what is 1/3^3 as a fraction

Answer: 30

Step-by-step explanation:

A sinusoidal equation can be used to describe the height because the height depends on a periodic motion, and the equation can be written as:

h(t) = 13ft*sin(pi*t) + 24ft

Remember that the sine function has a periodicity, such that:

sin(x + 2pi) = sin(x).

So, for a circle where if you do a complete rotation you end in the initial place, so there can be a relation between the height and a sinusoidal equation.

Notice that the initial position is 24ft above the ground, so we can write this, at the moment, as:

h(x) = Asin(n*t) + 24ft

A is the amplitude, it defines the maximum height and minimum height, both depend on the radius (the maximum height is 24ft plus the radius, the minimum height is 24ft minus the radius) then we write:

h(t) = 13ft*sin(kt) + 24ft

k depends on how much time takes to do a full rotation. We know that the sine function does a "complete cycle" in 2pi, while the wheel does a full rotation in 2 seconds, then we have that:

k*2 = 2pi

k = (2pi)/2s = pi

Then the sinusoidal equation that represents the height is:

h(t) = 13ft*sin(pi*t) + 24ft

If you want to learn more about sinusoidal equations, you can read:

https://brainly.com/question/9478364

Answer:

6and 7,8,9,10 CORRECT ME IF I'M WRONG

[tex] {x}^{2} - 8 = 8 \\ [/tex]

x^2 - 8 + 8 = 8 + 8

x^2 = 16

x = √16

x = 4

[tex]{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer:}}}}}}}}}}}}}}[/tex]

[tex] \blue{ {x}^{2} - 8 = 8}[/tex]

[tex] \purple{ {x}^{2} - 8 + 8 = 8 + 8}[/tex]

[tex] \red{ {x}^{2} = 16}[/tex]

[tex] \green{ \sqrt{ {x}^{2} } = \sqrt{16} }[/tex]

[tex] \pink{x = 4}[/tex]

Answer:

9

Step-by-step explanation:

cuz yes

Answer:

17/25

Step-by-step explanation:

68/100

divided by 2

34/50

divided by 2

17/25

and 17/25 is as simplified as it's going to get.

Answer:

  11.3

Step-by-step explanation:

The side opposite the given angle is unknown. The hypotenuse is also given. The trig function that relates the angle, opposite side, and hypotenuse is the sine function:

  Sin = Opposite/Hypotenuse

  sin(39°) = x/18

  x = 18·sin(39°) ≈ 11.3

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

[tex]x^2-2x-(c+4)=0[/tex].

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic [tex]ax^2+bx+d[/tex], the discriminant is [tex]\sqrt{b^2-4ad}[/tex].

(The discriminant is more commonly known as [tex]\sqrt{b^2-4ac}[/tex], but I changed the variable since we already have a [tex]c[/tex] in the quadratic given.)

In the quadratic above, we have [tex]a=1[/tex], [tex]b=-2[/tex], and [tex]d=-(c+4)[/tex]. Plugging this into the formula for the discriminant, we have

[tex]\sqrt{(-2)^2-4(1)(-(c+4))[/tex].

Using the distributive property to expand and simplifying, the expression becomes

[tex]\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.[/tex]

Setting the discriminant equal to 0 gives

[tex]2\sqrt{c+5}=0[/tex].

We can then solve the equation as usual: first, divide by 2 on both sides:

[tex]\sqrt{c+5}=0[/tex].

Squaring both sides gives

[tex]c+5=0[/tex],

and subtracting 5 from both sides, we have

[tex]\boxed{c=-5}.[/tex]

Answer:

HOPE ITS HELPFUL TO yours

[tex]\mathbb{FINAL\;ANSWER:}[/tex]

[tex]\huge\boxed{\sf{y-1=4(x+2)}}[/tex]

[tex]\mathbb{SOLUTION\;WITH\;STEPS:}[/tex]

Hi! Hope you are having a nice day!

