HELPvppvy o o p pyvph​

HELPvppvy O O P Pyvph

Answers

Answer 1

Answer:

the answer is

[tex]24 \sqrt{2} [/tex]

HELPvppvy O O P Pyvph
HELPvppvy O O P Pyvph
HELPvppvy O O P Pyvph

Related Questions

50 points + brainliest
Choose A B C or D for problems 8, 9, 10, and 11
*No explanation needed*
TY:))))

Answers

Answer:

8. B.

9. B.

10. B.

11. No answer choices.

Step-by-step explanation:

Yes, they are all actually B. Hope this helps!

Answer: B, B, B

Step-by-step explanation: The last question has no answer choices shown.

It is never helpful to rewrite a quadratic equation in standard form as a first
step in solving it.
True or False

Answers

Answer:

false and can you please help me on my last question i posted its bout john henry

Step-by-step explanation:

a
An aircraft has just taken off from an airport, the
Formula for it heights above the ground (hm) after it has
travelled d m horizontally is h= 3/8(d-480), make d the subject of the formala.
Use your result to find d when h= 500m.

Answers

The value of d when h is 500m is approximately 1,813m

How to find the height of the aircraft

Give the heights above the ground (hm) after it has dropped expressed as:

h = 3/8(d-480),

If h = 500m, then;

500 = 3/8(d - 480)

Cross multiply

500*8 = 3(d - 480)

4000 = 3(d - 480)

Expand
to have:

4000 = 3d - 1440

3d = 5440

d = 1,813.3m

Hence the value of d when h is 500m is approximately 1,813m

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The perimeter of a rectangular balcony is 32 feet. The balcony is 12 feet long. How wide is it?

Answers

Answer:

4 feet wide because to find the perimeter you add all the numbers around

Find the commission on a sale of $600 with a 5% commission rate.
$15
$30
$50
$45
Pls help me

Answers

Answer:

30

Step-by-step explanation:

5% of 600 is 30 so that should be ur answer

A business owner opens one store in town A. The equation p(x)= 10,000(1.075)^ 5 represents the anticipated profit after t years. The business owner opens a store in town B six months later and predicts the profit from that store to increase at the same rate. Assume that the initial profit from the store in town B is the same as the initial profit from the store in town A. At any time after both stores have opened, how does the profit from the store in town B compare with the profit from the store in town A? 65% 96% 104% 154%

Answers

Answer:

It's 96%

Step-by-step explanation:

Just took the test

The profit from the store in town B compared with the profit from the store in town A is the ratio represented by 96%.

What is a ratio?

The ratio is the simplest form of a fraction involving two quantities determining each other. It is written as a:b, read as "a is to b", and functions as a/b.

How to solve the question?

In the question, we are given that a business owner opens one store in town A. The equation p(x)= 10,000(1.075)^t represents the anticipated profit after t years. The business owner opens a store in town B six months later and predicts the profit from that store to increase at the same rate.

We are asked to assume that the initial profit from the store in town B is the same as the initial profit from the store in town A and find the comparison between the profits from the store in town B to the store in town A.

We take the time for the store in town A as t1.

Then the time for the store in town B is t1 - 0.5, as store in town B is opened 6 months after the store in town A.

To compare the profits, we take the ratio of the profits from the stores.

= Profit from the store in town B/Profit from the store in town BA

= 10,000(1.075)^(t1 - 0.5)/10,000(1.075)^t1

= (1.075)^(t1 - 0.5 - t1)

= 1.075^(-0.5)

= 1/(1.075)^0.5

= 0.96448

= 96% (approx.)

Therefore, the profit from the store in town B compared with the profit from the store in town A is the ratio represented by 96%.

Refer to the attachment for the proper question.

Learn more about ratios at

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Eric recorded the total number of push-ups he did each minute for four minutes write the order number pairs as ordered pairs

Answers

Answer:

(1, 15), (2, 30), (3, 45), (4, 60)

Step-by-step explanation:

So the values are already given to you in the table, it's just a matter of turning them into ordered pairs. Ordered pairs are a set of numbers that represent a point on the coordinate plane. On the graph, the x-axis (horizontal) is for time and the y-axis (vertical) is for the amount of push-ups. An ordered pair is (x, y) so you put (amount of minutes, amount of push-ups). For how they're related, how many push-ups he did increases by 15 for every minute. So, the y-value increases by 15 when the x-value increases by 1.

Why should you find out what kinds of damage are common in your area?

Answers

Answer:

Wind. “The most common source or cause of damage is wind-related,” Scott Humphrey, second vice president of risk control at Travelers, told TODAY Home. ...

