Answer:
7mm : 3000 mm ; 1 : 428 4/7
Step-by-step explanation:
Given that :
Given a drawing produced using a scale :
7 millimeters = 3 meters ; the scale factor for the drawing
Comparing units in millimeter and units on meter
1000 mm = 1 meter
Hence,
3000 mm = 3 meter
Then, we can say;
7 millimeters = 3000 millimeters
7mm : 3000 mm
Divide through by 7
1 : 428 4/7
-18+-6 please help
Answer:
-24
Step-by-step explanation:
If you are struggling with this here's a tip!
-18+-6 is what you are trying to solve
The 6 is negative, so get rid of the plus sign -18-6
2 negative numbers are just added like positive numbers
So add 18 and 6, you should get 24
Don't forget about the negative!
-24
An oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day. For each additional well that is drilled, the average production per well decreases by 25 barrels per day.
Required:
How many additional wells should be drilled to obtain the maximum amount of oil per day?
Answer:
The additional wells for maximum amount of oil per day is 3 wells.
Step-by-step explanation:
Given;
initial number of wells, n = 6
total production, T = 1800
average production per well, = 1800/6 = 300 barrels per day
Let the additional well = y
total number of wells after optimization = 6 + y
new production per well = 300 - 25y
new total production = (6+y)(300-25y)
t = 1800 - 150y + 300y - 25y²
t = 1800 + 150y - 25y²
dt / dy = 150 -50y
for maximum value, dt/dy = 0
150 - 50y = 0
50y = 150
y = 150 / 50
y = 3
Therefore, the additional wells for maximum amount of oil per day is 3 wells.
33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.
Given that an oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day, and for each additional well that is drilled, the average production per well decreases by 25 barrels per day, to determine how many additional wells should be drilled to to obtain the maximum amount of oil per day, the following calculation must be performed:
1800 x 6 = 10800 1200 x 30 = 36000 1000 x 38 = 38000 950 x 40 = 38000 900 x 42 = 37800 975 x 39 = 38025
Therefore, 33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.
Learn more in https://brainly.com/question/13581736
The normal distribution An automobile battery manufacturer offers a 31/54 warranty on its batteries. The first number in the warranty code is the free-replacement period; the second number is the prorated-credit period. Under this warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charge to the consumer. If the battery fails after 31 months but within 54 months, the manufacturer provides a prorated credit toward the purchase of a new battery. The manufacturer assumes that x, the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months. Use the following Distributions tool to help you answer the questions that follow. (Hint: When you adjust the parameters of a distribution, you must reposition the vertical line (or lines) for the correct areas to be displayed.)
1. If the manufacturer's assumptions are correct, it would reed to replace _______ of its batteries free.
2. The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect. A standard deviation of ____ results in a 1.07% replacement rate.
3. Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?
Answer:
1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.
2) a standard deviation of 6.0843 results in a 1.07% replacement rate
3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit
Step-by-step explanation:
based on the given data;
x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months
so
x → N( U = 45, ∝ = 5.6)
Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.
if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery
1) If the manufacturer's assumptions are correct,
p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )
= p( z < -2.5 )
using the standard normal table,
value of z = 0.0062 ≈ 0.62%
so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.
2)
The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%
so lets say;
p ( x < 31 ) = ( 1.07%) = 0.0107
p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107
now from the standard table
-2.301 is 1.07%
so
( 31 - 45 / ∝ ) = -2.301
-14 / ∝ = -2.301
∝ = -14 / - 2.301
∝ = 6.0843
therefore a standard deviation of 6.0843 results in a 1.07% replacement rate
3)
Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?
p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝] < [ 54 - 45 / ∝] )
= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝] < [ 54 - 45 / 6.0843] )
= p ( -2.301 < z < 1.4792 )
= p(Z < 1.5) - p(Z < -2.3)
= 0.9393 - 0.0108
= 0.919 ≈ 91.9%
therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit
y/15- 2/3= 4/5
Whats the answer for y
LUCILLE'S PENCIL POUCH WOULD HOLD 3/8
OF THE 48 PENCILS THAT SHE PURCHASED AT
THE BEGINNING OF THE NEW SCHOOL YEAR. How many pencils will fit in her pouch
HOW MANY PENCILS WILL FIT IN HER POUCH?
Answer:
The pouch would be able to hold 12.8 pencils :)
Step-by-step explanation:
because 3/8 is 37.5 and if you do that divided by 48 and add a decimal infront of the eight you will get your answer
Evaluate 12x−3y when x=−14 and y=3.
Answer:
-177
Step-by-step explanation:
12(-14) -3(3)
-168-9
-177
Answer:
-177
Step-by-step explanation:
Plug in -14 for x and 3 for y:
12(-14) - 3(3)
Note that when you multiply a positive and a negative number, your answer will be negative.
Multiply:
12 * -14 = -168
-3 * 3 = -9
Combine the terms:
-168 + (-9) = -168 - 9 = -177
-177 is your answer.
~
A nursery owner buys 8 panes of glass to fix some damage to his greenhouse. The 8 panes cost
$19.60. Unfortunately, he breaks 3 more panes while repairing the damage. What is the cost of
another 3 panes of glass?
Another 3 panes of glass cost $
Answer:
$8.85
Step-by-step explanation:
Step-by-step explanation: well if you take 23.60 and divide it by 8 you would get 2.95 times that by three and you would get 8.85 and there's your answer.
Answer:
7.35
because my kid got the question wrong
Find the slope of the line
graphed below.
Answer:
[tex]\frac{3}{5}[/tex] or 0.6
Step-by-step explanation:
This problem requires the slop formula which is [tex]\frac{y2-y1}{x2-x1}[/tex]
You start with the first point which is (-1,1). This will be x1 and y1.
The next point is (4,4). This will be x2 and y2.
You plug these values into your equation which gives you [tex]\frac{4-1}{4-(-1)}[/tex]
To solve, you evaluate, [tex]\frac{4-1}{4-(-1)}[/tex] = [tex]\frac{3}{5}[/tex] or 0.6
M/x =n-p, x for p ??
Answer:
the answer is A) X=m/n-p
Step-by-step explanation:
m/x=n-p
n-p=m/X
(n-p)×x=m
X=m/n-p
Multiply: -12y(y - 6) Enter the correct answer.
Find the exponential function that satisfies the given conditions: initial value = 70, decreasing at a rate of 0.43% per week
Answer choices:
A) f(t) = 70 x 0.9957^t
B) f(t) = 70 x 1.43^t
C) f(t) = 0.43 x 0.3^t
D) f(t) = 70 x 1.0043^t
Answer:
a- just took the test
Step-by-step explanation:
a. Suppose a BMW dealer in Fullerton, CA is trying to calculate the probability of his car sale for next week. The dealer knows that the sale of car is normally distributed with mean 50 and variance 9. The variance 9 was calculated from the weekly car sale data of 20 weeks, as the population variance is not known to the dealer. What is the probability that the dealer will sell 51 or more cars next week? (Hint: use t distribution) (15)
Answer:
0.45576
Step-by-step explanation:
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Standard Deviation = √variance
Mean = 50
= √9
= 3
z = 51 - 50/3
= 0.11111
Probability value from Z-Table:
P(x<51) = 0.54424
P(x>51) = 1 - P(x<51)
= 1 - 0.54424
= 0.45576
The probability that the dealer will sell 51 or more cars is 0.45576
which numerical pattern in nonlinear?
A. 3, 11, 19, 27,
B. 1, 3, 9, 27
C. 1, 4, 7, 10,
D. 2, 3, 4, 5
Answer:
I am going with B.1,3,9,27
Step-by-step explanation:
A,C and D the patterns are from addition ie. A +8, C+3 and D +1 but B it's ×3
find the number of terms in the arithmetic sequence
-7,-5.6,-4.2,-2.8,1.4,...,103.6
Answer:
80
Step-by-step explanation:
use the formula of arithmetic progression
There are 100 students at a school and three dormitories A, B, and C with capacities of 25, 35, and 40, respectively.
Required:
a. How many ways are there to fill up the dormitories?
b. Suppose that, of the 100 students, 50 are men and 50 arewomen and that A is an all-men's dorm, B is an all-women's dorm andC is co-ed. How many ways are there to fill thedormitories?
Answer:
a
[tex]N = 7.0 *10^{44} \ Ways [/tex]
b
[tex]U = 2.85 *10^{26}\ ways [/tex]
Step-by-step explanation:
From the question we are told that
The number of students are n = 100
The number of dormitories is k = 3
The capacity of the first dormitory is A = 25
The capacity of the second dormitory is B = 35
The capacity of the third dormitory is c = 40
Generally the number of way to fill the dormitory up is mathematically represented as
[tex]N = \frac{n!}{A! B!C!}[/tex]
=> [tex]N = \frac{100!}{25! 35! 40!}[/tex]
Here ! stands for factorial, so we will be making use of the factorial functionality in our calculators to evaluated the above equation
=> [tex]N = \frac{100!}{25! 35! 40!}[/tex]
[tex]N = \frac{9.332622* 10^{157}}{[1.551121* 10^{25}]* [1.0333148* 10^{40}] * [8.1591528*10^{47}]}[/tex]
[tex]N = 7.0 *10^{44} \ Ways [/tex]
From the question we are told that there are 50 men and 50 women and
A is all-men's dorm and B is all-women's dorm while C is co-ed
So
When A is filled , the number of men that will be remaining to fill dorm C is 50-25 = 25
While when B is filled the number of women that will be remaining to fill dorm C is 50-35 = 15
Generally the number of ways there to fill the dormitories is equivalent to the number of ways of selecting the 25 men and 35 women to fill dormitory A and B plus one more way which is filling dorm C with the remaining students this is mathematically represented as
[tex]U = ^{50}C_{35} * ^{50}C_{25} + 1[/tex]
Here C stands for combination hence we will be making use of the combination functionality in our calculators
[tex]U = 2.250829575* ^{12} * 1.264106064 * 10^{14} + 1[/tex]
=> [tex]U = 2.85 *10^{26}\ ways [/tex]
A worker at one farm is paid $486 for the week, plus $0.03 for every pound
of apples she picks. At another farm, a worker is paid $490 for the week, plus
$0.02 for every pound of apples. For how many pounds of apples are the workers
paid the same amount?
Answer:sorry this probably is t the most helpful but the closest i could get was 399 lbs. it’s is st$497.7 for one and $$497.8.
Step-by-step explanation:
Describe the relationship between the point B (16, 24) and the point
B' (8, 12) in terms of dilations.
(x, y) → ()
Answer:
(x/2,(y/2)
Step-by-step explanation:
(16/2,24/2)
(8,12)
State whether the given pair of sets are equal, equivalent, both, or neither. {0,9}; {8, 1)
Answer:
Equivalent
Step-by-step explanation:
A set is a well defined collection of objects.
Two sets are said to be equal if they have the same elements.
Two sets are said to be equivalent if they have the same number of elements.
Given sets are [tex]\{0,9\}\,,\,\{8,1\}[/tex]
These sets are not equal as both the sets have different elements.
Order of both the sets is 2 (number of elements in both sets is 2)
So,
these two sets are equivalent.
How do I solve for X?
Answer
50
Step-by-step explanation:
60 is supplementary to 120 so 60+70=130
and a triangle adds up to 180 so 180-130 would be 50
6 ≤ -3x + 12
can somone solve this for me *correctly* ill give u brainlest only if ur right
Answer:
x ≤ 2
Step-by-step explanation:
-3x+12≥6
-3x≥6
3x≤6
x ≤ 2
Answer:
x ≤ 2 is the correct answer!
Step-by-step explanation:
Hope this helps!
Write the equation of the line that passes through the points (1,-5)(1,−5) and (-9,2)(−9,2). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.
Answer:
y+5 = -0.7 (x-1)
Step-by-step explanation:
m = (change in y) / (change in x) = (2-(-5)) / (-9-1) = 7 / (-10) = -0.7
The distance from a point to two is five units. The point could be located at
-7
-6
6
-3
NEXT QUESTION
O ASK FOR HELP
Answer:
The correct answer is -3
Step-by-step explanation:
attached is a number line to show diagrammatically how to count five units from the chosen point to point 2 on a number line.
Moving five units from -3 to 2 on a number line is given as follows:
-3 ⇒ -2 ⇒ -1 ⇒ 0 ⇒ 1 ⇒ 2
From the motion expression shown above, moving from -3 to 2 involves moving 5 units.
another way of determining the correct answer is to find the difference in interval between the two points as shown below:
Let the point be x
2 - x = 5 units
2 - 5 = x
∴ x = -3
Answer:
-3
Step-by-step explanation:
it was on quiz baby
please help me with this question
Answer:
2c^2
Step-by-step explanation:
c3-c1=c2
d2-d2=0
8/4=2
Each picture shows how a mapping, f, maps elements of a domain onto a range.
Which mapping, f, is NOT a function?
Domain
Range
Domain
Range
-6
2.
5
6 00
4
7
7
1
9
8
Domain
Range
Domain
Range
5
4
2
→8
7
2
Answer:
Top left
Step-by-step explanation:
If an x value (domain) leads to more than one y-value (range), it is not a function. In other words, if each input value leads to only one output value, it is a function. It's still a function if the y-value leads to multiple x-values.
uestion 1:
Damon wants to sell his motorcycle that he paid $4,000 for 3 years ago. The motorcycle depreciated (decreased in value) at a constant rate each month over a 3-year period. If x represents the monthly depreciation amount, write an expression that shows how much Damon can sell his motorcycle for today.
Answer:
4,000 -x3
Step-by-step explanation:
x times 3 is equal to the decrease so therefore you take the decrease away form 4/oo
Answer:
3y-x=4,000
Step-by-step explanation:
Sophia says that you can solve the problem in the Example by multiplying both quantities in the ratio 60:36 by one-sixth. Is Sophia correct?
Answer:
Sophia is not correct
Step-by-step explanation:
The given situation represent the problem of a ratio and it is predicted to do the simplify the ratio by determining the smallest possible values
Here it can be presented 60:36 as a fraction i.e. [tex]\frac{60}{36}[/tex]
Now the fraction should be fall by dividing both the numerator and denominator by a common factor i.e. 6
Now after dividing it, the fraction would be [tex]\frac{10}{6}[/tex]
Now it can be further reduced by a common factor i.e. 2
So now the fraction is [tex]\frac{5}{2}[/tex]
Thus, the ratio is 5:2
Hence, she is not correct
Construct a table of values for the following functions using the integers from -4 to 4.
a. F(x)=6/x-2
b. r(x)=6x+12/x^-4
Step-by-step explanation:
Find the table attached
a) Given
F(x) = 6/x-2
When x = -4
F(-4) = 6/-4-2
F(-4) = 6/-6
F(-4) = -1
F(x) = 6/x-2
When x = -3
F(-3) = 6/-3-2
F(-3) = 6/-5
F(-3) = -1.2
F(x) = 6/x-2
When x = -2
F(-2) = 6/-2-2
F(-2) = 6/-4
F(-2) = -1.5
F(x) = 6/x-2
When x = -1
F(-1) = 6/-1-2
F(-1) = 6/-3
F(-1) = -2.0
F(x) = 6/x-2
When x = 0
F(0) = 6/0-2
F(0) = 6/-2
F(0) = -3
F(x) = 6/x-2
When x = 1
F(1) = 6/1-2
F(1) = 6/-1
F(1) = -6
F(x) = 6/x-2
When x = 2
F(2) = 6/2-2
F(2) = 6/0
F(2) = infty
F(x) = 6/x-2
When x = 3
F(3) = 6/3-2
F(3) = 6/1
F(3) = 6
F(x) = 6/x-2
When x = 4
F(4) = 6/4-2
F(4) = 6/2
F(4) = 3
b) Given
r(x)=6x+12/x^-4
When x = -4
r(-4) = 6(-4)+12/(-4)^-4
r(-4) = -24+12/(1/256)
r(-4) = -12(256)
r(-4) = -3072
When x = -3
r(-3) = 6(-3)+12/(-3)^-4
r(-3) = -18+12/(1/81)
r(-3) = -6(81)
r(-3) = -486
When x = -2
r(-2) = 6(-2)+12/(-2)^-4
r(-2) = -12+12/(1/16)
r(-2) = -0(16)
r(-2) = 0
When x = -1
r(-1) = 6(-1)+12/(-1)^-4
r(-1) = -6+12/(1)
r(-1) = -6+12
r(-1) = 6
When x = 0
r(0) = 6(0)+12/(0)^-4
r(0) = 0+12/0
r(0) = 12/0
r(0) = infty
When x = 1
r(1) = 6(1)+12/(1)^-4
r(1) = 6+12/1
r(1) = 18(1)
r(1) = 18
When x = 2
r(2) = 6(2)+12/(2)^-4
r(2) = 12+12/1/16
r(2) = 24(16)
r(2) = 384
When x = 3
r(3) = 6(3)+12/(3)^-4
r(3) = 18+12/1/81
r(3) = 30(81)
r(3) = 2430
When x = 4
r(4) = 6(4)+12/(4)^-4
r(4) = 24+12/1/256
r(4) = 36(256)
r(4) = 9216
We want to construct tables of values for the two given functions.
The tables are:
a)
[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]
b)
[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]
A table will be something like:
[tex]\left[\begin{array}{ccc}x&y\\-4&\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\\4&\end{array}\right][/tex]
Where the values of x go from -4 to 4.
To complete the tables, we just need to evaluate the functions in each one of the x-values at the left, and the outcome will be placed at the right.
a) f(x) = 6/x - 2
Now we just need to evaluate the function in all the given points:
f(-4) = 6/(-4) - 2 = -3/2 - 4/2 = -7/2
f(-3) = 6/-3 - 2 = -4
f(-2) = 6/-2 - 2 = -5
f(-1) = 6/-1 - 2 = -8
f(0) is undefined, as we can't divide by zero, here we can write NaN (Not a number).
f(1) = 6/1 - 2 = 4
f(2) = 6/2 - 2 = 1
f(3) = 6/3 - 2 = 0
f(4) = 6/4 - 2 = -1/2
Now we put all of these in the correspondent place of the table:
[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]
b) We do the same thing, here we have:
r(x) = 6*x + 12/x^-4 = 6*x + 12*x^4
Now we evaluate this in the given values:
r(-4) = 6*(-4) + 12*(-4)^4 = 3,048
r(3) = 6*(-3) + 12*(-3)^4 = 954
r(-2) = 6*(-2) + 12*(-2)^4 = 180
r(-1) = 6*(-1) + 12*(-1)^4 = 6
r(0) = 6*0 + 120^4 = 0
r(1) = 6*1 + 12*1^4 = 18
r(2) = 6*2 + 12*2^4 = 204
r(3) = 6*3 + 12*3^4 = 990
r(4) = 6*4 + 12*4^4 = 3,096
Now we place these values in the correspondent place on the table:
[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]
These are our two tables.
If you want to learn more, you can read.
https://brainly.com/question/8629807
-3/7 % -1/2 =??
What is the answer to this equation
Answer:
-0.21428571428
Most new buildings are required to have a ramp for the handicapped that has a maximum vertical rise of 11 feet for every 132 feet of horizontal distance.
Answer:
11/132 = 1/12
Step-by-step explanation:
just put the rise over the run and simplify
One package of blackberries costs $3. How many packages of blackberries can you buy for $15?
Answer:
5 packages
Step-by-step explanation:
One package of blackberries cost $3
Let x represent the number of packages that will cost $15
1 = $3
x= $15
3x= 15
Divide both sides by the coefficient of x which is 3
3x= 15/3
x= 5
Hence 5 packages of blackberries will cost $15