Is triangle EJH congruent to triangle EIH?

Yes or No?

Answer:

482.96 meters, Hope that helped

Answer:

Hope this helps you

Step-by-step explanation:

Mean= [tex]\frac{404}{75} = 5.386666666666667[/tex]

Therefore, the mean of the given distribution =5.39 or 3.4

If you did not understand anything you can ask in the comments

Using the combination formula, it is found that 84 different groups of 6 people are possible from the 9 remaining friends.

The order in which the friends are chosen is not important, hence the combination formula is used to solve this question.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 6 friends are chosen from a set of 9, hence:

[tex]C_{9,6} = \frac{9!}{6!3!} = 84[/tex]

84 different groups of 6 people are possible from the 9 remaining friends.

More can be learned about the combination formula at https://brainly.com/question/25821700

Answer:

this wrong

Step-by-step explanation:

Answer:

x = [12]

Step-by-step explanation:

=> [tex] \frac{x}{6} = \frac{6}{3} [/tex]

=> x = 2 × 6

=> x = 12

Given -

△ABC ∼ △DEF

To find -

the value of x.

Solution -

If △ABC ∼ △DEF then,

[tex]\frac{AB}{DE} =\frac{BC}{EF}[/tex]

➡ [tex]x=\frac{\cancel{12}^4}{\cancel{3}_1}\times2[/tex]

➡ [tex]x=4\times2[/tex]

➡ [tex]x=8[/tex]

Hence, the value of x is equal to 8.

Answer:

19.40-14=5.40

5.40÷0.20=ounces

Hope this helps!!!

Answer:

27 ounces

Step-by-step explanation:

$14 package original charging fee

+ .20x27 = 5.40

14 + 5.4 = 19.4

$19.4

[tex]\boxed{\tt \pink{Given:}}[/tex]

[tex]\red\star[/tex]Diameter of base of a cylinder = 20 cm.

[tex]\red\star[/tex]Height of cylinder = 5cm.

[tex]\\\\[/tex]

[tex]\boxed{\tt \pink{To~Find:}}[/tex]

[tex]\red\star[/tex]Volume of Cylinder.

[tex]\\\\[/tex]

[tex]\boxed{\tt \pink{Solution}}[/tex]

To find volume of Cylinder first we should know radius of Cylinder. We can get radius by diameter using this formula:-

[tex]\boxed{\rm Diameter = 2 radius}[/tex]

[tex]\\\\[/tex]

[tex]\hookrightarrow\sf Diameter = 2 radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow\sf 20= 2 radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow\sf \dfrac{20}{2}= radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow\sf \dfrac{2\times10}{2}= radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow \sf \dfrac{\cancel2\times10}{\cancel2}= radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow \sf \dfrac{1\times10}{1}= radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow \sf 10= radius[/tex]

[tex]\\[/tex]

[tex]\hookrightarrow \bf radius = \pmb{\blue{10 cm}}[/tex]

[tex]\\\\[/tex]

Now Finally Let's find volume of Cylinder.

we know:-

[tex]\boxed{\rm Volume ~ of ~ Cylinder = \pi radius^2 \times height}[/tex]

[tex]\\\\[/tex]

So:-

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi radius^2\times height\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi (10)^2\times 5\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi 10\times10\times5\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi 100\times5\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi\times 500\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \dfrac{22}{7}\times 500\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \dfrac{11000}{7}\\[/tex]

[tex]\\\\[/tex]

[tex]\dashrightarrow\bf Volume ~of ~Cylinder =\pmb{\blue{1,571.4~cm}}\\[/tex]

[tex]\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc}\small\underline{\sf{\pmb{ \gray{More \: Formulae}}}} \\ \\ \bigstar \: \bold{CSA_{(cylinder)} = 2\pi \: rh}\\ \\\bigstar \: \bold{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bold{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bold{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar\: \bold{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bold{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bold{Volume_{(cube)} ={(side)}^{3} }\\ \\ \bigstar \: \bold{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bold{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\\bigstar \: \bold{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bold{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bold{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]

The value of c in the missing triangle is 39

The side c can be found using Pythagoras theorem.

Therefore,

c² = a² + b²

c² = 36² + 15²

c² = 1296 + 225

c = √1521

c = 39

learn more on right triangle here: https://brainly.com/question/278669

If the raffle has 200 tickets total, then about 50 tickets will be in the dining out raffle.

An equation is an expression that shows the relationship between two or more numbers and variables.

From the diagram:

Percentage of dinner out = 65% - 40% = 25%

For 200 total tickets:

Number of dinning out raffle = 25% of 200 = 0.25 * 200 = 50 ticket

If the raffle has 200 tickets total, then about 50 tickets will be in the dining out raffle.

