Answer:
part 1
F1 cross -
RR * rr
Rr, Rr, Rr, Rr
F2 Cross
Rr * Rr
RR, Rr, Rr, rr
Part 2
Black is dominant over white
Explanation:
Let the allele for red color trait be R and white color trait be r
Red is dominant over white
Genotype of true breeding parents
Red - RR
white - rr
F1 cross -
RR * rr
Rr, Rr, Rr, Rr
All the offspring are red and of genotype Rr
F2 Cross
Rr * Rr
RR, Rr, Rr, rr
RR: Rr: rr = 1:2:1
Phenotype ration
red (RR, Rr) : white (rr)
3:1
part 2
Black is dominant over white
hence, in first generation cross all mice become white
Good information is characterized by certain properties. Explain how you understand these characteristtics of good information. Use examples to better explain your answer.
Answer:
here is your ans
Explanation:
Characteristics of good quality information can be defined as an acronym ACCURATE. These characteristics are interrelated; focus on one automatically leads to focus on other.
Accurate
Information should be fair and free from bias. It should not have any arithmetical and grammatical errors. Information comes directly or in written form likely to be more reliable than it comes from indirectly (from hands to hands) or verbally which can be later retracted.
Complete
Accuracy of information is just not enough. It should also be complete which means facts and figures should not be missing or concealed. Telling the truth but not wholly is of no use.
Cost-beneficial
Information should be analysed for its benefits against the cost of obtaining it. It business context, it is not worthwhile to spend money on information that even cannot recover its costs leading to loss each time that information is obtained. In other contexts, such as hospitals it would be useful to get information even it has no financial benefits due to the nature of the business and expectations of society from it.
User-targeted
Information should be communicated in the style, format, detail and complexity which address the needs of users of the information. Example senior managers need brief reports which enable them to understand the position and performance of the business at a glance, while operational managers need detailed information which enable them to make day to day decisions.
Relevant
Information should be communicated to the right person. It means person which has some control over decisions expected to come out from obtaining the information.
Authoritative
Information should come from reliable source. It depends on qualifications and experience and past performance of the person communicating the information.
Timely
Information should be communicated in time so that receiver of the information has enough time to decide appropriate actions based on the information received. Information which communicates details of the past events earlier in time is of less importance than recently issued information like newspapers. What is timely information depends on situation to situation. Selection of appropriate channel of communication is key skill to achieve.
Easy to Use
Information should be understandable to the users. Style, sentence structure and jargons should be used keeping the receiver in mind. If report is targeted to new-comer in the field, then it should explain technical jargons used in the report.
8. Write a sentence that gives the name of the first web page you visited and one fact
about your career you learned there. Write another sentence about how you knew the
website was trustworthy.
9. Write a sentence that gives the name of the second web page you visited and one fact
about your career you learned there. Write another sentence about how you knew the
website was trustworthy.
10.Write a sentence that gives the name of the third web page you visited and one fact
about your career you learned there. Write another sentence about how you knew the
website was trustworthy.
11.Write a sentence that explains the action required from the person reading the e-mail.
You could tell your instructor to ask you if they have questions, or to set up a time to
meet to talk about the information in the e-mail. TIP: The action required section will be
just for practice. You won't actually need to set up a time to meet.
12.Write a clear, professional closing.
Answer:
Explanation:
8. The first web page is careers ggle . I learn that working for ggle is fun. The site is trustworthy because it is ggle.
9. The second web page is money usnews the-100-best-jobs. It talks about many different jobs and they are all very good. The site is trustworthy because US News is a famous newspaper.
10. The third web page is careers organisation. I learn that there are a lot of resources online to help you find jobs. It is a non-profit so it is trustworthy.
The type of Al that computers can use to generate and understand human speech is called__________
processing
Answer:
Language or Vocal processing
Explanation:
Language processing in AI is used to understand languages, dialects and phrases, these AI have been trained to understand human language.
What does Al stand for?
B. Artificial Ingenuity
A. Actual Intelligence
C. Artificial Intelligence
D. Algorithm Intel
In Scheme, source code is data. Every non-atomic expression is written as a Scheme list, so we can write procedures that manipulate other programs just as we write procedures that manipulate lists.
Rewriting programs can be useful: we can write an interpreter that only handles a small core of the language, and then write a procedure that converts other special forms into the core language before a program is passed to the interpreter.
For example, the let special form is equivalent to a call expression that begins with a lambda expression. Both create a new frame extending the current environment and evaluate a body within that new environment. Feel free to revisit Problem 15 as a refresher on how the let form works.
