Which type of force can be used to kick a soccer ball?

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[tex]\\ \rm\Rrightarrow 1metre= 10^2cm[/tex]

[tex]\\ \rm\Rrightarrow 1m=10^3mm[/tex]

[tex]\\ \rm\Rrightarrow 1m=10^6\mu m[/tex]

[tex]\\ \rm\Rrightarrow 1m=10^{-3}km[/tex]

[tex]\\ \rm\Rrightarrow 1m=10^{9}nm[/tex]

Answer:

Below in the picture:-

I hope it helps.

Answer:

D

Explanation:

because the correct answer is D

Explanation:

Explanation for your Answer.

Answer:

Angular momentum increases and gravitational potential energy decreases after the bug lands.

Explanation:

After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.

As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.

The question has been asked and answered before: please see the following for previous answers.

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Answer:

There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Explanation:

This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Learn more about kinetic energy: https://brainly.com/question/15308590

(a) The initial speed of the rock is 19.1 m/s.

(b) The greatest height of the rock as measured from the base of the

cliff is 55.6 m.

(c) i. As the ball is thrown up, its kinetic energy is converted to potential energy.

ii. When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.

iii. When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.

The initial speed of the rock is determined by applying the principle of conservation of mechanical energy as shown below;

Ui + K.Ei = Uf + K.Ef

mghi + ¹/₂mvi² = mghf + ¹/₂mvf²

(0.37 x 9.8 x 37) + ¹/₂(0.37)vi² = (0.37 x 9.8 x 0) + ¹/₂(0.37 x 33)²

134.16 + 0.185vi² = 0 + 201.47

0.185vi² = 201.47 - 134.16

0.185vi² =  67.31

vi² = 67.31/0.185

vi² = 363.84

vi = √363.84

vi = 19.1 m/s

vf² = vi² - 2gh

0 = vi² - 2gh

2gh = vi²

h = vi²/2g

h = (19.1)²/(2 x 9.8)

h = 18.6 m

The maximum height from the base = 37 m + 18.6 m = 55.6 m

When the ball is thrown up, its kinetic energy is converted to potential energy.

When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.

When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.

Learn more about conservation of mechanical energy here: https://brainly.com/question/6852965

Answer:

Angular momentum increases and gravitational potential energy decreases after the bug lands.

Explanation:

After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.

As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.

The question has been asked and answered before: please see the following for previous answers.

https://brainly.com/question/21305995

this is the answer

pls give brainliest

Answer: Rock candy is candy made of large sugar crystals. To make rock candy, a supersaturated solution of sugar in water is created and left undisturbed for a few days. The driving force behind crystallization is supersaturation.

Answer:

If it has 12 nucleons and 6 of them are protons the other six must be neutrons (6).

Question :-

Answer :-

[tex] \rule {180pt} {2pt} [/tex]

Given :-

To Find :-

Solution :-

As per the provided information in the given question, we have been given that the Frequency of the Wave is 500 Hz . Its Speed is given [tex] \bf {200 \: m ^{-1}} [/tex] . And, we have been asked to calculate the Wavelength .

For calculating the Wavelength , we will use the Formula :-

Therefore , by Substituting the given values in the above Formula :-

⇒ Wavelength = 200 / 500

⇒ Wavelength = 2 / 5

⇒ Wavelength = 0.4

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

Answer:

A is the basis for all of the other assumptions.

Everything else supports A.

Answer:

A) The blades convert wind energy into rotational energy.

Explanation:

Wind turbines use blades to collect the wind's kinetic energy. Wind flows over the blades creating lift (similar to the effect on airplane wings), which causes the blades to turn. The blades are connected to a drive shaft that turns an electric generator, which produces (generates) electricity.

Answer:

Bbbbb. Metal disc.

Explanation:

Sent from my Huawei and I am not a good person and I am not a good person and I am not a good person and I am not a good person

Answer:

acceleration = change in velocity / change in time

acceleration = 14/10

acceleration = 1.4/s^2

Answer:

Forests helps in binding the soil together. Thus, prevent soil from erosion.

Answer:

True

Explanation:

Forest protect the soil from erosion because the trees in the forest hold the soil together not allowing it to erode.

Causes of earthquake:

1 Groundwater extraction – decrease in pore pressure

2. Groundwater – increase in pore pressure.

3. Heavy rain.

4. Pore fluid flow.

5. High CO2 pressure.

6. Building dams.

Effects of earthquake:

1. Loss of lives

2. Increase in government expenditure

3. Loss of properties

Protection against earthquake:

We cannot prevent natural earthquakes from occurring but we can significantly mitigate their effects by identifying hazards, building safer structures, and providing education on earthquake safety. By preparing for natural earthquakes we can also reduce the risk from human induced earthquakes.

Answer:

B. O.4692 mm

Explanation:

I hope its help keep safe

Answer:

Its  D trust me it is

Explanation:

Explanation:

here, force applied (N) = 345 N

or, mass of scooter (m) = 70 kg

now, acceleration (a) = ?

we know, force = mass × acceleration

or, 345 = 70 × acceleration

or, acceleration = 345/70

therefore, acceleration = 4.9 m/s2 (meter/second square)

Answer:

900 Revolution/Minute (rev/min)

=

94.24778 Radian/Second (rad/s)

Explanation:

Answer:

False, Hope this helps.

law of conservation of mechanical energy

PE1 = Ek2

mgh=1/2mv²

h = 12 sin 60

[tex]\tt v=\sqrt{2gh}=\sqrt{2\times 9.8\times 12\times sin~60}=14.27~m/s[/tex]

The current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.

