A uniformly charged ring has zero electric field at its center. Radially inwards toward negative point charge and outwards from positive charge is the electric field.
Which way does the electric field point in the center of a charged circular loop?Radially inwards toward negative point charge and outwards from positive charge is the electric field.A uniformly charged ring has zero electric field at its center.Both of the electric fields that are donated to the dipole are pointing in the same general direction—that is, toward the negative charge—in the middle of the dipole.The electric field's strength can be calculated using the equation E = k | Q | r 2 by using the formula. The charge's sign—negative in this instance—determines the direction of the electric field.To learn more about electric field refer to:
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What effect does increasing the moon’s mass have on the earth?
Answer:
Explanation:
If the moon doubled in mass, that means that the Earth will not experience a total solar eclipse like today also, if it doubled in mass, tide waves would increase in size, as the moon would be bigger and would have a bigger gravitational pull
The Kingda Ka roller coaster in New Jersey is the world's tallest ride of its kind. As the passenger cars are launched from rest at the start, they are accelerated uniformly to a speed of 57 m/s (128 mph) in just 3.5 s. (Assume the cars are launched in the positive horizontal direction. Indicate the direction with the sign of your answer where appropriate.)
(a) What is the acceleration experienced by passengers on this ride in m/s2?
m/s2
What is the acceleration experienced by passengers on this ride in g's?
g
(b) If a certain passenger has a mass of 68 kg, what is the force in newtons that acts on him during the launch phase of this ride?
N
What is the force in pounds that acts on him during the launch phase of this ride?
lb
a) The acceleration is 16.3 m/s^2
b) The acceleration is 1.66 g
c) The force that acts is 666.4 N
d) The force in pounds is 149.8 pounds
What is the acceleration?We have to note that when we talk about the acceleration, we mean the change in the velocity of the object with respect to the time that is taken. In the case of the problem that we have here, we are told that the passenger cars are launched from rest at the start, they are accelerated uniformly to a speed of 57 m/s (128 mph) in just 3.5 s.
Note that;
v = u + at
v = final velocity]
u = initial velocity
t = time taken
a = acceleration
Then;
a = v - u/t
a = 57 - 0/3.5
a = 16.3 m/s^2
The acceleration in g's is 16.3 m/s^2/9.8 m/s^2 = 1.66 g
The force that acts on the passenger is; 68 Kg * 9.8 m/s^2 = 666.4 N
The weight in pounds of the passenger is 149.8 Pounds
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a bullet is accelerated down the barrel of a gun. the average force exerted on a 0.020 kg bullet to accelerate it to a speed of 500.0 m/s in a time of 2.00 ms (milliseconds) is
The average force is then F = ma is 5,000 kg m/s2 = 5,000 N.
What is average force?Average force is the mean force of a set of forces. It is used to measure the average magnitude of a force over a period of time or over multiple forces. It is calculated by dividing the sum of all forces by the number of forces.
The average force exerted on the bullet is calculated using Newton's second law, F = ma. The acceleration of the bullet can be calculated by dividing the change in velocity (500.0 m/s) by the time interval (2.00 ms).
a = Δv/Δt
a = 500.0 m/s / 2.00 ms = 250,000 m/s2
The average force is then F = ma = (0.020 kg)(250,000 m/s2) = 5,000 kg m/s2 = 5,000 N.
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which of the following forces is an example of a contact force
a) gravitational force
b) magnetic force
c) electric force
d) frictional force
Answer:
d) frictional force
Explanation:
What Is a Contact Force?
Contact force is the phrase used to describe a push/pull interaction that occurs when an object comes into contact with another object.
The only force where there is contact between two bodies in the answer choices is frictional force
Answer
d) frictional force
Some crosswalks timers are set in consideration that persons older than 65 walk at an average pace of 2.9 ft/sec. Describe how you determined your pace, or average walking speed, in feet per second, by a method of your choice. How does your pace compare to the average pace of persons older than 65?
You can determine the average walking speed by registering the distance covered by different people in the same group. My pace is higher than people older than 65.
How to determine the walking pace?You can determine your average walking pace by recording information about the distance you cover in feet and the second it takes you to cover that distance. Here is an example:
450 feet / 100 seconds = 4.5 feet per second
How does my pace compare to the average of persons older than 65?My pace is faster than the walking pace of someone who is 65.
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In video 1 for Chapter 17, how does the fringe spacing change when the distance between the slits, d, is increased?
The fringes get farther apart.
The fringe spacing stays the same.
The fringes get closer together.
It depends on how wide the slits are.
As the gap between the slits, d, is widened, the fringe spacing changes, becoming more pronounced.
How would you define distance in plain English?Distance is an object's overall motion in a directionless fashion. Depending of the starting or terminating point, distance can be referred to as the amount of territory an element has travelled.
The purpose of distance calculationWe can find out an object's actual size by knowing how far away it is. The area an object occupies in space above us can be measured. Once we know how far away it is, we can calculate its true size. An thing appears smaller the further away it is.
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An object's speed is 3.6 m/s with a momentum of 180 kgm/s. What is the mass of the object?
Answer:
To solve the problem we must know the concept of momentum.
What is Momentum?
Momentum is defined as the product of the mass of an object and the velocity of an object. It is a vector quantity.
$$\rm{Momentum = velocity \times Mass$$
The mass of the object is 50 kg.
Given to us
velocity of the object = 3.60 m/s
momentum of the object = 180 kg m/s
Mass of the object
We know that momentum is the product of the mass of the object and the velocity of the object,
$$\rm{Momentum = velocity \times Mass$$
Substitute the values,
180 = 3.60 \times \rm Mass180=3.60×Mass
\rm Mass = \dfrac{180\ kg\ m/s}{3.6\ m/s}Mass=
3.6 m/s
180 kg m/s
\rm Mass = 50\ kgMass=50 kg
Hence, the mass of the object is 50 kg.
an object's elevation is a perspective cue to . group of answer choices distance shape shadowing size
A monocular cue called linear perspective helps us understand the depth and distance of an object.
Any depth indication that may be interpreted solely by one eye is referred to as a monocular cue. In contrast, binocular cues call for the use of both eyes in order to perceive depth and distance.
Things that are nearby seem to move more quickly than objects that are farther away thanks to a depth perception cue called motion parallax. It is a form of monocular cue, or a cue for depth perception, that may be seen with just one eye.
Perception time is the amount of time it takes to become aware of a situation and realize that stopping is necessary. About three-quarters of a second may pass during this. Less experienced drivers frequently take longer to recognize a threat. The distance a car goes during this time is called perception distance.
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An object is thrown straight up. Which of the following is true about
the sign of work
done by the gravitational force while the object moves up and then
down?
A.Work is positive on the way up, work is positive on the way down
B. Work is negative on the way up, work is negative on the way down
C.Work is negative on the way up, work is positive on the way down
D.Work is positive on the way up, work is negative on the way down E.
Work is zero the way up, work is zero on tâ
The correct option is C. Sign of Work is negative on way up and negative on way down due to gravitational force.
The definition of work is the energy that is either added to or subtracted from something by applying force along a displacement. For a constant force acting in the same direction as the motion, the work is simply equal to the product of the force's magnitude and the distance travelled.
A thrown object's acceleration due to gravity will cause negatively deaccelerate when we throw it vertically upwards.
We represented deacceleration by a (-) sign.
Thus, we may conclude that any work completed when an object is thrown upwards is negative since it defies gravity.
Now, g is accelerating force as it movies in direction of gravity when object comes downwards to earth. Work done when object moves down is positive.
Consequently, the best option will be option (C)
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Landon and Jocelyn are partners in pair figure skating. Last weekend, they perfected the death spiral element for inclusion in their upcoming competition. During this maneuver, Landon holds Jocelyn by the hand and swings her in a circle while she maintains her blades on the ice, stretched out in a nearly horizontal orientation. Determine the net force that must be applied to Jocelyn (m = 47.3 kg) if her center of mass rotates in a circle with a radius of 0.915 m once every 1.13 seconds.
The net force that must be applied to Jocelyn is 139 Newton.
How to calculate the net force?The net force acting on Jocelyn during the death spiral can be determined using the equation:
F = m * a
where F is the net force, m is her mass (47.3 kg), and a is her centripetal acceleration.
To find the centripetal acceleration, we can use the equation:
a = v^2 / r
where v is her velocity and r is the radius of rotation.
