the weight of an apple is 150g, rounded to the nearest 5g. What is the lower bound of the weight of the apple?
What is the upper bound of the weight of the apple?​

Relative error = absolute error / measured speed

Relative error = 1/52 = 0.01923

Percent = 0.01923 x 100 = 1.923%

Rounded to nearest tenth = 1.9%

Answer:

3/5 miles

Step-by-step explanation:

Average Distance = Total Distances / Total Number of Runners

Average Distance = [0.3+0.4+0.5+0.6+(4*0.7)+0.8] / 9 = 3/5

Answer:

180 cm³

Step-by-step explanation:

A rectangular prism with length, L, width, W, and Height, H, has a volume, V, given by the formula below.

V = LWH

Think of this solid as being a rectangular prism with a smaller rectangular prism taken out of the top right corner.

V = 6 cm × 5 cm × 8 cm - 3 cm × 5 cm × 4 cm

V = 240 cm³ - 60 cm³

V = 180 cm³

Step-by-step explanation:

he has 60%

so he needs 40%

40% of 120

of is ×

40% × 120

40% as a decimal is

put answer in comments

Answer:

[tex] - 4 \: \: \: \: \: 2 \ \\ - 3 \: \: \: 0[/tex]

Answer: (1,4) (2,7) (3,10)

HOpE iT hElpS

plS mArK As bRaiNlieSt -wiggly

Step-by-step explanation:

Answer: 27090 is invested. part at 13% part at 10% the interest earned at 13% exceeds the interest earned at 10% by 440.16 how much is invested at each rate.

Answer:

5

4x^11*y^6

In words:

5 over 4x to the 11th power times y to the 6 power.

Step-by-step explanation:

simplify from original to this:

5x^9*y^6

4x^20*y^12

=

5y^6

4x^11*y^12

=

5

4x^11*y^6

Answer:

c-9>23.

Step-by-step explanation:

The difference in an equation is c-9. Greator is >. So c-9>23.

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

- I have used different colours for indicating different process

- I used brown colour to indicate steps

- I used green colour for explaining solution

- Pink colour for known properties of integration

- Purple colour for the middle steps that are optional.

[Note :- For solving such questions it is mandatory that you should know all the functions and it's derivatives ]

[tex]\sf{=}{\sf{\dfrac{ x^{2}}{2}}}{\sf{ + 7x + 67x .In| x - 4 | - 30.In| x - 3 | + c }}[/tex]

Answer:

[tex]\displaystyle \large{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}[/tex]

Step-by-step explanation:

To find an integration of this function, first, you must know these integration methods and differences of them.

These methods above are common when it comes to integrating fractional functions, except there are differences when to use these methods.

Examples (of these integrands that require partial fraction technique)

[tex]\displaystyle \large{\int \frac{3}{x^2-5x+6} \ dx}\\\displaystyle \large{\int \frac{x+2}{x^2-4} \ dx}[/tex]

Examples (of these integrands that require long division)

[tex]\displaystyle \large{\int \frac{x^2+5x+6}{x+2} \ dx}\\\displaystyle \large{\int \frac{x^4+3}{x} \ dx }[/tex]

Therefore, from the given integral, the integrand requires long division method. (See attachment for long division.)

After long division, we should get:

[tex]\displaystyle \large{\int x+7+\frac{37x-81}{x^2-7x+12} \ dx}[/tex]

Recall important properties of integral such as:

[tex]\displaystyle \large{\int [f(x) \pm g(x)] \ dx = \int f(x) \ dx \pm \int g(x) \ dx}[/tex]

Hence:

[tex]\displaystyle \large{\int x \ dx + \int 7 \ dx + \int \frac{37x-81}{x^2-7x+12} \ dx}[/tex]

Recall important integration formula for polynomial and constant:

[tex]\displaystyle \large{\int x^n \ dx = \frac{x^{n+1}}{n+1} + C}\\\displaystyle \large{\int x \ dx = \frac{x^2}{2} + C}\\\displaystyle \large{\int k \ dx = kx + C \ \ \tt{(k \ \ is \ \ a \ \ constant.)}[/tex]

Therefore:

[tex]\displaystyle \large{\frac{x^2}{2}+7x+\boxed{\int \frac{37x-81}{x^2-7x+12} \ dx}}[/tex]

From the boxed integral above, we cannot evaluate it by default. From what I said, if the degree of numerator is less than the degree of denominator, we’ll use partial fraction technique.