We are given:

Can we write the equation of the line in Point-Slope Form? Sure!

y-y₁=m(x-x₁)

y-1=-4(x-(-2)

y-1=-4(x+2)

Hope you could understand everything.

#CarryOnLearning

Step-by-step explanation:

Our equation;

[tex]-5=\frac{y-7}{9}[/tex]

Multiply each side by 9 to remove the fraction;

[tex]-45=y-7[/tex]

Add 7 to each side;

[tex]\boxed{-38=y}[/tex]

Answer:

the ratio is easy to find if you subtract 52 to 24 which is 28 so the ratio is 28 to 24

Answer: 130, sorry if its wrong

Step-by-step explanation:

8 x 5 = 40 --> 40 x 3 1/4 = 130

Answer:

5, 6 are the solutions

step-by-step explanation:

Here, the cost of attending the festival is constant, the bottles of hot sauce keeps changing until less amount of money reached.

Inequality:

5h + 16 = 50

5h = 50 - 16

5h = 34

h = 34/5

h = 6.8

So, he can buy max or less than 6 bottles of hot sauce.

Answer:

The formula for the surface area of a prism is obtained by taking the sum of (twice the base area) and (the lateral surface area of the prism). The surface area of a prism is given as S = (2 × Base Area) + (Base perimeter × height) where "S" is the surface area of the prism.

Step-by-step explanation:

i dont know the base and height because you dont have a picture provided so you can use this as help

Answer: p=5+3/2 or p=5-3/2

Step-by-step explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: {p}^{2} - 10p + 7 = 0[/tex]

Now, let's use Quadratic formula :

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ - ( - 10) \pm \sqrt{ {( - 10)}^{2} - 4(1 \times 7) } }{2 \times 1} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ 10 \pm \sqrt{ 100- 28 } }{2 } [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ 10 \pm \sqrt{ 72 } }{2 } [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ 10 \pm6 \sqrt{ 2 } }{2 } [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ 2(5 \pm3 \sqrt{ 2 }) }{2 } [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = (5 \pm3 \sqrt{ 2 }) [/tex]

So, the required roots are :

[tex]\qquad \sf  \dashrightarrow \:x = 5 + 3 \sqrt{ 2 } [/tex]

and

[tex]\qquad \sf  \dashrightarrow \:x = 5 - 3 \sqrt{2} [/tex]

Answer:

The angles are adjacent (next to each other). Because they are adjacent, the angles equal 180 when added together. Therefore, X = 180-34. X = 146.

Hope this helps, and good luck with math! Have a great day/night :D

Answer:

15 m2 is the answer

Step-by-step explanation:

The side of a rhombus is 15 m2. If the length of one diagonal of the rhombus is 8 cm, then find length of the other diagonal. The side of a rhombus is 15 m2. If the length of one diagonal of the rhombus is 8 cm, then find length of the other diagonal. so, the answer is 15 m2

Answer: 22 m2

Step-by-step explanation:

Answer:

−

2

(

2

−

7

)

Step-by-step explanation:

Let's first write out

2s+4+(-6s)+10

now simplify

-4s+14

again

now correct

The length 2.3 and 7.8 units

We have given that ΔABC, c = 5. 4, a = 3. 3, and measure of angle A = 20 degrees.

The Law of Cosines, which tells us

[tex]a^{2}=b^{2} +c^{2} -2bccosA[/tex]

giving us a quadratic equation for b we can solve.  But let's do it with the Law of Sines as asked.

[tex]\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}[/tex]

We have c,a,A so the Law of Sines gives us sin C

[tex]sinC=\frac{csina}{a} =\frac{5.4sin20}{3.3} =0.5597[/tex]

There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse

[tex]C_{a}=arcsin(0.5597)=34.033^{0}[/tex]

[tex]C_{0}=180-C_{a} =145.96^0[/tex]

Both of these make a valid triangle with A=20°.   They give respective B's:

[tex]B_{a}=180-A-C_{a} =125.96^0[/tex]

[tex]B_{0}=180-C_{0} =14.033^0[/tex]

So we get two possibilities for b:

[tex]b=\frac{asinB}{sinA} \\\\b_{a} =\frac{3.3sin125.96}{sin 20} \\\\b_{a}=7.8\\\\ b_0=2.3[/tex]

2.3 units and 7.8 units

Therefore we get the length 2.3 and 7.8 units

To learn more about the low of sine and cosine visit:

https://brainly.com/question/4372174

Answer: 2.3 units and 7.8 units

Let's check it with the Law of Cosines:

There's a shortcut for the quadratic formula when the middle term is 'even.'

Looks good.

Answer:

10

Step-by-step explanation:

t+1/2t-1=5/7

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation

Answer:

80

Step-by-step explanation:

48 ÷ 6 = 8 per hour

8 x 10 hours = 80 dogs

Answer: Steve can train 80 dogs.

Step-by-step explanation:

How many dogs he can train divided by how many hours is: 48/6 = 8.
He is able to train 8 dogs per hour. So: 8 x 10 = 80.

Answer:

1 feet = 12 inches

therefore ,

5 feet = 5 × 12 = 60 inches

Now ,

16 inches to 60 inches ,

[tex] \frac{16}{60} \div \frac{4}{4} = \frac{4}{15} \\ [/tex]

hope helpful~

Answer: 6 1/3

Step-by-step explanation: 16 inches = 1 foot and 4 inches + 5 feet = 6' 4" 6 4/12 simplify = 6 1/3

Answer:

2/4, 4/8, 8/16, 16/32

Step-by-step explanation:

2/4
2x2/4x2 = 4/8
4x2/8x2 = 8/16
8x2/16x2 = 16/32

Answer:

You can know if the shapes are similar if the are the same type of shape, have proportional side lengths, congruent corresponding angles (the angles are in the same place proportional to the shape and have the same amount of degrees), and equal scale factors.

In number 19, the polygons are similar because they have proportional side lengths and congruent corresponding angles.

Number 20's trapezoid A and B are not similar because the side lengths are not proportional to each other ( 2 is half of 4, 4 is not half of 6)

Hope this helps!

Answer:

i) 4 females

ii) 8 females

Step-by-step explanation:

1. Ratio of males= 3x

3x = 3

Thus, x = 1

If there are 3 males, there will be 4 females

2.Rato of males= 3x

3x = 6

Thus x = 2 [6 divided by 3]

4x = 4 x 2 = 8

If there are 6 males, there would be 8 females.

Given :-

[tex] \\ \\ [/tex]

To find :-

[tex] \\ \\ [/tex]

Solution :-

[tex] \\ [/tex]

[tex] \looparrowright \sf3x + 5y = 60[/tex]

Put value of x in the equation!

[tex] \\ [/tex]

[tex] \looparrowright \sf3(10)+ 5y = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf3 \times 10+ 5y = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf30+ 5y = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf5(6 + y) = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf(6 + y) = 60 \div 5[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf6 + y= \dfrac{60}{5} [/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf6 + y=\cancel \dfrac{60}{5} [/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf6 + y= \dfrac{12}{1} [/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf6 + y=12[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf y=12 - 6[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \bf y=6[/tex]

[tex] \\ [/tex]

Verification:-

[tex] \\ [/tex]

[tex] \looparrowright \sf3x + 5y = 60[/tex]

Put value of x and y.

[tex] \\ [/tex]

[tex] \looparrowright \sf3(10)+ 5(6) = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf3 \times 10+ 5(6) = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf30+ 5(6) = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf30+ 5 \times 6= 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf30+ 30= 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \bf60= 60[/tex]

LHS = RHS

HENCE VERIFIED!

Answer:

c

Step-by-step explanation:

it’s equal

Answer:

f=4

Step-by-step explanation:

so, when we do this problem notice that there is a variable this can mean a lot of things but in this case, it just means were solving for f so we first move the constant (5) to the right-hand side and change its sign then we subtract 33 from 5 to get 28 so the equation would look like 7f = 33-5

to get 7f = 28 and now for the last step you divide both sides of the equation to get f = 4

Hope this helped :)