(let ((a 1) (b 2)) (+ a b))
;; Is equivalent to:
((lambda (a b) (+ a b)) 1 2)
These expressions can be represented by the following diagrams:
Let Lambda
let lambda
Use this rule to implement a procedure called let-to-lambda that rewrites all let special forms into lambda expressions. If we quote a let expression and pass it into this procedure, an equivalent lambda expression should be returned: pass it into this procedure:
scm> (let-to-lambda '(let ((a 1) (b 2)) (+ a b)))
((lambda (a b) (+ a b)) 1 2)
scm> (let-to-lambda '(let ((a 1)) (let ((b a)) b)))
((lambda (a) ((lambda (b) b) a)) 1)
In order to handle all programs, let-to-lambda must be aware of Scheme syntax. Since Scheme expressions are recursively nested, let-to-lambda must also be recursive. In fact, the structure of let-to-lambda is somewhat similar to that of scheme_eval--but in Scheme! As a reminder, atoms include numbers, booleans, nil, and symbols. You do not need to consider code that contains quasiquotation for this problem.
(define (let-to-lambda expr)
(cond ((atom? expr) )
((quoted? expr) )
((lambda? expr) )
((define? expr) )
((let? expr) )
(else )))
CODE:
; Returns a function that checks if an expression is the special form FORM
(define (check-special form)
(lambda (expr) (equal? form (car expr))))
(define lambda? (check-special 'lambda))
(define define? (check-special 'define))
(define quoted? (check-special 'quote))
(define let? (check-special 'let))
;; Converts all let special forms in EXPR into equivalent forms using lambda
(define (let-to-lambda expr)
(cond ((atom? expr)
; BEGIN PROBLEM 19
'replace-this-line
; END PROBLEM 19
)
((quoted? expr)
; BEGIN PROBLEM 19
'replace-this-line
; END PROBLEM 19
)
((or (lambda? expr)
(define? expr))
(let ((form (car expr))
(params (cadr expr))
(body (cddr expr)))
; BEGIN PROBLEM 19
'replace-this-line
; END PROBLEM 19
))
((let? expr)
(let ((values (cadr expr))
(body (cddr expr)))
; BEGIN PROBLEM 19
'replace-this-line
; END PROBLEM 19
))
(else
; BEGIN PROBLEM 19
'replace-this-line
; END PROBLEM 19
)))
Write the Flowchart to find Even number between 1 to 50
Answer:
See attachment for flowchart
Explanation:
Required
Flowchart to fine even from 1 to 50
The flowchart has been attached.
The rough algorithm (explanation) of the flowchart is as follows.
1. Start
2. Initialize num to 1
3. Check if num is less than or equal to 50
3.1 If yes
3.1.1 Check if num is even
3.1.1.1 If yes
3.1.1.2 Print num
3.1.3 Increase num by 1
3.2 If num is greater than 50
3.2.1 Stop
4. Goto 3
One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are received (not erased). Each packet gets erased independently with probability 0.8. How many packets should you send such that you can recover the message with probability at least 99%
Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / [tex]\sqrt{n*0.2*0.8}[/tex] ~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of n take the positive number
a predecessor of a work processor is
Answer: Printing of documents was initially accomplished using IBM Selectric typewriters modified for ASCII-character input. These were later replaced by application-specific daisy wheel printers, first developed by Diablo, which became a Xerox company, and later by Qume.
Explanation:
What are the disadvantages of using a series circuit in a lighting system?
Answer:
Throughout the following segment, the disadvantages of the given topic are summarized.
Explanation:
It's indeed impossible to monitor each unit, but the entire series can be switched open or closed.Unless the series-connected components vary in any way, they include varying voltages through themselves which could create difficulty when you both need a certain voltage.Working with such positive and negative sequence loads on sequence is extremely challenging.what is cyber ethics
Answer:
cyber ethics
Explanation:
code of responsible behavior on the Internet. Just as we are taught to act responsibly in everyday life with lessons such as "Don't take what doesn't belong to you" and "Do not harm others," we must act responsibly in the cyber world.
PYTHON:
Defining a Figure of Merit
Consider a string-matching figure of merit. That is, it tells you how close to a given string another string is. Each matching letter in the same spot is worth one point. Only letters need be considered.
For instance, if the secret string reads 'BLACKBEARD', then 'BEACKBEARD' is worth 9 points, 'WHITEBEARD' is worth 5 points, 'BEARDBLACK' is worth 4 points, and 'CALICOJACK' is worth 1 point.
