Which of the following equations represent linear functions?

y=4(2x)−3

x2+y=1

y=2x√

y=−2

Answer:

15

Step-by-step explanation:

12-k

12- (-3)

12+3

=15

Answer:

15

Step-by-step explanation:

Substitute the variable, "k" into "12-k" from the equation "k=(-3).

12-k

12-(-3)

12+3---> two negatives make a positive

15

Answer:

It would be C. The hexagon.

Answer:It would be C because you have 3 sides for the triangle than 4 sides for the rectangle, 5 sides for the pentagon, and 6 sides for the hexagon

Step-by-step explanation:

Answer:

I cant read all of that. Im sure others ant either.

Step-by-step explanation:

Answer:

i cant read it for some reason, can you type it?

Step-by-step explanation:

Answer:

StartRoot 58 EndRoot

Step-by-step explanation:

Given the coordinates (-4, -3) and (-1, 4)

To get the distance between the two points, we will use the formula:

D =√(y2-y1)²+(x2-x1)²

From the coordinates, x1 = -4, y1 = -3, x2 = -1 and y2 = 4

Substitute

D =√(4-(-3))²+(-1-(-4))²

D = √(4+3)²+(-1+4)²

D = √7²+3²

D = √49+9

D = √58

Hence the correct option is D

StartRoot 58 EndRoot

Answer:

D. 58

Step-by-step explanation:

Answer:

p - 6 = -14

p = -8

Step-by-step explanation:

       The difference between a number p and 6 is -14

  Let the number  = p;

Equation:

          difference between the numbers:

                         p - 6

          equality;

                         p - 6 = -14

Equation; p - 6 = -14

Solution:

                p - 6 = -14

            add (+6) to both sides of the expression;

                 p - 6 + (+6) = -14 +(+6)

                 p = -8

Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x = -50 cm and x = +50 cm. The charge densities on the planes are -50 nC/m² and +25 nC/m², respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x = +80 cm? (Hint:Use Gauss’ law.)

Answer:

ΔV = 2520 V

Step-by-step explanation:

We are given;

Charge density 1; σ1 = -50 nC/m² = -50 × 10^(-9) nC/m²

Charge density 2; σ2 = +25 nC/m² = +25 × 10^(-9) nC/m²

Now, formula for electric field strength is;

E = -(½ε)(|σ1| ± |σ2|)

ε is vacuum permittivity with a constant value as 8.85 × 10^(−12) C²/N.m²

|σ1| and |σ2| means we are taking the absolute values and would therefore not use the negative sign attached to them.

Now, in between x = 0 cm(0 m) and 50 cm (0.5 m), electric field generated by both charge densities would be in the same direction and thus;

E_in = -(½ε)(|σ1| + |σ2|)

E_in = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) + (25 × 10^(-9))]

E_in = -4200 V/m

In contrast, when x ≥ 50 cm (0.5 m), electric field generated by both charge densities would be in opposite directions and thus;

E_out = -(½ε)(|σ1| - |σ2|)

E_out = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) - (25 × 10^(-9))]

E_out = 1400 V/m

The magnitude of the potential difference from the origin to x = 80 cm(0.8 m) is calculated as attached;

From the attachment, we see that;

ΔV = 2520 V

Answer:

F

Step-by-step explanation:

Answer:

$ 2,273.25

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

if you do all the steps right you  should get 4

Answer:

answer is in picture

Step-by-step explanation:

Answer:

The answer is 5³.

Step-by-step explanation:

You have to apply Indices Law :

[tex] {a}^{m} \times {a}^{n} ⇒ {a}^{m + n} [/tex]

[tex] {a}^{m} \div {a}^{n}⇒ {a}^{m - n} [/tex]

[tex] { ({a}^{m} )}^{n} = {a}^{mn} [/tex]

So for this question :

[tex]( {( {5}^{2}) }^{3} \times {5}^{4} ) \div {5}^{7} [/tex]

[tex] = ( {5}^{6} \times {5}^{4} ) \div {5}^{7} [/tex]

[tex] = {5}^{10} \div {5}^{7} [/tex]

[tex] = {5}^{3} [/tex]

Answer:

37: 36

Step-by-step explanation:

You can not simplify. Have a good day!

Answer:

B

Step-by-step explanation:

Answer:

9 yards

Step-by-step explanation:

-5 + 14 = 9

Answer:

32%

Step-by-step explanation:

32/100 is 32%

Answer:

x= 16 degrees

Step-by-step explanation:

the angles can be a little hard to remember but just know that the angles that are outside of the transversal are exterior angles and if they are on the opposite sides of the line that passes through the parallel lines then they're alternate exterior angles and those angles that are inside are interior angles and if they are on the opposite sides of the line passing through the parallel then they are alternate interior angles .

