The Family Fair Committee wants to show a good
family movie at their next event. They want to
select a movie that will appeal to families with
young children. Which of the following samples
would be the BEST representation of that
population?
A. Ask 100 people at local Senior Citizen Bingo
night
B. Ask 100 students who are in the local Band.
C. Ask 100 parents at the local playground.
D. Ask 100 Dads at the high school football
game.
O
OA

Answer:

(x - 3) is not a factor

Step-by-step explanation:

If (x - h) is a factor of f(x) then f(h) = 0

here

f(x) = x³ - 5x² - 4x + 6 , then

f(3) = 3³ - 5(3)² - 4(3) + 6 = 27 - 5(9) - 12 + 6 = 27 - 45 - 6 = - 24

since f(x) ≠ 0 then (x - 3) is not a factor of f(x)

So

The range is

So

Option D is correct

Answer:

the last one (bottom right)

Step-by-step explanation:

all the others have at least one x value with several associated y values.

but for a function, for all values of x there can be only one value of y.

Answer:

70 meters

Step-by-step explanation:

Based on the given conditions, formulate:: 45x5/3

Cross out the common factor: 14x5

Calculate the product or quotient: 70

The width of the parking lot in the drawing is, 70 milliliters.

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

She used the scale 5 millimeters: 3 meters.

And, The actual width of the parking lot is 42 meters.

Hence, We can formulate;

The width of the parking lot in the drawing = 42 × 5 / 3

                                                                  = 70 milliliters

Learn more about the multiplication visit:

https://brainly.com/question/10873737

#SPJ2

[tex]\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}[/tex]

[tex]\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)[/tex]

Answer:

I believe it is x=−b2a

Step-by-step explanation:

Looked it up

Answer:

35

Step-by-step explanation:

There are 3 angles in a triangle

∠1 , ∠2 , ∠3

Of which

∠1 = ∠2

∠3 = 110

By angle sum property

∠1 + ∠2 + ∠3 = 180

∠1 + ∠2 = 180-110

∠1 + ∠2 = 70

∠1 = 70 ÷ 2

=35

∠1 = ∠2 = 35

Hence , 35+35+110 = 180

Answer:

35°, 35°, 110°

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180°

let the equal angles be x , then

x + x + 110 = 180 , that is

2x + 110 = 180 ( subtract 110 from both sides )

2x = 70 ( divide both sides by 2 )

x = 35

the measure of each angle is 35° , 35° , 110°

Answer:

7:25

Step-by-step explanation:

Overall it took her 130 minutes while she was out so if you put that in time measurement it would be 7:25.

Answer:

6/12 = 0.5

Step-by-step explanation:

you add all the other tiles plus the green and then you do the green divided by that number

Solution:

Note that:

Probability that the tile will be green: Green tiles/Total tiles

The probability (In decimal) of obtaining a green tile is 0.5.

Answer:

B.

Step-by-step explanation:

-5x + 10 > -15

-5x + 10 - 10 > -15 - 10

-5x > -25

-5x / -5 > -25/(-5)

x < 5

We're given:

To find the area of the garden alone, we can subtract the area of the garden from the combined area of the garden and walkway:

[tex]4.5(8x + 4)-4(5.5x + 1.5)[/tex]

Open up the parentheses:

[tex]= 36x +18 -22x - 6[/tex]

Combine like terms:

[tex]= 36x +18 -22x - 6\\= 14x +18 - 6\\= 14x +12[/tex]

The area of the walkway around the garden is 14x + 12.

A beam of length 10m can support a weight of 62kg.

It is given that

Weight W ∝ 1/ Length L

W ∝ 1/L

W = k/L...........eq1

where k is constant of proportionality

The constant of proportionality is the ratio that relates two given values.

It is given that when L= 2m, W = 310kg

310 = k/2

k = 620

So put the k value in eq1,

eq1 becomes,

W = 620/L

when L = 10

W = 620/10

W =62kg

Therefore, a beam of length 10m can support a weight of 62kg.

To get more about the constant of proportionality visit:

https://brainly.com/question/26171814

Answer:

32°

Step-by-step explanation:

line segment= 180 - 20 (we know that) 160. divide that by 5 (cause there are 5 x's, gets you 32°

Step-by-step explanation:

[tex]m + 148 = 3m + 10[/tex]

[tex]148 - 10 = 3m - m[/tex]

therefore

3m = 138

m = 138/3

m = 46°

pls give brainliest

¶ Cσncєptѕ tσ вє uѕєd hєrє :

✦ Degree of a polynomial íѕ thє híghєѕt pσwєr σf α vαríαвlє ín thє gívєn pσlчnσmíαl.

✦ numвєr σf tєrmѕ = díѕtínguíѕhєd tєrmѕ ín α pσlчnσmíαl hαvíng díffєrєnt єхpσnєntíαl pσwєr, αnd ѕєpєrαtєd вч mαthєmαtícαl σpєrαtσrѕ ( + αnd - )

➳ nσtє :

#1. Combine the like terms before performing any operation.