Nonweather-Related Water. ...

Hail. ...

Weather-Related Water.

Theft.

hope i correct

What does mean mean on sports teams

Answers

Answer:

Physical activy used for pleasure.

Step-by-step explanation:

It's just a meaning so I can't provide an explanation.

What is the value of x if the angles are complementary?

1.) 35

2.) 20

3.) 25

4.) 15 ​

Answers

Answer:

4.) 15

Step-by-step explanation:

90 - 75 = 15 which would be the answer.

what is the equation by looking at this graph y=-x+2, y=2x+2,y=x+3,y=x+2

Answers

Answer:

(32,92) and (−1,2)

Step-by-step explanation:

You have to equal the two Ys, meaning their values as well or you can find the value of the first x and then plug it in the second equation. There are many ways to solve this to.

The speed of hair growth for humans is about 1, centimeters per month. Susan's hair has grown 3 centimeters since the last time she got it cut. Let z be the number of months she has been growing her hair. Write a number model to show how many months she has been growing her hair. Then solve the problem.​

Answers

Answer: z = 3

Step-by-step explanation: 1 centimeter = 1 month so 3 centimeter = 3 months

Find the derivative of the function. f(x) = (tan5(x) + 2)^2

Answers

[tex]f(x) = (tan(5x)+2)^2\\\\f'(x) = 2(tan(5x) +2)*\frac{d}{dx}(tan(5x)+2) = 2(tan(5x)+2)*5sec^2(5x)\\ =(2tan(5x)+4)*5sec^2(5x)\\ =10tan(5x)*sec^2(5x)+20sec^2(5x)[/tex]

Hope that helps!

What is the domain and range of the function shown on the graph below

Answers

Answer:

C

Step-by-step explanation:

D: {-3,0,1,3}

R: {-5,-4,1,5}

Which of the following statements is true about the three quadrilaterals?
O E and Fare similar but not congruent.
O E and G are similar but not congruent.
O G and Fare similar and also congruent.
O E and G are similar and also congruent.

Answers

E and G are similar but not congruent

An ostrich is
running at a speed
of 43 miles per
hour
Is it proportional or non proportional

Answers

The relationship iof the ostrich running at 43 miles per hour is proportional.

Speed of the ostrich

Since speed = distance per unit time

The speed of the ostrich is 43 miles per hour. This means that the ostrich covers a distance of 43 miles every hour.

Since the ostrich always covers a distance of 43 miles every hour, we see that distance is proportional to time.

So, the relationship iof the ostrich running at 43 miles per hour is proportional.

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Change 7 square yard to feet

Answers

22 square feet !! hope this helps

Find the area of this rectangle if ( L= 5 1/2) and (w = 3 1/2)

Answers

Answer:

A= 19 1/4

Step-by-step explanation:

to find the area of a rectangle, it would be LxW

so you would take 5 1/2 x 3 1/2. this would give you 19 1/4


[tex]\begin{gathered} \rm Prove \: that :- \\ { { \rm { f ( x ) = f ( 0 ) + \dfrac{x}{1!} f'(0) + \dfrac{x²}{2!} f''(0) + \dfrac{x³}{3!} f'''(0) + \cdot \cdot \cdot \cdot \cdot \cdot \cdot }}}\end{gathered}[/tex]




Answers

The series you had provided is generally the Maclaurin's series , and we want to prove the series , this series is very very much useful in calculus , especially when you have to substitute a function by it's series . So now let's start !

Consider the function f(x) as series of a polynomials of nth (n ≥ 1) degree as

[tex]{\boxed{\bf{f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}}}[/tex]

Now , at x = 0

[tex]{:\implies \quad \sf f(0)=a_{0}+a_{1}(0)+a_{2}(0)^{2}+a_{3}(0)^{3}+a_{4}(0)^{4}+\cdots \cdots \infty}[/tex]

[tex]{\boxed{:\implies \quad \sf f(0)=a_{0}}}[/tex]

Now , again consider the function that we assumed

[tex]{:\implies \quad \sf f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}[/tex]

Differentiating both sides w.r.t.x will yield

[tex]{:\implies \quad \sf f^{\prime}(x)=0+a_{1}\times 1+a_{2}\times 2\times x+a_{3}\times 3\times x^{2}+a_{4}\times 4\times x^{3}+\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime}(x)=a_{1}+2a_{2}x+3a_{3}x^{2}+4a_{4}x^{3}\cdots \cdots \infty}[/tex]

Now , put x = 0 ;

[tex]{:\implies \quad \sf f^{\prime}(0)=a_{1}+2a_{2}(0)+3a_{3}(0)^{2}+4a_{4}(0)^{3}\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime}(0)=a_{1}}[/tex]

[tex]{\boxed{:\implies \quad \sf a_{1}=\dfrac{f^{\prime}(0)}{1!}}}[/tex]

Now , consider ;

[tex]{:\implies \quad \sf f^{\prime}(x)=a_{1}+2a_{2}x+3a_{3}x^{2}+4a_{4}x^{3}\cdots \cdots \infty}[/tex]

Differentiating both sides w.r.t.x now ;

[tex]{:\implies \quad \sf f^{\prime \prime}(x)=0+2\times a_{2}\times 1+3\times a_{3}\times 2\times x+4\times a_{4}\times 3\times x^{2}\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime \prime}(x)=2a_{2}+6a_{3}x+12a_{4}x^{2}+\cdots \cdots \infty}[/tex]

Now , putting x = 0 will yield ;

[tex]{:\implies \quad \sf f^{\prime \prime}(0)=2a_{2}+6a_{3}(0)+12a_{4}(0)^{2}+\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime \prime}(0)=2a_{2}}[/tex]

[tex]{\boxed{:\implies \quad \sf a_{2}=\dfrac{f^{\prime \prime}(0)}{2!}}}[/tex]

Now , similarly we can prove that ;

[tex]{\boxed{:\implies \quad \sf a_{n}=\dfrac{f^{n}(0)}{n!}}}[/tex]

Now , as we had considered ;

[tex]{:\implies \quad \sf f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}[/tex]

Now , putting the values we obtained above ;

[tex]{:\implies \quad \sf f(x)=f(0)+\dfrac{x}{1!}f^{\prime}(0)+\dfrac{x^2}{2!}f^{\prime \prime}(0)+\dfrac{x^3}{3!}f^{\prime \prime \prime}(0)+\dfrac{x^4}{4!}f^{\prime \prime \prime \prime}(0)+\cdots \cdots \dfrac{x^n}{n!}f^{n}(0)+\cdots \cdots \infty}[/tex]

Hence , Proved

A cloud directly above you is about 10° across. From the weather report, you know that the cloud is at an altitude of 2200 m. How wide is the cloud?

Answers

The width of the cloud is 12500 meters wide.

The situation forms a right angle triangle.

What is a right angle triangle?

Right angle triangle are triangle that has one of its sides as 90 degrees. The sides can be found using trigonometric ratios.

Therefore, the altitude is the opposite side of the triangle formed. The width of the cloud is the adjacent side of the triangle formed.

tan 10 = opposite / adjacent

Therefore,

tan 10° = 2200 / a

cross multiply

a = 2200 / tan 10°

a = 2200 / 0.1763269807

a = 12500 meters

Therefore, the width of the cloud is 12500 meters .

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I don't understand how the problem wants me to set up the equation, much less how to find the right answer.

Answers

Two things to remember first remember that in the given eq:
V=4/3piR^3 where r = radius
So we know we just need to plug the given equation for radius.
Where radius = 2x^3y^-4
V= 4/3pi(2x^3 * y^-4)^3
Remember the exponent rule: (a*b)^n = a^n*b^n
Also remember the negative exponent rule
X^-n = 1/x^n
Now with this:
V= 4/3 * pi(8x^9/y^12)
V= 32pi*x^9/3y^12
Or A

Given: ABCD is a parallelogram GEC ∠GEC≅∠HFA and AE ≅ FC .
Prove: △GEC≅△HFA.

Answers

Answer:

Step-by-step explanation:

3) Congruent segments added to congruent segments form congruent segments

4) [tex]\overline{AD} \parallel \overline{BC}[/tex] (opposite sides of a parallelogram are parallel)

5) [tex]\angle FAH \cong \angle GCE[/tex] (if 2 parallel lines are cut by a transversal, the alternate interior angles are congruent)

6) [tex]\triangle GEC \cong \triangle HFA[/tex] (ASA)

What is 0.666... in fraction FORM?

Answers

The answer is 2/3. O.6 repeating is 2/3

find the perimeter of the figure. round to the nearest tenth. numbers only. do not label.

Answers

The perimeter of the figure, rounded to the nearest tenth is: 17.2 units.

What is the Perimeter of a Figure?

Perimeter of a figure is the total length of all sides of the figure.

The distance formula, [tex]d = \sqrt{(x_2 - x_2)^2 + (y_2 - y_1)^2}[/tex], can be used to find the length of each segment of a figure on a coordinate plane.

Thus, we have:

A(0, 4)

B(4, 4)

C(1, 0)

D(4, 1)

Perimeter of the figure = AB + BC + CD + DA

AB = |4 - 0| = 4 units

BC = √[(1−4)² + (0−4)²]

BC = √25

BC = 5 units

CD = √[(1−4)² + (0−1)²]

CD = √10

CD = 3.2 units

DA = √[(0−4)²+ (4−1)²]

DA = √25

DA = 5 units

Therefore:

Perimeter of the figure = 4 + 5 + 3.2 + 5 = 17.2 units.

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Explain how you can use the Properties of Equality to solve the following equation:

72 = 5x + 2

Answers

Answer:

x=14

Step-by-step explanation:

subtract 2 from both of the sides

70=5x

divide each side by 5

x=14

what is the result of converting 81 inches to feet

Answers

Answer:

81 inches is 6.75 feet

Step-by-step explanation:

hope this helps

Answer:

6.75

Step-by-step explanation:

Given;

81 Inches to Feet

Note;

Formula of Inches to Feet : divide the length value by 12

Solve;

81/12 = 6.75

Thus, Result of converting 81 inches to feet is 6.75

[RevyBreeze]

Simplify Expression:
3b+8b+9b

Answers

Answer:

20b

Step-by-step explanation:

3+8+9

3+8=11

9+11=20

3b+8b+9b

3b+8b=11b

11b+9b=20b

Answer:

Since they all have the same variable, you add them all together. so it would be 20b !!

Step-by-step explanation:

Find the discriminant and State of real and imaginary solutions.

9n^2 - 3n - 8= -10

-2x^2 - 8x -14= -6​

Answers

[tex]\qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ 9n^2-3n-8=-10\implies 9n^2-3n+2=0 \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{9}n^2\stackrel{\stackrel{b}{\downarrow }}{-3}n\stackrel{\stackrel{c}{\downarrow }}{+2}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases}[/tex]

[tex](-3)^2-4(9)(2)\implies 9-72\implies -63\leftarrow \stackrel{\textit{two \underline{imaginary} solutions}}{\textit{no real solution}} \\\\[-0.35em] ~\dotfill\\\\ -2x^2-8x-14=-6\implies -2x^2-8x-8=0 \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{-8}x\stackrel{\stackrel{-8}{\downarrow }}{-8}=0\qquad \qquad \qquad \qquad (-8)^2-4(-2)(-8) \\\\\\ 64-64\implies 0\leftarrow \textit{one \underline{real} solution}[/tex]

Explain how to use the Zero-Product Property to find the solution of the equation 3x(x – 6) = 0.

Answers

Answers: set the expression 3x equals to 0 and set the expression x-6 equal to 0, then solve both equations for x

Step-by-step explanation: x = 0, x = 6

NEED HELP ASAP WILL MARK BRAINLIEST Read the following scenario and answer the questions. Your manufacturing company incurs several costs to make the finished product, which are cans of eco-friendly paint. You purchase 100 empty cans at $2.00 each and 200 labels for the cans of paint at $1.00 each. You have two employees who bottle the paint into the cans and one additional employee who places a label on each can. You take a printout from your clock where the employees have entered their time and find that the wages due to these three employees is $2,000.00. You must also pay payroll taxes in the amount of $140.00 total for these three employees. A number of other costs incurred must be taken into consideration as well: depreciation on the factory machine of $150.00, utilities of $200.00, prepaid insurance of $600.00, and property taxes on your building of $2,000.00. Prepare the journal entries to record the purchase of the raw materials, the labor incurred, and the overhead incurred. Assume that $100.00 of the raw materials and $1,000.00 of the indirect materials were used. Prepare the journal entries to assign these materials to the jobs and overhead. Of the $2,140.00 in factory labor, $500.00 was attributed to indirect labor costs. Prepare the journal entry to assign the labor to jobs and overhead. You determine that direct labor cost is the activity base for determining the predetermined overhead rate. The following information is known about the estimated annual costs: overhead costs: $18,000.00 direct labor costs: $25,000.00 What is the predetermined overhead rate? What is the journal entry to assign overhead to jobs? Prepare the journal entry to transfer costs to Finished Goods. A sale of the goods takes place. The goods are sold for $5,000.00. Prepare the journal entry to record this sale.

Answers

Answer:

answer is 2.8 im not sure so check with another person mark me as brainliest

Step-by-step explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

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