Value Grocery Mart and Market City are both having a sale on the same popular crackers. McKayla is trying to determine which sale is the better deal. Using the given table and equation, determine which store has the better deal on crackers? Explain your reasoning. (Remember to round your answers to the nearest penny.)

Value Grocery Mart:
Number of Boxes of Crackers
3
6
9
12
Cost (in dollars)
5
10
15
20

Answer:

48 lbs

Step-by-step explanation:

say that the cat weighs x pounds. then the dog weighs 8x pounds. together they weigh 54 pounds. So our equation is x+8x=54. solve for x to get the cat's weight, and you get x=6. The cat weighs 6 lbs. all I need to do now is multiply 6 by 8 so this the dog weighs 8 times as much as the cat. 8•6=48. the dog weighs 48 pounds.

Answer:

The answer is $85.45 after the 5% discount

it is 9    aahh it says to short   well 3 times 9 is 27 then minus 17 is less than 13

Answer:

v <= 10

(-infinity, 10]

Step-by-step explanation:

3v - 17 <= 13

+17 +17

3v <= 30

3v/3 30/3

v <= 10

(-infinity, 10]

Answer:

y = - 3x - 2

Step-by-step explanation:

Step 1:

y = mx + b     Slope Intercept Form

Step 2:

y = - 3x + b     Input Slope

Step 3:

4 = - 3 ( - 2 ) + b     Input x and y

Step 4:

4 = 6 + b     Multiply

Step 5:

- 2 = b       Subtract 6 on both sides

Answer:

y = - 3x - 2

Hope This Helps :)

Answer:

2/5

Step-by-step explanation:

Answer:

2.25 is your answer

Step-by-step explanation:

Answer:

-53, f(n) = -6(n-1) + 13

Step-by-step explanation:

given the equation to this linear/arithmetic sequence for the nth term: f(n) = -6(n-1) + 13

f(12) = -6(12-1) + 13

f(12) = -6(11) + 13

f(12) = -66 + 13

f(12) = -53

*substitute and simplify*

______________

f(n) = f(1) + d(n-1)

given f(1) = 13, f(2) = 7, and f(3) = 1

7-13 = 1-7 = -6 = d

= f(1) + d(n-1)

f(1) = 13 so

the equation must be f(n) = 13 - 6(n-1) or -6(n-1) + 13

Answer:

B.

Step-by-step explanation:

Answer:

0.05 per ounce

Step-by-step explanation:

5.20 per 40 is 0.13 per ounce

whereas

2.70 per 15 is 0.18 per ounce

Answer:

I'm on Edulastic.com taking a 100 Q test and this question is on it!

Step-by-step explanation:

Imao im fgging confused

The graph of the required line [tex]\bold{y=\frac{x}{4}+2}[/tex] is given below.

An equation of line with slope m and passing through point (p, q) is:

(y - q) = m × (x - p)

We have been given the slope of the line m = 1/4,

and a point (p, q) = (0, 2)

Using the slope-point form equation of line would be,

⇒ (y - 2) = 1/4 × (x - 0)

⇒ (y - 2) = 1/4(x)    

⇒ y = x/4 + 2                          ...............................(1)

So, the equation of the line is [tex]y=\frac{x}{4} +2[/tex].

To plot the line we need at least  two coordinate points.

We have been given a point (0, 2).

We need to find another point.

Substitute x = -4 in equation (1),

⇒ y = (-4)/4 + 2

⇒ y  = -1 + 2

⇒ y = 1

So, another point on the line would be (-4, 1).

Now, we plot points (0, 2) and (-4, 1) on coordinates plane.

Then the graph of the line [tex]\bold{y=\frac{x}{4}+2 }[/tex] is as shown in figure.

Learn more about the graph of a line here:

https://brainly.com/question/23680294

#SPJ2

Answer:It take her 20 minutes, but I dont know how to graph yet, so I can only tell you that xx=20

Answer:they are both neagtive numbers.

Step-by-step explanation:

they say it right in front of you.

Answer:

Step-by-step explanation:

Answer:

dhvbhdvhdhddjbd

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Lets say 4 boys to 6 girls if there are 36 girls do 4x6 to figure out the ratio of boys would be 24 boys and 36 girls if the other way around it would be 24 girls and 36 boys

Answer:

I want the free points. Sorry :)

Answer:

12 t-shirts

Step-by-step explanation:

12 x 75% = 9 = 9 t-shirts

Answer:

ROC

Step-by-step explanation:

ROC. rate of change

On a table or graph, the constant change is same as the unit rate, rate of change or slope, which can be denoted as m.

Constant change on a graph or table simply refers to the rate of change of the output (y) over the change in input (x).

Constant change in a graph or table is the same as the unit rate or the slope value which is dented by the letter m.

Constant rate of change, unite rate, and slope can be denoted as m of a graph or table.

Learn more here:

https://brainly.com/question/23184256

Answer:

5

4

6

.........................

Answer:

x= - 8/9

Step-by-step explanation:

Answer:

The value of a and b are 8 and 1 respectively

Step-by-step explanation:

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 , \text{otherwise}\end{matrix}\right.[/tex]

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1\\\\c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1\\\\\frac{c}{2}\int_{0}^{1}x\left ( 1-y^2\right )\text{dx}=1\\\\\frac{c}{2}\int_{0}^{1}(x-x^3)\text{dx}=1\\\\\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1\\\\\frac{c}{2}\left [ \frac{1}{2}-\frac{1}{4} \right ]=1\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1\\\\c=8[/tex]

Conditional pdf of [tex]f_{x,y}(x|0.5)[/tex]

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

Normalizing pdf of 1

[tex]f_{y}y=\int_{0}^{y} 8yx \text{dx}[/tex]

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\\f_{y}y=4y(y^2)\\f_{y}y=4y^3\\f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}=\frac{2x}{0.25}=8x[/tex]

We are given that PDF [tex]f_{x|y}(x|0.5)[/tex] is of the form [tex]ax^b[/tex]

So, on comparing 8x with [tex]ax^b[/tex]

So, a = 8 , b = 1

So, the value of a and b are 8 and 1 respectively

The resulting value of a and b given  the conditional PDF of fX|Y(x|0.5) is mathematically given as

a = 8 , b = 1 .

Question Parameters:

a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,

For x∈[0,0.5]

the conditional PDF fX|Y(x|0.5)

Generally, the equation for the function of (x,y)   is mathematically given as

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 ,\end{matrix}\right.[/tex]

Therefore

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1[/tex]

[tex]c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1[/tex]

[tex]\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1[/tex]

[tex]\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1[/tex]

C=8

Where, the conditional PDF fX|Y(x|0.5)

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

We have

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\[/tex]

[tex]f_{y}y=4y^3[/tex]

[tex]f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}[/tex]

f_{x|y}(x|0.5)=8x

In conclusion. with the pdf in the form of ax^2

8x comparing ax^b

The value of a = 8 , b = 1 .

Read more about Arithmetic

https://brainly.com/question/22568180

Answer:

if u could include a photo it may help more ..thanks

Answer:

s=3

Step-by-step explanation:

Answer:

s=3

Step-by-step explanation:

simplify the equation to the form, which is simple to understand  

and then move all terms containing s to the left and all other terms to the right!

Answer:

transitive property of equality

Step-by-step explanation:

I know cus i took the test also sorry it took so long dude

Answer:

Step-by-step explanation:

Answer:

k>3/2

Step-by-step explanation:

To solve this, you need to do fraction cross-multiplying.

So, If a/b=c/d, then a*d=c*b

After you cross-multiply, you get this: (11k-15)*4>3(5-2k)

If you simplify 3(5-2k), you get 15-6k

Then, simplify the next side as well

The full simplified expression should be: 44k-60>15-6k

If you add 60 to both sides, you get 44k>-6k+75

Then add 6k to both sides 50k>75

Then all you have to do is divide both sides by 50 and you get:

K>3/2 OR k>1.5

Is there more information so that I solve?

Domain: hours worked

Domain Values: 1,2,3,4

Range: dollars charged

Range Values: 165, 215, 265

The relation is a function. Each domain value is paired with exactly one range value.

Answer:

56 - 38 = 18

Step-by-step explanation:

Answer:

18 paper clips

Step-by-step explanation:

56 paperclips originally - x paperclips = 38 paperclips

56 - x = 38

    + x    + x

56      = 38 + x

- 38       - 38

18       =         x  

x = 18

Answer:

20, 10, 12.50

Step-by-step explanation: