What is the midpoint of the line segment with endpoints (-4, 5)
and (4, 3).

Step-by-step explanation:

it will be c as shown in the photo

Answer:

25 kilograms

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Think about the ratio between the current number of large bottles of soda(8) and the current number of jugs of water (12)

By finding the GCF (Greatest Common Factor) of the two numbers, we can conclude that if both numbers were to be divided by the GCF, 4, we would get a 2:3 ratio.

For every 2 bottles of soda, 3 jugs of water will be placed. Keep doing this until we run out of both sources of liquid, in this case, 4 tables where we would use all the bottles of soda and the jugs of water.

Answer:

Step-by-step explanation:

g(x) = -2f(x)

Vertical stretch                       by virtue of the factor 2

Reflection over the x-axis      by virtue of the factor -1

The transformations which must be applied to function F to produce the graph of function g are vertical stretch and reflection over the x-axis.

To transform the function f(x)=12ˣ into the function  g(x)=−2(12)ˣ

Since g(x) is multiplied by -2 compared to f(x), this represents a vertical compression.

The absolute value of the multiplier indicates the degree of compression/stretch.

The negative sign in front of 2(12)ˣ in g(x) reflects the graph over the x-axis. This means that the graph of g(x) is reflected below the x-axis compared to f(x).

Hence, vertical stretch and reflection over the x-axis are the transformations which must be applied to function F to produce the graph of function g.

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Answer:

19/18

Step-by-step explanation:

substitute the value of m(11/6) in m-7/9

which is equal to 11/6 -7/9 =19/18

Answer:

Angle 6

Step-by-step explanation:

They are both the same angle size

Answer:

Angle 1

Step-by-step explanation:

Refer to the attached picture

Answer:

Step-by-step explanation:

A = ½(b₁ + b₂)h

b₂ = 2A/h - b₁

b₂ = 2(58)/4 - 12

b₂ = 17 ft

Answer: I need the map good sir please show it

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

I assume the function is [tex]f(x)=1+\frac{5}{x}-\frac{4}{x^2}[/tex]

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, [tex]x=0[/tex] is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

[tex]f(x)=1+\frac{5}{x}-\frac{4}{x^2}[/tex]

[tex]f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}[/tex]

[tex]0=-\frac{5}{x^2}+\frac{8}{x^3}[/tex]

[tex]0=-5x+8[/tex]

[tex]5x=8[/tex]

[tex]x=\frac{8}{5}[/tex]

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

[tex]f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}[/tex]

[tex]f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3[/tex]

Therefore, the function increases on the interval [tex](0,\frac{8}{5})[/tex] and decreases on the interval [tex](-\infty,0),(\frac{8}{5},\infty)[/tex].

C) Since we determined that the slope is 0 when [tex]x=\frac{8}{5}[/tex] from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, [tex]f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}[/tex], meaning there's an extreme at the point [tex](\frac{8}{5},\frac{41}{16})[/tex], but is it a maximum or minimum? To answer that, we will plug in [tex]x=\frac{8}{5}[/tex] into the second derivative which is [tex]f''(x)=\frac{10}{x^3}-\frac{24}{x^4}[/tex]. If [tex]f''(x)>0[/tex], then it's a minimum. If [tex]f''(x)<0[/tex], then it's a maximum. If [tex]f''(x)=0[/tex], the test fails. So, [tex]f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}<0[/tex], which means [tex](\frac{8}{5},\frac{41}{16})[/tex] is a local maximum.

D) Now set the second derivative equal to 0 and solve:

[tex]f''(x)=\frac{10}{x^3}-\frac{24}{x^4}[/tex]

[tex]0=\frac{10}{x^3}-\frac{24}{x^4}[/tex]

[tex]0=10x-24[/tex]

[tex]-10x=-24[/tex]

[tex]x=\frac{24}{10}[/tex]

[tex]x=\frac{12}{5}[/tex]

We then test where [tex]f''(x)[/tex] is negative or positive by plugging in test values. I will use -1 and 3 to test this:

[tex]f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34<0[/tex], so the function is concave down on the interval [tex](-\infty,0)\cup(0,\frac{12}{5})[/tex]

[tex]f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0[/tex], so the function is concave up on the interval [tex](\frac{12}{5},\infty)[/tex]

The inflection point is where concavity changes, which can be determined by plugging in [tex]x=\frac{12}{5}[/tex] into the original function, which would be [tex]f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}[/tex], or [tex](\frac{12}{5},\frac{43}{18})[/tex].

E) See attached graph

Answer:

The 6-minute half-mile time is continuous data; the number of people trying out for the team is discrete data.

Step-by-step explanation:

Answer:

Step-by-step explanation:

We know that:

First, we need to change the 'y' sign.

Now, let's compare both of the equations to find slope.

We can see that the slope is 1 and the y-intercept is -6.

Conclusion:

Therefore:

Hoped this helped.

Answer:

125

Step-by-step explanation:

Answer:

The equation would be y=2x+3 I am pretty sure

Step-by-step explanation:

This is because you take the slope which is 2 from the line y=-1/2x-6. To find the slope perpendicular to the line, you need to find the exact opposite of the slope: -1/2, and in this case, it would be 2.

(Ex: if it was -3/4, you would need to use a slope of 4/3 since it is the opposite)

Then you take that slope (2) and the point (0, 3) and put it into "y-y1=m(x-x1)"

y-y1=m(x-x1)

y-3=2(x-0)

-distribute the 2-

y-3=2x-0

-add 3 on both sides-

so equation would be y=2x+3

Not sure if this is all correct, but I hope it helps! :)

Answer:

A is the correct solution

Step-by-step explanation:

     3x³ + 4x² + 0x - 1  /  x - 2

             3      10    20

-2 | 3       4       0    -1

 -  (3      -6)

             10       0

      -     (10    -20)

                      20    -1

                 -   (20  -40)

                              39

3x² + 10x + 20 + 39/(x - 2)

Answer:

a

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.shshs

x ≤  3 (closed dot going to the left)

Answer:

y = -3

Step-by-step explanation:

3x + 4y = 3

2x - 4y = 12

5x       = 15       Add the two equation together because the y terms are

                       opposite each other and goes out when you add the equations

x = 5

Substitute into the first equation and solve for y when x = 5

 3x + 4y = 3

3(5) + 4y = 3

 15 + 4y = 3

    4y = 3 - 15

    4y =  -12

      y = -3  

Answer:

Step-by-step explanation:

2 AND 4

Answer:

14/10

OR

7/5

Step-by-step explanation:

(7*2)/(2*5) = 14/10

(14/2) / (10/2) = 7/5

Answer:

Mixed fraction: 1 2/5

Decimal form: 1.4

Hope this helps :)

Answer:

q

Step-by-step explanation:

Answer:

I think its 6

Step-by-step explanation:

Answer:

1 flmpysc - ax + x - y - 2

this could help

Answer:

x = 5

y = -4

Step-by-step explanation:

The amount at a given time can be calculated by multiplying the previous amount by a value less than 1, which represents exponential decay. Hence, option B is the right choice.

A quantity grows (or depreciates) linearly if it increases (or decreases) by the same amount per unit of time.

A quantity grows (or depreciates) exponentially if the increase (or decrease) in the amount is a multiple of the previous amount.

In the question, we are asked to identify the option that best describes an exponential decay.

We assess each option and try to identify the exponential decay among them.

Therefore, the amount at a given time can be calculated by multiplying the previous amount by a value less than 1, which represents exponential decay. Hence, option B is the right choice.

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