Answer:
See Explanation
Explanation:
[tex]8 {x}^{2} + {y}^{2} = 10 \\ \\ {y}^{2} = 10 - 8 {x}^{2} \\ \\ differentiating \: w \: r \: t \: x \: on \: both \: sides \\ \\ 2y \frac{dy}{dx} = \frac{d}{dx} (10 - 8 {x}^{2} ) \\ \\ 2y \frac{dy}{dx} = 0 - 8 \times 2 {x} \\ \\ 2y \frac{dy}{dx} = - 16{x} \\ \\ \frac{dy}{dx} = \frac{ - 16x}{2y} \\ \\ \frac{dy}{dx} = - \frac{8x}{y} [/tex]