What will happen to this force if the distance between the charges is doubled and the -4μC is cut in half ? Use proportional reasoning to find the answer and then check by changing and moving the charges.

Answer:

A ,D

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Figure B and Figure C represents diffuse reflection. So, the correct options are B and C

Diffuse reflection is defined as the reflection of light or other waves or particles from a surface, such that a ray incident on a surface is scattered at many angles rather than just at a single angle, as is the case with specular reflection.

For example, an illuminated ideal diffuse reflective surface will have the same brightness from all directions in the hemisphere surrounding the surface, i.e. Lambertian reflectance.

If the surface is microscopically rough, the light rays will be reflected and scattered in many different directions as in figure B and C above, with rough surfaces showing diffuse reflections.

Thus, Figure B and Figure C represents diffuse reflection. So, the correct options are B and C

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Answer:

C. Mass of object 1 = 12 kg

Mass of object 2 = 12 kg

Distance between objects = 1.5 m

Explanation:

From the universal gravitation equation

Force of gravity between two objects is directly proportional to the product of mass 1 and mass 2 and inversely proportional to the square of the distance apart

Option B is has the greatest factor

Force of gravity between the objects = (15 x 12)/(0.5)^2

Force of gravity between the objects = 720G

Option C has the least factor and the answer

Force of gravity between the objects = (12 x 12)/(1.5)^2

Force of gravity between the objects = 64G

G = The constant of proportionality = 6.673 x 10-11 N m^2/kg^2

how much pressure is created when a force of 55N is applied over an area of 8m²

We have been asked to determine the pressure exerted when given magnitude of force acting on given area.

[tex]☄\bf \qquad \mathcal{Pressure} = \mathcal{\dfrac{Force}{Area}}[/tex]

Put all given value we obtain

[tex]\qquad \sf \longrightarrow \:Pressure \: = \dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = \cancel\dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = 6.875 \: Pa.[/tex]

Therefore,

The ratio m/q for this particle is mathematically given as

m/q=2.39*10^{-6}

Question Parameters:

After being accelerated to a speed of 1.17×105 m/s

the uniform magnetic field of strength 0.800 T and travels in a circle of radius 35.0 cm

Generally, the equation for the Centrifugal force  is mathematically given as

[tex]qvB=\frac{mv^2}{r}[/tex]

Therefore

m/q=(0.8*0.35)/(1.17*10^{5})

m/q=2.39*10^{-6}

In conclusion, the ratio m/q for this particle

m/q=2.39*10^{-6}

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The weight is equal to 'mg' where m is the mass and the g is the gravitational constant on that certain planet

In this case, the mass is 150 kg and the gravitational constant is about 9.8.

so the weight = 150 * 9.8 = 1470 Newtons.

Hope that helped!

The weight of the box with the given mass on Earth is 1470 Newtons.

Given the data in the question;

Weight is the force acting on the mass of a particular object or particle due to gravity. It is the gravitational force acting on an object with mass. It is measured in newtons. It is expressed as;

[tex]W = m * g[/tex]

Where m is mass of object and g is acceleration due to gravity on earth ( [tex]g = 9.8m/s^2[/tex] )

To find the weight of the box, we substitute our values into the expression above;

[tex]W = 150kg * 9.8m/s^2\\\\W = 1470kgm/s^2\\\\W = 1470N[/tex]

Therefore, the weight of the box with the given mass on Earth is 1470 Newtons.

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The speed will be calculated by dividing the distance traveled by the object by the time elapsed.

Based on the information given, an overview will be given to you on how to calculate the speed of the cart.

Average speed is a scalar quantity and is gotten by dividing the distance by time taken. For example, if the distance traveled is 100km and the time taken is 4 hours. The speed will be:

= Distance/Time

= 100/4.

= 25km/h.

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GPE=mgh

10³=60 x 9.8 x h

h=1.7 m

The value of her height will be 1.7 m. The formula for the gravitational potential energy is used in the given problem.

Gravitational potential energy is found as the product of the mass, gravity, and height attained by the object during a fall.

The given data in the problem is;

m is the mass of a girl =60 kg

E is the gravitational potential energy= 10 kJ

h is the height traveled during free fall.

The expression for the gravitational potential energy is;

[tex]\rm \ GPE(E) = mgh \\\\ h = \frac{E}{mg} \\\\ h = \frac{10\times 10^3 }{60 \times 9.81 } \\\\ h= 1.7 \ m[/tex]

Hence her height will be 1.7 m.

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Answer:

bevz there may be a inward for acting upon to

cause inward acceleration

Answer:

58600 = momentum answer

Answer:

One piece has a north pole only, and the other piece has à soutn pole only.

