The boiling points of alkenes and alkynes are generally lower than those of alkanes.
phase observed:
a.) Methane, Ethane, Propane, and Butane are in a gaseous form in Alkanes (Table 1).
The liquid states of pentene, hexane, heptane, and octane are present.
in alkenes (table 2)
Gaseous forms of ethene, propane, and 1-butane exist.
Both one-pentene and one-hexene are liquids.
c.) Ethyne, propyne, and 2-butane are in the gas phase whereas pentyne is in the liquid phase in the alkynes (table 3).
Number of carbon atoms actually seen:
Alkanes - join one carbon atom to another in a single bond.
Double bonds between carbon atoms are formed in alkenes.
Triple bonds between carbon atoms are formed in alkynes.
Boiling point:The structure of alkanes, alkenes, and alkynes is shown by their boiling points. when a material transitions from the liquid to gas phases, its temperature.
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1
Methane burns in oxygen to make carbon dioxide and water:
methane + oxygen → carbon dioxide + water
For most reactions to happen, the reactant molecules have to collide. But collisions
between them might not always cause a reaction.
Why might a collision between a methane molecule and an oxygen molecule not
always result in a reaction?
A reaction between a methane and oxygen molecule collision could not occur for a number of reasons: (1) The energy of the impact could not be sufficient to withstand the reaction's activation energy.
(2) The reactant molecules may not establish chemical connections with one another because the impact may not be directed properly. (3) The reactant molecules may not have enough time to form chemical interactions with one another after the impact. (4) It's possible that the reactant molecules lack particular characteristics, such as a specific quantity of unpaired electrons, which are required for chemical reactions to occur. (5) The reaction may be reversible and the products' ability to reactivate the reactants may need more energy.
the smallest component of a material that possesses both its chemical and physical characteristics. One or more atoms make up molecules.
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25.00 cm³ of the hydrochloric acid reacted with 23.50 cm³ of the 0.100 mol/dm³
barium hydroxide solution.
The equation for the reaction is:
2 HCl(aq) + Ba(OH)2(aq) → BaCl₂(aq) + 2H₂O(1)
Calculate the concentration of the hydrochloric acid in mol/dm³.
Please help!!
Answer:
0.111 moldm⁻³
First work out the moles of NaOH dispensed from the burette:
1. (25.0/1000)x0.100 = 0.00250 moles of HCl
Next use the balanced equation to reason how many moles of HCl are present in the flask:
2. 1:1 therefore 0.00250 moles NaOH
Lastly, now that you have both the volume and the number of moles of HCl, work out its concentration.
3. 0.0025/(22.5/1000) = 0.111 moldm⁻³
Explanation:
Answer:
The concentration of the hydrochloric acid is 0.00047 mol/dm³.
Explanation:
The balanced equation for the reaction is:
2 HCl(aq) + Ba(OH)2(aq) → BaCl₂(aq) + 2H₂O
We know that 25.00 cm³ of the hydrochloric acid reacted with 23.50 cm³ of the 0.100 mol/dm³ barium hydroxide solution.
Given the balanced equation, it is clear that 2 moles of hydrochloric acid react with 1 mole of barium hydroxide. As we know the volume and concentration of the barium hydroxide, we can calculate the number of moles of barium hydroxide present in the 23.50 cm³ of solution.
23.50 cm³ of 0.100 mol/dm³ barium hydroxide = (23.50 x 0.100) / 1000 = 0.00235 moles
As 2 moles of hydrochloric acid react with 1 mole of barium hydroxide, and we know the number of moles of barium hydroxide, we can calculate the number of moles of hydrochloric acid.
0.00235 moles of barium hydroxide / 2 = 0.001175 moles hydrochloric acid
We have the number of moles of hydrochloric acid, we can calculate the concentration in mol/dm³.
0.001175 moles hydrochloric acid / 25.00 cm³ = 0.00047 mol/dm³
The concentration of the hydrochloric acid is 0.00047 mol/dm³.
In the SI system of units, the mole is one of seven base units. It is frequently used in
chemical calculations. However, a mole of something is just a particular quantity of it, It
unit of measure in the way that meters, seconds, and kilograms are,
Calculations performed with the number of moles of a substance could also be
performed with the number of particles of a substance, Based on this information, do
you think that the mole should be considered a base unit in the Sl system? Explain why
or why not
The fact that the amount of substances is fundamental means that its unit, the mole should be a base unit.