We know that Jocelyn completes one rotation every 1.13 seconds, so we can calculate her velocity:
v = 2 * pi * r / T
where T is the time for one rotation
Plugging in the known values:
v = 2 * pi * 0.915 m / 1.13 s
v = 5.09
Now we can substitute the value of v into the centripetal acceleration equation:
a = v^2 / r
a = 5.09² / 0.915
a = 28.3
F = ma
F = 47.3 × 28.3
F = 1339 Newton
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002 (part 2 of 3) 10.0 points what is the magnitude of the potential difference vy x across the terminals y and x of the battery? answer in units of v. answer in units of v. 003 (part 3 of 3) 10.0 points what power is dissipated by the internal resistance of the battery? answer in units of w. answer in units of w.
The power dissipated by the battery is 100V2/R.
What is power dissipated?Power dissipated is the rate at which energy is converted from one form to another. It refers to the amount of energy that is lost due to heat or vibration when electricity flows through a component or system. Power dissipation is an important concept in electrical engineering since it affects the efficiency, reliability and temperature of a system.
The power dissipated by the internal resistance of the battery can be calculated using the formula P=IV,
where I is the current and V is the potential difference across the terminals. Since we know that V = 10V,
we can calculate I by dividing V by the internal resistance (R) of the battery: I = 10V/R.
The power dissipated by the battery is then given by P = IV = (10V/R)*(10V) = 100V2/R.
Thus,
In units of watts, the power dissipated by the battery is 100V2/R.
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after being kicked, a soccer ball flies upward into the air, slowing down as it reaches its maximum height.T/F
False. As the soccer ball reaches its maximum height, it begins to slow down and then fall back to the ground due to the force of gravity.
What is gravity?Gravity is a natural force of attraction that exists between any two objects with mass. It is the weakest of the four fundamental forces of nature and acts over a very short distance. It is responsible for keeping the planets in orbit around the sun and for keeping objects on the earth's surface. Gravity also affects the motion of objects in the air, causing them to accelerate downward toward the ground. In addition, gravity affects the tides and other oceanic phenomena. On a smaller scale, gravity affects the movement of particles such as electrons and protons.
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Tension force has units of ________. Check all that apply.
Answer:
Newton (N)
Explanation:
A space probe is launched from Earth headed for deep space. At a distance of 10,000 miles from Earth's center, the gravitational force on it is 264 lb. What is the size of the force when it is at each of the following distances from Earth's center?
(a) 20,000 miles
lb
(b) 30,000 miles
lb
(c) 100,000 miles
lb
The size of the force when it is at 20,000 miles distances from Earth's center is 66 lb.
The size of the force when it is at 30,000 miles distances from Earth's center is 29.33 lb.
The size of the force when it is at 100,000 miles distances from Earth's center is 2.64 lb.
What is gravitational force?
The force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.
(a) the size of the force when it is at 20,000 miles distances from Earth's center = (264)/(2²) lb = 66 lb.
(b) the size of the force when it is at 20,000 miles distances from Earth's center = (264)/(3²) lb = 29.33 lb.
(c) the size of the force when it is at 100,000 miles distances from Earth's center = (264)/(10²) lb = 2.64 lb.
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the fraction of ice which is submerged in water only depends on the density of the ice and the water. for this problem, assume the density of ice is 928.5 kg/m3.
0.917 fraction of ice which is submerged in water only depends on the density of the ice and the water.
What is density?The density of a material is its mass per unit volume. The most common sign for density is, however the Latin letter D can also be used. The density of a substance is the measure of how densely it is packed together. It is expressed as mass per unit volume. Symbol for density: D or Formula for Density: = m/V, where is the density, m is the object's mass, and V is the object's volume. The density of something describes how compact or dense it is. Let's say you have two boxes, one huge and one tiny. They both, however, weigh the same. That means the small box has a higher density than the large box. Density also tells how concentrated or crowded something is.
Here,
The density of the ice and the water have no effect on the 0.917 proportion of ice that is submerged in water.
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An object attached to a spring vibrates with simple harmonic motion as described by the figure below.
For this motion, find the following.
