If a soil has e=0.72, moisture content = 12% and Gs=2.72, find the weight of water in KN/m3 to be added to make the soil saturated.

Answers

Answer 1

Answer:

453 KN/m^3 of water should be added make the soil saturated.

Explanation:

As we know

Gs * w = S*e

S = Gs * w/e

S = 2.72 * 0.12/0.72 = 0.453

The amount of water to be added

0.453 *1000/10 = 453 KN/m^3


Related Questions

A total knee replacement experiences a spectrum of loading events, some rapid and some nearly steady state (but for a limited duration). Estimate the duration of the possible loading events, and compute the Deborah number for each, assuming a transition time for the polymer bearing of one day. Are any of these expected to occur in a fluid-like regime

Answers

Answer: your question is quite vague hence i will just give you the general answer regarding your question

answer : Deborah number = time of relaxation / time of observation

Explanation:

Estimate of the duration of the possible loading events

to estimate the duration of the possible loading events will first determine the Deborah number as shown

Deborah number = time of relaxation / time of observation

lets assume; Time of observation = 1 and time of relaxation = 1 day

Deborah number is dimensionless and it is used to determine viscoelastic behavior of a material hence the viscoelastic response during observation time is proportional to Deborah number

Taking the convection heat transfer coefficient on both sides of the plate to be 860 W/m2 ·K, deter- mine the temperature of the sheet metal when it leaves the oil bath. Also, determine the required rate of heat removal from the oil to keep its temperature constant at 45°C.

Answers

Answer:

Hello your question is incomplete attached below is the complete question

answer :

a) 95.80°C

b) 8.23 MW

Explanation:

Convection heat transfer coefficient = 860 W/m^2 . k

a) Calculate for the temp of sheet metal when it leaves the oil bath

first step : find the Biot number

Bi = hLc / K  ------- ( 1 )

where : h = 860 W/m^2 , Lc = 0.0025 m ,  K = 60.5 W/m°C

Input values into equation 1 above

Bi = 0.036 which is < 1  ( hence lumped parameter analysis can be applied )

next : find the time constant

t ( time constant ) = h / P*Cp *Lc  --------- ( 2 )

where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C

Input values into equation 2 above

t ( time constant ) = 0.10092 s^-1

Determine the elapsed time

T = L / V = 9/20 = 0.45 min

∴   temp of sheet metal when it leaves the oil bath

= (T(t) - 45 ) / (820 - 45)  = e^-(0.10092 * 27 )

T∞ =  45°C

Ti = 820°C

hence : T(t) = 95.80°C

b) Calculate the required rate of heat removal form the oil

Q = mCp ( Ti - T(t) ) ------------ ( 3 )

m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s

Cp = 434 J/kg°C

Ti =  820°C

T(t) = 95.80°C

Input values into equation 3 above

Q = 8.23 MW

Can anyone tell me all the corrects answers to these? I’m sorry if this is the wrong subject I’m not sure what to put it under but I really need help!

Answers

Answer:

Crankshaft position sensor - F     I can't quite make out the letter but it's the thing at the bottom almost touching the notched wheel.

Coil Module - B  

Knock Sensor - D

Coil Pack -E

Fuse Block - A

Powertrain Control Module - C

A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was 5 in.2 and that approximately 2.3 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 200 mpy for this alloy in seawater, estimate the time of submersion in years. The density of steel is 7.9 g/cm3.

Answers

Answer:

the estimated time of submersion is 17.7 years

Explanation:

Given the data in the question;

estimate the time of submersion in years.

we write down the relation between time of submersion and corrosion penetration as follows;

CPR(mpy) = K × W(mg) / [ A(in²) × p(g/cm³) × t(hr) ]

we solve for t

t = (K × W) / ( AP × CPR )

given that;  

Area A = 5 in²

W = 2.3 kg = 2.3 × 10⁶ mg

density of steel p = 7.9 g/cm³

CPR = 200

we know that K is 534

so we substitute

t = (534 × 2.3 × 10⁶ mg) / ( 5 in² × 7.9 g/cm³ × 200 mpy )

t = 1,228,200,000 / 7900

t = 155468.3544 hr

t = 155468.3544 hr × ( 1 yrs / ( 365 × 24 hrs )

t = 17.7 years

Therefore, the  estimated time of submersion is 17.7 years

If a nurse does not agree to the discipline set due to a complaint made against this nurse, after reviewing the proposed agreed order, they can request a

Answers

Ans: If the nurse doesn't agree with the proposed order, the conference provides the nurse with an opportunity to respond to the allegations and dispute the evidence or proposed disciplinary action and to provide additional information for the board's consideration.

4. Oil system cleaning products should not use solvents because:
A) O Solvents smell bad
B) Solvents are completely removed during the service
CO Solvents have no impact on dirt and debris
DO Solvents can damage certain plastics and rubbers found in the engine
<< Previous Page
Next Pag

Answers

Answer:

Solvents can damage certain plastics and rubbers found in the engine

Explanation:

A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as heat to boiler tubes that pass through the furnace. The combustion products pass from the furnace to a stack at 6500C. Water enters the boiler tubes as a liquid at 200C and leaves the tubes as saturated steam at 20 bar absolute. Calculate the rate (kg/h) at which steam is produced.

Answers

The rate at which steam is produced is equal to 701 kg/hour.

What is a Boiler?

A Boiler may be characterized as a type of device or instrument that significantly transforms water into steam. There are two types of boiler are found. They are water tube boilers and fire tube boilers.

According to the question,

The power generated by combustion, W = 813kW.

The efficiency of the boiler, η = 65% = 0.65.

Temperature, To = 650°C.

Water enters the boiler tubes as a liquid, T1 = 20°C.

Water leaves the tubes as saturated steam, P2 = 20 bar.

The enthalpy of water at 20°C, [tex]h_1[/tex] = 83.9kJ/kg.

The enthalpy of water at 20 bar pressure, [tex]h_2[/tex] = 2797.29kJ/kg.

Enthalpy change can be calculated by ΔH = [tex]h_2-h_1[/tex]

= 2797.29kJ/kg - 83.9kJ/kg = 2713.3 kJ/kg.

The total energy that can be developed can be calculated by the formula:

Q = W × η = 813 × 0.65 = 528.45 kW.

The mass of the flow rate of the rate at which steam is produced is calculated by the following formula:

[tex]m^.[/tex] = Q/ΔH

             = 528.45 kW/2713.3 kJ/kg.

             = [tex]\frac{528.45kW }{2713.3kJ/kg} *\frac{3600kJ/h}{1kW}[/tex] = 701 kg/hour.

Therefore, the rate at which steam is produced is equal to 701 kg/hour.

To learn more about Boilers, refer to the link:

https://brainly.com/question/15421700

#SPJ1

What distinguishes the research, investigation, and analysis phase from later phases of the historical preservation process?


It involves careful attention to the history of the structure.

It is the only phase that does not involve construction.

It is primarily involved with fact finding.

It is the only phase that does not involve design.

Answers

Answer:

c

Explanation:

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