Find out more on equation at: https://brainly.com/question/2972832

Answer:

ok so use the degrees

Step-by-step explanation:

x should be 8 + 17 and then multiply the 110 degrees by 8 + 17

Answer:

x = 6

The marked angle is 110°

Step-by-step explanation:

See how there are 8 angles in this type of image. The angles either are EQUAL, or they ADD UP TO 180°. It's just two numbers for the degrees of these angles. Four of them are the same and the other four are the same.

In your question the 8 + 17x = 110°

Solve.

Subtract 8.

17x = 102

Divide by 17.

x = 6

If your question says find the measure of the angle it is 110°, if you are to find x, then x = 6.

Jfyi, four of these angles are 110°. The other four are 70°.

Answer:

the large boxes weigh 40 pounds and the smaller boxes weigh 30 pounds

Step-by-step explanation:

define variables:

b is the weight of large boxes and s is the weight of small boxes. you can create two equations to represent what you know:

b + s = 70 (the weight of one large box and one small box is 70 pounds)

60b+ 55s = 4050 (the total weight of the 60 large boxes and the 55 small boxes is 4050)

then by making one of the equations equal to a variable, you can use substitution to solve.

s = 70 - b

so 60b + 55s = 4050 now becomes:

60b + 55(70 - b) = 4050, and next you solve for b

60b + 3850 - 55b = 4050

5b = 200

b = 40.

now you know that the large boxes weigh 40 pounds. to solve for the small box weight, you plug in b in either equation. i am going to choose the first once since it's fewer steps

b + s = 70 -> 40 + s = 70

s = 30

and now you know that the smaller boxes weigh 30 pounds.

Answer:

7

Step-by-step explanation:

6 + 7x = 55

7x = 55 - 6

7x = 49

x = 49/7

therefore x = 7

Step-by-step explanation:

just ratio and need to identify which lines are pairs.

Answer:

19 is equal or less than X

Step-by-step explanation:

I know this because wherever the arrow goes, that’s equal to X. We also know that if the dot is colored, that means it equals: 19 is equal or less than X.

Answer:

adg

Step-by-step explanation:

adg is the range for the side lengths AB of ABC

Hope it's help

Answer:

B

Step-by-step explanation:

The height of 3 cut the base in half and perpendicular to the base, so

[tex]x = \sqrt{(4/2)^2 + 3^2}= \sqrt{13|[/tex]

That is B

Answer:

f(x)= -5x+1 and g(x)=x^3,

(g • f)(0)=  g(f(0))

but f(0) = -5 (0)+1 = 1

(g • f)(0)= g(1) = 1^3 = 1

Step-by-step explanation:

hope this helps

Answer:

-1

Step-by-step explanation:

f(x) = 5x - 1

g(x) = x³

f(0) = 5(0) - 1

= -1

g(-1) = (-1)³

= -1

Answer:

5.step 1

26=y+x

y=x

26=x+x

26=2x

then x=13

6.substitute y with the given equation equal to y the equate them with the first one and collect like terms the find x

Answer:

Not sure if this is right but it might be something like

350,000-4%+1671m

or

3500,000-4%y/1671m

Step-by-step explanation:

The numbers we know are 350,000 4% and 1671 per month

350,000 is the full mortgage

4% is the APR or annual percentage rate like interest

and we know the monthly for the mortgage is 1671 per month

Answer:

%70.83

Step-by-step explanation:

91.66 + 50 = 141.66

141.66÷2=70.83

Answer:

its C 40

Step-by-step explanation:

Answer:

5/9 = 25/45

Step-by-step explanation

multiply 5/9 by 5/5 this will turn it into 25/45

5x5=25

5x9=45

Answer:

14

Step-by-step explanation:

Relative Frequency =  [tex]\frac{Frequency*100}{Total Frequency}[/tex]

Frequency for the class with lower class is 23 =7

Total Frequency= 7+7+7+9+9+9+2=50

Relative Frequency =  [tex]\frac{7*100}{50}[/tex] = 14

The relative frequency for lower class limit 23 is 14

Answer:

B

Step-by-step explanation:

logₓ 7 = 3

x³ = 7

Take cube root both sides

[tex]x= \sqrt[3]{7}[/tex]

Answer:

±4i, ±3

p(x) = A(x - 4i)(x + 4i)(x - 3)(x + 3), with A = 1.

Step-by-step explanation:

±4i, ±3

p(x) = A(x - 4i)(x + 4i)(x - 3)(x + 3), with A = 1.

Answer:

No

Step-by-step explanation:

1 yard = 3 feet, so 3 yards = 9 feet

Hope this helps :)

Step-by-step explanation:

154 is my answer thank you

Answer: 4/6 = 2/32/3 = 2/3

Step-by-step explanation: hope this help

Answer:

Range is [tex]\{y|y\neq 1\}[/tex]

Step-by-step explanation:

[tex]f(x)=x+1\\g(x)=\frac{1}{x}\\ \\(f\circ g)(x)=f(g(x))=f(\frac{1}{x})=\frac{1}{x}+1[/tex]

Thus, the range of the composite function is [tex]\{y|y\neq 1\}[/tex], indicated by the horizontal asymptote.