Mrs. Feiner gets 80% right on a quiz with 20 questions.

How many questions does she get right?
A. 15
B. 16
c. 18
D.19

Answer:

C

Step-by-step explanation:

Multiply the number of muffins by how much baking powder is in each muffin. That's read as 6/1 × 3/8 which equals 18/8.

Answer:

I have no idea and I'm not that smart

Step-by-step explanation:

try this option; for more info see the attachment. New figure is painted with red colour (triangle A'B'C').

Answer:

[tex]\displaystyle 18,28 ≈ x[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x[/tex]

OR

[tex]\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x[/tex]

Information on trigonometric ratios

[tex]\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ[/tex]

I am joyous to assist you at any time.

Answer:

wait i will comment

can you wait

Answer:

Fiona can type 26 words per minute.

Step-by-step explanation:

Just divide 78÷3 (78 words divided by the x3), which gives you 26.

Hope it helps!

[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{vertex}{\stackrel{h}{-6}~~,~~\stackrel{k}{4}}\qquad \implies f(x)=a[x-(-6)]^2+4\implies \underline{f(x)=a(x+6)^2+4} \\\\[-0.35em] ~\dotfill[/tex]

[tex]f(x-2)=a[(x-2)+6]^2+4\implies \underline{f(x-2)=a(x+4)^2+4} \\\\\\ f(x-2)-2\implies [a(x+4)^2+4]-2\implies \underline{a(x+4)^2+2=g(x)} \\\\\\ a[x-(\stackrel{h}{-4})]^2\stackrel{k}{+2}=g(x)\qquad \stackrel{vertex}{-4~~,~~2}[/tex]

Answer: 564 patrons. also omg chiaki pfp so based

Answer: Sara's transaction involved more money.

Step-by-step explanation: 47 is less than 80 and since its in dollars, Sara's $80 would be the answer.

Answer:

(10 + q) ÷ 5

Explanation:

the sum of  10 and a number q is 10 + q

one fifth is dividing by 5

so (10+q) ÷ 5

Answer:

tax is 37,750 $

Step-by-step explanation:

Hope It Helps

The claim supported by the confidence interval is as follows:

The southern frogs are likely to have a greater mean number of croaks per hour than the northern frogs.

The 95% confidence interval for the difference(southern - northern) is given by:

(7.1, 8.1)

Since the entire confidence interval is above 0, the claim supported by it is as follows:

The southern frogs are likely to have a greater mean number of croaks per hour than the northern frogs.

More can be learned about confidence intervals at https://brainly.com/question/25890103

Abby's January finance charge is $7.22, the correct option is C.

Adjusted balance method: Based on finance charges on the amount(s) owed at the end of the current billing cycle after posted credits and payments.

The total amount on which interest will be applied using the adjusted balance method is;

[tex]=722.10 + 18.12-65.00 +18.00 + 44.79+ 34.25 - 40.00\\\\= 732.26[/tex]

Abby’s January finance charge will be;

[tex]= 732.26 \times 11.83 \times \dfrac{30}{360}\times \dfrac{1}{100}\\\\= 7.22[/tex]

Hence, Abby's January finance charge is $7.22.

To get more about the adjusted balance method please refer to the link,

brainly.com/question/14351468

Abby has a credit card which uses the adjusted balance method to compute finance charges. her card has an apr of 11.83%, and she is on a 30-day billing cycle. the table below shows her transactions in the month of January. date amount ($) transaction 1/1 722.10 beginning balance 1/6 18.12 purchase 1/7 65.00 payment 1/14 18.00 purchase 1/20 44.79 purchase 1/23 34.25 purchase 1/27 40.00 payment what will Abby’s January finance charge be? a. $6.08 b. $7.12 c. $7.22 d. $8.25

The answer is C.

Answer:

2533 1/3

Step-by-step explanation:

becuase if you take the denominator you get it[tex]\sqrt{x} x_{123} \\ x^{2} x^{2} \alpha \beta \lim_{n \to \infty} a_n \leq \alpha \\[/tex]

Answer:

D: 5253 3/25 mm²

The maximum profit is $288, and you should charge $6 per dozen.

Let's assume that demand depends linearly on price, such that we can write:

q = a*p + b

where q is the demand and p is the price.

We have 3 points of that line:

The slope of the line is given by:

[tex]a = \frac{q_2 - q_1}{p_2 - p_1}[/tex]

Where these are values of demand and prize for two different points, if we use the first two points we get:

[tex]a = \frac{72 - 80}{3 - 2} = -8[/tex]

Then the line is something like:

q = -8*p + b

Remember that when p = 2, the demand is equal to 80, replacing that we get:

80 = -8*2 + b

80 + 16 = b = 96.

So the line is:

q = -8*p + b

Profit is given by the product between the demand and the price, so we have.

Profit = p*q = p*(-8*p + 96) = -8p^2 + 96p

We want to maximize that, notice that is a quadratic equation of negative leading coefficient, so the maximum is at the vertex, using the equation for the vertex of a quadratic equation we will see that the maximum is at:

p = -96/(2*-8) = 6

Then the maximum profit is:

profit = -8*(6)^2 + 96*6 = 288

The maximum profit is $288, and you should charge $6 per dozen.

If you want to learn more about linear relations, you can read:

https://brainly.com/question/1884491

Answer:

a=(x+7)(x+-2)

Step-by-step explanation:

(x+a)(x+b)=x²+(a+b)x+(ab)

Answer:

  a) (x +7)(x -2)

  b) x = -7 or +2

Step-by-step explanation:

A trinomial is factored by realizing that the constant term (-14) is the product of the binomial constants, and the coefficient of the linear term (5) is their sum. Here, we can examine the factorization of -14 to see which factors may have a sum of 5:

  -14 = (-1)(14) = (-2)(7) = (-7)(2) = (-14)(1)

Sums of these factor pairs are 13, 5, -5, -13. Clearly, we could stop writing factorizations when the sum stops being positive. The values of interest are -7 and 2. They tell us the trinomial is factored as ...

  x² +5x -14 = (x +7)(x -2)

__

The zeros of the quadratic are the values of x that make the above factors be zero. The zero product rule tells you the only way the product will be zero is for a factor to be zero.

  x +7 = 0   ⇒   x = -7

  x -2 = 0   ⇒   x = 2

The solutions are x = -7 or x = 2.

Answer:

9,508.8 dollars spent

Step-by-step explanation:

subtraction.

Answer:

$9,508.8

Step-by-step explanation:

10,000-491.2=ans

Answer:

x = 5

Step-by-step explanation:

Given:

To Find:

What is the value of x?

Note:

Two angles that add up to give you 90° is a complementary angle.

Thus, Since angle A and angle B sum up to give 90°, they are complementary angles.

Solve:

The following equation can be created to solve for the value of x:

m ∠A + m∠ B

Substitute

40 + 4x + 30 = 90

Add like terms

4x +70 = 90

Subtract 70 from both sides

4x = 90-70

4x = 20

Divide both sides by 4

x = 5

Therefore, the value of x is 5

~Learn with Lenvy~

Answer:

4x+3y=6

Step-by-step explanation:

hope this helps

Answer:

883.57

Step-by-step explanation:

closet answer I can find

Answer:

There were 5 students in the back of the room.

Step-by-step explanation:

8x3=24

Which means that there were 24 students on the stage

Then...

29-24=5

Which means that there were 5 students in the back of the room.

Thanks!

Answer:

ok........

Step-by-step explanation:

Answer:

84.33333333

or rounded...

84.3

or 84 if asked to be rounded to whole

Answer:

A. North

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Use z score formula.

55 is x

plug in u and sd.

Answer:

[tex]y^{10}-\dfrac{25}{64}x^2[/tex]

Step-by-step explanation:

Given expression:

[tex](\frac58x+y^5)(y^5-\frac58 x)[/tex]

Change the order of the terms in the first parentheses:

[tex]\implies (y^5+\frac58x)(y^5-\frac58 x)[/tex]

Apply the Difference of Two Squares: [tex](a+b)(a-b)=a^2-b^2[/tex]

[tex]\implies (y^5)^2-(\frac58x)^2[/tex]

Apply exponent rule [tex](a^b)^c=a^{b\cdot c}[/tex]

[tex]\implies y^{10}-(\frac58x)^2[/tex]

Apply exponent rule [tex]\left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}[/tex]

[tex]\implies y^{10}-\left(\dfrac{5^2}{8^2}x^2\right)[/tex]

[tex]\implies y^{10}-\dfrac{25}{64}x^2[/tex]