What is the SI system?We have to know that the SI unit is the internationally accepted unit that we can be able to use to obtain the quantities that are basic in physics. We know that there are some units that we call the base units.
The reason why we call them the base units is because all other computations are based on them. The mole should be a base unit because the mole deals with the amount of substance which is quite fundamental in science.
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Chemical
energy.
chemica
Fuels contain a store of energy called
When fuels are burned the
energy. Some fuels, called
were formed from the remains of plants or
energy is changed into
fossil
fuels,
Coal was formed from dead
The plants were buried in
, which stopped them
away.
More mud buried and squashed them. The mud turned into
and the dead plants turned into
that lived in
Oil and gas were formed from plants and
to the sea bed and were
the sea. When they died they
buried. Over
of years they were squashed and heated,
and turned into
Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels.
are composed of the remnants of plants and animals that existed millions of years ago.Coal was generated by burying dead plants in mud and silt, which prevented them from decaying. More muck covered and squished the plants over time, and the sludge hardened into rock.Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels. The dead plants were converted into coal. Plants and animals that fell to the sea floor and were covered by silt produced oil and Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt.
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how many moles in 85 grams of calcium
Mole present in 85 grams of calcium is 2.12 moles
It is given that
given mass of calcium = 85 grams
molar mass of calcium = 40 grams
We have to find the moles
The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12, its symbol is “mol”
moles = given mass/molar mass
moles = 85 gram/40 gram
moles = 2.12
Hence, moles in 85 grams of calcium is 2.12 moles
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How do matter and energy move in and out of the atmosphere? How do changes in one area of the atmosphere affect other areas? The planet as a whole?
Matter and energy move in and out of the atmosphere through several processes.
How do matter and energy move in and out of the atmosphere?These include evaporation, precipitation, condensation, convection, and advection. Evaporation is the process by which liquid water turns into vapor and is released into the atmosphere.Precipitation is the process by which water droplets form in the atmosphere and then fall as rain, snow, hail, or other forms of precipitation.Condensation is the opposite of evaporation in which water vapor in the atmosphere condenses into liquid droplets. Convection is the transfer of heat energy through the movement of air and water molecules. Advection is the transfer of heat energy through the movement of air masses.Changes in one area of the atmosphere can affect other areas in a variety of ways. For example, if there is an increase in temperature in one area, this can lead to an increase in convection, which can cause air masses to move from one area to another, potentially bringing in warm air from other parts of the planet.This can, in turn, affect the temperature and weather patterns in other areas. Similarly, changes in precipitation, such as an increase in rain or snowfall, can lead to changes in the amount of water vapor in the atmosphere, which can affect weather patterns in other areas. These changes can also have global effects, such as increasing sea levels or changing global wind patterns.To learn more about matter and energy move in and out of the atmosphere refer to:
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If 19. 4 grams of ammonium chloride are used, how many grams of water are
theoretically produced?
O 25. 73 g
6. 53 g
9. 55 g
10. 63 g
Con
If 19.4 grams of ammonium chloride are used, option D (10.63 g) of water are theoretically produced.
The balanced equation for the reaction between ammonium chloride and water is:
NH4Cl + H2O ---> NH3 + HCl
From the balanced equation, we can see that for every 1 mole of NH4Cl, 1 mole of H2O is produced.
To find out how many grams of water are theoretically produced, we can use the conversion factor of 1 mole = molar mass.
The molar mass of NH4Cl is (114.01 + 41.01) = 18.05 g/mol
19.4 g of NH4Cl is equal to 19.4/18.05 = 1.07 mol
So, theoretically 1.07 mol of H2O is produced, which is equal to the molar mass of H2O (18.02 g/mol) x 1.07 mol = 19.37 grams of water.
So, the answer is 19.37g of water.
Therefore, The correct answer is 19.37g, but option D (10.63 g) is the nearest correct answer as the question given.
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A container holds a mixture of gases. Gas A has a partial pressure
of 453. 9 mmHg. Gas B has a partial pressure of 287. 6 mmHg. Gas
C has a partial pressure of 382. 4 mmHg. What is the total
pressure of the gases inside the container?
The total pressure of the gases inside the container is the sum of the partial pressures of all the gases present.
