A phone company charges a base fee of $12 per month plus an additional charge per minute. The monthly phone cost can be represented by this equation: = 12 + • , where is the additional charge per minute, and is the number of minutes used. Which equation can be used to find the number of minutes a customer used if we know and ? a. = C-12/a b. =(−12)− c. =−12 d. = −12

Answer:

6.68, 13.37, 14.95

Step-by-step explanation:

One of the legs is twice as long as the other.

b = 2a

The perimeter is 35.

35 = a + b + c

The triangle is a right triangle.

c² = a² + b²

Three equations, three variables.  Start by plugging the first equation into the second and solving for c.

35 = a + 2a + c

c = 35 − 3a

Now plug this and the first equation into the Pythagorean theorem:

(35 − 3a)² = a² + (2a)²

1225 − 210a + 9a² = a² + 4a²

1225 − 210a + 4a² = 0

Solve with quadratic formula:

a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)

a = (210 ± √24500) / 8

a ≈ 6.68 or 45.82

Since the perimeter is 35, a = 6.68.  Therefore, the other sides are:

b ≈ 13.37

c ≈ 14.95

Answer:

D) 2a-6

Step-by-step explanation:

Graham sold 6 less = -6

Than double what Adriania sold. = 2a

2a - 6

Answer:

32 multiplied by 8 over 31 8 over 32 plus

Step-by-step explanation:

i think this is the answer not quite sure tho

Answer:

32 multiplied by 8 over 31 8 over 32 plus

Step-by-step explanation:

Explanation:

Let's say,

(x1,y)  (x2,y2)

are two points in a

xy

plane. We can find the shortest distance between two point by applying the distance formula stated as:

Distance

=√(x2−x1) 2+(y2−y1) 2

So by putting our given points

(x1,y1)=(6,−5) and (x2,y2)=(−1,−4)

in the distance formula, we have:

¯¯¯¯¯¯CD=√(−1−6)2+(−4−(5)2

Simplify to get:

5√2

To find the relative frequency of something, take the frequency and divide by the total number of data values.

Total number of data values = 1170

Row one: relative frequency = 5 / 1170 = 0.0043

Row two: relative frequency = 17 / 1170 = 0.0145

Row three: relative frequency = 52 / 1170 = 0.0444

Row four: relative frequency = 118 / 1170 = 0.1009

Row five: relative frequency = 172 / 1170 = 0.1470

Row six: relative frequency = 232 / 1170 = 0.1983

Row seven: relative frequency = 219 / 1170 = 0.1872

Row eight: relative frequency = 172 / 1170 = 0.1470

Row nine: relative frequency = 95 / 1170 = 0.0812

Row ten: relative frequency = 57 / 1170 = 0.0487

Row eleven: relative frequency = 23 / 1170 = 0.0197

Row twelve: relative frequency = 8 / 1170 = 0.0068

Answer: She has 38 nickels

Step-by-step explanation:

Let's define:

N as the number of nickels, D as the number of dimes, and Q as the number of quarters.

She has 140 coins in total, so we can writen:

N + D + Q  = 140.

And the total value is $19.00

Then we have:

N*0.05 + D*0.10 + Q*0.25 = 19

And "The difference in the number of dimes and the number of quarters is 10."

D - Q = 10.

So we have a system of 3 equations and 3 variables:

N + D + Q  = 140.

N*0.05 + D*0.10 + Q*0.25 = 19

D - Q = 10.

First, let's isolate one of the variables in the third equation, i will isolate D.

D = 10 + Q.

Now we can replace this in the other two equations:

N + (10 + Q) + Q = 140

N*0.05 + (10 + Q)*0.10 + Q*0.25 = 19.

Now we can isolate Q in the first equation:

N + 10 + 2*Q = 140

2*Q = 140 - 10 - N

Q = 130/2 - N/2. = 65 - N/2

Now we can replace this in the other equation:

N*0.05 + 10*0.10 + Q*(0.10 + 0.25) = 19

N*0.05 + 10*0.10 + (65 - N/2)*( 0.35) = 19

Now we can find the number of nickels.

N*0.05 + 1 + 22.75 - N*0.175 = 19

23.75 - N*(0.175 - 0.05)  = 19

23.75 - 19 = N*0.125

4.75/0.125 = N

38 = N

She has 38 nickels

Answer:

A or 38 nickels

Step-by-step explanation:

Answer:

(x,y)--(-X, "): A' is at (5, -1)

Step-by-step explanat

Answer:

(x,y)→(−x,−y); A' is at (5, −1)

Step-by-step explanation:

Answer:

y = -3

Step-by-step explanation:

2y +3y = -10 -5 (collect the terms then calculate)

5y = -15 ( divide both sides )

then you'll get your answer which is y = -3

Answer:

[tex]\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 30 & 24 & 6\end{bmatrix}[/tex]

Step-by-step explanation:

Given matrix is,

[tex]\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & 3 & -2 & 5\\ 0 & 10 & 8 & 2\end{bmatrix}[/tex]

Operations performed,

-10R₂ → R₂

[tex]\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 10 & 8 & 2\end{bmatrix}[/tex]

3R₃ → R₃

[tex]\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 30 & 24 & 6\end{bmatrix}[/tex]

Answer:

the multiple choice is A

Step-by-step explanation:

Answer:

One solution

Step-by-step explanation:

-4 + 6n = 7n

you will subtract (6n-6n) which will cancel each other out, than subtract (7n - 6n) which will be (1n)

So now you will have    -4 = 1n

Now you will divide ( -4/1) which is -4

You don't have to divide -4 with 1, because its the same way as multiplying it.

Now you will have -4 = n

Answer:

I think the first one.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

the answer is a i did the quiz

Step-by-step explanation:

Answer:

$909.62

Explanation:

If Sonjesa makes $47,300 a year and in a year there are 52 weeks we do the equation...

$47,300 / 52 weeks = weekly salary

47300 / 52 = 909.615

If we round that equals $909.62

Hope this helps!

Answer:

240

Step-by-step explanation:

57600=10×24×10×24

Answer:

A segment is called a perpendicular bisector of another segment if it goes through the midpoint and is perpendicular to the segment. While there can be many segments that bisect another segment, only one segment can be the perpendicular bisector.

Step-by-step explanation:

perpendicular bisector

Answer:

200 students

Step-by-step explanation:

Since there are 7 buses and 6 of them are full you would multiply 30•6. Then you would multiply 2/3 with 30 to find how many are on the 7th bus, which is 20. So you would add 180 and 20 to get the answer

Answer:

a, c, and f

Step-by-step explanation:

becuase i took the test

Answer:

Step-by-step explanation:

Umm

Answer:

(7,0)

Step-by-step explanation:

Answer:

This is a quadratic function, which is usually defined on all reals. But, the domain is restricted to x>=0 because it does not make sense to produce a negative number of units.

Find the vertex of the parabola at

(10.14, 164.5)

Since the parabola opens up, the range is y>=164.5

Step-by-step explanation:

Answer:

  1/6

Step-by-step explanation:

2/3 - 1/2 = 4/6 - 3/6 = 1/6

1/6 quart remains.

Answer:

There are 1/6 quarts left in the container.

Step-by-step explanation:

You need to subtract 1/2 (the paint used) by 2/3 (the paint in the container)

First, find the LCD (lowest common denominator) if you want to subtract.

3 x 2 = 6; you do the same to the numerator 2 x 2 = 4

4/6 (paint in the container)

2 x 3 = 6; you do the same to the numerator 1 x 3 = 3

3/6 (paint used)

Now, you subtract.

4/6 - 3/6 = 1/6 quarts

Answer:

It has three sides

Step-by-step explanation:

Common sense

Answer:

The properties in a right triangle include

-one 90 degree angle

-the two angles that are not the right angle (90 degree angle) will always be acute angles

-the hypotenuse can easily be found by using the Pythagorean Theorem (a squared plus b squared equals c squared

-it has three sides

-it has three angles

Answer:

1) Linear Pair

2) Adjacent

3) Complmentary

4) Vertical

Answer:

(-1,5)

Step-by-step explanation:

To find this, you have to add both "x" coordinates, then divide them by two.

Same thing goes for the "y" coordinates, add them, then divide them by two.

x-coordinates --->  2+(-4)= -2

y-coordinates ---> 1+9= 10

-2÷2= -1

10÷2= 5

That gives you, (-1,5).

Answer:

-27

Step-by-step explanation:

Answer:-27

Step-by-step explanation:

Answer: [tex]\frac{2(y^2-4y+40)}{(y-8)(y+4)}[/tex]

Step-by-step explanation:

To solve this problem, we want to make sure the denominators are the same on both fractions. Once they are equal, we can dd them together.

[tex]\frac{y+4}{y-8} +\frac{y-8}{y+4}[/tex]                      [multiply first fraction by y+4 and second by y-8]

[tex]\frac{(y+4)(y+4)}{(y-8)(y+4)} +\frac{(y-8)(y-8)}{(y-8)(y+4)}[/tex]   [distribute by FOIL]

[tex]\frac{y^2+8y+16}{(y-8)(y+4)} +\frac{y^2-16y+64}{(y-8)(y+4)}[/tex]   [add numerator]

[tex]\frac{y^2+8y+16+y^2-16y+64}{(y-8)(y+4)}[/tex]         [combine like terms]

[tex]\frac{2y^2-8y+80}{(y-8)(y+4)}[/tex]                       [factor out 2 from numerator]

[tex]\frac{2(y^2-4y+40)}{(y-8)(y+4)}[/tex]                  

Now we know that [tex]\frac{2(y^2-4y+40)}{(y-8)(y+4)}[/tex] is the factored form after adding.

Answer:

não sei....................