The amount of paint required by Madeline will be 0.8325 gallons
What amount of paint will be required by Madeline?Given that
[tex]1cm=1.5ft[/tex]
We will first find the area of the wall
Area of the wall = Area of trapezoidal shape+ Area of triangular shape
Area of trapezoid = [tex]\dfrac{a+b}{2} \times h[/tex]
a= 4cm
b=14cm
h=10cm
putting this values
[tex]A=\dfrac{4+14}{2} \times 10[/tex]
[tex]A=90cm^{2}[/tex]
Area of triangular shape= [tex]\dfrac{1}{2} \times width\times height[/tex]
width=14cm
height=8cm
putting the values
[tex]A=\dfrac{1}{2} \times 14\times 8=58cm^{2}[/tex]
[tex]Total area of the wall= 90+58=148cm^{2}[/tex]
since we have
[tex]1cm=1.5ft[/tex]
[tex]148cm^{2} = 148\times (1.5)^{2} =333 ft^{2}[/tex]
Now
[tex]1gallon = 400ft^{2}[/tex]
so for [tex]333 ft^{2}[/tex] amount of paint in gallons required will be
[tex]1ft^{2} =\dfrac{1}{400} gallons[/tex]
[tex]333ft^{2} =\dfrac{333}{400} gallons=0.8325gallons[/tex]
Thus the amount of paint required by Madeline will be 0.8325 gallons
To know more about the area of trapezoid follow
https://brainly.com/question/1463152
2. Simplify each expression into its standard
(x - 3)(6x - 2)
Answer: 6x² - 20x + 6
Step-by-step explanation:
x(6x - 2) -3(6x - 2)
= 6x² - 2x - 18x + 6
= 6x² - 20x + 6
Look at the cards below. When the cards are face down, your chances of picking an "A" card out of the group are 2/5. Approximately how many times would you pick an "A" card if you chose 50 times? XA GAP x S Р Hint: Set up a proportion
50 times; 40% A
2/5(50) = A
A = 20
Answer:
50 times; 40% A
2/5(50) = A
A = 20
Step-by-step explanation:
I NEED THIS DONE IN 5 MIN SOMEONE HELP
Answer:
4
Step-by-step explanation:
What is 3/8 to the nearest half? I need an explanation too cause I don't understand how to say it :)))
Answer:
HOP IT HELPS
3/8=1.5/4
because when you divide
3÷2 and 8÷2
you get
1.5/ 4
Answer:
1/2
Step-by-step explanation:
3/8 to the nearest 1/2.
The question wants to know if you round 3/8 to the nearest half, what value would that be? On a number line from 0 to 1, we could mark every 1/8 unit:
0/8==1/8==2/8==3/8==4/8==5/8==6/8==7/8==8/8
Note that 0/8 is 0, 4/8 is 1/4 and 8/8 is 1.
3/8 is one step from 4/8, or 1/2. So the nearest half would be 1/2.
Using your knowledge of 2- and y-intercepts, which graph matches the equation y = x + 2x - 3?
Answer:
ANSWER (A.
Step-by-step explanation:
HOPE IT HELP'S !
what is the area, please help me!
Answer:
30ft2. (C.)
I did this question once.
Sorry for my Lack of explanation.-
Answer:
C
Step-by-step explanation:
Draw a line to make 2 separate shapes and find the area of each them then add the 2 areas together
18+12=30
The perimeter of a square is equal to the perimeter of rectangle of length = 16 cm and breadth=4 cm. What is the perimeter and side of the square?
Describe in detail how you would create a number line with the following points: 1, 3.25, the opposite of 2, and – (–4fraction of one-half). Please be sure to describe on which tick marks each point is plotted and how many tick marks are between each integer. It may help for you to draw this number line by hand on a sheet of paper first.
Answer:
Step-by-step explanation:
Given : points 4 , 1 ,25 , opposite of 3 , -1/2
To Find : draw on Number Line
Solution :
Numbers with a negative sign are less than zero
Right of zero represented by ‘+’ sign and to the left of zero represented by ‘–’ sign.
+ sign numbers can be denoted as simply numbers
On a number line the number increases as we move to the right and decreases as we move to the left.
1 : Draw a line and mark some points at equal distance on it as shown in the figure below Mark a point as zero on it. Points to the right of zero are positive integers and are marked simply 1, 2, 3 and so on , while points to the left of zero are negative integers and are marked – 1, – 2, – 3 and so on
2. Go 4 unit on right sides from Zero to show 4
3. Go 3 units on Left from zero to show opposite of 3
4. Divide number line between 1 & 2 in 4 Equal parts and go 1 part right of 1
5. Divide number line between 0 & -1 in 2 Equal parts and go 1 part left of 0
give brainliest.
A standard sheet of paper in the United States is 11 inches long and 8.5 inches wide. Each inch is 2.54 centimeters. How long and wide is a standard sheet of paper in centimeters?
Hi i have a trick question 2 actually so we started to do simply fy and i dont understand these 2 so here it is -2 x y +7x
and 10x + 2y - 2x +2y/2 +8y
Answer:
The first one is: -2xy+7x
The second one is: 12x+9y
Number one is a little weird in how you put it, but I hope this helps!
[tex]v = \frac{er}{r + a} [/tex]
Find R in image
Step-by-step explanation:
[tex]V = \frac{ER}{R + a} [/tex]
[tex]V(R+a)=ER[/tex]
[tex]VR + Va=ER[/tex]
[tex]Va= ER-VR[/tex]
[tex]Va=R(E-V)[/tex]
[tex]R = \frac{Va}{E-V} [/tex]
Find f(6) if f(x) = x2 ÷ 3 + x.
18
21
10
4
Answer:
the answer for d question is 10
Solve for x and y
2x-5y=1, 3x+2y=11
2x - 5y = 1
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.
[tex]\rm{2x - 5y = 1 }\\ [/tex]
[tex] \rm{2x - 5y + 5y = 1 + 5y}\\[/tex]
Subtract -5y from both sides of the equation
Simplify 2x - 5y + 5y = 1 + 5y
Cancel -5y with 5y
Reorder 1 + 5y so highest order terms are first
[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]
Move factors not having X from the left side of equation 2x = 5y + 1
[tex] \rm{ \frac{2x}{2} = \frac{5y + 1}{2} } \\ [/tex]
Divide both sides of equation 2x = 5y + 1 by 2
Cancel 2 with 2
[tex] \rm{ \frac{\cancel{2}x}{\cancel{2}} = \frac{5y + 1}{2} } \\ [/tex]
[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]
Therefore, the x of 2x - 5y = 1 is [tex] \rm{ \frac{5y + 1}{2} } [/tex]
Solve for y2x - 5y = 1
[tex]\rm{-5y + 2x = 1}\\ [/tex]
Reorder 2x -5y so highest order terms are first
-5y = -2x + 1
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1
[tex]\rm{-5y + 2x - 2x = 1 - 2x}\\[/tex]
Subtract 2x from both sides of the equation
Simply - 5y + 2x -2x = 1 - 2x
Cancel 2x with -2x
Reorder 1 - 2x so highest order terms are first
[tex] \rm{y = - \frac{2x + 1}{5} }\\[/tex]
Move factors not having y from the left side of equation -5y = -2x + 1
[tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} }\\ [/tex]
Divide both sides of equation -5y = -2x +1 by -5
Simplify [tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} } [/tex]
Cancel 5 with -5
Resolve sign on fraction [tex] \rm{\frac{ - 2x + 1}{ - 5} }[/tex]
Therefore, the y of 2x-5y = 1 is [tex]\rm{\frac{ - 2x + 1}{ - 5} } [/tex]
Solve for x3x + 2y = 11
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y
Subtract 2y from the both sides of the equation
Simplify 3x + 2y - 2y = 11 - 2y
Cancel 2y with 2y
Reorder 11 - 2y so highest order terms are first
[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]
Move the factors not having x from the left side of equation 3x = -2y +11