The partial pressure of a gas is the pressure that the gas would have if it were alone in the container at the same temperature. In this case, the container holds three gases: Gas A, Gas B, and Gas C. The partial pressures of Gas A, Gas B, and Gas C are given as 453.9 mmHg, 287.6 mmHg, and 382.4 mmHg, respectively. To find the total pressure of the gases inside the container, we add the partial pressures of all three gases: 453.9 mmHg + 287.6 mmHg + 382.4 mmHg = 1123.9 mmHg. Therefore, the total pressure of the gases inside the container is 1123.9 mmHg.
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An element has 2 isotopes: 6X at 7.59% and 7X at 92.41%. What is the average atomic mass?
Record answer to the hundredths (2 decimals):
i’ll give brainliest
Answer: An element has 2 isotopes: 6X at 7.59% and 7X at 92.41%. What is the average atomic mass?
Explanation:
In a bid to calculate the average atomic mass, we multiply the fraction of each isotope by the mass number , then add them together.
This is more like weighted average, as shown below:
average atomic mass=(mass number of first isotope*fraction)+(mass number of second isotope*fraction)
average atomic mass=(6X*7.59%)+(7X*92.41%)
average atomic mass= 6.92X
which element is a gas at stp
Answer:
At standard temperature and pressure (STP), which is defined as 0 °C (273.15 K) and 100 kPa (1 atmosphere), several elements exist as gases.
The elements that are gases at standard temperature and pressure include:
Helium (He)
Neon (Ne)
Argon (Ar)
Krypton (Kr)
Xenon (Xe)
Radon (Rn)
Hydrogen (H2)
Answer:
At standard temperature and pressure (STP), which is defined as 0 °C (273.15 K) and 100 kPa (1 atmosphere), several elements exist as gases.
The elements that are gases at standard temperature and pressure include:
Helium (He)
Neon (Ne)
Argon (Ar)
Krypton (Kr)
Xenon (Xe)
Radon (Rn)
Hydrogen (H2)
sulfur, s8, combines with oxygen at elevated temperatures to form sulfur dioxide. if 240 oxygen molecules are used up in this reaction, how many sulfur molecules reacted?
The equation must have the following form to be balanced: 4CO2 + 2H2O = 2C2H2 + 5O2
S8: O2 = 1/8; S8 utilized = 240/8 = 30SO2 generated is equal to the number of sulphur molecules used, which is 240. Stoichiometry is the name given to the study of chemical processes in mathematics. Numerous calculations can be done, such as stoichiometry, which is most usually performed with moles but can also be done with masses and even percentages. Stoichiometric ratio A stoichiometric ratio is important when considering the interactions between specific elements or molecules. This exact ratio of reactant to product coefficients is necessary for a reaction to occur properly. Let's discuss some problems you can run across when you learn about stoichiometry. Chemical Equations in Balance Equations needing to be balanced is a fairly common stoichiometric issue type. This is an essential chemistry skill since a reaction can only occur if the ratio of reactants to products is correct.possess. Additionally, it provides an essential framework for organic chemistry. Balance the ensuing reply: _ CO2 + _ H2O C2H2 + _ O2 To be balanced, equations must have an equal number of each element on both sides of the reaction. Before balancing the oxygen, you can start by balancing the carbons and hydrogens. The equation must have the following form to be balanced: 4CO2 + 2H2O = 2C2H2 + 5O2
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g calculate the amount of heat needed to boil 15.5 g of methanol (ch3oh). the molar heat of vaporization for methanol is 35.21 kj/mol. the molar mass of methanol is 32.04 g/mol.
The amount of heat needed to boil 15.5 g of methanol (ch3oh). the molar heat of vaporization for methanol is 35.21 kj/mol. the molar mass of methanol is 32.04 g/mol.
To calculate the amount of heat needed to boil 15.5 g of methanol, we need to use the formula: Q = mL
Where Q is the heat energy, m is the mass of the substance, and L is the molar heat of vaporization.
First we need to find the moles of methanol:
moles = mass / molar mass
moles = 15.5 g / 32.04 g/mol = 0.4828 moles
Then we can calculate the heat energy required to boil the methanol:
Q = mL
Q = 0.4828 moles * 35.21 kJ/mol
Q = 17.04 kJ
So, 17.04 kJ of heat energy is required to boil 15.5 g of methanol.
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Look at the symbol equation below. Which is the missing product? mgco3+2hcl-->___+h2o+co2
MgCO₃ + 2HCl ⇒ MgCl₂ + H₂O + CO₂ is the balanced chemical equation. Therefore, the missing product is MgCl₂.
What is balanced chemical equation ?The term balanced chemical equation is defined as a chemical equation in which mass is conserved and there are the same numbers of atoms of each element on both sides of the equation.
The chemical equation must be balanced in order to obey the law of conservation of mass. When the number of different atoms of elements in the reactants side equals the number of atoms in the products side, the chemical equation is balanced.
Thus, MgCO₃ + 2HCl ⇒ MgCl₂ + H₂O + CO₂ is the balanced chemical equation. Therefore, the missing product is MgCl₂.
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youtibe aleks initially there are 3.4 mol of a and 7.5 mol of b in a 20.0 l container. if there is 0.57 mol of a at equilibrium, what is the value of kp?
The value of the Kp is 0.0036.
Kp is used to represent the equilibrium constant expression in terms of partial pressure. Equilibrium constant Kp is measured when the partial pressure of products is divided by partial pressure of reactants and the partial pressure are raised with some power which is equal to the coefficient of the substance present in the balanced chemical equation.
A + B ⇆ 2C
t = 0 3.4 7.5 0
Equilibrium 3.4 - x 7.5 - x 2x
According to the question,
2x = 0.57
⇒ x = 0.57/2 = 0.285
Kc = (2x)²/{(3.4 - x) (7.5 - x)}
⇒Kc = (0.285)²/(3.115 × 7.215)
⇒Kc = 0.081225/22.47425
⇒Kc = 0.0036
The given question is incomplete so I have answered it on general basis.
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if we have 325 g of glucose and 137 g o 2 , what is the limiting reagent, and what mass of co 2 will be produced?
If we have 325 grams of glucose and 137 grams of oxygen, the limiting reagent is oxygen. The mass of carbon dioxide that will be produced is 137 grams.
This means that the reaction will be limited by the amount of oxygen available, and not by the amount of glucose. The mass of carbon dioxide that will be produced will be equal to the mass of oxygen used in the reaction. In this case, 137 grams of carbon dioxide will be produced.
The reaction can be written as: glucose + oxygen --> carbon dioxide + water. This equation shows that for every molecule of glucose, 6 molecules of oxygen are needed to produce 6 molecules of carbon dioxide and 6 molecules of water.
Therefore, the amount of carbon dioxide produced will depend on how much oxygen is available. In this case, 137 grams of oxygen is available, so 137 grams of carbon dioxide will be produced.
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Predicting Moles Worksheet Directions: Show your work for the following calculations. Circle your answers. NO work = NO credit!!! 1. How many moles of methane (CH4) are needed to produce 5.75 moles of water vapor? (Assume excess oxygen.) CH4(g) + 202(g) → CO₂(g) + 2H₂O(g) I will give all 100 of my points just to get this worksheet out the way honestly. I'm getting too stressed out by my people just bc I can't do this singular worksheet
The number of mole of methane, CH₄ needed to produce 5.75 moles of water vapour is 2.875 moles
How do I determine the mole of CH₄ needed?We'll begin by obtaining the moles of CH₄ that reacted from the balanced equation:
CH₄ + 2O₂ -> CO₂ + 2H₂O
From the balanced equation above,
2 moles of H₂O were obtained from 1 mole of CH₄
Using the above information, we can determine the number of moles of CH₄ needed for the reaction. Details below:
From the balanced equation above,
2 moles of H₂O were obtained from 1 mole of CH₄
Therefore,
5.75 moles of H₂O will be obtained from = (5.75 × 1) / 2 = 2.875 moles of CH₄
Thus, we can conclude that the number of moles of CH₄ needed is 2.875 moles
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a 64.8 g 64.8 g sample of the compound x2o5 x 2 o 5 contains 48.0 g 48.0 g of oxygen atoms. what is the molar mass of element x?
A 64.8 g 64.8 g sample of the compound x2o5 x 2 o 5 contains 48.0 g 48.0 g of oxygen atoms. The molar mass of element x is 56 g/mol.
To determine the molar mass of element X, we can use the information provided about the mass of the compound and the mass of the oxygen atoms.
First, convert the mass of the compound to moles by dividing it by the molar mass of the compound:
(64.8 g) / (molar mass of X2O5) = moles of X2O5
Next, use the moles of X2O5 to determine the moles of oxygen atoms by multiplying by the number of oxygen atoms per molecule of X2O5:
moles of X2O5 x (5 moles of O / 1 mole of X2O5) = moles of O
Then, convert the mass of the oxygen atoms to moles by dividing it by the molar mass of oxygen:
(48.0 g) / (16.00 g/mol) = 3.00 moles of O
We know that the mass of the compound is equal to the mass of the element X and the mass of the oxygen atoms.
mass of X = mass of the compound - mass of the oxygen atoms
mass of X = 64.8 - 48.0 = 16.8 g
convert the mass of element X to moles by dividing it by the molar mass of X:
(16.8 g) / (molar mass of X) = moles of X
Now we can calculate the molar mass of element X by using the moles of X and the mass of X
molar mass of X = mass of X / moles of X
molar mass of X = 16.8 g / (3.00 moles of O x (1 mole of X2O5 / 2 moles of X)) = 56 g/mol.
The molar mass of element X is 56 g/mol.
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URGENT: What is the original concentration of a Strontium Hydroxide Solution with a pH of 13. 22?
The concentration of the strontium hydroxide, Sr(OH)₂ solution is 0.083 M.
What is the pH of a solution?The pH of a solution is a measure of the molar concentration of hydrogen ions in the solution and as such is a measure of the acidity or basicity of the solution.
The letters pH stand for "power of hydrogen" and the numerical value is defined as the negative base 10 logarithms of the molar concentration of hydrogen ions.
Mathematically;
pH = - log [H⁺]
pOH = 14 - pH
where;
[H⁺] = concentration of hydrogen ions
[OH⁻] = concentration of hydroxide ions
pOH = 14 - 13.22
pOH = 0.78
The concentration of hydroxide ions in the solution is:
[OH⁻] = 10⁻⁰°⁷⁸
[OH⁻] = 0.166 M
The concentration of the strontium hydroxide, Sr(OH)₂ solution = 0.166/2 M
The concentration of the strontium hydroxide, Sr(OH)₂ solution = 0.083 M
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the heat of vaporization of diethyl ether is . calculate the change in entropy when of diethyl ether condenses at .
The change in entropy Δs when 3.4 g of diethyl ether condenses at 34.6 °C is 4.1 J/K.
Enthаlpy (H) is defined аs the аmount of energy releаsed or аbsorbed during а chemicаl reаction. Entropy (S) defines the degree of rаndomness or disorder in а system.
The relаtionship between both pаrаmeters is given аs;
ΔS = ΔH ÷ T
ΔH = 26.7 KJ/mol for 1 mol of diethyl ether
number of moles = mаss ÷ molаr mаss
number of moles = 3.4 ÷ 72 = 0.04722
ΔH = 26700 × 0.04722 = 1260.77 J
T = 34.6 + 273 = 307.6 (upon converting to Kelvin temperаture)
ΔS = 1260.77 ÷ 307.6
ΔS = 4.1 J/K
Your question is incomplete, but most probably your full question can be seen in the Attachment.
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this experiment tests how the temperature of water affects the time it takes for antacid tablets to dissolve. 1. what is the independent variable? 2. what is the dependent variable? materials
The independent variable in this experiment is the temperature of the water. The dependent variable in this experiment is the time it takes for the antacid tablets to dissolve.
The independent variable in this experiment is the temperature of the water. This is the variable that is being manipulated and changed in order to observe its effect on the dependent variable. The dependent variable in this experiment is the time it takes for the antacid tablets to dissolve. This is the variable that is being measured and observed in relation to the independent variable. The change in the independent variable (temperature of the water) will result in a change in the dependent variable (time for the antacid tablets to dissolve).
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A colorless liquid was added to anhydrous copper {ii} sulphate which turned blue.Why is it wrong to conclude the liquid is pure water?
The conclusion the student that the colorless liquid that was added to anhydrous copper {ii} sulfate which turned blue is pure water because anhydrous copper {ii} sulfate does not react with pure water.
What are the reaction of water and anhydrous copper {ii} sulfate?
A sample of anhydrous copper(II) sulfate becomes blue when water is present.
In the absence of water, it is also known as anhydrous copper(II) sulfate and is colorless.
When water molecules are added to anhydrous copper {ii} sulfate, the individual water molecules are held within the ionic lattice surrounding the copper(II) ions, it is still a dry solid resulting in the formation of blue hydrated copper {ii} sulfate.
This reaction does not occur with pure water.
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3 Ca(OH)2 + 2 H3PO4 → 6 H2O + Ca3(PO4)2
How many moles of H2O would be produced if 5.2 moles of H3PO4 are reacted with excess calcium hydroxide?
2.6 moles H2O
11 moles H2O
15.6 moles H2O
7.8 moles H2O
Answer:
15.6 moles
Explanation:
For every 2 moles of H3PO4 that is reacted, 6 moles of H2O are produced.
So if 5.2 moles of H3PO4 are reacted with calcium hydroxide, calculate the moles of H2O produced by this:
5.2 moles H3PO4 * (6 moles H2O / 2 mole H3PO4) = 15.6 moles H2O
Therefore 15.6 moles of H2O would be produced if 5.2 moles of H3PO4 are reacted with calcium hydroxide.
Please match the following.
Volume of one mole of gas at STP = 22.4 L
number of particles in one mole of any substance = 6.022 ×10²³
What is the mass of 9.30 mole of SiH₄ = 298.81
What is a mole?The mole, abbreviated as mol, is the International System of Units' unit of material amount (SI). The amount of substance is a metric for how many elementary entities of a specific substance there are in a given object or sample. An elementary entity can be any of the following, depending on the substance: an atom, a molecule, an ion, an ion pair, or a subatomic particle like an electron. For instance, although having different volumes and masses, ten moles of water (a chemical compound) and ten moles of mercury (a chemical element) contain precisely the same amount of substance and each ion in the mercury is present in exactly one molecule of water.
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volume displacement is used to determine the volume of an irregularly shaped metal sample. the gradauted cylinder initially contains 23.6 ml of water. after the metal sample is added to the graduated cylinder, the volume is 29.8 ml . what is the volume of the metal sample?
The volume of the metal sample is 6.2 ml
The theory behind this is that the volume of the metal is what causes the increase in water volume in the cylinder.
This means that by comparing the volume occupied by the water and metal together and the amount occupied by the water alone in the cylinder, you can determine the volume of the metal.
To be more specific, the volume of the metal will be,
Vmetal= Vwater + metal - Vwater
In this case, we have
Vwater = 23.6 ml
Vwater + metal = 29.8 ml
So,
Vmetal = 29.8 ml - 23.6 ml = 6.2 ml
Thus the volume of the metal sample is 6.2 ml.
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consider chlorine, which occurs as a mixture of two isotopes: chlorine-35, with a natural abundance of 75.8% and an exact mass of 34.97 amu and chlorine-37, with a natural abundance of 24.2% and an exact mass of 36.97 amu. what is the average atomic mass of chlorine? report to two decimal places.
If the natural abundance of chlorine-35 is 75.8% and that of chlorine-37 is 24.2%, then the average atomic mass of chlorine will be 35.44 amu.
Chlorine exists in two isomeric forms which are the chlorine-35 and chlorine-37. The atomic mass of the chlorine elements is basically the average atomic mass of its isotopes depending upon their abundance in nature.
The atomic mass of chlorine-35 is 34.97amu and a natural abundance equal to 75.8 %. The atomic mass of chlorine-37 is equal to 36.97 amu with an abundance of 24.2%.
To calculate the average atomic mass of chlorine,
The abundance of chlorine-35 = 75.8% = 0.758
The abundance of chlorine-37 = 24.2% = 0.242
⇒ Average atomic mass = 34.97 × 0.758 + 36.97 × 0.242
⇒ Average atomic mass = 26.50 + 8.94
⇒ Average atomic mass = 35.44 amu
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Pls help:)! What are dipole-dipole interactions?
Answer:
Explanation:
Dipole-dipole interactions are a type of chemical bonding that occurs between two polar molecules. In a dipole-dipole interaction, the positively charged end of one molecule is attracted to the negatively charged end of another molecule. This creates a strong force between the two molecules, which holds them together. Dipole-dipole interactions are weaker compared to covalent and ionic bonds, but they can still play an important role in determining the properties of a substance.
The graph below shows the phase change for H2O. Which statement best describes what is occurring at segment C? A. As energy increases, the temperature remains the same. B. As energy increases, temperature also increases. C. As temperature increases, energy remains the same. D. Energy and temperature remain the same.
