What is the value of min the figure below? In this diagram, AABD ABCD.
8
m
C
A. 136
B. 572
C. 32
Ο Ο Ο
D. V632
E. 147
o
F. 274
HELP

This is equivalent to 2*sqrt(34)

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Explanation:

First let's find BD

The three triangles are similar, allowing for the proportion to be set up

AD/BD = BD/DC

9/x = x/8

9*8 = x*x

x^2 = 72

x = sqrt(72)

BD = sqrt(72)

Now we can use the pythagorean theorem. Focus on triangle BDC.

The legs are BD = sqrt(72) and DC = 8. Let's find the hypotenuse

(BD)^2 + (DC)^2 = (BC)^2

(sqrt(72))^2 + (8)^2 = m^2

72 + 64 = m^2

136 = m^2

m^2 = 136

m = sqrt(136)

We can simplify this but your teacher has chosen not to. If you want to simplify, then,

m = sqrt(136)

m = sqrt(4*34)

m = sqrt(4)*sqrt(34)

m = 2*sqrt(34)

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