13. Solve for x. Please help

The machine can make 20 soda bottles each minute.

In Mathematics and Geometry, the slope of any straight line simply refers to the rate of change and it can be calculated by using this mathematical equation (expression);

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

From the information provided above, we have the following data points located on the line:

Substituting the given points into the slope formula, we have the following;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (140 - 100)/(7 - 5)

Slope (m) = 40/2

Slope (m) = 20.

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The ending balance if the amount is compounded continusoly is $6,244.84

The interest earned is $4,244.84.

If an amount is compounded continuously, it means that both the amount invested and the interest earned increases in value infinitely over the investment period.

The formula for calculating future value when there is continuous compounding is : A x e^r x N

Where:

Interest = future value - amount invested

2000 x e^0.04 x 3 = $6,244.84

Interest = $6,244.84 - $2000 = $4,244.84

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The arrow diagram that represents a mapping include the following: arrow diagram C.

The domain of this arrow diagram is equal to {a, c, d}

The range of this arrow diagram is equal to {q, r, s}.

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function is defined.

This ultimately implies that, a domain is the set of all possible input numerical values (x-values) to a function and the domain of a graph comprises all the input numerical values (real numbers) which are located on the x-coordinate.

In this scenario, we can reasonably infer and logically deduce that only the above mentioned relation (arrow diagram C) represents a function because each input variable (domain) has exactly an output variable (range) as illustrated in the diagram.

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The scale factor for the dilation in this problem is given as follows:

2.

A dilation happens when the coordinates of the vertices of an image are multiplied by the scale factor, changing the side lengths of a figure.

As the side lengths are changed, with a dilation the figure loses it's congruence relative to the original figure.

The equivalent side lengths in this problem are given as follows:

The dilated triangle is triangle DAB, hence the scale factor is obtained as follows:

k = 8/4 = 2.

(that is, the side lengths of triangle DEF were multiplied by 2 to generate triangle DAB).

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If the ratio of profit shares is 3:7:9, then the total profit yield is 38000.

What is ratio?

Comparing two amounts of the same units and determining the ratio tells us how much of one quantity is in the other. Two categories can be used to categorise ratios. Part to whole ratio is one, and part to part ratio is the other. The part-to-part ratio shows the relationship between two separate entities or groupings.

The share of Juma's profit is = 3

The share of Ali's profit is = 7

The share of Hassan's profit is = 9

The ratios can be written as 3x : 7x : 9x

The amount of money Juma received is = 6000

The equation for Juma's profit is -

3x = 6000

x = 6000/3

x = 2000

So, the value for Ali's profit -

7x = 7 × 2000

= 14000

The value for Hassan's profit -

9x = 9 × 2000

= 18000

Now, the total profit is represented by the equation -

= 3x + 7x + 9x

= 6000 + 14000 + 18000

= 38000

Therefore, the total profit is 38000.

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Here we are interested in finding the slope of the line. From the given graph we can see that that the line passes through points (6,0) and (0,-8) . We know that slope can be calculated by ,

[tex]\longrightarrow slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1} =\tan\theta [/tex]

[tex]\longrightarrow m =\dfrac{y_2-y_1}{x_2-x_1}\\[/tex]

[tex]\longrightarrow m =\dfrac{0-(-8)}{6-0}\\[/tex]

[tex]\longrightarrow m =\dfrac{8}{6}\\ [/tex]

[tex]\longrightarrow m =\dfrac{4}{3}\\ [/tex]

[tex]\longrightarrow \underline{\underline{ m = 1.\bar{3}}}[/tex]

And we are done!

The inequality to determine the number of 100-kilogram crates that can be loaded into the shipping container is 27500 ≤ 5400 + 100x

A shipping container will be used to transport several 100-kilogram crates across the country by rail. The greatest weight that can be loaded into the container is 27500 kilograms. Other shipments weighing 5400 kilograms have already been loaded into the container.

Therefore, the inequality that can be used to determine x, the number of 100-kg crates that can be loaded into the shipping container can be calculated as follows:

27500 ≤ 5400 + 100x

where

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The required of the sidewalk to the nearest square foot is 13.14 ft².

The area a rectangle occupies is the space it takes up inside the limitations of its four sides. The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth.

A circle's area is the area that it takes up in a two-dimensional plane. It can be simply calculated using the formula A = r2, (Pi r-squared), where r is the circle's radius. The square unit, such as m2, cm2, etc., is the unit of area.

We have,

Length = 5 ft, width = 2 ft, Radius of circle = 2 ft

Now,

Area of sidewalk = area of rectangle + area quadrant

Area of sidewalk = (5×2) + π(2)^2/4

Area of sidewalk = 10 + 3.14

Area of sidewalk = 13.14 ft²

Thus, required area of the sidewalk is 13.14 ft².

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Answer:

x=1

Step-by-step explanation:

4(5x-3)-3(2x-5)=17

20x-12-6x+15=17

14x+3=17

     -3.  -3

14x=14

/14.  /14

x=1

Answer: 3 11/12

Step-by-step explanation:

Rewrite the equation with the parts seperated:

4 + 2/3 − 3/4

Find the LCD of 2/3 and 3/4

(Which is 12)

Keep going

8/12−9/12= −1/12

Finally, subtract 4 − 1/12 to get 3 11/12

Hope this helps!

The original matrix's rank > the augmented matrix's rank. So the option C "the solution set is empty" is correct.

The matrix is

[tex]\left [ \begin{matrix}1 & 7&3 & -4\\ 0& 1& -1 & 3\\ 0& 0 & 0& 2\\ 0&0 & 1&1 \end{matrix} \right ][/tex]

To determine the solution set we simplify the given matrix by performing the row operations.

[tex]R_{4}\leftrightarrow R_{3}[/tex]

[tex]\left[\left.\begin{matrix}1 & 7 &3 \\ 0& 1 & -1\\ 0& 0 & 1\\ 0&0 &0 \end{matrix}\right|\begin{matrix}-4\\ 3\\ 1\\ 2\end{matrix}\right][/tex]

The rank of main matrix = 3

The rank of augmented matrix = 4

The rank of main matrix < The rank of augmented matrix

So, there is no solution. The solution set is empty.

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The complete question is:

The augmented matrix of linear system has been reduced by row operations to the form shown. Continue the appropriate row operations and describe the solution set of the original system:

[tex]\left [ \begin{matrix}1 & 7&3 & -4\\ 0& 1& -1 & 3\\ 0& 0 & 0& 2\\ 0&0 & 1&1 \end{matrix} \right ][/tex]

Select the correct choice below and; if necessary; fill in the answer boxes to complete your choice.

A: The solution set has exactly one element

B. The solution set has infinitely many elements

C. The solution set is empty

The solution to the expression with decimals rounded to the nearest tenth is: -2

Examine the hundredth number to round the decimal number to the nearest tenth. If the number is more than 5, multiply it by one. If it is less than 5, leave the tenth place value alone and eliminate any numbers after the tenth. 4.624, for example, is 4.6 rounded to the closest tenth.

Thus, given the expression:
2.29 + 9.11 + 15.381 - 5.414 - 7.631.11 + 5.99 - 5.734 + 6.893 - 18.355 -4.411

We first round them up to the nearest tenths is:

2.1 + 9.1 + 15.4 - 5.4 - 7.6 + 6.0 - 5.7 + 6.9 - 18.4 - 4.4  = -2

Thus, it is correct to state that the version of the above-given expression resolved to the nearest tenths (2.1 + 9.1 + 15.4 - 5.4 - 7.6 + 6.0 - 5.7 + 6.9 - 18.4 - 4.4) = -2

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Answer:1325

Step-by-step explanation:

Julio's down payment would be 20% of the total cost of the car. If he is financing $14,000 of the remaining cost, the total cost of the car would be $14,000 / (1 - 0.20) = $14,000 / 0.80 = $17,500. Therefore, Julio's down payment would be $17,500 * 0.20 = $3,500.

What is a percentage in plain English?

A percentage is a portion of a total stated as a number between 0 and 100 as opposed to being expressed as a fraction. The percentages of everything are 100%, nothing is 0%, 50% of something is 50%, and nothing is 0%. To calculate the percentage, divide the component by the total and multiply the result by 100.

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Using percentage, Julio's down payment would be  $3,500.

In contrast to being expressed as a fraction, a percentage is a portion of a total expressed as a number between 0 and 100. The percentages are as follows: 100% of everything, 0% of nothing, 50% of something, and 0% of nothing. Divide the component by the total, then multiply the result by 100 to get the percentage.

Julio's down payment would be 20% of the total cost of the car.

If he is financing $14,000 of the remaining cost,

the total cost of the car would be

$14,000 / (1 - 0.20)

= $14,000 / 0.80

= $17,500.

Therefore, Julio's down payment would be $17,500 * 0.20 = $3,500.

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The value of x is 76°. The solution has been obtained using the properties of hexagon.

What is a hexagon?

A closed, two-dimensional, six-sided polygon in geometry is called a hexagon. It has six vertices, which together create six internal angles, and six line segments. The total of a hexagon's internal angles is 720°.

We know that sum of angles on a straight line is 180°.

So, on the first line with angle 60°, the other angle will be

180° - 60° = 120°

Similarly, on the second line with angle 64°, the other angle will be

180° - 64° = 116°

Similarly, on the third line with angle 36°, the other angle will be

180° - 36° = 144°

Similarly, on the fourth line with angle 48°, the other angle will be

180° - 48° = 132°

Similarly, on the fifth and sixth lines with angle x°, the other angles will be

180° - x° = (180-x)°

We know that sum of angles of interior angles of a hexagon is 720°

Therefore,

⇒ 120° + 116° + 144° + 132° + (180-x)° + (180-x)° = 720°

⇒ 512° + 180° - x° + 180° - x° = 720°

⇒ 872° - 2x° = 720°

⇒ 2x° = 152°

⇒ x = 76°

Hence, the value of x is 76°.

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Answer:

height = 12

Step-by-step explanation:

The formula for the area of a triangle is: [tex]\frac{1}{2}(b*h)[/tex] = A

A = area of a triangle

b = base

h = height

The problem states that the area (A) of triangle is 48, and the base (b) is 8, so we can plug those values into the equation above:

48 = [tex]\frac{1}{2}(8*h)[/tex]

Let's solve for h now:

48 = [tex]\frac{1}{2}8h[/tex]

48 = 4h

h = 48/4

h = 12

Answer:

12 inches

Step-by-step explanation:

Formulae (Area of a triangle): 1/2 × Measure of Base × Measure of Height

Given Information:

Substitute the information into the formula to create an equation;

Solve the equation to find out the measure of the height;

Therefore, the measure of the height is 12 inches.

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Note that the figure with an angle of 300° on a circle in standard position is: "An angle in standard position with the terminal side at two-thirds of a full revolution counterclockwise." (Option D)

A standard position angle is one measured counterclockwise from the positive x-axis in a coordinate plane.

This signifies that the angle's starting side is on the positive x-axis, while the angle's terminal side is in the first or fourth quadrant. The angle's vertex is placed at the origin.

Angles are commonly measured in degrees or radians, with a full rotation being comparable to 360 degrees or 2 radians. Angles may now be readily graphed and compared to one another in a coordinate plane.

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The equation in slope-intercept form for this line is y = -5/4x + 3.

What is the slope-intercept form of the line?

The slope-intercept form is a way of representing the equation of a straight line in the form y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis). The slope of a line represents the steepness of the line, and the y-intercept represents the point at which the line crosses the y-axis.

A line can be represented by two points (x1, y1) and (x2, y2) the slope can be calculated by the formula:

m = (y2 - y1) / (x2 - x1)

In this case, the line passes through the point (-8, -9) and has a slope of -5/4, we can use the point-slope form of the equation of a line to find the equation of this line:

y - y1 = m(x - x1)

y - (-9) = (-5/4)(x + 8)

y = (-5/4)x + (-9) + (2*9)

y = (-5/4)x + 3

Hence, the equation in slope-intercept form for this line is y = -5/4x + 3.

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Answer:

What is the question please respond so I may give a complete response

Answer: c

Step-by-step explanation:

Answer:

Step-by-step explanation:

its $89,372 i did the math took the test

The coordinate points on the first quadrant represent the possible dimensions of the rectangle with an area of 32 m².

In geometry, two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

Given are two figures as shown in the image attached.

{ 1 } -

The image in question {12} cannot be proved congruent by AAS congruence rule.

{ 2 } -

For the triangles shown in question {13}, we can prove the triangles congruent by AAS rule as -

90° = 90°    { Equal right angles }

Sides opposites to right angles are equal. So, the angles opposite to these angles {let x° and  y°} will be equal. We can write -

x° = y°

Two equal sides given

Hence, triangles are proved AAS congruent rule.

Therefore, the triangles along with their respective congruency proofs are given above.

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The largest δ value of the given limit [tex]\lim_{x \to 1^+} \frac{1}{x^2-1}=\infty[/tex] and M=1000 is calculated. The required δ value is [tex]\delta=\sqrt{1+10^{-3}}-1[/tex].

When no values are defined, a limit is used to assign values to certain functions. It is possible to assess the limits using algebraic techniques. A collection of guidelines for manipulating limits when using other operators is known as the algebra of limits. Given the expression  [tex]\lim_{x \to 1^+} \frac{1}{x^2-1}=\infty[/tex]  and M=1000. When x>1, we write this expression as,

[tex]\begin{aligned} \frac{1}{x^2-1}& > 1000\\x^2-1& < 1000^{-1}=10^{-3}\\x^2& < 10^{-3}+1\\x& < \sqrt{1+10^{-3}}\end{aligned}[/tex]

Now, choosing, [tex]\delta=\sqrt{1+10^{-3}}-1[/tex] when we have δ > 0. Therefore, [tex]\sqrt{1+10^{-3}} > 1[/tex]. Then, [tex]x\in(1, 1+\delta)[/tex]. This is given by,

[tex]\begin{array}{ccc}1& < x& < 1+\delta\\1& < x& < \sqrt{1+10^{-3}}\end{array}[/tex]

This implies, [tex]\frac{1}{x^2-1} > 1000=M[/tex].

Therefore, the largest δ value will be [tex]\sqrt{1+10^{-3}}-1[/tex].

The complete question is -

For each limit, use graphs and algebra to approximate the largest δ or the smallest magnitude N that corresponds to the given value of ∈ or M, according to the appropriate formal limit definition.

[tex]\lim_{x\to 1^+} \frac{1}{x^2-1}=\infty[/tex], M=1000, find largest δ > 0.

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Answer:

ii) Reduce :

[tex]$\begin{aligned} 5 \ln x-2 \ln (x y) & =\ln x^5-\ln (x y)^2 \\ & =\ln \left(\frac{x^5}{(x y)^2}\right) \\ & =\ln \left(\frac{x^5}{x^2 y^2}\right) \\ & =\ln \left(\frac{x^3}{y^2}\right)\end{aligned}$[/tex]

iii ) Expand :

[tex]\begin{aligned}\log _3\left(\frac{x^5}{y}\right)^4 & =4 \log _3\left(\frac{x^5}{y}\right) \\& =4 \log _3 x^5-4 \log _3 y \\& =20 \log _3 x-4 \log _3 y\end{aligned}[/tex]

Answer:

[tex]\textsf{ii)} \quad \ln \left(\dfrac{x^3}{y^2}\right)[/tex]

[tex]\textsf{iii)} \quad 20 \log_3 x-4 \log_3y[/tex]

Step-by-step explanation:

Given expression:

[tex]5 \ln x-2 \ln (xy)[/tex]

[tex]\textsf{Apply the power law}: \quad n \ln x=\ln x^n[/tex]

[tex]\implies \ln (x^5) - \ln ((xy)^2)[/tex]

[tex]\textsf{Apply the quotient law}: \quad \ln x - \ln y=\ln \left(\dfrac{x}{y}\right)[/tex]

[tex]\implies \ln \left(\dfrac{x^5}{(xy)^2}\right)[/tex]

This is where the error occurred in the original calculation as the log quotient law was applied incorrectly.

[tex]\textsf{Apply exponent rule} \quad (ab)^c=a^{c}b^c\quad \textsf{to the denominator}:[/tex]

[tex]\implies \ln \left(\dfrac{x^5}{x^2y^2}\right)[/tex]

Simplify the fraction:

[tex]\implies \ln \left(\dfrac{x^3}{y^2}\right)[/tex]

Given expression:

[tex]\log_3\left(\dfrac{x^5}{y}\right)^4[/tex]

[tex]\textsf{Apply the log power law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 4\log_3\left(\dfrac{x^5}{y}\right)[/tex]

[tex]\textsf{Apply the log quotient law}: \quad n\log_a \left(\dfrac{x}{y}\right)=n\log_ax - n\log_ay[/tex]

[tex]\implies 4 \log_3 x^5-4 \log_3y[/tex]

This is where the error occurred in the original calculation as the coefficient 4 was not applied to the both logarithms when applying the log quotient law.

[tex]\textsf{Apply the log power law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 5 \cdot 4 \log_3 x-4 \log_3y[/tex]

[tex]\implies 20 \log_3 x-4 \log_3y[/tex]

Nine pencils at $0.05 each, 2. Five pencils at $0.10 each and three pencils at $0.05 each 3.Six pencils costing $0.05 apiece and three pencils costing $0.15 each. Pencils: four for $0.15 each, and five for $0.05 each.

This question uses the combination theory, which states that the total number of combinations of a set of items is equal to the number of variations in one item multiplied by the number of variations in the second item, and so on.

in this question

1. Nine pencils at $0.05 each: Kay can buy nine pencils for $0.45. Nine pencils times $0.05 each equal $0.45.

2. Five pencils at $0.10 each and three pencils at $0.05 each: Kay can buy five pencils for $0.50 and three pencils for $0.15.

Five pencils times $0.10 each equal $0.50 and three pencils times $0.05 each equal $0.15.

Adding the two totals together equals $0.45.

3. Three pencils at $0.15 each and six pencils at $0.05 each: Kay can buy three pencils for $0.45 and six pencils for $0.30.

Three pencils times $0.15 each equals $0.45 and six pencils times $0.05 each equal $0.30.

Adding the two totals together equals $0.45.

4. Four pencils at $0.15 each and five pencils at $0.05 each:

Kay can buy four pencils for $0.60 and five pencils for $0.25.

Therefore, Four pencils times $0.15 each equals $0.60 and five pencils times $0.05 each equal $0.25. Subtracting the two totals together equals $0.45.

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The solution of the given system of equations is (4, 7).

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

The given system of equations are y=3x-5 -------(I) and y=1/2 x+5 -------(II)

Substitute equation (I) in (II), we get

3x-5=1/2 x+5

3x-1/2 x=5+5

2.5x=10

x=4

Substitute x=4 in equation (I), we get

y=3(4)-5

y=7

So, solution is (4, 7)

Therefore, the solution of the given system of equations is (4, 7).

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The area under the density curve from 15 to 100 is 0.80.

With pdf f and cdf f, consider X to be a continuous random variable.

By definition, integrating the pdf yields the cdf: F(x)=x∫−∞f(t)dt.

By differentiating the cdf, one may find the pdf according to the Fundamental Theorem of Calculus: f(x) = ddx[F(x)]

An interval or group of intervals makes up the sample space of a continuous random variable, X.

1- 0.20 0.80

[tex]\int\limits^[/tex] f(x) dx from 0 to 100 = 1

[tex]\int\limits^[/tex]  f(x) dx from 0 to 15 + int 15 ^ 100 =1

[tex]\int\limits^[/tex]  d from 15 to 100 =1-0.20=0.80.

The area under the density curve from 15 to 100 is 0.80.

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Answer:

see below

Step-by-step explanation:

1 foot = 30 centimeters or 0.30 meters-

1 pound =450 grams or 0.45 kilograms-

1 fluid ounce = 29.5 milliliters-

According to the information ∠1 and ∠2 are complementary to each other.

∠1 ⊥ ∠2
Since PR is parallel to VO and RO is parallel to PV, it follows that PR is congruent to RO. This means that ∠1 and ∠2 are supplementary angles and thus, complementary.
Since PR // VO and RO // PV, then by the Transitive Property of Congruence, VO // PV.

Since PR ≅ RO and VO // PV, then by the Corresponding Angles Postulate, ∠1 ≅ ∠2.

Since ∠1 and ∠2 are congruent, then by the definition of complementary angles, ∠1 and ∠2 are complementary.

Thus, ∠1 and ∠2 are complementary.

∴ ∠1 and ∠2 are complementary

Congruent refers to something that is "absolutely equal" in terms of size and shape. The shapes hold true regardless of how we rotate, flip, or turn them. Draw two circles with the same radius, for instance, cut them out, and stack them on top of one another.

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