Twenty percent of all seventh graders have watched a horse race. In a sample of 15 seventh graders, 4 have watched a horse race. Does the sample closely estimate the percentage of seventh grades who have watcher a horse race?

Answer:

b=negative 5/2

Step-by-step explanation:

first, convert the decimal into a fraction

−28.3= -3.3+b/1/10

simplify the complex fraction

-28.3=-3.3+10b

add 3.3 to both sides

-25=10x

divide each side by 10

x=negative 5/2 or x=negative 2.5

Answer:

y = - [tex]\frac{5}{3}[/tex]

Step-by-step explanation:

6x - 3y = - 7 → (1)

2x + 3y = - 9 → (2)

multiplying (2) by - 3 and adding to (1) will eliminate x

- 6x - 9y = 27 → (3)

add (1) and (3) term by term to eliminate x

0 - 12y = 20

- 12y = 20 ( divide both sides by - 12 )

y = [tex]\frac{20}{-12}[/tex] = - [tex]\frac{5}{3}[/tex]

Answer:

h³-21h-100

Step-by-step explanation:

You only have to subtract 25h from 4h.

to find radius; 8.4/2,

Answer:

398.5

Step-by-step explanation:

a (surface area) = 2πrh + 2π[tex]r^{2}[/tex]

r (radius) = 8.4/2

r = 2.4

a = 2π (4.2 x 10.9) + 2π (4.2 x 4.2)

a = 2π x 45.78 + 2π x 17.64

a = 287.64 + 110.83

a = 398.5

if we take 837 as the 100%, what is 97 off of it in percentage?

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 837&100\\ 97&x \end{array}\implies \cfrac{837}{97}=\cfrac{100}{x}\implies 837x=9700 \\\\\\ x=\cfrac{9700}{837}\implies x\approx 11.59[/tex]

Answer:

it would just be 10a^5 since we dont know what a is

Step-by-step explanation:

Answer:

10a^5

To solve this problem, we first have to look at what we know and what we don't know.

We know we have to multiply 10 by a and then raise the result to the 5th power.

We don't know the value of a.

That means we just have to solve what we can.

10 x a = 10a

10a to the 5th power is 10a^5

Answer:

a. 16; b. mean = 43.75; median = 43; mode = none

Step-by-step explanation:

Put all the numbers in order:

36, 38, 40, 41, 45, 48, 50, 52

a. Range:

52 - 36

= 16

b. Mean:

(36 + 38 + 40 + 41 + 45 + 48 + 50 + 52) /8

= 43.75

Median:

36, 38, 40, 41, 45, 48, 50, 52

=> (41 + 45) / 2

= 43

Mode: None (no numbers come again)

Answer:

ok

Step-by-step explanation:

x:

X is adjacent to the 75 angle so x + 75 need to be 180.

180 - 75 = 105

x = 105

z:

Z is on opposite across outside corners from X so it will be the same thing.

z = 105

y:

Y is adjacent to Z so Y + Z must equal 180.

Z = 105

y + 105 = 180

y = 75

Step-by-step explanation:

m ( < E ) = m ( < N )

m ( < H ) = m ( < J )

m ( < A ) = m ( < O )

NH = EJ

NA = EO

AH = JO

Answer:

18 boys

Step-by-step explanation:

boys/girls = 3/11 = b/66

3/11 = b/66

11b = 3 × 66

b = 3 × 6

b = 18

There are 18 boys.

Answer:

3/13

Step-by-step explanation:

Put the total number that tapped the ground AND 5/10 worms (which is 3) over the total number which is 13

so 3/13 which doesn't simplify

hope this helped :)

Answer:

4580.442

Step-by-step explanation:

the closest answer I can fight

Answer:

5.25

Step-by-step explanation:

Answer: 105/20 in decimal = 5.25

Step-by-step explanation: The fraction bar means "divided by" in the fraction 105/20, where 105 is the numerator and 20 is the denominator. As a result, the fraction 105/20 can be written as "105 divided by 20" or "105 20."

We discovered that 105/20 in decimal form is: 105 20 = 5.25 when we divided 105 by 20.

As a result, 105/20 has a decimal form of 5.25.

Hope this helps.

This is a trick question. They eat 1/3 of the gallons given. Multiply

1/3 * 1/3 = 1/9 gallons or 0.111 gallons

Answer: Aye aye, cap'in

Step-by-step explanation:

So we start off with our base value, 1/3 gallons.

We are trying to find how many gallons we have eaten, so we do 1/3*1/3, since we need to find what is 1/3rd of that gallon.

For reference, if you wanted to find how much is left over, we multiply by 2/3 since 1-1/3 = 2/3, so there are 2/3 of the 1/3rd gallons left. Not important for solving this problem, but it might help you understand why we decided to multiply by 1/3.

1/3 * 1/3 = 1/9

Our answer is 1/9.

From the given data

93% of the bar is silver :

[tex]\small\bold{ → 93\% \: \: of \: \: 7kg}[/tex]

[tex]\small \bold{→\frac{93}{100} \times 7 }[/tex]

[tex]\small \bold{→ \frac{651}{100} }[/tex]

[tex]\small \bold{→ 6.51 \: kg }[/tex]

Therefore, 6.51 Kg of Silver is there in the bar.

» A metal bar weighs 7 Kg. 93% of the bar is Silver. How many Kgs of silver is there in the bar?

— — — — — — —

Therefore, 6.51 kg of Silver is there in the bar.

_______________❦︎_______________

The range of acceptable values for production to continue working of the company without stoppage is 15.85 to 16.15.

Range is the area of fluctuation between the upper and lower limit. The range of the acceptable values is all the values between the upper and lower limit.

Here, a company manufactures 16-oz boxes of cereal.  Now, this boxes are randomly weighted to ensure the correct amount.

As the discrepancy in weight is more than 0.15 oz then the production of the company is stopped.

To proper functioning of the company without stoppage, the limit of the production should be with in 0.15 oz.

The company produce, 16-oz boxes of cereal and the disperancy is 0.15 oz. Thus the value of the lower limit will be,

[tex]L=16-0.15\\L=15.85\rm \; oz[/tex]

The value of the upper limit will be,

[tex]U=16+0.15\\U=16.15\rm \; oz[/tex]

Thus, the range will be {15.85-16.15 oz}

Hence, the range of acceptable values for production to continue working of the company without stoppage is 15.85 to 16.15.

Learn more about the range here;

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Answer:

Thoma is 11

Step-by-step explanation:

We can call Aldo 'a' and Thoma 't'.

"Aldo's age is three times Thoma's age" can be written algebraically as a = 3t

"The sum of their ages is 44" can be written as a + t = 44

Because we know that a = 3t, we can substitute this into the equation a + t = 44 to get 3t + t = 44. This can be simplified to 4t = 44. If we divide both sides by four we get t = 11. This means that Thoma is 11.

Hope this helps!

Answer:

456.2 units², so answer d

Step-by-step explanation:

The area of the square base is ...

 base area = w² = (10 units)² = 100 units²

The lateral area is 4 times the area of one rectangular face:

 lateral area = 4wx = 4(10 units)(5 units) = 200 units²

The area of one triangular face is half the product of its base length (w) and its slant height (h). The latter is found using the Pythagorean theorem:

 h² = y² +(w/2)² = (6 units)² +((10 units)/2)² = 61 units²

 h = √61 units

So, the area of 4 triangles is ...

 area of triangular faces = 4(1/2)wh = 2(10 units)(√61 units) ≈ 156.2 units²

Now we have the areas of the parts, so we can add them together to get the total surface area:

 surface area = base area + lateral area + area of triangular faces

 = 100 units² + 200 units² + 156.2 units²

 surface area = 456.2 units²

The Viola’s monthly payment more than the loan is unsubsidized than if the loan is subsidized is $35.05.

Compound interest is the amount charged on the principal amount and the accumulated interest with a fixed rate of interest for a time period.

The formula for the final amount with the compound interest formula can be given as,

[tex]A=P\left(1+\dfrac{R}{n\times100}\right)^{nt}[/tex]

Here, A is the final amount (principal plus interest amount) on the principal amount P of with the rate r of in the time period of t.

Viola took out a $8,470 Stafford loan at the beginning of her four-year college career. The loan has a duration of ten years and an interest rate of 7. 5%, compounded monthly.

Put this values in the above formula as,

[tex]A=8470\left(1+\dfrac{7.5}{12\times100}\right)^{12\times4}\\A=11422.6348[/tex]

For the four years, the monthly payment is,

[tex]m=\dfrac{11422.6348}{12\times4}\\m=237.97[/tex]

The monthly payment of unsubsidized loan is $237.97.

The monthly payment of subsidized loan is $202.80.

The difference between the unsubsidized and subsidized loan monthly payment is,

[tex]d=237.97-202.80\\d=35.17\\d\approx 35.05[/tex]

Thus, the Viola’s monthly payment more than the loan is unsubsidized than if the loan is subsidized is $35.05.

Learn more about the compound interest here;

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We are given with a function y and need to find dy/dx or the first Derivative of y w.r.t.x , but let's recall

Now consider :

[tex]{:\implies \quad \sf y=e^{x}-\dfrac{1}{x}+log_{e}x}[/tex]

Differentiating both sides w.r.t.x

[tex]{:\implies \quad \sf \dfrac{d}{dx}(y)=\dfrac{d}{dx}\bigg\{e^{x}-\dfrac{1}{x}+log_{e}x\bigg\}}[/tex]

[tex]{:\implies \quad \sf \dfrac{dy}{dx}=\dfrac{d}{dx}(e^x)-\dfrac{d}{dx}\left(\dfrac{1}{x}\right)+\dfrac{d}{dx}(log_{e}x)}[/tex]

[tex]{:\implies \quad \sf \dfrac{dy}{dx}=e^{x}-\dfrac{d}{dx}(x^{-1})+\dfrac{1}{x}}[/tex]

[tex]{:\implies \quad \sf \dfrac{dy}{dx}=e^{x}-(-1)(x)^{-1-1}+\dfrac{1}{x}}[/tex]

[tex]{:\implies \quad \sf \dfrac{dy}{dx}=e^{x}+(x)^{-2}+\dfrac{1}{x}}[/tex]

[tex]{:\implies \quad \sf \dfrac{dy}{dx}=e^{x}+\dfrac{1}{x^{2}}+\dfrac{1}{x}}[/tex]

Simplifying will yield

[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{\dfrac{dy}{dx}=\dfrac{e^{x}x^{2}+x^{2}+x}{x^{2}}}}}[/tex]

This is the required answer

Step-by-step explanation:

is the same as

[tex]x^5 + 3^5\\x^5 + 243[/tex]

Does that make sense

please mark brainest

Given expression :

[tex]{\qquad \sf \dashrightarrow{ (x+3)^{5} } }[/tex]

We need to simplify it.

We can write the expression as,

[tex]{\qquad \sf \dashrightarrow{ (x+3)^{} }{ (x+3)^{} }{ (x+3)^{} }{ (x+3)^{} }{ (x+3)^{} }}[/tex]

[tex]{\qquad \sf \dashrightarrow{ (x+3)^{2} }{ (x+3)^{2} }{ (x+3)^{} }}[/tex]

We know that,

[tex]{\qquad \sf \dashrightarrow{ (a+b)^{2} } = {a}^{2} + 2ab + {b}^{2} }[/tex]

Now, using the formula in the expression:

[tex]{\qquad \sf \dashrightarrow{ (x {}^{2} + 2x.3 +3^{2}) }{ (x {}^{2} + 2x.3 +3^{2}) }{ (x+3)^{} }}[/tex]

[tex]{\qquad \sf \dashrightarrow{ (x {}^{2} + 6x +9) }{ (x {}^{2} + 6x +9) }{ (x+3)^{} }}[/tex]

[tex]{\qquad \sf \dashrightarrow{ ( {x}^{4} + 6 {x}^{3} + 9 {x }^{2} + 6x {}^{3} + 36 {x}^{2} + 54x + 9 {x}^{2} + 54x + 81 ) }{ (x+3)^{} }}[/tex]

[tex]{\qquad \sf \dashrightarrow{ ( {x}^{4} + 12{x}^{3} + 54 {x }^{2} + 108x + 81 ) }{ (x+3)^{} }}[/tex]

[tex]{\qquad \sf \dashrightarrow{ \: {x}^{5} + 12 {x}^{4} + 54 {x}^{3} + 108 {x}^{2} + 81x + 3 {x}^{4} + 36x {}^{3} + 162 {x}^{2} + 324x + 243 }}[/tex]

Adding the like terms we get :

[tex]{\qquad \sf \dashrightarrow{ \: {x}^{5} + 15 {x}^{4} + 90 {x}^{3} + 270 {x}^{2} + 405x + 243 }}[/tex]

Answer: Triangle 4

The specific translation or shifting is "move 9 units to the right and 4 units down".

We can prove this by looking at something like point A(-10,2) and note how it moves to (-4,-2). Going from (-10,2) to (-4,-2) is exactly 9 right and 4 down.

In terms of x,y notation the translation rule is [tex](x,y) \to (x+9,y-4)[/tex]

Answer:

i think it is 24

i think it is Step-by-step explanation:

Answer:

The players club is playing with the players

Step-by-step explanation:

give me a good Answer to my Question

What is the scale factor of this dilation? a:1/2 b:2/3 c:3/4 d:3/2

Answer:16

Step-by-step explanation:

For 1/8 of the lawn it takes 2 hours

So, for the entire lawn it will take 2/(1/8) = 16

So, your final answer is 16 hoursHope this helps!

Answer:

1) 0.25
2)4

Step-by-step explanation:

1) 12 divided by 48 is 0.25

2) 48 divided by 12 is 4

hope this helps

Answer: 26

Step-by-step explanation:

Answer:

For the 2 first exponents you multiply for the last 2 you add the powers

Step-by-step explanation:

-2x4=-8=4^-8

2x-1=-2 4^-2

2+6= 4^8

5-3=2 4^2

Using the z-distribution, as we have the standard deviation for the population, it is found that it does not appear that there is a difference.

At the null hypothesis, it is tested that there is no difference, that is, the mean of the distribution of the differences is of 0, hence:

[tex]H_0: \mu = 0[/tex]

At the alternative hypothesis, it is tested if there is a difference, hence:

[tex]H_1: \mu \neq 0[/tex]

It is given by:

[tex]z = \frac{\overline{x} - \mu}{s}[/tex]

In which:

In this problem, the parameters are as follows: [tex]\mu = 1.11, s = 4.28[/tex].

Hence:

[tex]z = \frac{\overline{x} - \mu}{s}[/tex]

[tex]z = \frac{1.11 - 0}{4.28}[/tex]

[tex]z = 0.26[/tex]

Considering a two-tailed test, as we are testing if the mean is different of a value, with a standard significance level of 0.05, the critical value is of [tex]|z^{\ast}| = 1.96[/tex].

Since the absolute value of the test statistic is less than the critical value, we do not reject the null hypothesis, that is, it does not appear that there is a difference.

To learn more about the z-distribution, you can check https://brainly.com/question/26454209