[tex] \rm{ \frac{3x}{3} = \frac{-2y + 11}{3} } \\ [/tex]
Divide both sides of equation 3x = 2y + 11 by 3
Cancel 3 with 3
[tex] \rm{ \frac{\cancel{3}x}{\cancel{3}} = \frac{-2y + 11}{3} } \\ [/tex]
[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]
Therefore, the x for 3x + 2y = 11 is [tex] \rm{ \frac{2y + 11}{3} } [/tex]
Solve for y2y + 3x = 11
Reorder 3x + 2y so highest order terms are first
[tex]\rm{2y + 3x = 11}\\[/tex]
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11
[tex]\rm{2y + 3x - 3x = 11 - 3x}[/tex]
Subtract 3y from the both sides of the equation
Simplify 2y + 3x - 3x = 11 - 3x
Cancel 3x with - 3x
Reorder 11 - 3x so highest order terms are first
[tex] \rm{y= - \frac{3x + 11}{3} } \\ [/tex]
Move factors not having y from the left side of equation 2y = -3x + 11
[tex] \rm{ \frac{2y}{2} = \frac{-3x + 11}{3} } \\ [/tex]
Divide both sides of equation 2y = -3x + 11 by 2
Cancel 2 with 2
[tex] \rm{ \frac{\cancel{2}y}{\cancel{2}} = \frac{-3x + 11}{3} } \\ [/tex]
[tex] \rm{y = \frac{-3x + 11}{3} } \\ [/tex]
Therefore, the y for 2y + 3x = 11 is [tex] \rm{ \frac{-3x + 11}{3} } [/tex]
evaluate each expression (-1) • 2 • 3
Answer:
-6
Step-by-step explanation:
-1 * 2 * 3
= -2 * 3
= -6
Answer:
-1 x 2 = -2
-2 x 3 = -6
Answer:
-6
What is the overlap of Data Set 1 and Data Set 2?
high
moderate
low
none
Two line plots with the same scale and interval, from fifty two to sixty two, with tick marks every one unit. The plots are stacked vertically for comparison. Each plot has eleven data values. Values appear as x marks above the line. Upper plot data values are one x mark above fifty three, one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, and one x mark above sixty. Lower plot data values are one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, one x mark above fifty nine and one x mark above sixty.
Answer:
Well my answer is high data set I took the test and got 100%
Step-by-step explanation:
Answer:
High
Step-by-step explanation: I took the test.
97 is what percent of 837? Round to the nearest whole #
Answer:
12
Step-by-step explanation:
Normal body temperature is 98.6 degrees Fahrenheit. When Tyler had a fever, his temperature went up to 102.2 degrees. By how much did Tyler's temperature increase?
Can someone pls explain me how to do this pls!!!
Answer:
A, C, E
Step-by-step explanation:
You would want to graph the points an if the line goes through them then that would be the answer
Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. respectively.
Given :
The radii of the circular paths are 210 m. and 490 m.To Find :
The area of the region between two concentric circular paths.Solution :
Area of the outer circle :
[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}} [/tex]
⠀
Area of the inner circle :
[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}} [/tex]
⠀
Therefore,
Area of the region inside the circular paths :
[tex]\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}[/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}[/tex]
2x+3y=53 what is the value of y and x
Answer:
[tex]2x = 53 - 3y \\ x = \frac{53 - 3y}{2} \\ y = \frac{53 - 2x}{3} [/tex]
Need Help Please!!!!!!
Answer:
64°
.
.........................
Rewrite the Equation in Ax+By=C form. Use Integers for A,B, and C
Answer:
-x + 5y = 15
Step-by-step explanation:
Hello! This question simply asks us to rearrange the equation.