Compose a function pirate which accepts a string of characters guess and returns the number of characters which match the secret string 'BLACKBEARD'. It should be case-insensitive; that is, you should convert input to upper-case letters. It should return zero for strings which are not ten characters in length.
Your submission should include a function pirate( guess ) which returns a float or int representing the number of matching characters. (You should provide the secret string 'BLACKBEARD' inside the function, not outside of it.)
strings should not have same lengths
Answer:
figure of merit is a quantity used to characterize the performance of a device, system or method, relative to its alternatives. In engineering, figures of merit are often defined for particular materials or devices in order to determine their relative utility for an application.
Following are the Python program to find the string-matching figure:
Python Program:def pirate(g):#defining the method pirate that takes one variable in parameter
if len(g)!= 10:#defining if block that check the parameter length value that is not equal to 10
return 0 #using the return keyword that return a value that is 0
else:#defining else block
g= g.upper()#defining g variable that converts the parameter value into upper value
secretString = "BLACKBEARD"#defining string variable secretString that holds string value
c = 0#defining integer variable c that holds integer value
for i in range(0, len(g)):#defining loop that counts and check value is in string variable
if g[i] == secretString[i]:#defining if block that checks value in secretString variable
c += 1; #defining c variable that increments its value
return c;#using return keyword that return c value
print(pirate("BEACKBEARD"))#using print method that calls pirate method and prints its value
print(pirate("WHITEBEARD"))#using print method that calls pirate method and prints its value
print(pirate("BEARDBLACK"))#using print method that calls pirate method and prints its value
print(pirate("CALICOJACK"))#using print method that calls pirate method and prints its value
Output:
Please find the attached file.
Program Explanation:
Defining the method "pirate" that takes one variable "g" in parameter.Inside the method an if block that checks the parameter length value that is not equal to 10, and uses the return keyword that returns a value that is 0In the else block, define the "g" variable that converts the parameter value into the upper value, and use a string variable "secretString" that holds the string value. In the next step, define an integer variable "c" that holds an integer value, and define a loop that counts and checks the value in a string variable.Inside this, define if block that checks the value in the "secretString" variable, increments the "c" value, and returns the "c" value.Outside the method, a print method that calls the "pirate" method prints its value.Find out more about the string-matching here:
brainly.com/question/16717135
In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:
take a string input and store this in the variable str1
copy this string into another variable str2 using the String constructor
change str1 to the upper-case version of its current contents
print str1 on one line, then str2 on the next
1 /* Lesson 4 Coding Activity Question 2 */
2
3 import java.util.Scanner;
4
5 public class U2_L4_Activity_Two{
6 public static void main(String[] args){
7
8 Scanner = new Scanner(System.in);
9 String str1 = scan.nextLine();
10 String str2 = String(str1);
11 str1 = toUpperCase(str1);
12 System.out.println("str1");
13 System.out.println("str1");
14
15 }
16 }
Answer:
The corrected code is as follows:
import java.util.Scanner;
public class U2_L4_Activity_Two{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
String str1 = scan.nextLine();
String str2 = str1;
str1 = str1.toUpperCase();
System.out.println(str1);
System.out.println(str2);
}
}
Explanation:
This corrects the scanner object
Scanner scan = new Scanner(System.in);
This line is correct
String str1 = scan.nextLine();
This copies str1 to str2
String str2 = str1;
This converts str1 to upper case
str1 = str1.toUpperCase();
This prints str1
System.out.println(str1);
This prints str2
System.out.println(str2);
perceptron simplest definition
Answer:
A perceptron is a neural network with a single layer
What are the individual presentation objects that are found in the PowerPoint program and used to display content to an audience?
files
slides
cells
charts
Answer:
The answer is slides
Explanation:
If the pictures are not the same size when they are selected from a file,
PowerPoint will use AutoCorrect so they are the same size.
the picture will be overcorrected.
these pictures will remain the size as in the file.
the layout should be fit to the slide.
Answer:
The correct answer is C) the pictures will remain the size as in the file
Explanation:
Microsoft Office PowerPoint is a multi-media presentation tool. It supports, videos, pictures, and hyperlinks.
When a picture is inserted by selection from a file, PowerPoint does not automatically resize. The editor or user will need to manually adjust the size(s) of the picture(s) to fit the dimensions they require.
Cheers
what is class in python
Answer:
It is a code template for creating objects.
