The student 2 did the MOST work because he pushed the box to a greater height.
The given parameters:
Force applied by Student 1 = 500 NHeight of table for student 1 = 1.2 mHeight of ramp for student 2 = 5 mThe work done by student 1 is calculated as follows;
Work = P.E = mgh
P.E = 1.2mg
The work done by the student 2 is calculated as;
P.E = 5mg
where;
m is the mass of the boxThus, we can conclude that the student 2 did the MOST work.
Learn more about work done here: https://brainly.com/question/8119756
Situation You are going through a very rough time. You feel so down that you need someone to talk to you send a text message to your friend asking her if she could come over to make you feel better. You friend gives you a call then tells you she will be there in 20 minutes. You are so happy to see her, you give her a big hug. then pour your heart out. After crying to her for a good 30 minutes. she gives some comforting words. You finally say that you feel so much better. Your mend then says. "That's good to know. Now we're done, could we settle my expenses for this - 20 pesos for the phone call, 35 pesos for the tricycle nde going to your place, 20 pesos for all the tissue paper you drew from my tissue pack, and 10 pesos for the time I lost to working productively because had to come here. Thanks." What would be your reaction to your friend after she says this? Fourreaction
Answer:
she is your bestfriend so she should always be there for you as long as you are there for them but be like omg im so sorry.
Explanation:
wow tea is pouring
classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine force A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on
What is the difference between folk dance and ballroom dance
Answer:
folk dancing is old music and ball room is young dancing
An airplane initially travels at 12 m/s when passing the "acceleration line." The airplane then
accelerates to 9 m/s2 until reaching its take off velocity of 40.0 m/s. What is the displacement of
the plane during the acceleration?
The displacement of the plane during the acceleration is equal to 80.89 meters.
Given the following data:
Initial velocity = 12 m/sFinal velocity = 40 m/sAcceleration = 9 [tex]m/s^2[/tex]To determine the displacement of the plane during the acceleration, we would use the third equation of motion;
[tex]V^2 = U^2 + 2aS[/tex]
Where:
V is the final speed.U is the initial speed.a is the acceleration.S is the displacement traveled.Substituting the given parameters into the formula, we have;
[tex]40^2 =12^2 + 2(9)S\\\\1600=144+18S\\\\18S=1600-144\\\\18S=1456\\\\S=\frac{1456}{18}[/tex]
Displacement, S = 80.89 meters.
Read more: https://brainly.com/question/13086772
What ions are produced from acids and bases?
Answer:
Give person above me brainliest
Explanation:
how does cells and tissues work together with the brain to do its job
A 263 g ball of clay falls onto a vertical spring.
The spring constant k = 2.52 N/cm.
The clay sticks to the spring and as the spring compresses a distance of 11.8 cm the clay momentarily comes to rest.
Determine the speed of the clay just before it hit the spring in [m/s]?
As the spring is compressed, it performs
-1/2 (252 N/m) (0.118 m)² ≈ -1.75 J
of work on the clay, while gravity does
(0.263 kg) (9.80 m/s²) (0.118 m) ≈ 0.304 J
on it. Then the total work W performed on the clay ball is approximately -1.45 J.
By the work-energy theorem, W is equal to the change in the clay ball's kinetic energy ∆K. If v is the speed with which it hits the spring, then
W = ∆K
-1.45 J = 0 - 1/2 mv²
Solve for v :
-1.45 J = -1/2 (0.263 kg) v²
v² ≈ 11.0 m²/s²
v ≈ 3.32 m/s
Help me as soon as possible <3
Answer: ??? what the
Explanation:
A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass
A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9
Answer:
5)
Solution
initial velocity = 15 m/s
acceleration = 3m/s^2
time = 4 s
final velocity = 15+3×4
=15+12
=27m/s
A car accelerates from 20m/s to 30m/s in 10 second
T9 be honest I think some part of the second question is missing
Why aren’t the Appalachian Mountains still as tall as the Himalayas?
Answer:
mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.
Answer:
It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.
Explanation:
A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?
Have a great day!
Answer:
1176.798 J
Explanation:
[] Use the following equation:
U = mgh
m - mass
g - gravitational field
h - height
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
_____
Additional comment
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
40 POINTSS. Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fingertip. Note how much opposition to your push you feel. Repeat the steps, but this time push the piece of plastic or wood across a rug, carpet, or piece of fabric. If you’re using fabric, be sure to secure the fabric so it doesn’t move. How does the opposition to motion on the tabletop compare with that of the rug, carpet, or fabric? WILL MARK BRAINLIST IF RIGHT
Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.
What happens to a liquid in a U-tube manometer when placed in a vacuum
Answer:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid, as indicated by h, exactly balances the pressure.
Answer:
Here
Explanation:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid
describe the working principle of a hydraulic press using pascals principle
Answer:
A hydraulic press works on the principle of Pascal's law, which states that when pressure is applied to a confined fluid, the pressure change occurs throughout the entire fluid. Within the hydraulic press, there is a piston that works as a pump, that provides a modest mechanical force to a small area of the sample.
Explanation:
18 through 22 multiple choice please help
Answer:
18:equilibrium
19:10.8
20:separating the surfaces with a layer of air
21:it remains motionless
22:cm/s
Identify the class of lever whch is not used for lifting heavy loads but as used for making work faster. Explain your answer.
Answer:
3 class lever .
Explanation:
Third class lever: In the third class lever, the effort is located in between fulcrum and load. Here, effort arm is shorter than the load arm. It cannot lift the heavy load but increases the speed of doing work. ............. can you me as brainlist pls
A car travels 80 km at an avarage speed of 40 km/h. It travels the remaining distance in 3h. What is its dis placement if the average speed of the car is 30 km/h.? And explain
A) 100 km
B)120 km
C)150km
D)180km
When traveling with average speed 40 km/h, the car would cover a distance of 80 km in time t such that
40 km/h = (80 km) / t ⇒ t = 2 h
so the total travel time is 2 h + 3 h = 5 h.
Average speed is defined as the total distance traveled divided by the time it took to cover that distance. So if the overall average speed was 30 km/h, then
30 km/h = (80 km + x) / (5 h) ⇒ x = 70 km
where x is the distance traveled in the last 3 h of the trip.
Then the total displacement of the car is 80 km + 70 km = 150 km.
assume that the hubble constant is 72 km/s/mpc. if a galaxy is 100mpc away, how fast is it moving away from us?
The galaxy is 7200 km/s moving away from us.
A Hubble is a large telescope in space.
The question can be solved using the formula below
⇒ Formula
v = Cd........................ Equation 1⇒ Where:
v = Speed of the galaxyC = Hubble constantd = Galaxy's distance⇒ Given:
C = 72 km/s/mpcd = 100 mpc⇒ Substitute these values into equation 1
v = 72(100)v = 7200 km/s.Hence, the galaxy is 7200 km/s moving away from us.
Learn more about Hubble here: https://brainly.com/question/14615983
An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground
Answer:
20 ft/sec / 32 ft/sec^2 = .625 to reach top
2 * .625 = 1.25
It will be on the ground at t = 0 and t = 1.25
You can also solve the equation:
H = 0 = V0 t - 1/2 g t^2
Obviously, at t=0 h = 0
V0 = 1/2 g t is a solution
t = 20 * 2 / 32 = 1.25 sec
4. In not less than 150 words, write your substantial insights on what you have learned in the past modules in relevance to what is happening now.
Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
Hope this helps !!A bullet of mass 20 g has its kinetic energy equal to 400 J. Find the speed of the bullet.
Answer:
m=20g=0.02kgK.E=400J[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}(0.02)v^2=400[/tex]
[tex]\\ \sf\longmapsto 0.01v^2=400[/tex]
[tex]\\ \sf\longmapsto v^2=40000[/tex]
[tex]\\ \sf\longmapsto v=200m/s[/tex]
☆ Correct and rewrite the following statements:
_____
e). electroplating is based on magnetic effect of electricity.
f). an electric bulb glows due to the chemical effect of electricity.
_______________________
#No spam
#No Internet answers, please #Explanation needed
Answer:
e)Question:-Electroplating is based on magnetic effect of electricity.Answer:-It's incorrect sentence As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.So correct sentence is:
Electroplating is based of chemical effect of electricity. f)Question:-An electric bulb glows due to the chemical effect of electricity.Answer:-It's incorrect sentence As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.So correct sentence is:
An electric bulb glows due to the heating effect of electricity.Help it’s multiple choice 11 through 15 please!
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Two lumps of clay approach each other from opposite directions and collide head on inelastically, combing into one large lump after they collide. the first lump has a mass of 0.140kg and has a speed of 3.50 m/s before the Collision. the second lump has a mass of 0.620kg and has a speed of 4.81 m/s before the collison in a direction opposite that of the first lump. what velocity does the combined lump have after the collision?
Answer:
Before collision:
momentum to right = .14 * 3.5 = .49 kg m / s
momentum to left = .62 * 4.81 = 2.98 kg m / s
Total momentum = .49 - 2.98 = - 2.49 to left
M V = -2.49 net momentum to left
V = -2.49 / (.14 + .62) = -3.28 m/s to left
how do you find average velocity (vaverage) from acceleration (a) and time (t)?
Answer:
1) Average velocities:
Given the magnitudes of 2 velocity vectors, in different time instants, the average velocity is defined as the difference of the 2 velocity magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the velocity magnitudes.
2) Average acceleration
Given the magnitudes of 2 acceleration vectors, in different time instants, the average acceleration is defined as the difference of the 2 acceleration magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the acceleration magnitudes.
As you see the definitions are pretty similar.
Note: I didn't copy-paste this answers from any other site.
will give brainlyiest what is the main need or want this wave technology meets to efficiently communicate with others to hear and see others in real time to efficiently store and share music with others to speak with and see others who are far away
Answer: To see objects surrounding more clearly
Explanation: