now, to get the fixed amount we put an equation: Subtracting both sides by 510 we get:Dividing both sides by 17 we get:Therefore, the fixed amount Geet earns for each television is $60.

Answer:

$15 Fixed Amount Per TV

Step-by-step explanation:

13 x 15 = 195 - Extended Warranty

845 - 195 = 650

650 ÷ 13 = 50 - Fixed Amount

Answer:

SEE BELOW

Step-by-step explanation:

1 - 12000 ft

2 - 10 minutes

3 - The third segment in he graph is not as steep as the first segment because the flight took more time to lose altitude than the time taken to gain altitude.

Hope it helped

Step-by-step explanation:

Total number of stickers is 500.

25% of the total number is hearts:

The rest of the stickers are stars:

The correct null hypothesis and alternate hypothesis will be

[tex]H_{0} =\mu=195\\H_{a} =\mu > 195[/tex]

It is given that

The mean price of a prom dress was $195. 00 with a standard deviation of $12. 0

Given that Alyssa thinks that her school is more fashion-conscious and that students spent more than $195.00.

She collected data from 20 people in her high school and found that the average price spent on a prom dress was $208.00.

Since she wants to check whether the sample mean [tex]\mu[/tex] is the same as the population mean  [tex]\mu[/tex] = 195

[tex]H_{0} =\mu=195\\H_{a} =\mu > 195[/tex]

(Right hypothesis  test)

Thus the correct null hypothesis and alternate hypothesis will be

[tex]H_{0} =\mu=195\\H_{a} =\mu > 195[/tex]

To learn more about null hypotheses follow

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Answer: OPTION A

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\bf\: Probability = \frac{4}{9}}[/tex]

Step-by-step explanation:

According to the given information,

Then, total pairs of pants = 2 + 1 + 2 = 5

Similarly,

Then, total number of T-shirts = 4

This gives us the total nunber of clothing articles with Jenny, i.e.,

Total pairs of pants + Total number of T-shirts

= 5 + 4

= 9

Now, the probability of pulling out a pair of black pants & a blue T-shirt will be:

Total pairs of black pants + Total nunber of blue T-shirts/Total clothing articles

= 2 + 2 / 9

= 4/9

[tex]\rule{150}{2}[/tex]

Answer:

A: (-2.12, 0.5)

D: (2, 5.12)

E: (3.5, -4.12)

I'm going to assume that the three digit numbers have a decimal :))

Answer:

v >_100

Step-by-step explanation:

there is a line underneath the sign it won't let me write that so I just wanted to let u know.

Answer:

0

Step-by-step explanation:

Its equal to something multiplied by 0 so it is 0

The given table is an example of constant exponential decay.

It is given that

X          Y

-4          16

-1           2

2          0.25

4          0.0625

5          0.03125

An exponential function is a relation of the form y = a^x, with the independent variable x ranging over the entire real number line as the exponent of a positive number a.

The y-value at -4 is 16 while the y-value at -1 is 2, a decrement of 1/8 times for an increment in x-value by 3

Again, the y-value at 2 is 0.25 while the y-value at 5 is 0.03125, a decrement of 1/8 times for an increment in x-value by 3.

In both cases, the rate of decrement is constant.

So we can say that this is an example of constant exponential decay.

We can also see this behavior from the attached graph.

Therefore, the given table is an example of constant exponential decay.

To get more about exponential function visit:

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Answer:

tony

Step-by-step explanation:

tony is older than him