Answer:
What is a class? A class is a code template for creating objects. Objects have member variables and have behaviour associated with them. In python a class is created by the keyword class . An object is created using the constructor of the class.
You are on a team of developers writing a new teacher tool. The students names are stored in a 2D array called “seatingChart”. As part of the tool, a teacher can enter a list of names and the tool well return the number of students in the class found with names that matching provided list. For this problem you will be completing the ClassRoom class in the problem below. Your job is to complete the numberOfStudents found method. This method accepts an array of Strings that contain names and returns the quantity of students with those names. For example:
Assume that a ClassRoom object named “computerScience” has been constructed and the seating chart contains the following names:
“Clarence”, “Florence”, “Ora”
“Bessie”, “Mabel”, “Milton”
“Ora”, “Cornelius”, “Adam”
When the following code executes:
String[] names = {"Clarence", "Ora", "Mr. Underwood"};
int namesFound = computerScience.numberOfStudents(names);
The contents of namesFound is 3 because Clarence is found once, Ora is found twice, and Mr. Underwood is not found at all. The total found would be 3.
Complete the numberOfStudents method
public class ClassRoom
{
private String[][] seatingChart;
//initializes the ClassRoom field seatingChart
public ClassRoom(String[][] s){
seatingChart = s;
}
//Precondition: the array of names will contain at least 1 name that may or may not be in the list
// the seating chart will be populated
//Postcondition: the method returns the number of names found in the seating chart
//TODO: Write the numberOfStudents method
public int numberOfStudents(String[] names){
}
public static void main(String[] args)
{
//DO NOT ENTER CODE HERE
//CHECK THE ACTUAL COLUMN FOR YOUR OUTPUT
System.out.println("Look in the Actual Column to see your results");
}
}
Answer:
Wait what? Some of the words are mashed together...
A profit of ₹ 1581 is to be divided amongst three partner P,Q and R in ratio 1/3:1/2:1/5.theshareof R will be?
Answer:
R's share = 306
Explanation:
Sum of ratio = 1/3 + 1/2 + 1/5
LCM = 30
Sum of ratio = (10 + 15 + 6) / 30 = 31 /30
Profit to be shared = 1581
P = 1/3 ; Q = 1/2 ; R = 1/5
Share of R :
(Total profit / sum of ratio) * R ratio
[1581 / (31/30)] * 1/5
(1581 / 1 * 30/31) * 1/5
51 * 30 * 1/5
51 * 6 = 306
1. If Earth's plates are constantly moving, why don't we need to update the locations of -
continents on world maps (such as the one above) all the time?
The Value of Fossil Evidence
Answer:
Because the tectonic plates are moving so slowly in such small incraments that it would take a while before there was any noticable change.
Explanation:
Earth's plates are constantly moving, but we do not need to update the locations because the movement of the plates does not dramatically alter the surface of the Earth's landscape.
What are continents?Any of the numerous enormous landmasses is a continent. Up to seven geographical regions are typically recognized by convention rather than by any precise criterion.
The actions of plate movement take place closer to the Earth's crust, beneath the surface of the earth, and in the lithosphere.
The Earth's plates travel deep within the planet toward the crust, but when they intersect, the result is felt as earthquakes on the surface.
Thus, because plate movement has little impact on the terrain and positioning of the Earth's surface, it is not necessary to update the locations of continents on global maps.
To learn more about earth's plates, refer to the below link:
https://brainly.com/question/16802909
#SPJ2
Consider the language defined by the following regular expression. (x*y | zy*)* Does zyyxz belong to the language? Yes, because xz belongs to both x*y and zy*. Yes, because both xz and zyy belong to zy*. Yes, because zyy belongs to both x*y and zy*. No, because zyy does not belong to x*y nor zy*. No, because zyy belongs to zy*, but does not belong to x*y. No, because xz does not belong to x*y nor zy*. Does zyyzy belong to the language? Yes, because zy belongs to both x*y and zy*. Yes, because zyy belongs to both x*y and zy*. Yes, because both zy and zyy belong to zy*. No, because zy does not belong to x*y nor zy*. No, because zyy does not belong to x*y nor zy*. No, because zyy belongs to zy*, but does not belong to x*y
Answer:
Consider the language defined by the following regular expression. (x*y | zy*)* 1. Does zyyxz belong to the language?
O. No, because zyy does not belong to x*y nor zy*
2. Does zyyzy belong to the language?
Yes, because both zy and zyy belong to zy*.
Explanation:
the largest network in tje world is
the largest network in the world is the internet.
Answer:
it should be the internet
According to the article, each of the following
is a challenge in incorporating computer
science in classrooms EXCEPT?
Answer:
A
Explanation:
makes more sense to me, would have to read the articles to know
Edhesive 3.7 code practice
Answer: To hard to answer :)
Explanation: hurts my brain
9.4 code practice edhesive. PLEASE PLEASE PLEASE HELP
Answer:
a = [[34,38,50,44,39],
[42,36,40,43,44],
[24,31,46,40,45],
[43,47,35,31,26],
[37,28,20,36,50]]
for r in range(len(a)):
for c in range (len(a[r])):
if (a[r][c]% 3 != 0):
a[r][c]=0
for i in range(len(a)):
for j in range (len(a[i])):
print(a[i][j], end=" ")
print(" ")
Explanation:
We start off by declaring an array called "a". As introduced in the previous lessons, we use two for loops to fully go through all the rows and columns of the two-dimensional arrays. We then add in the line that checks if the remainder of any of these is not equal to zero, then print them as zero on the grid.
(I also got 100%)
mark as brainliest pls hehe
In this exercise we have to use the knowledge in computational language in python to describe a code that best suits, so we have:
The code can be found in the attached image.
What is the function range?The range() function returns a number series in the range sent as an argument. The returned series is an iterable range-type object and the contained elements will be generated on demand. It is common to use the range() function with the for loop structure. In this way we have that at each cycle the next element of the sequence will be used in such a way that it is possible to start from a point and go incrementing, decrementing x units.
To make it simpler we can write this code as:
a = [[34,38,50,44,39], [42,36,40,43,44], [24,31,46,40,45], [43,47,35,31,26],
[37,28,20,36,50]]
for r in range(len(a)):
for c in range (len(a[r])):
if (a[r][c]% 3 != 0):
a[r][c]=0
for i in range(len(a)):
for j in range (len(a[i])):
print(a[i][j], end=" ")
print(" ")
See more about python at brainly.com/question/19705654
Pleaseeeeee help!!!!
Answer:
1.klone
2.internet information services
3.nginx web server
4 apache HTTP
I hope you like it
Kenneth bought a new phone and added two of his friends' numbers to his phonebook. However, he forgot to transfer the phonebook from his previous phone beforehand. Help Kenneth keep the most up-to-date phone numbers for all his friends on his new device. That is, if there is a number saved on both old and new devices for the same friend, you should keep the number saved on the new phone; or if there is only one phone number for a friend, you should keep it, regardless of which device contains it.
Answer:
The program in Python is as follows:
phonedirs = {'Maegan': 1 , 'McCulloch': 2, 'Cindy': 3}
for i in range(2):
name = input("Name: ")
phonenum = int(input("Phone: "))
phonedirs [name] = phonenum
print(phonedirs)
Explanation:
Given
The instruction in the question is incomplete.
See attachment for complete question
Required
Write a code that carries out the 4 instructions in the attachment
See answer section for solution.
The explanation is as follows:
(1) This initializes the phone book
phonedirs = {'Maegan': 1 , 'McCulloch': 2, 'Cindy': 3}
The following is repeated for the two friends
for i in range(2):
(2) This gets the name of each friend
name = input("Name: ")
(2) This gets the phone number of each friend
phonenum = int(input("Phone: "))
(3) This updates the phone book with the inputs from the user
phonedirs[name] = phonenum
(4) This displays the updated phone book
print(phonedirs)
how do you open links in this app
Answer:
Hhhhh
Explanation:
Hhhh
Answer:
Explanation:
Don't open the links there viruses
Using the supplied file (lab10.json), write a program that prints each personâs name, along with their friendsâ LAST names. For example, the first line should look like this:Daisy Ingram is friends with Chase, Horton, Rollins.Hint: This particular JSON file starts with a square bracket [. That means that when you load it using the JSON library, it will be a list, rather than a dict.
How How How How How How How How
Implement the above in c++, you will write a test program named create_and_test_hash.cc . Your programs should run from the terminal like so:
./create_and_test_hash should be "quadratic" for quadratic probing, "linear" for linear probing, and "double" for double hashing. For example, you can write on the terminal:
./create_and_test_hash words.txt query_words.txt quadratic You can use the provided makefile in order to compile and test your code. Resources have been posted on how to use makefiles. For double hashing, the format will be slightly different, namely as follows:
./create_and_test_hash words.txt query_words.txt double The R value should be used in your implementation of the double hashing technique discussed in class and described in the textbook: hash2 (x) = R – (x mod R). Q1. Part 1 (15 points) Modify the code provided, for quadratic and linear probing and test create_and_test_hash. Do NOT write any functionality inside the main() function within create_and_test_hash.cc. Write all functionality inside the testWrapperFunction() within that file. We will be using our own main, directly calling testWrapperFunction().This wrapper function is passed all the command line arguments as you would normally have in a main. You will print the values mentioned in part A above, followed by queried words, whether they are found, and how many probes it took to determine so. Exact deliverables and output format are described at the end of the file. Q1. Part 2 (20 points) Write code to implement double_hashing.h, and test using create_and_test_hash. This will be a variation on quadratic probing. The difference will lie in the function FindPos(), that has to now provide probes using a different strategy. As the second hash function, use the one discussed in class and found in the textbook hash2 (x) = R – (x mod R). We will test your code with our own R values. Further, please specify which R values you used for testing your program inside your README. Remember to NOT have any functionality inside the main() of create_and_test_hash.cc
You will print the current R value, the values mentioned in part A above, followed by queried words, whether they are found, and how many probes it took to determine so. Exact deliverables and output format are described at the end of the file. Q1. Part 3 (35 points) Now you are ready to implement a spell checker by using a linear or quadratic or double hashing algorithm. Given a document, your program should output all of the correctly spelled words, labeled as such, and all of the misspelled words. For each misspelled word you should provide a list of candidate corrections from the dictionary, that can be formed by applying one of the following rules to the misspelled word: a) Adding one character in any possible position b) Removing one character from the word c) Swapping adjacent characters in the word Your program should run as follows: ./spell_check
You will be provided with a small document named document1_short.txt, document_1.txt, and a dictionary file with approximately 100k words named wordsEN.txt. As an example, your spell checker should correct the following mistakes. comlete -> complete (case a) deciasion -> decision (case b) lwa -> law (case c)
Correct any word that does not exist in the dictionary file provided, (even if it is correct in the English language). Some hints: 1. Note that the dictionary we provide is a subset of the actual English dictionary, as long as your spell check is logical you will get the grade. For instance, the letter "i" is not in the dictionary and the correction could be "in", "if" or even "hi". This is an acceptable output. 2. Also, if "Editor’s" is corrected to "editors" that is ok. (case B, remove character) 3. We suggest all punctuation at the beginning and end be removed and for all words convert the letters to lower case (for e.g. Hello! is replaced with hello, before the spell checking itself).
Do NOT write any functionality inside the main() function within spell_check.cc. Write all functionality inside the testSpellingWrapper() within that file. We will be using our own main, directly calling testSpellingWrapper(). This wrapper function is passed all the command line arguments as you would normally have in a main
mips Write a program that asks the user for an integer between 0 and 100 that represents a number of cents. Convert that number of cents to the equivalent number of quarters, dimes, nickels, and pennies. Then output the maximum number of quarters that will fit the amount, then the maximum number of dimes that will fit into what then remains, and so on.
Answer:
Explanation:
The following program was written in Java. It creates a representation of every coin and then asks the user for a number of cents. Finally, it goes dividing and calculating the remainder of the cents with every coin and saving those values into the local variables of the coins. Once that is all calculated it prints out the number of each coin that make up the cents.
import java.util.Scanner;
class changeCentsProgram {
// Initialize Value of Each Coin
final static int QUARTERS = 25;
final static int DIMES = 10;
final static int NICKELS = 5;
public static void main (String[] args) {
int cents, numQuarters,numDimes, numNickels, centsLeft;
// prompt the user for cents
Scanner in = new Scanner(System.in);
System.out.println("Enter total number of cents (positive integer): ");
cents = in.nextInt();
System.out.println();
// calculate total amount of quarter, dimes, nickels, and pennies in the change
centsLeft = cents;
numQuarters = cents/QUARTERS;
centsLeft = centsLeft % QUARTERS;
numDimes = centsLeft/DIMES;
centsLeft = centsLeft % DIMES;
numNickels = centsLeft/NICKELS;
centsLeft = centsLeft % NICKELS;
// display final amount of each coin.
System.out.print("For your total cents of " + cents);
System.out.println(" you have:");
System.out.println("Quarters: " + numQuarters);
System.out.println("Dimes: " + numDimes);
System.out.println("Nickels: " + numNickels);
System.out.println("Pennies: " + centsLeft);
System.out.println();
}
}