Explanation:

mark me brainliest!!

Answer: B

Explanation:

When we split a magnet in half, both halves act as magnets, with each having a north and south pole. As with the original magnet, the matching north and south poles remain on the sides as in the original magnet. This means that the 2 broken sides must be polarized in the opposite direction.

Answer:

25 J

Explanation:

Using Law of Conservation of Energy

Total Energy before = Total Energy After

Potential Energy1 + Kinetic Energy1 = Potential Energy2 + Kinetic Energy2

Potential Energy1 + 0 = 0 + Kinetic Energy2

Potential Energy1 = [tex]\frac{1}{2}*m*v^{2}[/tex] =0.5*0.5*10*10= 25 J

Answer:

1 mile = 1609 meters

10 miles = 16090 meters

16090m/(24.0m/s) = 670s

16090m/(30.0m/s) = 536s

Average Speed = Total distance/Elapsed time

Average Speed = [16090m(2)]/(670s+536s) = 32080m/1206s = 26.7m/s

(a) The car's average speed is less than 27.0m/s

(b) The car's average speed is 26.7m/s

Explanation:

1 mile = 1609 meters

10 miles = 16090 meters

16090m/(24.0m/s) = 670s

16090m/(30.0m/s) = 536s

Average Speed = Total distance/Elapsed time

Average Speed = [16090m(2)]/(670s+536s) = 32080m/1206s = 26.7m/s

(a) The car's average speed is less than 27.0m/s

(b) The car's average speed is 26.7m/s

The acceleration of one of those bugs is equal to 305mi/s.

To calculate the insect's acceleration, the action and reaction force of the impact must be considered.

As the insect will hit the helmet, the force it hits is the same force it receives, so we can make the following expression:

                                          [tex]m_m \times a_m = m_b \times a_b[/tex]

                                        [tex]550 \times 0.0027 = 5 \times 10^{-3} \times a_b[/tex]

Speed ​​has been converted to miles per second

                                          [tex]a_b = 305 mi/s[/tex]

So, the acceleration of one of those bugs is equal to 305mi/s.

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We can say that having a testing site such as the mars yard helps scientists to test previously theoretical knowledge in a realistic environment.

Testing sites help scientists by providing a realistic place to test knowledge that may have previously been only theoretical through performing experiments on such test sites. This is of vital importance in the detection of errors in order to achieve a successful future mission.

Therefore, we can confirm that having a testing site such as the mars yard helps scientists to test previously theoretical knowledge in a realistic environment.

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Answer:

When a sound source moves faster than the speed of sound, a shock wave is produced as the sound waves interfere. A sonic boom is the intense sound that occurs as the shock wave moves along the ground.

More importantly, all of the energy gets concentrated into a very small distance this is called a shock wave. In this case, the observer does not hear the approaching source at all until the shock wave hits with all of the energy in the wave. For sound waves, this can cause a very loud noise, called a sonic boom.

Sonic booms produced by aircraft flying supersonic at altitudes of less than 100 feet, creating between 20 and 144 pounds overpressure, have been experienced by humans without injury. Damage to eardrums can be expected when overpres- sures reach 720 pounds

Explanation:

marke as brainliest

Answer:

Explanation:

V₁ = <20, -15, 15>, V = <0, 0, 20>

V₂ = V - 2V₁ = <0, 0, 20> - <40, -30, 30> = <-40, 30, -10> = -40i + 30j - 10k

magnitude = [tex]\sqrt{40^2+30^2+10^2}}=51[/tex]

Answer:

1 or 2

Explanation:

Compared to RNA and DNA backbone, protein backbone has a relatively simple chemical structure - a nitrogen atom, two carbon atoms, one or two oxygen atoms, and a few hydrogens.

Answer:

B) parabolic

Explanation:

A parabolic path is defined as :-

"The angle of trajectory of a projectile", such as a cannon ball, which moves in such a path after being launched from a cannon.

The theoretical electricity consumption is 268.179 kilowatt-hours per metric tonne.

The theoretical minimum of electricity consumption is 60.340 % of the practical minimum of electricity consumption.

The theoretical electricity consumption is equal to the sum of sensible heat ([tex]q_{s}[/tex]) and latent heat ([tex]q_{l}[/tex]) needed to melt a metric ton of steel, in kilowatt-hours per metric tonne:

[tex]q = q_{s}+q_{l}[/tex]   (1)

By definitions of sensible and latent heat, we have the following formulas:

[tex]q = c\cdot (T_{f}-T_{o}) + L_{f}[/tex]   (1)

Where:

If we know that [tex]c = 1.294\times 10^{-1}\,\frac{kWh}{ton\cdot ^{\circ}C}[/tex], [tex]T_{o} = 20\,^{\circ}C[/tex], [tex]T_{f} = 1500\,^{\circ}C[/tex] and [tex]L_{f} = 76.667\,\frac{kWh}{ton}[/tex], then the theoretical electricity consumption is:

[tex]q = \left(1.294\times 10^{-1}\,\frac{kWh}{ton\cdot ^{\circ}C} \right)\cdot (1500\,^{\circ}C-20\,^{\circ}C)+76.667\,\frac{kWh}{ton}[/tex]

[tex]q = 268.179\,\frac{kWh}{ton}[/tex]

The theoretical electricity consumption is 268.179 kilowatt-hours per metric tonne. [tex]\blacksquare[/tex]

According to the document "Theoretical Minimum Energies to Produce Steel for Selected Conditions" done by R.J. Fruehan et al. in March 2000. The practical minimum of electricity consumption for a electric arc furnace (EAF) is:

[tex]q_{real, min} = 444.444\,\frac{kWh}{ton}[/tex]

This indicator consider common energy losses throughout steel production.

The theoretical minimum of electricity consumption is 60.340 % of the practical minimum of electricity consumption. [tex]\blacksquare[/tex]

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Answer: B

Explanation: I think its B or A but mostly B

Answer:

The enthalpy of a reaction does not depend on the reactant path taken

Explanation:

i just took the test on a pex :)

Answer:

c because that's the answer

She would weigh 31 pounds more on Mars than on Pluto. Therefore option C is correct.

To calculate the differences in weight using the given information.

1. Weight on Earth: 100 pounds

Now, let's calculate the weight differences for Pluto and Mars:

2. Weight on Pluto:

Pluto's gravity is about 0.06 times that of Earth's.

Weight on Pluto = Weight on Earth × Pluto's gravity

Weight on Pluto = 100 pounds × 0.06 = 6 pounds

3. Weight on Mars:

Mars' gravity is about 0.38 times that of Earth's.

Weight on Mars = Weight on Earth × Mars' gravity

Weight on Mars = 100 pounds × 0.38 = 38 pounds

Comparing the weight differences:

Weight difference between Earth and Pluto = 100 pounds - 6 pounds = 94 pounds

Weight difference between Earth and Mars = 100 pounds - 38 pounds = 62 pounds

Therefore, the correct answer is C. She would weigh 31 pounds more on Mars than on Pluto.

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Explanation:

the electrons that are the furthest from the nucleus

Answer:

Closed circuit

Explanation:

See the switch is not connected with circuit.

What is the difference between the fourth harmonic and the nth harmonic?

The fourth harmonic has frequency f4= v/λ4= 4v/2L = 4f1, and, to generalise, The nthharmonic has frequency fn= v/λn= nv/2L = nf1. All waves in a string travel with the same speed, so these waves with different wavelengths have different frequencies as shown.

Question :-

Answer :-

[tex] \rule {180pt} {2pt} [/tex]

Given :-

To Find :-

Solution :-

As per the provided information in the given question, we have been given that the Radius of the Watch is 5 meter , Time is given 2 seconds . And, we have been asked to calculate the Velocity of the Watch .

For calculating the Velocity , we will use Formula :-

Therefore , by Substituting the given values in the above Formula :-

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5

Using first equation of kinematics

[tex]\\ \rm{:}\dashrightarrow v=u+at[/tex]

[tex]\\ \rm{:}\dashrightarrow v-u=at[/tex]

[tex]\\ \rm{:}\dashrightarrow 6.1-10.2=-1.77t[/tex]

[tex]\\ \rm{:}\dashrightarrow -4.1=-1.77t[/tex]

[tex]\\ \rm{:}\dashrightarrow t=2.32s[/tex]

Answer:

Momentum change of the rock = 3835 kgm/s

Chane in earth's velocity = 6.4 x 10⁻²² m/s

Explanation:

m = 50.0 kg, M = 6.0 x 10²⁴ kg

d = 300.0 m

final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s

Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s

Inital momentum of the rock+earth system = 0

final momentum = 0 (momentum conservation)

momentum of rock and momentum of earth are same magnitude and opposite directions.

mv - MV = 0

Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s

Answer:

"F = 52.93 [N]

Since the Rock is thrown upwards, there are only two forces, one is the force of the rubber (55[N]) and the other is the force of gravitational acceleration acting in the opposite direction to the movement of the rock, therefore this acceleration will be taken as negative.

F = 55 - m*g

where:

F = total force [N] (units of Newtons)

m = mass = 0.21 [kg]

g = gravity acceleration = 9.81 [m/s²]

F = 55 - (0.21*9.81)

F = 52.93 [N]"