Answer:

Assuming you want slope formula for this, it's y= (5/9)x -1

Answer:

It should be 1/2

Step-by-step explanation:

y = -11x2 – -52 or y = -5.5x – 52

Answer:

you pay 240 dollars a year

Step-by-step explanation:

y=20x

x is 12

20*12=

240

Answer: $250

Step-by-step explanation:

Answer:

24.99

Step-by-step explanation:

Answer:

f = (100 - 2h) / 5

Step-by-step explanation:

Given:

5f + 2h = 100

Solve the equation for f.

5f + 2h = 100

Subtract 2h from both sides

5f + 2h - 2h = 100 - 2h

5f = 100 - 2h

Divide both sides by 5

5f / 5 = (100 - 2h) / 5

f = (100 - 2h) / 5

If f = 1 full box

h = 1/2 box

h = 1/2 of f

h = 1/2f

Substitute h = 1/2f into

f = (100 - 2h) / 5

f = {100 - 2(1/2f)} / 5

f = (100 - 2/2f) / 5

5f = 100 - f

5f + f = 100

6f = 100

f = 100 / 6

= 16.67

f = 16.67

The required value of f is 16.67.

Given that ;

Kiran sells full box of fruit cost for each box = f = $5

And Kiran sells half box of fruit cost for each = h = $2

According to the question ;

For full box cost  + for half box cost = Total cost of his band trip

5f + 2h = 100

Solve the equation following equation for f .

5f + 2h = 100

Subtract 2h from both sides

5f + 2h - 2h = 100 - 2h

5f = 100 - 2h

Divide both sides by 5

[tex]\frac{5f}{5} = \frac{100}{5} - \frac{2h}{5}[/tex]

f = 20-2h

For full box f = 1 full box

For half box h = 1 half box

It means h = [tex]\frac{1}{2}[/tex] of f

h = [tex]\frac{1}{2}f[/tex]

Substitute the value of h  

[tex]f = \frac{(100-2h)}{5} \\f = \frac{100-2(\frac{1}{2f} )}{5}[/tex]  

[tex]f = \frac{100-f}{5}[/tex]

5f = 100 - f

5f + f = 100

6f = 100

[tex]f = \frac{100}{6}[/tex]

f = 16.67

The required value of f is 16.67.

For more details about the making equation click the link given below.

https://brainly.com/question/9151865

Answer:

9/8

Step-by-step explanation:

change in y/change in x= slope

so in this case -9/-8 or 9/8 bc the negatives cancel out

Answer:

26

Step-by-step explanation:

square root of 81 is 9, 9*2 is 18, square root of 64 is 8, 18+8 is 26

Answer:

26

Step-by-step explanation:

2(square root of 81)+square root of 64

2(9)+8=

18+8=

26

Answer:

[tex]q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]

Step-by-step explanation:

[tex]6-3q\leq 1\\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-3q-6\le \:1-6\\\\Simplify\\\\-3q\le \:-5\\\\\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\\\left(-3q\right)\left(-1\right)\ge \left(-5\right)\left(-1\right)\\\\Simplify\\\\3q\ge \:5\\\\\mathrm{Divide\:both\:sides\:by\:}3\\\\\frac{3q}{3}\ge \frac{5}{3}\\\\Simplify\\\\q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]

======================================================

Explanation:

This sequence is arithmetic

The first term is a = -9

The common difference is d = 6 since we're adding 6 to each term to get the next one (eg: -3+6 = 3 or 3+6 = 9 or 9+6 = 15)

Plug those values into the arithmetic nth term formula below

an = a + d*(n-1)

an = -9 + 6*(n-1)

an = -9 + 6n-6

an = 6n - 15

--------------

As a check, let's plug in something like n = 1

an = 6n - 15

a1 = 6*1 - 15

a1 = 6 - 15

a1 = -9

We see that the 1st term is -9, which matches the sequence given

Now let's plug in n = 2

an = 6n - 15

a2 = 6*2 - 15

a2 = 12 - 15

a2 = -3

The 2nd term is -3. This also matches.

I'll let you check the other values of n to confirm the answer.

Answer: It could be, just add two dots at the smiley face, BOOM! The function of Facial muscles in humans.

Step-by-step explanation:

Answer:

the cist of entry for x adults

Answer:

i think it would be d)

Step-by-step explanation:

cuz like, it says to write an expression. for an expression, most of the time you need more than one like number and variable

hope this helped :)

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