The graph below shows the phase change for water. The statement that describes what is occurring at segment C is energy and temperature remain the same. The correct option is D.
What is phase change?A phase diagram is a visual representation of a substance's physical state under various pressures and temperatures.
Temperature is on the x-axis and pressure is on the y-axis in a typical phase diagram. Phase changes happen as we go across the lines or curves on the phase diagram.
Therefore, the correct option is D. Energy and temperature remain the same.
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The question is incomplete. Your most probably complete question is given below: the graph is attached.
Use the periodic table to answer the questions below.
Which diagram shows the correct electron configuration for nitrogen (N)?
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third arrow has an up and a down arrow; the fourth has an up arrow only, and the third has no arrows. The third, fourth, and fifth lines are bracketed with the label 2 p.
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third, fourth, and fifth lines each have an up arrow and are bracketed with the label 2 p.
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third and fourth lines each have an up arrow; the fifth line has a down arrow. The third, fourth, and fifth lines are bracketed with the label 2 p.
Atomic mass is the sum of the total number of protons and neutrons in an atom, while atomic number is the number of protons in the nucleus of an atom.
The difference between atomic mass and atomic numberThese two values are related, but they measure different properties.Atomic mass is the total mass of an atom, including the protons and neutrons, while the atomic number is the number of protons in the nucleus of an atom.This number is also used to identify elements, since each element has a unique atomic number.Therefore, the difference between atomic mass and atomic number is that atomic mass is the sum of the total number of protons and neutrons in an atom, while atomic number is the number of protons in the nucleus of an atom.The correct electron configuration for nitrogen (N) can be represented by a group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below.This indicates that the first electron is in the 1s orbital. The second line has an up and a down arrow and is labeled 2 s; this indicates that the second electron is in the 2s orbital.The third, fourth, and fifth lines each have an up arrow and are bracketed with the label 2 p; this indicates that the third, fourth, and fifth electrons are in the 2p orbital.This arrangement of electrons in the appropriate orbitals gives nitrogen its unique chemical properties, which makes it an essential component of all living organisms.To learn more about The difference between atomic mass and atomic number refer to:
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Answer:
The answer is B
Explanation:
That's what the person above said.
find the concentration of barium hydroxide using titration data trial
We can calculate the molarity by dividing the quantity of barium hydroxide in moles by the volume of the initial solution.
How do you find the hydroxide concentration?Implement the titration formula.The formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base when the titrant and analyte have a mole ratio of 1:1.The concentration of a solution, measured in moles of solute per liter of solution, is known as its molarity.After dissociation, the concentration of barium hydroxide will be half that of the hydroxide ions because barium hydroxide dissociates into its ions when dissolved in water as:A barium hydroxide solution with a pH of 12.22 therefore has a concentration of 8.29 10 3 M.To learn more about hydroxide concentration refer
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indicate whether or not each of the structures is considered to be aromatic. compound a is a 3 carbon ring with a double bond between carbons 1 and 2. carbon 3 has a lone pair and a negative charge and is bonded to one hydrogen. compound b is a 5 carbon ring with two double bonds. the non alkene carbon has a carbocation. which is true?
Neither Compound A nor Compound B is aromatic.
The statement "compound A is a 3 carbon ring with a double bond between carbons 1 and 2. carbon 3 has a lone pair and a negative charge and is bonded to one hydrogen" and "compound b is a 5 carbon ring with two double bonds. the non-alkene carbon has a carbocation" is true.
Compound A is not considered to be aromatic because it does not meet the criteria for aromatic compounds. Aromatic compounds have a specific type of cyclic and fully conjugated system of electrons which allows them to have delocalized pi electrons and a cyclic ring of alternating single and double bonds. Compound A has a three-carbon ring with a double bond between carbons 1 and 2, but the third carbon has a lone pair and a negative charge, which breaks the conjugation of the ring.
It also lacks the cyclic ring of alternating single and double bonds, which is a requirement for aromaticity.
Compound B is not considered to be aromatic because it does not meet the criteria for aromatic compounds. Aromatic compounds have a cyclic ring of alternating single and double bonds. Compound B has a 5-carbon ring with two double bonds but it also has a carbocation which again breaks the conjugation of the ring and it is not a cyclic ring of alternating single and double bonds.
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