#2. íf thєrє íѕ α multíplícαtíσn σr dívíѕíσn σpєrαtσr ín thє pσlчnσmíαl, wє hαvє tσ fínd thє prσduct fírѕt tσ pєrfσrm αnч σthєr σpєrαtíσn.

[tex]\sf \#1 \: \: \: \{-9 {x}^{4} - 3x \}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex]\sf \#2 \: \: \: \{-2v \}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex] \sf \#3 \: \: \: \{9 {n}^{3} - 6n + 10\}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex] \sf \#4 \: \: \: \{3 + 4 p {}^{4} + ( 4{p}^{4} - 5)\}[/tex]

[ cσmвínє thє líkє tєrmѕ ]

[tex] \sf \#4\: \: \: \{ 8p {}^{4} - 2\}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex]\sf \#5 \: \: \: \{(8v+6v³) - ( v - 3v {}^{3 }{+ 5 {v}^{2} } )\}[/tex]

[ cσmвínє thє líkє tєrmѕ ]

[tex]\sf \#5 \: \: \: \{9v³ - 5 {v }^{2} + 7v \}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex] \sf \#6 \: \: \: \{(3y + 4)(2y - 6) \}[/tex]

[ pєrfσrm thє multíplícαtíσn ]

[tex] \sf \#6 \: \: \: \{ 6 {y}^{2} - 10y - 24\}[/tex]

[tex]\rule{20cm}{1 mm}[/tex]

[tex]\qquad \qquad\huge \dag \: \normalsize \sf \boxed{ \underline{ǤríʍɌεαƿєr}} \: \huge \dag[/tex]

Answer:

5145cm²

125/343=1875/x

x=1875×343÷125=5145

Answer:

14+19=33 33 divided by 23=?

Step-by-step explanation:

triangle with the given side is a right triangle;14mm, 19mm, 23mm ... Use the Pythagorean theorem that only works for right triangles.

Answer:

10 cm

Step-by-step explanation:

Out of that [tex]160 cm^2[/tex], part of it is given by the surface of the top and bottom faces, which have area [tex]2\times 5 cm^2 = 10 cm^2[/tex] each, for a total of [tex]20 cm^2[/tex] . We are then left with [tex]140 cm^2[/tex] of surface from the side area. That area you can imagine as a rectangle of height h (which we need to know) and base [tex]5+2+5+2 cm = 14 cm[/tex] (imagine it as a box opened on a flat surface)

At this point we have [tex]140cm^2 = 14 cm \times h \rightarrow h= 10 cm[/tex]

so the investigator found the skid marks were 75 feet long hmmm what speed will that be?

[tex]s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ d=75 \end{cases}\implies s=\sqrt{30(0.7)(75)}\implies s\approx 39.69~\frac{m}{h}[/tex]

nope, the analysis shows that Charlie was going faster than 35 m/h.

now, assuming Charlie was indeed going at 35 m/h, then his skid marks would have been

[tex]s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ s=35 \end{cases}\implies 35=\sqrt{30(0.7)d} \\\\\\ 35^2=30(0.7)d\implies \cfrac{35^2}{30(0.7)}=d\implies 58~ft\approx d[/tex]

Answer:

A= Origen C= q1 B=Q2

Step-by-step explanation

your left-hand side is quadrant TWO Your top right-hand corner is Quadrant ONE and your second to the last one is left-hand side down Is Quadrant THREE last but not least is Quadrant FOUR. And the zero in the middle means ORIGEN.

Answer:

all you have to do is round to the nearest.

Step-by-step explanation:

just do it .

Answer:

40%

Step-by-step explanation:

6.75 + 1.25 = 8 (Total she just spent)

8 (Total she just spent) + 12 (Total she had left) = 20 (Total she started with)

8/20 = 0.4 = 40%

(Total spent / total she started with = 40%)

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here, We have

The given function represents the total distance in miles covered by the traveller.

For initial interval that is x = 1 , Distance covered by the traveller

[tex]\sf{ f(x) = -45x + 270 }[/tex]

[tex]\sf{ f(1) = - 45(1) + 270 }[/tex]

[tex]\sf{ f(1) = - 45 + 270 }[/tex]

[tex]\sf{ f(1) = 225 }[/tex]

For final interval that is x = 3, Distance covered by the traveller

[tex]\sf{ f(x) = - 45x + 270 }[/tex]

[tex]\sf{ f(1) = - 45(3) + 270 }[/tex]

[tex]\sf{ f(1) = - 135 + 270 }[/tex]

We have to find the average rate of change over the given time interval

Average rate of change in the given time interval

[tex]\sf{ = }{\sf{\dfrac{ f(1) + f(3) }{3 - 1}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 225 + ( -135) }{ 2}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 225 - 135 }{ 2}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 90 }{ 2}}}[/tex]

[tex]\sf{ = 45 }[/tex]

Hence, The average rate of change over the given interval is 45 miles per hour.

Answer: C - 4 = 14

Step-by-step explanation: In the expression, "c" is colin's age so, if you subtract 4 years for his age, you get Katie's age, which is 14.