please please help me i dont know

Answer:

Range:{ 1 , 0 , -1 }

Answer:

$651.36

Step-by-step explanation:

13.57x48

Answer:

I think it is 3x-7y=-28

Answer:will hope it help to find the answer with an unqualified

Step-by-step explanation:

Answer:

he can make 6 goodie bags

Step-by-step explanation:

Answer:

y = -1

Step-by-step explanation:

there is no graph

but only this answer passes the (3,1)

Please add picture next time

<3

Red

Answer:

2

Step-by-step explanation:

Slope equation: (y2-y1)/(x2-x1)

y2 = 4, y1 = -2, x2= 5, x1 = 2

4 – -2 = 6

5 - 2=3

6/3 = 2

Answer:

Step-by-step explanation:

The weights in pounds of the defensive linemen were :

254,311, 297, 323, 260, 242, 300, 252, 303, 274

Ascending order: 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

The weights in pounds of the offensive linemen were :

310 ,315, 305, 318, 298, 301, 321, 332, 320

Ascending order:298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

a)

Offensive line       Stem        Defensive line

                               24     |            2

                               25     |            2 , 4

                               26     |            0

                               27     |            4

         8             |      29     |           7

      1,5              |      30     |           0,3

     0,5,8           |      31      |           1

     0,1               |      32     |           3

      2                |      33     |

Five number summary of offensive line:

1) minimum: 298

2) maximum: 332

3)

Lower quartile:298 ,301 ,305 ,310

Q1 is the median of lower quartile

[tex]Q1=\frac{301+305}{2}=303[/tex]

4)

Upper quartile:318 ,320 ,321 ,332

Q3 is the median of upper quartile

[tex]Q3=\frac{320+321}{2}=320.5[/tex]

5)

Q2 is the median

 298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

Mid value =[tex]\frac{9+1}{2}[/tex]=5th term = 315

Q2=315

Five number summary of defensive line:

1) minimum: 242

2) maximum: 323

3)

Lower quartile:242 ,252 ,254 ,260 ,274

Q1 is the median of lower quartile

Q1=254

4)

Upper quartile:297 ,300 ,303 ,311 ,323

Q3 is the median of upper quartile

Q3=303

5)

Q2 is the median

 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

Mid value =\frac{274+297}{2}=285.5

Q2=285.5

c) Mean weight of offensive line = [tex]\frac{298+301+305+310+315+318+320+321+332}{9}=313.33[/tex]

Mean weight of defensive line = [tex]\frac{242+252+254+260+274+297+300+303+311+323}{10}=281.6[/tex]

Mean weight of offensive line is more

So, Offensive group of players tends to be heavier

Answer:

[tex]A = 97.50 + H[/tex]

Step-by-step explanation:

Given

Stocks: AT&T and IBM HockUnx

Required

Determine the algebraic expression

Represent AT&T with A and IBM HockUnx with H.

Since AT&T is 97.5 more than IBM HockUnx;

The required expression is:

[tex]A = 97.50 + H[/tex]

Answer:

x=2

Step-by-step explanation:

12=12 2=2

the sides have the same x

i'm not sure how much the lanes are, so i'm gonna list the prices of pairs of shoes so you can just add the price of the lanes and find the answer:

1 pair - 2.95

2 pairs - 5.90

3 pairs - 8.85

4 pairs - 11.80

5 pairs - 14.75

6 pairs  - 17.70

7 pairs - 20.65

8 pairs - 23.60

(thats the highest amount of shoes he could get)

Answer:

please spare me

Step-by-step explanation:

Answer:

Step-by-step explanation:

The number of rectangles and combinations:

Total

Now the number of,

Rectangles and combinations are,

→ 1 rectangle = 6

→ 2 rectangles = 5

→ 3 rectangles = 4

→ 4 rectangles = 3

→ 5 rectangles = 2

→ 6 rectangles = 1

Then the total number is,

→ 6+5+4 + 3+2+1

→ 15 + 6 = 21

Hence, total number is 21.

Answer:

54.7599

Step-by-step explanation:

Answer:

constant proportanality is 12 k=12

Step-by-step explanation:

because 5 time 12= 60 and it keep going and going

Answer:

C.50

Step-by-step explanation:

It would be 50 because there are 2 sides to the coin. So if you take 100/2 you get 50. that would be the best estimate answer in my opinion

Number of times the coin will land heads will be 50

Number of trials or observation when each trial has the same probability of attaining one particular value. It determines the probability of observing a specified number of successful outcome in a specific number of trial.

Here , number of times the coin had tosses: 100

P(probability of getting a head in a coin ) : number of time head can come when flipped once / total number of observations

 since , head can come once and there are two possibility either head or tail

hence P= 1/2

this implies number of times heads land up = n*P = 100 *(1/2) = 50

option c) 50

Let us learn more about binomial distribution:

https://brainly.com/question/13634543?referrer=searchResults

#SPJ2

Step-by-step explanation:

Given data

Let the cheese be x

And strawberry be y

So

6x+6y=96-------1

x+4y=52----------2

Solving 1 and 2 simultaneously

Let us multiply equation 2 by 6 we have

6x+6y=96

6x+24y=312

-0-18y=-216

18y=216

y=216/18

y=12

Put y=12 in equation 2

x+4*2=52----------2

x+8=52

x=52-8

x=44

cheese =44

strawberry =12

Answer:

162 is greater than 130.. if that's what your are talking about..

Answer:

D

Explanition:

Answer:

21/4 x 51/2 - k use the app Photomate if wrong

Answer:

b y= 3x+6 is the ans but not sure

Answer:

i thank it is 25 seconds.  

Step-by-step explanation:

Answer:

y=-1.9x-1

Step-by-step explanation:

Answer:

[tex]x = 4y[/tex]

Step-by-step explanation:

Given

[tex]y = kx[/tex]

See attachment for options.

Required

Determine which of the options answers the question

Analyzing the option one after the other:

[tex]\frac{x}{y} = 4[/tex]

Multiply through by y

[tex]y * \frac{x}{y} = 4 * y[/tex]

[tex]x = 4y[/tex]

Divide through by 4

[tex]\frac{x}{4} = \frac{4y}{4}[/tex]

[tex]\frac{x}{4} = y[/tex]

This can be rewritten as

[tex]y = \frac{x}{4}[/tex]

[tex]y = \frac{1}{4} x[/tex]

By comparison with [tex]y = kx[/tex]

we have:

[tex]y = y[/tex]

[tex]x = x[/tex]

[tex]k = \frac{1}{4}[/tex]

Hence: this answers the question.