Therefore, factor the denominator:

[tex]\displaystyle \large{\frac{37x-81}{(x-4)(x-3)}}[/tex]

Set to A/x-4 and B/x-3

[tex]\displaystyle \large{\frac{37x-81}{(x-4)(x-3)} = \frac{A}{x-4} + \frac{B}{x-3}}[/tex]

Multiply both sides by (x-4)(x-3).

[tex]\displaystyle \large{\frac{37x-81}{(x-4)(x-3)} \cdot (x-4)(x-3)= \frac{A}{x-4} \cdot (x-4)(x-3) + \frac{B}{x-3} \cdot (x-4)(x-3)}\\\displaystyle \large{37x-81= A(x-3) + B(x-4)}\\\displaystyle \large{37x-81= Ax-3A+Bx-4B}\\\displaystyle \large{37x-81= (A+B)x-(3A+4B)}[/tex]

Then compare the coefficients:

[tex]\displaystyle \large{\left \{ {{A+B=37} \atop {3A+4B=81}} \right}[/tex]

Solve the simultaneous equation for A and B.

[tex]\displaystyle \large{\left \{ {{A=37-B} \atop {3A+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {3(37-B)+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {111-3B+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {111+B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {B=81-111}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {B=-30}} \right}\\\displaystyle \large{\left \{ {{A=67} \atop {B=-30}} \right}\\[/tex]

Therefore, A = 67 and B = -30. Substitute the values in:

[tex]\displaystyle \large{\int \frac{67}{x-4}-\frac{30}{x-3} \ dx}\\\displaystyle \large{\int \frac{67}{x-4} \ dx -\int \frac{30}{x-3} \ dx}[/tex]

Recall the integration formula for above:

[tex]\displaystyle \large{\int \frac{k}{x-a} \ dx = \int k \cdot \frac{1}{x-a} \ dx = k\ln |x-a| + C}[/tex]

Therefore:

[tex]\displaystyle \large{\int \frac{37x-81}{x^2-7x+12} \ dx = \int \frac{67}{x-4}-\frac{30}{x-3} \ dx = 67\ln |x-4| - 30\ln |x-3|}[/tex]

Back from this:

[tex]\displaystyle \large{\frac{x^2}{2}+7x+\boxed{\int \frac{37x-81}{x^2-7x+12} \ dx}}[/tex]

Substitute in:

[tex]\displaystyle \large{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}[/tex]

Therefore the solution is:

[tex]\displaystyle \large \boxed{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}[/tex]

Answer:

x-intercept is 5

y-intercept is -6

Step-by-step explanation:

To find x-intercept put y=0

since 6x-5y=30 then 6x=30

x=30/6 = 5

To find y-intercept put x=0

since 6x-5y=30 then -5y=30

y=30/-5 = -6

Answer:

divide it into smaller shapes and find the area then find the sum

Answer:

58.45

Step-by-step explanation:

Use BIDMAS

14.5 X 3.1 = 44.95

44.95 + 13.5 = 58.45

Answer:

58.45

Step-by-step explanation:

The Given Polynomial has three different parameters scattered, first we have to rearrange and then solve for the missing numbers the answer is gotten as 2x^2+7x+4

Given Data

2x−6+4x^2+5x−2x^2+10

We begin by collecting like terms

4x^2-2x^2+2x+5x-6+10

Carrying out addition and subtraction operation on like terms

2x^2+7x+4

The Simplified polynomial is

2x^2+7x+4

Learn more about polynomial here:

https://brainly.com/question/2833285

Answer:

[tex]46\frac{1}{8}[/tex]

Step-by-step explanation:

Formulate

[tex]1845\div40[/tex]

Calculate

[tex]\frac{1845}{40}[/tex]

Cross out the common factor

[tex]\frac{369}{8}[/tex]

Write [tex]\frac{369}{8}[/tex] as a mixed fraction

[tex]46\frac{1}{8}[/tex]

I hope this helps you

:)

Answer:

do you already have it answer.lol.

Answer:

The answer should be 24

Step-by-step explanation:

All you need to do is replace the variables (a, b, and c) with the numbers given.

16 +64/8 would equal to 24

step 1

[tex]\begin{matrix}\:\:\:\:\emptyspace0.\:\:\:\:\:\:\:\:\:\:\:\\ 8\overline{|\smallspace3.0}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace0}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\emptyspace3\emptyspace0\:\:\:\:\:\:\:\:\:\:\end{matrix}[/tex]

step 2

[tex]\begin{matrix}\:\:\:\:\emptyspace0.\emptyspace3\:\:\:\:\:\:\:\:\:\\ 8\overline{|\smallspace3.0\cdot \:0}\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace0}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\emptyspace3\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace6\emptyspace0\:\:\:\:\:\:\:\:\end{matrix}[/tex]

step 3

[tex]\begin{matrix}\:\:\:\:\emptyspace.\emptyspace3\emptyspace7\:\:\:\:\:\:\:\\ 8\overline{|\smallspace 3 0\ \ \:}\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace0}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\emptyspace3\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace6\emptyspace0\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\emptyspace4\emptyspace0\:\:\:\:\:\:\end{matrix}[/tex]

step 4

[tex]\begin{matrix}\:\:\:\:\epe0.\ece3\empt7\e5\:\:\:\:\:\\ 8\overline{|\sm30 \ \ \ \ }\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace0}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\em3\e0\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\eme6\ece0\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\empte5\ee6}\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\ee4\ece0\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\underline{\ee4\epace0}\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\e0\:\:\:\:\:\:\end{matrix}[/tex]

Answer:

3.75

Step-by-step explanation:

[tex]\mathrm{Write\:the\:problem\:in\:long\:division\:format}[/tex]

[tex]\begin{matrix}8\overline{|\smallspace3.0}\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;30\;by\;8\;to\;get\;3}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\emptyspace3.\:\:\:\:\:\:\:\:\:\:\:\\ 8\overline{|\smallspace30.0}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace6\emptyspace0\:\:\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;60\;by\;8\;to\;get\;7}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\emptyspace3.\emptyspace7\:\:\:\:\:\:\:\:\:\\ 8\overline{|\smallspace30.0\cdot \:0}\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace6\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\emptyspace4\emptyspace0\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;40\;by\;8\;to\;get\;5}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\emptyspace3.\emptyspace7\emptyspace5\:\:\:\:\:\:\:\\ 8\overline{|\smallspace30.0\cdot \:0}\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace4}\:\:\:\:\:\:\:\:\:\:\:\:\\ \emptyspace6\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\:\:\\ \emptyspace4\emptyspace0\:\:\:\:\:\:\:\:\\ \underline{\emptyspace4\emptyspace0}\:\:\:\:\:\:\:\:\\ \emptyspace0\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{3}{0.8}\:\mathrm{is}\:3.75[/tex]

~lenvy~

Answer:

y=2x+3

Step-by-step explanation:

y=mx+b

Answer:

y=$3 + $2x.

Step-by-step explanation:

y=3+2x. Make a table, at week 1 Nate has $2 + the $3 he started with. At week 2, Nate has $4 plus the $3 he started with.  And so on.  Plug the number of weeks in for x and solve for y for the total at any number of weeks given.

Answer:

10 = 3 hours

one hour = 3.33 dollars

Step-by-step explanation:

Answer:

Its C: 12 units × 8 units are the dimensions of the rectangle

Step-by-step explanation:

Answer:

(3/2, -1/2)

Step-by-step explanation:

add the 2 inequalities together.

you get 2X<3 so x<3/2. plug X back in and solve for y and you get y= -1/2

Answer:

[tex]\boxed{a=2,\:b=4}[/tex]

Step-by-step explanation:

[tex]\begin{bmatrix}3a+5b=26\\ a+5b=22\end{bmatrix}[/tex]

Isolate a from 3a + 5b = 26,

[tex]a=\cfrac{26-5b}{3}[/tex]

[tex]\begin{bmatrix}\cfrac{26-5b}{3}+5b=22\end{bmatrix}[/tex]

[tex]\begin{bmatrix}\cfrac{26+10b}{3}=22\end{bmatrix}[/tex]

Now, Isolate b for  

[tex]\cfrac{26+10b}{3}=22\:\:\boxed{b=4}[/tex]

Now, Substitute b=4

[tex]a=\cfrac{26-5\times \:4}{3}[/tex]

[tex]\cfrac{26-5\times \:4}{3}\:\:\boxed{a=2}[/tex]

[tex]\boxed{a=2,\:b=4}[/tex]

~

Answer:

[tex]x = \frac{4}{3}- 1[/tex]

x=4/3 , -1

Answer:

the answer send me a 100dollar gift card

Answer:

16+ 2x

Step-by-step explanation:

2(10) +2(x-4)

20 + 2x -8

16+ 2x

Answer:

It's asking what 3^k+2 is in terms of m. That is where the 2 comes from.

Please let me know if this helped <3

Answer:

6/8 red paint

10/8 blue paint

4th grade savvas realize