So we have this:
y - 2 = 5(x + 5)
Okay, so we need to get an answer with integers for x and y, but no brackets. This means we can start by expanding them:
5y - 10 = x + 5
now, let's put y and x on the same side of the equation, and numbers on the other side:
5y - x = 5 + 10
5y - x = 15
we can put x first, but it's not necessary:
-x + 5y = 15
A = -1
B = 5
C = 15
And that's it!
I hope this makes sense :))
Answer:
5x - y = - 27
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
given
y - 2 = 5(x + 5) ← distribute parenthesis
y - 2 = 5x + 25 ( add 2 to both sides )
y = 5x + 27 ( subtract 5x from both sides )
- 5x + y = 25 ( multiply through by - 1 )
5x - y = - 27 ← in standard form
If someone can answer these both I’ll give 75 points
Solution (1):
Note that:
Sum of interior angles = 180°This means that...
5x + 3x + 2 + 130 = 180Finding the value of x.
5x + 3x + 2 + 130 = 180=> 8x + 132 = 180=> 8x = 180 - 132=> 8x = 48=> x = 6Solution (2):
Note that:
Sum of interior angles = 180°This means that...
x + 66 + x + 86 + 50 = 180°Finding the value of x.
x + 66 + x + 86 + 50 = 180°=> 2x + 202 = 180°=> 2x = -22=> x = -11the hot air popcorn maker used at the movies theater produces 14 cups of popcorn in 2.5 minutes. what is the unit rate per minute?
high speed train travels at a speed of 200 km/h if the train sets off from station A at 12 24 and reaches station B AT 14 12 find the distance in between two stations giving your answer in meters.
Answer: 360000m
Step-by-step explanation:
Okay, so since we know that this train’s speed is 200km/h, let’s find the time difference between 12 24 and 14 12.
14 12 - 2hrs = 12 12
12 12 + 12min = 12 24
2hrs -12min = 1hr 48 min
1hr 48 min also equals to 1.8hrs in decimals. So:
200km x 1.8 = 360km
Now we have to find the answer in meters. Since 1km is equal to 1000m,
That means 360km equals 360000m.
Therefore 360000m is the answer
Use the graph above to answer the question. Select all the terms that describe the graph of the function in interval 3 HELPPPPPPPP
Answer:
true false false true true
3. Angles X and Y have a sum of 159 degrees. Angle X is 43 degrees smaller than angle Y.
Write a system of equations that represent this, then solve it to find the measures of both
angles.
[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]
[tex]\longrightarrow[/tex]Since angle X and Y have a sum of 159
[tex]\implies \bf Y + X= 159 \_\_\_\_(1) [/tex]
[tex]\longrightarrow[/tex]Since X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -
[tex]\implies \bf Y - X = 43 \_\_\_\_(2) [/tex]
Adding Equation (1) and (2)
[tex]\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered} [/tex]
Putting Y in eq (1)
[tex]\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf X = 153-101 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \boxed{\sf{ X = 52 }}\\\end{gathered} [/tex]
HELLLLLPPPPPPPP!!!!!!!!!!!!! IT GOT DELETED LAST TIME!!!!!!
4x^3y^2 x 3x^6y^3/24x^11y^2
Answer:
x²⁰y⁷
____
2
Step-by-step explanation:
multiply
combine exp
cancel terms
combine multiplied terms
combine exp
Help pls
MODELING WITH MATHEMATICS The period of a
pendulum is the time the pendulum takes to complete
one back-and-forth swing. The period T in seconds)
can be modeled by the function T = 1.11ve, where
l is the length (in feet) of the pendulum. Graph the
function. Estimate the length of a pendulum with a
period of 2 seconds. Explain your reasoning.
Answer:
Approximately 1.6
Step-by-step explanation:
To graph. a function, let use desmos or graphing calculator.
Here the function.
The length of the pendulum as shown here when x=2, is 1.6
Samantha saw two bottles of ketchup at the store for the same price. One bottle contained 4 pints of ketchup, and the other contained 1.25 quarts of ketchp. Which bottle was the better bargain?
Answer:
The bottle with 1.25quarts is the better bargain because a quart is the same thing as 2pints