Please help me 87x89 PLEASE

The two equations that can be used to find the height are as follows

12 / 4 = h  /5

5 / 4 = h  / 12

We have given that,

Amelia is 5 feet tall and casts a 4-foot shadow. A tree next to her casts a 12-foot shadow.

Similar triangles are not necessarily the same in size. Corresponding angles of similar triangles are congruent. The sides of a similar triangle are a ratio to each other.

The tree casts a shadow of 12 ft. Let's establish the proportion base on similar triangles. The height of the tree is h. Therefore,

h / 12 = 5 / 4

Therefore, h / 12 = 5 / 4

cross multiply

4h = 60

divide both sides by 4

h = 60 / 4

h = 15 ft

Therefore, the two equations that can be used to find the height are as follows

12 / 4 = h  /5

5 / 4 = h  / 12

To learn more about the triangle visit:

https://brainly.com/question/17335144

#SPJ1

Answer:

i am on ttm

Step-by-step explanation:

12/4=h/5

5/4=h/12

Answer:

y = -3/2x + 2

Step-by-step explanation:

Since you know it has a point at (0, 2) - the y intercept, put those values into the equation and solve. To be perpendicular it seems the reciprocal of the slope with the opposite sign, so 2/3 is the original slope, and -3/2 becomes the new slope.

y = 2/3x + 8 becomes

2 = -3/2(0) + b  We substitute in the x and y values, but we have to figure out what the last number will be.

2 = 0 + b

b = 2

So put the whole equation together

y = -3/2x + 2

Answer:

$168

Step-by-step explanation:

1  dozen = 12

proportions

12 books ⇔ $144

14 books ⇔ $B

B = 144*14/12

B = $168

Well, it says that 34 kids like physics and since there is 100 students, we know 34% of the kids like physics. This means 66% like biology.

Answer:

Step-by-step explanation:

Given polynomial:

Group as follows:

As we see all terms have (x² + 1) as factor apart from the last one.

It means the remainder is - x

Correct choice is C

a.

The required equation is  23p + 19.50 = 180.50

Let p represent the number of people who can go to the amusement park.

Since the ticket costs $23 per person, the total amount paid for ticket is rate × number of person = $23 × p = 23p.

Since we pay $19.50 for parking, the total amount spent is T = 23p + 19.50

Since the total amount equals $180.50. T = 180.50

So, 23p + 19.50 = 180.50

The required equation is  23p + 19.50 = 180.50

b.

Solving 23p + 19.50 = 180.50, we have

23p = 180.50 - 19.50

23p = 161

p = 161/23

p = 7

So, the number of people who can go to the amusement park is 7.

Learn more about linear equations here:

https://brainly.com/question/24307397

Q10

Q11

Answer:

297 J

Step-by-step explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

D = (7, -9)

E = (8, -10)

hope this helps!

Answer: M = 12.50

Step-by-step explanation:

We know the slope intercept formula. Using the formula, we can find the slope.

Now, let's compare both equations to find out what is the slope.

            y = 4x - 6

We can clearly see that m is replacing with 4. That basically means the slope is 4.

Hoped this helped.

[tex]-BrainiacUser1357-[/tex]

Answer:

2

Step-by-step explanation:

i^2 = -1

i^4 = 1

i^20 repeats the cycle 5 times, making i^20 = 1

Answer:

the answer is D) i

Step-by-step explanation: i got it wrong to the bozo who said 1 and it says the answer is i

Step-by-step explanation:

4+5 (2x-3)-6x

9 (2x-3)-6x

18x-27-6x

12x-27

Answer:

[tex] \sf \: 4x - 11 [/tex]

Step-by-step explanation:

Given expression,

→ 4 + 5(2x - 3) - 6x

Let's simplify the expression,

→ 4 + 5(2x - 3) - 6x

→ 4 + 10x - 15 - 6x

→ (10x - 6x) + (4 - 15)

→ (4x) + (-11)

→ 4x - 11

Hence, the answer is 4x - 11.

Answer:

The answer is 852 I think. Please tell me if this is correct.

Step-by-step explanation:

Answer:

$750

Step-by-step explanation:

did the problem

Answer:

75081

Step-by-step explanation: multiply 80950 by 0.9275

-8.1

Step-by-step explanation:

[tex] \frac{ - 4}{9} x + 2.4 = 6[/tex]

Times all by 9 to get rid of fraction

[tex] - 4x + 21.6 = 54[/tex]

Take 21.6 away from both sides

[tex] - 4x = 32.4[/tex]

Divide by -4

[tex]x = - 8.1[/tex]

Answer: -8 1/10

Step-by-step explanation:

Answer:

1200 I THINK

Step-by-step explanation:

Answer :-

Step by step explanation :-

Here,

The intrest payable on 100$ for 1 year = 12 $

The interest payable on 10,000$ borrowed for 1 year

so, at the eand of the year , he has to give an amount of $ ( 10,000 + 1200 )

Answer:

x= -1

y= 2

Step-by-step explanation:

Notice that when x = 0 the value of y is 2/1 so this line "cuts" the y axis at y= 2

 y-intercept = 2/1  =  2

When y = 0 the value of x is 1/-1 Our line therefore "cuts" the x axis at x= -1

 x-intercept = 2/-2 = 1/-1  = -1

The answer 120 MESSAGES

Answer:

5

Step-by-step explanation:

Answer:

5/8 * 100 = 62.5 %

Answer:

What's this question? Oh my gosh!

The isosceles triangle having an angle bisector [tex]\overline{AD}[/tex] forms two congruent triangles.

Reasons:

The given parameters are;

ΔABC is an isosceles triangle.

[tex]\overline{AB}[/tex] ≅ [tex]\overline{AC}[/tex]

[tex]\overline{AD}[/tex] bisects ∠BAC

Therefore, the proof that ∠ABD  ≅ ∠ACD is given as follows;

1. [tex]\overline{AB}[/tex] ≅ [tex]\mathbf{\overline{AC}}[/tex] (Given)

2. [tex]\overline{AD}[/tex] bisects ∠BAC (Given)

3. ∠BAD ≅ ∠CAD (Definition of angle bisector)

4. [tex]\overline{AD}[/tex] ≅ [tex]\mathbf{\overline{AD}}[/tex] (Reflexive property of congruency)

5. ΔBAD ≅ ΔCAD (Side Angle Side, SAS rule of congruency based on steps 1, 3 and 4)

6. ∠ABD ≅ ∠ACD (Congruent Parts of Congruent Triangle are Congruent, CPCTC)

Learn more about SAS rule of congruency here:

https://brainly.com/question/6422888

Answer:

Slope is -3/5

Slope intercept form: y<-3/5x+2

Step-by-step explanation:

Your going to have a shaded region, with a dashed line

the y intercept will be (2)

the x intercept will be (3.333,0)

Answer:

1. RQP

2. QOP

Step-by-step explanation:

the answer for the first question is RQP and the answer for the second question is QOP

Answer:

i)PQO

ii)QOP

Step-by-step explanation:

Answer:

SAS is the answer

Step-by-step explanation:

Answer:

HL.

Step-by-step explanation:

Right triangles with the hypotenuse and one leg congruent