2. Suppose that all possible n = 50 samples are selected from a population. How would the mean,
standard deviation, and shape of the resulting sampling distribution compare to a sampling
distribution based on all possible n= 100 samples?
Using the Central Limit Theorem, it is found that the mean and the shape would remain the same, while the standard deviation would be multiplied by the square root of 2.
Central Limit TheoremThe Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the sampling distribution is also approximately normal, as long as n is at least 30.
In this problem:
The sample size would remain above 30, hence the shape would still be normal.The mean does not depend on the sample size, hence it would remain constant.The standard deviation is inversely proportional to the square root of the sample size, then since the sample size would be divided by 2, the standard deviation would be multiplied by the square root of 2.More can be learned about the Central Limit Theorem at https://brainly.com/question/24663213
How many reports for colleges does the ACT registration fee cover?
&
Ο Α. 4
Β. 2
Ο Ο Ο
Ο C. 5
D. 1
Answer:
Your fee waiver covers one report to your high school and up to six college choices. After registration, you can request up to an additional 20 regular score reports for free.
The French built settlements and forts along the?
Answer:
The French built settlements and forts along the Mississippi River and its tributaries in what is now the central and southern United States.
Explanation:
Choose the correct option.
OPTION
From the given options, three are similar to each other because they follow the
same pattern. Identify the option that is dissimilar to the other three.
DEK
PRW
EGL
TVZ
Answer:
1 is dissimilar
Explanation:
DEK is the option that is dissimilar to the other three. As three are similar to each other because they follow the same pattern. Hence, option A is correct.
What is meant by same pattern?Comparable goods or objects have traits in common when they are two different things. Exemplar: a pattern or model recommended for imitation.
Something made or used as a model for creation is called a dressmaker's pattern. Examples of designs or forms that are artistic, musical, literary, or mechanical are a geometric pattern in a carpet or a strict pattern of rhyme and rhythm in a sonnet.
In order to generate a duplicate, a design, or an expected behaviour, someone or something is used as a pattern. A pattern, or dress pattern, is a set of paper pieces that a seamstress uses to construct a dress.
Thus, option A is correct.
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so point a is named by the ordered pair can u help neee
Answer:
A point is named by its ordered pair of the form of (x, y)
Write the equation of a sine or cosine function to describe the graph.
Answer:
y = -3 + 3sin(2t)
Explanation:
Amplitude = 3
period = 5π/4 - π/4 = π
shift down 3
y = -3 + 3sin(2t)
Answer(s):
[tex]\displaystyle y = 3cos\:(2x - \frac{\pi}{2}) - 3 \\ y = 3sin\:2x - 3[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3cos\:2x - 3,[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3cos\:(2x - \frac{\pi}{2}) - 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{3}{4}\pi, -6],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{4}, -6],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -3,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
identify five phyco-social factors to learners
Typically, psychological factors include attitudes, motivations, perceptions, learning abilities, and emotions
The five phyco-social factors which can affect learners are:
MotivationPerceptionLearningAttitudeFamilyWhat is psychosocial factors?Psychosocial factors refers to characteristics that can influence an individual psychologically and socially. The psychosocial helps to describe the relationship of an individual with their social environment and the effects on their mental health.
Therefore, the five psychosocial factors that can affect learners academically are Motivation, Perception, Learning, Attitude, Family.
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How to find a good roommate in college?
Answer:
find someone with the same interests with you that is someone that you could become friends with
Explanation:
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)
Compute the probability that exactly five of the six M&M’s are blue.
Compute the probability that four or five of the six M&M’s are blue.
Compute the probability that at most five of the six M&M’s are blue.
Compute the probability that at least five of the six M&M’s are blue.
If you repeatedly select random samples of six peanut M&M’s, on average how many do you expect to be blue? (Round your answer to two decimal places.)
blue M&M’s
With what standard deviation? (Round your answer to two decimal places.)
blue M&M’s
pls don't use this app this app is makes you spoiled
A population of values has a normal distribution with mean = 241.7 and standard deviation = 48.3. You intend to draw a random sample of size n = 79. = Find the probability that a single randomly selected value is between 233 and 242.2. P(233 < X < 242.2)
Answer:
wow that's sound easy but I can't help you cause your very spoiled to do your modules
A vessel located between an artery and a capillary is a(n) ___________.
Answer:
spinal cord that is located between the artery and capillary
A. Identify and discuss at least five challenges that hinders the teacher from effectively managing the classroom
Answer:
Some of the common classroom challenges faced by teachers include lack of teamwork, minimal personal time, working towards long term goals, arguments and student excuses, etc.
Explanation:
what unit of measurement is closest to the meter in length? is it
miles or feet or inches or yards?
Answer:
yards
Explanation:
1) There are about 0.000621 miles in 1 meter. The number of miles is clearly way smaller than 1, so miles is not the closet
.
2) There are about 3.28 feet in 1 meter. Again, this shows that 1 foot is not close to 1 meter, so feet is not the closet.
3) There are about 39.37 inches in 1 meter. Clearly, 1 inch is not close to 1 meter.
4)There are about 1.09 yards in 1 meter. 1.09 can round down to 1, so this is the closest to a meter.
Andrew opened a savings account and deposited $800. He earned 1.6 percent interest, compounded annually. At the end of the year, he has $812.80. What is the principal?
Answer: $800
Explanation:
Compound interest formula:
A = P(1 + r/n)^nt
In our case:
812.80 = 800(1 + 0.016)^1
Very clear that 800 is the principle