Why do some of the questions I type. Don't pop up any answers?

Answer:

Julie has 5 bunnies. She looses 2. How many bunnies does she have now?

Answer: 3 bunnies left

RIP BUNNIES!!

If you wanted a harder one, then please, be more specific.

Answer:

Their are many other answers to this question this is one of the ones that are correct.

Answer:

194

Step-by-step explanation:

you would do 340 divided by 2 and that gets you 170 then you would subtract 24 from Rita and that is 146 so Rita drove 146 miles. then for Joel you add 170 +24 = 194. So Joel drove 194 miles.

Answer:

[tex]\bold\purple{Quadratic \: \: eq {}^{n} = x {}^{2} - ( \alpha + \beta )x + \alpha \beta} \\ [/tex]

Sum of roots ,

[tex]( \alpha + \beta ) = (3 + 9) = 12[/tex]

Product of roots ,

[tex]( \alpha \beta ) = (3)(9) = 27[/tex]

Substituting the values in the above equation ,

[tex]\bold{x {}^{2} - ( \alpha + \beta )x + \alpha \beta} \\\\ \bold{⇢ x {}^{2} - (12)x + 27} \\\\ \bold\blue{ ⇢x {}^{2} - 12x + 27}[/tex]

hope helpful~

Answer:

girls = 61

boys = 73

Step-by-step explanation:

Let x = number of girls

Let y = number of boys

Given the difference between the number of the girls and the number of the boys in the outdoors club is 12:

⇒ y - x = 12

Given there are 4 times the number of the girls decreased by 25 equals 3 times the number of the boys:

⇒ 4x - 25 = 3y

Rearrange x - y = 12 to make y the subject:

⇒ y = 12 + x

Substitute x = 12 + y into 4x - 25 = 3y and solve for y:

⇒ 4x- 25 = 3(12 + x)

⇒ 4x- 25 = 36 + 3x

⇒ x = 61

Now we have found the value of x, substitute this into y = 12 + x and solve for y:

⇒ y = 12 + 61

⇒ y = 73

Answer:

A. multiplied by

Step-by-step explanation:

For example, sub n = 2

8(2) = 16

Hello.

The correct word is "multiplied by"

Eight multiplied by a number n equals 8n.

Remember that

[tex]\bigstar[/tex] We always write the number next to the variable.

[tex]\bigstar[/tex] We write the number and the variable together.

Can we write 8×n? Sure! However, we usually write it as

8n

Therefore, the correct answer is "[tex]\mathrm{multiplied\:by}[/tex]"

I hope it helps.

Have a great day.

[tex]\boxed{imperturbability}[/tex]

Answer: D

You get the same answer from doing both!

Answer:

a

Step-by-step explanation:

The investment of the kelly at the end of 8 years is $7393.78.

It is given that

The principle P= $5000

rate of interest R=4.9%

The rate is compounded monthly so

[tex]CI=P(1+\dfrac{R}{12}^{12t} )[/tex]

By putting the value

[tex]CI= 5000\times (1+\dfrac{0.049}{12}^{12\times8} )[/tex]

[tex]CI=7393.78[/tex]

Thus the investment of the kelly at the end of 8 years is $7393.78.

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Step-by-step explanation:

= a_(n-1) x 1.5

1.5a_(n-1)

Answer:

20%

Step-by-step explanation:

20 * 20% = 4

or you can change it to a decimal

20 * .2 = 4

hope this helped! :)

Answer:

4 maybe??...

Step-by-step explanation:

I really dunno P-P

25

Step-by-step explanation

Let the ones's digit =x.

So, sum of the digits =7

Tens's digit =7−x

Original no. =10(7−x)+x=70−10x+x=70−9x

Reversed no. =10x+7−x=9x+7

2(orig no) = reversed no. −2

2(70−9x)=9x+7−2

140−18x=9x+5

27x=135

x=5

Ten's digit =7−5=2

No. =25

Answer:

5mn(2m + 6n + 1)

Step-by-step explanation:

Look at the coefficients (the numbers): 10, 30, 5

The greatest common factor of 10, 30, and 5 is 5.

Now look at the variable parts of the three terms.

Start with the variable m.

There is m², m, and m.

The GCF of m², m, and m is m.

Now look at the variable n.

There is n, n², n.

The GCF on n, n², and n is n.

The GCF for the entire polynomial is 5mn.

Now we factor out 5mn from all terms.

To factor out 5mn, you divide each term by the GCF, 5mn.