(a) the amplitude
(b) the period
(c) the angular frequency
(d) the maximum speed
(e) the maximum acceleration
(f) an equation for its position x in terms of a sine function (Do this on paper. Your instructor may ask you to turn in this work.)
The graph provided is a displacement-time graph. The object's displacement is shown on the x-axis, while its travel time is shown on the y-axis.
The largest displacement that an object may make is known as its amplitude. The maximum displacement made by the object is 2 cm.
As a result, the object has an amplitude of 2 cm according to the definition of amplitude.
The amplitude of the object depends on the displacement made by the object. The maximum displacement is made when the object moves to an extreme position in an oscillation.
An object moves from a mean position to an extreme position in a straightforward harmonic motion. One oscillation or cycle is said to be complete when the object travels from the mean position to the extreme position and returns to the mean position.
The displacements are shown on the graph as positive when it moves to the extreme position and negative when it moves back from the extreme position.
According to the presented graph, it takes 4 seconds to complete one oscillation or cycle.
As a result, the time period is 4 seconds according to the definition of time period. Therefore, the time period as ω = 2π/T.
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some psychologists believe that eating disorders representative fence against unconscious conflicts related to sexual development. These psychologists have adopted a _____ approach to eating disorders.
Some psychologists believe that eating disorders represent a defense against unconscious conflicts related to sexual development. These psychologists have adopted a Psychoanalytic approach to eating disorders.
What is a Psychoanalytic approach?A psychoanalytic approach is based on the idea that our unconscious thoughts, feelings, and motivations can have a powerful influence on our behavior by focusing on helping individuals to gain insight into their unconscious processes, recognize and resolve conflicts, and modify their behavior.
Therefore, with this data, we can see that a Psychoanalytic approach is based on unconscious mental processes to develop a cure.
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problem 1-45: the column is made of concrete having a density of 2.30 mg/m3 . at its top b it is subjected to an axial compressive force of 15 kn. determine the average normal stress in the column as a function of the distance z measured from its base.
The average normal stress in the column as a function of the distance z from its base is (237.68 - 21.43z) kPa or (237,684.54 - 21,431.12z) Pa.
The full question is in the attachment. There is a weight force that works in the concrete column. The formula w = mg
m = mass of the column (kg) g = the acceleration due to gravity (9.8 m/s²) w = the weight (N)The mass of the column is unknown but the density is known. The formula for density ρ = m ÷ V
m = ρV
ρ = the density = 2.30 Mg/m³ = 2,300 kg/m³ V = the volume of the column The volume of the tubular columnThe weight force
w = mg = ρVg = ρg × πr²h
w = 2,300 × 9.8 × 3.14 × 0.18² × (4 - z)
w = 2,293.13 (4 - z)
w = (9,172.52 - 2,293.13z) N
The column is in equilibrium then Newton's first law applies
The axially compressive force = F₁ = 15 kN = 15,000 N∑F = 0
N - F₁ - w = 0
N = F₁ + w
N = 15,000 + (9,172.52 - 2,293.13z)
N = (24,172.52 - 2,293.13z) Newton
The average normal stress can be calculated by the formula
σ = F/A
σ = the stress (Pascal) F = the force (N) A = the area of the baseσ = N ÷ A
σ = (24,172.52 - 2,293.13z) ÷ 0.1017
σ = (237,684.54 - 21,431.12z) Pascal
σ = (237.68 - 21.43z) kPa
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A 4.0 kg mass is released from rest at the top of a frictionless ramp 2.0 m above ground. It slides down the ramp to a level, horizontal portion of frictionless track and then collides with a stationary 8.0 kg mass. Immediately after the collision, the larger mass has a velocity v_l = +3.5 m/s (i.e., heading to the right)
The velocity of the smaller mass just after the collision is B) +0.7 m/s.
To calculate the velocity of the smaller mass after the collision:
Use the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision: (m1 * v1) + (m2 * v2) = (m1 * v1') + (m2 * v2')
Substitute in the known values: (4.0 kg * 0 m/s) + (8.0 kg * 0 m/s) = (4.0 kg * v4) + (8.0 kg * (vg + 3.5 m/s))
Solve for the velocity of the smaller mass (v4): v4 = (8.0 kg * (vg + 3.5 m/s)) / 4.0 kg
Substitute in the value for the velocity of the larger mass (vg) which is not given in the question: v4 = (8.0 kg * (0 m/s + 3.5 m/s)) / 4.0 kg
Solve for the velocity of the smaller mass (v4): v4 = (8.0 kg * 3.5 m/s) / 4.0 kg
Simplify the calculation: v4 = 2.8 m/s / 4.0 kg
Divide the final value by the mass of the smaller object: v4 = 0.7 m/s
So the velocity of the smaller mass just after the collision is 0.7 m/s.
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Which of the following describes a benefit of the fact that oll never wears out?
Because oll never wears out, it can be used again and again.
Because oll never wears out, farmers will never run out of it.
Because oll never wears out, it never needs to be replaced.
O Because oll never wears out, its cost remains low.
The option that best describes the benefit of the fact that oll never wears out is that oll never wears out, it can be used again and again.
The correct option is A.
What is the benefit of durability in materials?Durability is the ability of material to last in usage for a long time.
Duravle materials provides benefits to the owners in that it:
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scallops use muscles to close their shells. opening the shell is another story--muscles can only pull, they can't push. instead of muscles, the shell is opened by a spring, a pad of a very elastic biological material called abductin. when the shell closes, the pad compresses; a restoring force then pushes the shell back open. the energy to open the shell comes from the elastic energy that was stored when the shell was closed. (figure 1) shows smoothed data for the restoring force of an abductin pad versus the compression. when the shell closes, the pad compresses by 0.15 mm. How much elastic potential energy is stored?
10J elastic potential energy is stored.
The mechanical potential energy stored in the configuration of a material or a physical system during elastic deformation as a result of work applied to it is known as elastic energy. When objects are momentarily compressed, stretched, or otherwise distorted, elastic energy is produced. Solid body and material mechanics formalisms are essentially produced via elasticity theory. Calculations of mechanical equilibrium positions using the elastic potential energy equation. The energy is potential because when the object is permitted to return to its original shape (reformation) by its elasticity, it will change into other forms of energy, such as kinetic energy and sound energy.
compression = expansion
force=2.5N
K= [tex]\frac{F}{x}[/tex]=[tex]\frac{2.5N}{0.2\times10^{-3} }=1.25\times10^4 N/m[/tex]
compression=0.15mm
Energy= [tex]\frac{1}{2}Kx^{2}[/tex]
Energy= [tex]\frac{1}{2}1.25\times 10^{-4}( 2.25\times10^{-10})J[/tex]
Energy=[tex]1.40625\times 10^{-4}\\[/tex]joules
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The speed of a pendulum is greatest (a) when the pendu- kinetic energy is a minimumb) when the pendu lum's acceleration is a maximum, (c) when the pendulum's potential energy is a minimumof the preceding
Answer:
Explanation:
b. when the pendulum's acceleration is a maximum.
The speed of a pendulum is greatest when the acceleration of the pendulum is at a maximum. This occurs when the pendulum is at the bottom of its swing, where the force of gravity is causing the greatest acceleration. At this point, the pendulum's kinetic energy is at a maximum and potential energy is at a minimum.
kicked the ball in the air with an initial velocity of 12m/s at an angle of 40° above the horizontal. If the ball travels a horizontal distance of 15m , how long will it fly in the air?
The soccer ball rose 5.24 meters in the air.
VO =?, max H =?, range = 25m, angle A = 40°
Projectile motion is being used in this situation. Range = vo2 * sin 2A / g is the formula for range. calculating the initial velocity vo's square and its original value.
Range is equal to vo2*sin2A/g.
VO2 * SIN (2 * 40°) / 9.8 m/s = 25 m
vo2 = sin 80° / 9.8 m/s / 25 m
2 vo = 15.77 m/s and 2 vo = 248.8 (m/s) respectively.
The ball's starting speed is 15.77 m/s.
The height of the object, max H, can be calculated as follows: max H = vo * (sin A) * 2g max H = 248.8 (m/s) * (sin 40°) * 19.6 m/s * 2g max H = 5.24 meters
The soccer ball rose 5.24 meters in the air.
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Each choice below describes how a few astronomical phenomena are related to time periods. Which list is entirely correct? (Careful: some lists are partially correct.) A) Earth's rotation defines a day.The cycle of the Moon's phases takes about a month.Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years. B) Earth's rotation defines a day.The cycle of the Moon's phases takes about a week.Earth's orbit defines a year.Earth's cycle of axis precession defines a month. C) Earth's rotation defines a day.The Sun's rotation defines a week.The Moon's rotation defines a month.Earth's orbit defines a year.D) Earth's rotation defines a day.The saros cycle of eclipses defines a month.Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years.
The correct list is D) Earth's rotation defines a day. The saros cycle of eclipses defines a month.
What is Earth's rotation?Earth's rotation is the rotation of the planet around its own axis. This axis is an imaginary line that passes through the North and South Poles. Earth rotates from west to east, which is why the Sun appears to rise in the east and set in the west. The length of a day is determined by the time it takes for Earth to make one full rotation around its axis.
Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years. This is because the Earth's rotation defines a day, the saros cycle of eclipses defines a month, the Earth's orbit defines a year, and the Earth's cycle of axis precession takes 26,000 years.
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A 21 g ball of clay traveling east at 3.2 m/s collides with a 32 g ball of clay traveling north at 2.1 m/s. What are the speed and the direction of the resulting 53 g ball of clay?
The resulting ball of clay after the collision is moving with a speed of 2.53 m/s in a direction between east and north.
To determine the speed and direction of the resulting 53 g ball of clay after the collision, we need to use the conservation of momentum principle.
Let us call the initial momentum of the first clay ball (21 g) "p1", and the initial momentum of the second clay ball (32 g) "p2". The final momentum of the resulting clay ball (53 g) will be "p3".
The initial momentum of the first clay ball can be calculated as p1 = m1 * v1 = 21 g * 3.2 m/s = 67.2 gm/s (going east)
The initial momentum of the second clay ball can be calculated as
p2 = m2 * v2 = 32 g * 2.1 m/s = 67.2 gm/s (going north)
So, the total initial momentum is p1 + p2 = 67.2 gm/s + 67.2 gm/s = 134.4 g*m/s
After the collision, the total momentum of the resulting clay ball is 134.4 gm/s, and its mass is 53 g. So, we can use the following equation to find its final velocity: p3 = m3 * v3 = 134.4 gm/s = 53 g * v3
So, the final velocity of the resulting clay ball is v3 = 134.4 g*m/s / 53 g = 2.53 m/s.
To find the direction of the resulting clay ball, we can use the vector addition of the initial velocities of both clay balls. The direction of the final velocity vector would be the angle formed between the sum of the vectors and the x-axis.
So, the final velocity vector of resulting clay ball is a vector sum of the initial velocities of both clay balls, and its direction would be somewhere between the east and north direction.
Therefore, the resulting ball of clay after the collision is moving with a speed of 2.53 m/s in a direction between east and north.
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which of the following word is the correct option for below question: component, points, parts. when solving conservation of motion problems in two dimensions it is important to break te velocity of each objet into x and y
When solving conservation of motion problems in two dimensions, it is important to break the velocity of each object into x and y component.
What is velocity?Velocity is a vector representation of an object's or particle's displacement with respect to time. The meter per second (m/s) is the standard unit of velocity magnitude (also known as speed). Alternatively, velocity magnitude can be expressed in centimeters per second (cm/s). The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change. Simply put, velocity is the rate at which something travels in a certain direction. For example, the speed of a car driving north on a highway or the speed of a rocket after launch.
Here,
When addressing conservation of motion issues in two dimensions, it is necessary to divide each object's velocity into x and y components.
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Calculate the increase in length of a 40 cm brass rod that is heated from 30 ° C to 50 ° C ( linear expansion of Brass is 1.9 x 10³8¹¹ )
a. 0.015 cm b.0.051 cm c.1.9 cm d. 15.20 cm
The solution for the increase in length of a 40 cm brass rod that is heated from 30 ° C to 50 ° C ( linear expansion of Brass is 1.9 x 10³8¹¹ ) is
0.051 cm. In this case Option B is correct.
Linear Expansion Theory: What Is It?
The linear expansion theory, which is used in this question, states that when an object is heated or cooled, its expansion or contraction will be proportional to its original length and the temperature change.
First, determine Brass' linear expansion (1.9 x 108 11).
Step 2: Determine how long the 40 cm brass rod will grow. Increase in length equals (Brass linear expansion) times (Temperature change) times (Rod length).
(1.9 x 108 11) x (20°C) x (40 cm) length increase
Step 3: Determine the lengthening.
lengthening equals 0.051 cm
Response: 0.051 cm
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A bottle with a volume of 195 U. S. fluid gallons is filled at the rate of 1.7 g/min. (Water has a density of 1000 kg/m3, and 1 U.S. fluid gallon = 231 in.3.) How long does the filling take?
The time that have been taken by the liquid is 4.4 * 10^5 min.
How long does it take to be filled?The question that we have been asked here is about the rate of the filling of the bottle. We can see that we have been given the volume of the bottle clearly.
We know that the volume of the solution that we have is 195 U. S. fluid gallons or 0.74 m^3. Then we have that;
Density = mass/volume
mass = Density * volume
= 0.74 m^3 * 1000 Kg/m^3
= 740 Kg or 740000 g
Rate = mass/time
Time = mass/rate
Time = 740000 g/1.7 g/min.
= 4.4 * 10^5 min
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assuming that each cubic centimeter of water has a mass of exactly 1 g, find the mass of 1.87 cubic meter of water.
Assuming that each cubic centimeter of water has mass of exactly 1 g , then mass of 1.87 cubic meter of water is 1.87 kg.
What is mass?We define mass as measure of the amount of matter in a body. And SI unit of mass is Kilogram (kg) and the mass of a body does not change at any time.
As we know, mass = volume x density
where volume is given in cubic meter and density is given in g/cm^3
As water has a density of 1 g/cm^3 at 4 degree Celsius, this means that 1 cm^3 of water has a mass of 1 g.
So, mass = 1.87 m^3 x 1 g/cm^3 = 1.87 kg
Therefore, the mass of 1.87 cubic meter of water is 1.87 kg.
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find the time-domain voltage over the capacitor using phasor domain techniques. the voltage and current source are both ac (cos) sources with frequency of 1mhz and with the amplitudes of 12 v and 20ma, respectively. assume that, r1
To find the time-domain voltage over the capacitor using phasor domain techniques, we need to first convert the circuit to the phasor domain by replacing the time-varying voltage and current sources with their phasor equivalents. The phasor equivalents of the voltage and current sources are:
V_s = 12 V * e^(j2pift)
I_s = 20mA * e^(j2pift)
where f is the frequency of the sources (1 MHz) and t is time.
The phasor voltage across the capacitor can be found using the following equation:
V_C = V_s - I_s * (R_1 + R_2 + j2pifL) - I_s * (1/(j2pifC))
Substituting in the values for the resistance and reactance of the circuit, we get:
V_C = 12 V * e^(j2pift) - 20mA * e^(j2pift) * (1000 Ohm + 2000 Ohm + j2pi10^620e-6 H) - 20mA * e^(j2pift) * (1/(j2pi10^6200e-12 F))
Simplifying, we get:
V_C = 12 V * e^(j2pift) - 20mA * e^(j2pift) * (3000 Ohm + j40pi) - 20mA * e^(j2pift) * (5e5 Ohm)
So, the phasor voltage across the capacitor is V_C = 12 V * e^(j2pift) - 0.02 A * e^(j2pift) * (3000 Ohm + j40pi) - 0.02 A * e^(j2pift) * (5e5 Ohm)
Finally, to find the time-domain voltage over the capacitor, we need to take the inverse Fourier transform of the phasor voltage. This can be done using the following equation:
v_c(t) = real (V_C * e^(-j2pift))
Substituting in the value for V_C, we get:
v_c(t) = real (12 V * e^(j2pift) - 0.02 A * e^(j2pift) * (3000 Ohm + j40pi) - 0.02 A * e^(j2pift) * (5e5 Ohm)
Complete question:
Find the time-domain voltage over the capacitor using phasor domain techniques. The voltage and current source are both AC (sine) sources with frequency of 1MHz and with the amplitudes of 12 V and 20mA, respectively. Assume that, R_1 = 1 k Ohm, R_2 = 2k Ohm, C = 200pF, and L = 20mu H.
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