The current that will allow the upper to float will form zero resultant force due to the current at the left and the current at the right.

W =  mg

W = (σL)g

[tex]F_1 = F_2 = \frac{\mu_o I^2 l}{2\pi r}[/tex]

The total force due to angle formed by the top wire

[tex]F_t = F_1cos\theta + F_2 cos \theta= 2Fcos\theta = \frac{2\mu_o I^2 l \times cos\theta}{2\pi r} \\\\F_t = \frac{\mu_o I^2 l \times cos\theta}{\pi r}[/tex]

At equilibrium the upward force must equal downward force

[tex]\sigma lg=\frac{\mu_o I^2 l \times cos\theta}{\pi r}\\\\I^2 = \frac{\sigma lg \pi r}{\mu_0 l \times cos\theta} = \frac{\sigma g \pi r}{\mu_0 \times cos\theta} \\\\I^2 = \frac{(0.055)\times 9.8\pi \times 0.04 }{4\pi \times 10^{-7} \times cos60} \\\\I^2 = 107,800\\\\I = \sqrt{ 107,800} \\\\I = 328.3 \ A[/tex]

Thus, the current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.

Complete question is below:

The figure is a cross section through three long wires with linear mass density 55.0 g/m. They each carry equal currents in the directions shown. The lower two wires are 4.0 cm apart and are attached to a table. (Figure 1). What current I will allow the upper wire to "float" so as to form an equilateral triangle with the lower wires?

Learn more about magnetic force here: https://brainly.com/question/13277365

Answer:

it is d that my answer to the question

a. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

Momentum is the product of mass and velocity

It is given by ,

p= mv

where, p = momentum

m = mass

v = velocity

velocity is the rate of change of displacement.

To solve , we use Law of conservation of momentum and Law of conservation of  mechanical energy

Law of conservation of momentum states that  in absence of any external forces , the momentum of a system always remains conserved.

i.e,

The momentum  of the system before collision = momentum of the system after collision.

[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]

Where,

m₁ = mass of first body.

m₂ = mass of the second body.

u₁ = velocity of first body before collision,

u₂ = velocity of the second body before collision

v₁ = velocity of first body after collision

v₂ = velocity of first body after collision.

v₂ = velocity of second body after collision.

The Law states that the total mechanical energy of a system remains conserved and energy can be converted from one form to another form.

The sum of kinetic energy an potential energy is equal to total mechanical energy which is a constant.

So, K.E + P.E = constant

a, Here mass of clay m₁ = 10g = 0.01kg,

velocity of the clay = 12m/s.

therefore, momentum  p = mv.

p = 0.01 x 12 = 0.12kg m/s.

Hence momentum of clay is 0-12kg m/s.

b. The momentum of clay - bob system after collision is

From law of conservation of momentum ,

final momentum = initial momentum

since initial momentum  = 0.12kg m/s

therefore momentum of the clay-bob system after collision is 0.12kg m/s

c. To find the velocity of the body we apply law of conservation of momentum

[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]

Here  m₁u₁ = 0.12kgm/s

m₂u₂ = 0 (since bob is at rest initally)

m₁ = 10g = 0.01kg

m₂ =  50g = 0.05kg

after collision the system moves with a common velocity v

So,

m₁u₁ = (m₁ + m₂)v

0.12 = (0.01 + 0.05 ) v

So, v = 0.12/0.06 = 2m/s

Hence velocity of clay -bob system after collision is = 2m/s.

d. The kinetic energy of the clay-bob system after the collision.

kinetic energy = 1/2 mv²

Here. m = 0.06kg

v = 2m/s

therefore K.E = (1/2)x 0.06 x 2²

K.E = 0.12J

Hence Kinetic energy of the clay-bob system after collision is 0.12J

e. The maximum height of the clay-bob system that they deflect after the collision.

From Law of Conservation of mechanical energy we have,

The kinetic energy = The potential energy

so, 1/2 mv² = mgh

Here, m = 0.06kg

g= 9,8m/s²

h = height.

So,  h =  2/9.8 = 0.204m

Hence height to which the clay-bob system will rise after collision is 0.204m

e.  To find the velocity that clay should possess  before collision in order for the clay- bob   system to gain the velocity so that it completes the circle -

The velocity that the particle should have at the bottom of the circle in order to complete the circle is v = [tex]\sqrt{5rg\\}[/tex]

Where, r = radius of the circle

g = acceleration due to gravity

Here,

r = 0.7m

g = 9.8m/s

So, v = [tex]\sqrt{5 X0.7 X 9.8 }[/tex] = 5.85m

So clay-bob system should have a velocity of 5.85m at the bottom of the circle so that it can complete the circle

Now,  applying Law of conservation of momentum

m₁u₁ = (m₁ + m₂)v

Here, m₁ = 0.01kg

m₂ = 0.05kg

v = 5.85m/s

So, 0.01u₁ = 0.06 x 5.85  

Hence u₁ = 35.13m/s

So velocity that clay should have is 35.13m/s.

Therefore  the solution of the question is

. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

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Answer is ...

Happy to help ..

Answer:

B) work-energy

Explanation:

It is the work-energy theorem as there is no theorem called "mass-acceleration theorem" [unless you consider Newton's Second Law (maybe?) but not really].

Its postulates are :

Answer:

top box: upthrust

right box: water resistance

bottom box:gravity / weight

left box: thrust

Explanation:

You too have a fruitful day! Hope I could help!

#Down

#Up

#Left

The force of motor

#Right

Answer: All organisms generate waste and dead material that is recycled by decomposers.

Explanation: Give me brainiest!