10m²n + 30mn² + 5mn = 5mn(2m + 6n + 1)

The area of shaded region is 32 square units.

"The area can be defined as the space occupied by a flat shape or the surface of an object.  The area of a figure is the number of unit squares that cover the surface of a closed figure. The area is measured in square units such as square centimeters, square feet, square inches, etc."  

To find the area of the shaded region

1. Find the area of the biggest square ([tex]A_{1}[/tex])

Formula for area of a square

[tex]A_{1}[/tex] = side × side

⇒[tex]A_{1}[/tex] = 10×10

⇒[tex]A_{1}[/tex] = 100 square units.

2. Find the area of the unshaded region ([tex]A_{2}[/tex])

[tex]A_{2}[/tex] = X(biggest square)+ 2.Y(smallest square)

⇒[tex]A_{2}[/tex] = [tex](6[/tex]×[tex]6)[/tex] + [tex]2(4[/tex]×[tex]4)[/tex]

⇒[tex]A_{2} =36+2.(16)[/tex]

⇒[tex]A_{2}=68[/tex] square units

3. Find the difference of [tex]A_{1}[/tex] and [tex]A_{2}[/tex]

Area of the shaded part = [tex]A_{1}[/tex] - [tex]A_{2}[/tex]

= 100-68

= 32 square units.

Hence, The area of shaded region is 32 square units.

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Answer:

a way to not find the answer is to do anything but divide 9 by 16

Step-by-step explanation:

hope this helps, brainliest appreciated :)

Answer:

see image

Step-by-step explanation:

Supplementary means the angles add up to 180°.

Add the given angles and set equal to 180°

To solve, combine like terms, add 10, divide by two to get x all by itself.

Replace x with 95 to find the measures of Angles A, C, D.

Use the supplementary definition a second time to find the measure of Angle B.

see image.

Answer:

$1556.25

Step-by-step explanation:

Answer:

the answer is x=6

Step-by-step explanation:

Answer: 73.9

Step-by-step explanation:

Answer:

Step-by-step explanation:

Circumference formula: C = 2πr

Compare with given value and determine the radius:

Find the area of the cross-section.

Area formula: A = πr²

Area: A = 9²*π = 81π m²

Find radius

So.area

The expression that is equivalent to m(n(x)) is [tex]25x^{2} +90x+84[/tex].

It is given that

[tex]m(x) = x^{2} +3\\n(x) = 5x+9[/tex]

If there are two functions f(x) and g(x), f(g(x)) will be obtained by replacing x by g(x) into f(x).

So, [tex]m (n(x))= (5x+9)^2+ 3[/tex]

[tex]m (n(x))= 25x^{2} +81+90x +3[/tex]

[tex]m (n(x))= 25x^{2} +90x+84[/tex]

Therefore, the expression that is equivalent to m(n(x)) is [tex]25x^{2} +90x+84[/tex].

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Answer:

b

Step-by-step explanation:

Answer:

angle 2 is 85

Step-by-step explanation:

since its facing the 85

Answer:

Answer:1 is 95°

2 is 85°

3 is 95°

Step-by-step explanations

opposite angles are equal so 2 is 85° 95°Step-by-step explanation:directly opposite angles are equal so 2 is 85angles on a straight line add up to 180°

Answer:1 is 95°2 is 85°3 is 95°Step-by-step explanation:directly opposite angles are equal so 2 is 85angles on a straight line add up to 180° so 3 is 180-85=95°

Answer:1 is 95°2 is 85°3 is 95°Step-by-step explanation:directly opposite angles are equal so 2 is 85angles on a straight line add up to 180° so 3 is 180-85=95°then 3 is directly opposite to 1 so both are 95

Answer:1 is 95°2 is 85°3 is 95°Step-by-step explanation:directly opposite angles are equal so 2 is 85angles on a straight line add up to 180° so 3 is 180-85=95°then 3 is directly opposite to 1 so both are 95 I hope you're helped?

Answer:

7x, 4y

Step-by-step explanation:

terms are numbers with variables in expressions. usually able to count because + and - split them

Answer:

it is a pattern. 8: add 1. 9: multiply m by 3 to get n

Answer: 15

Step-by-step explanation:

We know that the scale factor of the dilation is the ratio of similtude, and that the ratio of similitude is equal to the ratio of the perimeters. So, the new perimeter is 30(0.5)=15.

A. Both [tex]f(x)[/tex] and [tex]g(x)[/tex] have the same domain of [tex](9, +\infty)[/tex].

In this question we must analyze the domain, range, x-intercepts and increase intervals:

[tex]Dom \{f(x)\} = \mathbb{R}[/tex]

[tex]Dom \{g(x)\} = \mathbb{R}[/tex]

Both functions are continuous.

[tex]Ran \left\{f(x)\right\} = (3.875, +\infty)[/tex]

[tex]Ran \{g(x)\} = (-5, +\infty)[/tex]

[tex]f(x):[/tex] [tex](x,y) = \emptyset[/tex]

[tex]g(x):[/tex] [tex](x,y) = (2.322, 0)[/tex]

[tex]f(x):[/tex] According to the graph, [tex]f(x)[/tex] increase over the interval of [tex](3.875, + \infty)[/tex].

[tex]g(x) :[/tex] According to the graph, [tex]g(x)[/tex] increase over the interval of [tex]\mathbb{R}[/tex]

After a quick analysis, we conclude that option A offer the best approximation to characteristics of both functions. [tex]\blacksquare[/tex]

The statement presents mistakes and is poorly formatted. Correct form is:

Given a polynomial function [tex]f(x) = 2\cdot x^{2}-3\cdot x + 5[/tex] and an exponential function [tex]g(x) = 2^{x}-5[/tex]. What key features do [tex]f(x)[/tex] and [tex]g(x)[/tex] have in common?

A. Both [tex]f(x)[/tex] and [tex]g(x)[/tex] have the same domain of [tex](9, +\infty)[/tex].

B. Both [tex]f(x)[/tex] and [tex]g(x)[/tex] have the same range of [tex](-\infty, 0][/tex].

C. Both [tex]f(x)[/tex] and [tex]g(x)[/tex] have the same x-intercept of [tex](2,0)[/tex].

D. Both [tex]f(x)[/tex] and [tex]g(x)[/tex] increase over the interval of [tex](-4, +\infty)[/tex].

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Answer: See below

Step-by-step explanation:

[tex]\begin{bmatrix}y=x^2-20x+73\\ y=-3x+3\end{bmatrix}[/tex]

[tex]\mathrm{Subtract\:the\:equations:}[/tex]

[tex]y=x^2-20x+73[/tex]

[tex]-[/tex]

[tex]\underline{y=-3x+3}[/tex]

[tex]y-y=x^2-20x+73-\left(-3x+3\right)[/tex]

[tex]\mathrm{Simplify:}[/tex]

[tex]0=x^2-17x+70[/tex]

[tex]x^2-17x+70=0[/tex]

[tex]\mathrm{Solve\:with\:the\:quadratic\:formula}[/tex] [tex]\mathrm{for\:}\ a=1,\:b=-17,\:c=70:[/tex]

[tex]x_{1,\:2}=\frac{-\left(-17\right)\pm \sqrt{\left(-17\right)^2-4\cdot \:1\cdot \:70}}{2\cdot \:1}[/tex]

[tex]x_{1,\:2}=\frac{-\left(-17\right)\pm \:3}{2\cdot \:1}[/tex]

[tex]\mathrm{Separate\:the\:solutions:}[/tex]

[tex]x_1=\frac{-\left(-17\right)+3}{2\cdot \:1},\:x_2=\frac{-\left(-17\right)-3}{2\cdot \:1}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=10,\:x=7[/tex]

[tex]\mathrm{Plug\:the\:solutions\:}x=10,\:x=7\mathrm{\:into\:}y=x^2-20x+73:[/tex]

[tex]\mathrm{For\:}y=x^2-20x+73\mathrm{,\:subsitute\:}x\mathrm{\:with\:}10[/tex]

[tex]y=10^2-20\cdot \:10+73[/tex]

[tex]y=10^2-200+73[/tex]

[tex]y=100-127[/tex]

[tex]y=-27[/tex]

[tex]\mathrm{For\:}y=x^2-20x+73\mathrm{,\:subsitute\:}x\mathrm{\:with\:}7[/tex]

[tex]y=7^2-20\cdot \:7+73[/tex]

[tex]y=7^2-140+73[/tex]

[tex]y=49-67[/tex]

[tex]y=-18[/tex]

[tex]\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=x^2-20x+73,\:y=-3x+3\mathrm{\:are\:}:[/tex]

[tex]\begin{pmatrix}x=10,\:&y=-27\\ x=7,\:&y=-18\end{pmatrix}[/tex]

Answer:

bbbbb

Step-by-step explanation: