Write an equation of the line that passes through point (2,-4) and has the slope m= 1/2
y =

(-2,-4) , (-2, -3) , (-4, -3)

when you rotate 180° then the x and y of each point will become the opposite

Answer:

(x-2,y-4), (x-2,y-3) and (x-4,-y3)

Step-by-step explanation:

The rule is (x,y)-->(-x,-y) so

(x2,y4)=(x-2,y-4)

(x2,y3)=(x-2,y-3)

(x4,y3)=(x-4,-y3)

never mined rong center point It would not let me change any thange

The equation of the sum of any two squares x and y is x^2 + y^2 = (x + y)^2 - 2xy

The question is incomplete, as there are no parameters to determine the last digit of the first number.

So, I will give a general explanation

The sum of squares of two numbers x and y is:

[tex]x^2 + y^2 = (x + y)^2 - 2xy[/tex]

Assume the numbers are 5 and 6, then the equation becomes

[tex]5^2 + 6^2 = (5 + 6)^2 - 2*5*6[/tex]

Evaluate

[tex]5^2 + 6^2 = 61[/tex]

Read more about sum of squares at:

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Answer:

Given equation:

[tex]\sqrt{30-2x} =x-3[/tex]

Square both sides:

[tex]\implies (\sqrt{30-2x})^2 =(x-3)^2[/tex]

[tex]\implies 30-2x =(x-3)^2[/tex]

Expand the right side:

[tex]\implies 30-2x =x^2-6x+9[/tex]

Add [tex]2x[/tex] to both sides:

[tex]\implies 30 =x^2-4x+9[/tex]

Subtract 30 from both sides:

[tex]\implies x^2-4x-21=0[/tex]

Factor:

[tex]\implies (x-7)(x+3)=0[/tex]

Therefore,

[tex]x-7=0 \implies x =7[/tex]

[tex]x+3=0 \implies x=-3[/tex]

Substitute both values of [tex]x[/tex] into the original equation to check:

[tex]x=7 :[/tex]

[tex]\implies\sqrt{30-2(7)} =7-3[/tex]

[tex]\implies 4=4[/tex]

correct!

[tex]x=-3[/tex]

[tex]\implies\sqrt{30-2(-3)} =-3-3[/tex]

[tex]\implies 6 \neq =-6[/tex]

incorrect!

Therefore, [tex]x=7[/tex] is the only correct solution, and [tex]x=-3[/tex] is the extraneous solution

**Extraneous solution: a root of a transformed equation that is not a root of the original equation**

That's possible when function tends to zero

[tex]\\ \rm\hookrightarrow 0.25x^2-x+9.5=0[/tex]

[tex]\\ \rm\hookrightarrow 1/4x^2-x+19/2=0[/tex]

[tex]\\ \rm\hookrightarrow x^2-x+38=0[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{1-152}}{2}[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{151}i}{2}[/tex]

Answer:

8.5 ft

Step-by-step explanation:

[tex]f(x) = 0.25x^2 - x + 9.5[/tex]

To find the minimum point of the function, differentiate:

[tex]f'(x) = 0.5x - 1[/tex]

set to zero and solve for x:

[tex]f'(x) =0\\ \implies0.5x - 1=0\\\implies x=2[/tex]

Substitute found value of x into function to find y (height):

[tex]f(2) = 0.25(2)^2 - 2 + 9.5=8.5[/tex]

Therefore, the lowest point on the bottom edge of the banner is 8.5 ft above the floor.

Answer: A, C

Step-by-step explanation:

a) True since this is when the graph intersects the x axis.

b) False, this is a minimum, not a maximum.

c) True, this is tue turning point.

d) False, the axis of symmetry is x=-3, not y=-4.

Answer:

The value of x round to the nearest tenth is 12.04

Step-by-step explanation:

We have used trigonometric ratios to calculate the required value.

Answer:

B

Step-by-step explanation:

among the following below which of these represents a plane screen of a cellphone .

Answer:

see explanation

Step-by-step explanation:

8(16) + 8(6) ← factor out 8 from each term

= 8(16 + 6)

= 8(22)

= 8 × 22

= 176

Answer: 52 degrees

Step-by-step explanation:

Answer:

A: -6 + 2

Step-by-step explanation:

remember two negative signs makes a positive sign

Answer:

half

Step-by-step explanation:

Answer:

1/2 of the mango or half

Step-by-step explanation:

Answer:

The answer is 13.25 I'm so sorry if its incorrect please let me know so I can fix it

Answer:

B

Step-by-step explanation:

Plug in coordinates to see if they match the answer.

It's easier in slope-intercept form, so lets change it first.

-2x+y=7

+2x    +2x

y=2x+7

Now we can plug in the coordinates to see if they match.

Lets try A.

11=2(-2)+7

11=-4+7

11=3

A is incorrect.

Lets try B.

11=2(2)+7

11=4+7

11=11

B is a solution, therefore is on the graph.

Subtract the difference:

2690 - 284 = 2406

Divide by 2:

2406 / 2 = 1203

Ricky Had 1,203

Pedro had 1203 + 284 = 1,487

Area of a circle = pi x r^2

Area of the pizza = pi x 6 ^2 = 36pi

half the pizza = 36pi/2 = 18 pi

answer: 18pi

The point that approximates the solution for Tenisha's system of equations is (1, 1.4).

given functions are:

[tex]f(x) =log_{3} 5x\\\\f(x) = log_{5} (2x+8)[/tex]

One needs to plot the graphs and can get the intersection points of these two functions on coordinate axes and intersection points will be the required solution.

Find the attached graph

In the attached graph, we can see that the intersection point of given functions is approximately (1, 1.4)

Therefore, the point that approximates the solution for Tenisha's system of equations is (1, 1.4).

To get more about the graphs visit:

https://brainly.com/question/14323743

Answer:

1

Explanation:

1 is the mode due to the fact that it is repeated the most times out of all of the numbers in the expression that you gave (1 appears four times, whereas 2 only appears once, 3 only appears twice, 4 appears three times, and 5 also appears three times).

Answer:

The maximum height (vertex) is at (0,256), which is also when it began (Y-Intercept). It will take 4 units for it to hit the ground.

Let us know how you do on the test.

Answer:

[tex]\displaystyle -\sqrt{3} - 2[/tex]

Explanation:

If you recall the unit circle [from the polar graph], you would have no trouble at all figuring this out, but sinse you have trouble, do not worry about it. So, here is what you should have realised:

[tex]\displaystyle \boxed{1\frac{1}{2}\pi} = \frac{18}{12}\pi[/tex]

If you did not notise, [tex]\displaystyle 1\frac{7}{12}\pi,[/tex]or [tex]\displaystyle \frac{19}{12}\pi,[/tex]is just [tex]\displaystyle \frac{\pi}{12}[/tex]more than [tex]\displaystyle 1\frac{1}{2}\pi,[/tex]which means the exact value will either be a radical, followed by an integer or just a radical. In this case, accourding to the unit circle, you will have a radical, followed by an integer, and that will be this:

[tex]\displaystyle \frac{sin\:1\frac{7}{12}\pi}{cos\: 1\frac{7}{12}\pi} = tan\:1\frac{7}{12}\pi \\ \\ \boxed{-\sqrt{3} - 2} = \frac{sin\:1\frac{7}{12}\pi}{cos\: 1\frac{7}{12}\pi}[/tex]

It is all about memorisation of the unit circle, which I know is difficult, but you will get used to it soon.

*Now, if you had to find [tex]\displaystyle cos\:\frac{7}{12}\pi,[/tex]then the exact value would be the OPPOCITE of the exact value of [tex]\displaystyle sin\:\frac{7}{12}\pi,[/tex]which is [tex]\displaystyle -\frac{\sqrt{2} + \sqrt{6}}{4},[/tex]because you would be crossing into the second quadrant where the x-coordinates are negative, accourding to both the cartesian and polar graphs. In addition, sinse you ALREADY have both values for sine and cosine [accourding to your PREVIOUS QUESTION ASKED], all you need to do is divide both values in the order given above to arrive at the exact value for [tex]\displaystyle tan\:1\frac{7}{12}\pi.[/tex]

I am joyous to assist you at any time.

The mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Constants who are in multiplication with variables are called coefficients of those variables.

For example, in [tex]10x^2[/tex] we have 10 as coefficient of [tex]x^2[/tex]

Those variables who have got no visible coefficient has 1 as their coefficient. Thus, [tex]x^2[/tex] has got its coefficient as 1. It is true since 1 multiplied with any number is that number itself.( [tex]x^2 = 1 \times x^2[/tex] )

If we have [tex]a^b[/tex] then 'a' is called base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

[tex]a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\\\ a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\(ab)^c = a^c \times b^c[/tex]

For the considered situation, the expression that Anja is simplifying is:
[tex]\dfrac{10x^{-5}}{-5x^{10}}[/tex]

Anja simplified it to [tex]\dfrac{15}{x^{15}}[/tex]

She performed operations with variable 'x' correctly since

[tex]\dfrac{x^{-5}}{x^{10}} = \dfrac{1}{x^5} \times \dfrac{1}{x^{10}} = \dfrac{1}{x^{15}}[/tex]

But coefficients will also get divided. Instead of dividing 10 by -5, she subtracted them (as 10 - (-5) = 10 + 5 = 15)

This was her mistake.

The correct simplification would be: [tex]\dfrac{10x^{-5}}{-5x^{10}} = \dfrac{10}{-5} \times \dfrac{x^{-5}}{x^{10}} = -2 \times \dfrac{1}{x^{15}} = \dfrac{-2}{x^{15}} = -2x^{-15}[/tex]

Thus, the mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Learn more about exponent and bases here:

https://brainly.com/question/847241

Answer: c

Step-by-step explanation:

The inequality that can be used to determine whether the bag can be sold is; x + 7 >= 60

According to the question;

It then follows that since, the expected mass should be 60 grams.

The required inequality is; x + 7 >= 60

Read more on inequalities;

https://brainly.com/question/24372553

Answer:

the correct answer is : b

Answer:

Step-by-step explanation: