____ is the amount of matter an object and the mass of an _____ does not change location.​

Answers

Answer 1

Answer:

Mass

Object

Explanation:

Answer 2

Answer:

Mass is the amount of matter in an object and the mass of an object does not change location.


Related Questions

In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- vestigated occurs when the external field Bext has magnitude 0.78 T. Assume that Bint and Bext are in the same direction and take the pro- ton magnetic moment component u, to be 1.41 X 10-26 J/T. What is the magnitude of Bint?

Answers

Answer:

[tex]B_{int}=-0.015T[/tex]

Explanation:

From the question we are told that:

RF source oscillation speed [tex]\sigma= 34 MHz[/tex]

The external field [tex]Bext =0.78 T[/tex].

Pro- ton magnetic moment component [tex]\mu=1.41 X 10-26 J/T[/tex]

Generally the equation for magnitude of [tex]B_{int}[/tex] is mathematically given by

[tex]B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}[/tex]

[tex]B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}[/tex]

[tex]B_{int}=0.78-0.7957[/tex]

[tex]B_{int}=-0.015T[/tex]

helpppppppppppppppppppppppppppp............



an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.​

Answers

Answer:

0.5 m/s 2 is the acceleration

Explanation:

hope it helped!!!

What is the difference between center of mass and center of gravity?

Answers

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field.

Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

hope this helps you ☺️☺️

Which of these properties of light is a constant?
speed in a vacuum
amplitude
wavelength
frequency

Answers

Answer:

speed in vacuum

Explanation:

lets say we are in an empty universe and you are moving 10% the speed of light you wont slow down or speed up.

Infrared radiation from young stars can pass through the heavy dust clouds surrounding them, allowing astronomers here on Earth to study the earliest stages of star formation, before a star begins to emit visible light. Suppose an infrared telescope is tuned to detect infrared radiation with a frequency of 1.61THz. Calculate the wavelength of the infrared radiation. Round your answer to 3 significant digits.

Answers

Answer:

λ = 1.86 x 10⁻⁴ m = 186 μm

Explanation:

The relationship between the wavelength and the frequency of a wave is given by the following equation:

[tex]c = f\lambda\\\\\lambda = \frac{c}{f}[/tex]

where,

λ = wavelength of infrared radiation = ?

c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s

f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz

Therefore,

[tex]\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}[/tex]

λ = 1.86 x 10⁻⁴ m = 186 μm

Two window washers, Bob and Joe, are on a 3.00 m long, 395 N scaffold supported by two cables attached to its ends. Bob weighs 805 N and stands 1.00 m from the left end. Two meters from the left end is the 500 N washing equipment. Joe is 0.500 m from the right end and weighs 820 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable

Answers

Answer:

- the forces on the left hand side is 1.038 kN

- the forces on the right hand side is 1.483 kN

Explanation:

Given the data in the question, as illustrated in the image below;

Length of the scaffold = 3 m

weight of the scaffold = 395 N

Weight of Bob = 805 N and stands 1 m from the left end

weight of washing equipment = 500N and on sits 2 m from the left end

Weight of Joe = 820 N and stand 0.500 m from the right end

so the force on the left cable will be;

[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ (805 N)( (3-1) m) + ( 395 N )( [tex]\frac{3}{2} m[/tex]) + ( 500 N )(1m ) + ( 820 N)( 0.500m ) ]

[tex]T_{left[/tex] =  [tex]\frac{1}{3m}[/tex][ 1610 + 592.5 + 500 + 410 ]

[tex]T_{left[/tex] =  [tex]\frac{1}{3m}[/tex][ 3112.5 ]

[tex]T_{left[/tex] =  1037.5 N

[tex]T_{left[/tex] =  1.038 kN

Therefore, the forces on the left hand side is 1.038 kN

On the right hand side;

[tex]T_{Right[/tex] =  ( 805 N + 395 N + 500 N + 820 N ) - 1037.5 N

[tex]T_{Right[/tex] =  2520 N - 1037.5 N

[tex]T_{Right[/tex] =  1482.5 N

[tex]T_{Right[/tex] =  1.483 kN

Therefore, the forces on the right hand side is 1.483 kN

what happen when you take off your clothes very quickly​

Answers

Answer:

Nothing

Explain

Nothing happenes when you take off your cloths quickly.

Scientificly nothing really happnes.

Types of telescope
for Space
observation​

Answers

Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.

Answer:

oii me manda mensagem fofo vc tem namorada fofo

Can someone make a list of 10 simple things people can do to maintain fitness ? Or don’t list a lot

Answers

Answer:

1. sleep well

2. drink water

3. eat healthy

4. less sugar and salt

5. exercise 30 minutes daily

6. eat whole grains

7. eat fruits and vegetables

8. practice mental health

9. stay motivated

10. eat a variety of foods

According to Lenz's law, the current is induced in the closed conducting loop in such a direction that the magnetic field induced by this current opposes the change in the flux through the loop.

a. True
b. False

Answers

Answer:

True

Explanation:

It is true that the real definition of lenz's law in magnetism is the current is induced in the closed conducting loop in such a direction that the magnetic field induced by this current opposes the change in the flux through the loop.

This means that induced current opposes the very cause that produces it.

Another word for kinetic energy
could be
energy.
A. Safe
B. Moving
C. Stored
D. Potential

Answers

Answer:

moving

Explanation:

hope it helped!!!

Answer:

B

Explanation:

please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING

Answers

Number 7 is no motion


A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is
the KE of the student at the bottom of the slide?

Answers

Answer:

https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html

Explanation:

Two vectors have magnitudes 3 and 4 . how are the directions of the two vectors related if: a/the sum has magnitude 7.0 ​

Answers

Same directions
Perpendicular
Opposite directions

Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.

A) 117°


B) 88.1°


C) 26.6°


D) 30.0°


E) 45.2°

Answers

Answer:

C) 26.6

Explanation:

I don't know how to calculate vector

The angle between the two vectors is 117⁰

The given parameters;

vector A = 3.00i + 1.00j

vector B = -3.00i + 3.00j

The  angle between the two vectors is calculated as follows;

[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]

The dot product of vector A and B is calculated as;

[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]

The magnitude of vector A and B is calculated as;

[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]

The  angle between the two vectors is calculated as;

[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]

Thus, the angle between the two vectors is 117⁰

Learn more here: https://brainly.com/question/15006306

One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) technique. As corn photosynthesizes, it concentrates the isotope carbon-13, whereas most other plants concentrate carbon-12. Overreliance on corn consumption can then be correlated with certain diseases, because corn lacks the essential amino acid lysine. Archaeologists use a mass spectrometer to separate the 12 C and 13 C isotopes in samples of human remains. Suppose you use a velocity selector to obtain singly ionized (missing one electron) atoms of speed 8.50 km/s, and you want to bend them within a uniform magnetic field in a semicircle of diameter 25.0 cm for the 12 C. The measured masses of these isotopes are 1.99×10−26kg(12C) and 2.16×10−26kg(13C).
(a) What strength of magnetic field is required?
(b) What is the diameter of the 13 C semicircle?
(c) What is the separation of the 12 C and 13 C ions at the detector at the end of the semicircle? Is this distance large enough to be easily observed?

Answers

Answer:

[tex]0.0084575\ \text{T}[/tex]

[tex]0.272\ \text{m}[/tex]

2.2 cm easily observable

Explanation:

[tex]m_1[/tex] = Mass of 12 C = [tex]1.99\times 10^{-26}\ \text{kg}[/tex]

[tex]m_2[/tex] = Mass of 13 C = [tex]2.16\times 10^{-26}\ \text{kg}[/tex]

[tex]r_1[/tex] = Radius of 12 C = [tex]\dfrac{25}{2}=12.5\ \text{cm}[/tex]

B = Magnetic field

v = Velocity of atom = 8.5 km/s

[tex]r_2[/tex] = Radius of 13 C

The force balance of the system is

[tex]qvB=\dfrac{m_1v^2}{r}\\\Rightarrow B=\dfrac{m_1v}{rq}\\\Rightarrow B=\dfrac{1.99\times 10^{-26}\times 8500}{12.5\times 10^{-2}\times 1.6\times 10^{-19}}\\\Rightarrow B=0.0084575\ \text{T}[/tex]

The required magnetic field is [tex]0.0084575\ \text{T}[/tex]

Radius is given by

[tex]r=\dfrac{mv}{qB}[/tex]

[tex]r\propto m[/tex]

So

[tex]\dfrac{r_2}{r_1}=\dfrac{m_2}{m_1}\\\Rightarrow r_2=\dfrac{m_2}{m_1}r_1\\\Rightarrow r_2=\dfrac{2.16\times 10^{-26}}{1.99\times 10^{-26}}\times 12.5\times 10^{-2}\\\Rightarrow r_2=0.136\ \text{m}[/tex]

The required diameter is [tex]2\times 0.136=0.272\ \text{m}[/tex]

Separation is given by

[tex]2(r_2-r_1)=2(0.136-0.125)=0.022\ \text{m}[/tex]

The distance of separation is 2.2 cm which is easily observable.

Which type of diffraction occurs when the point source and the screen are at finite distances from the obstacle forming the diffraction pattern?
A. fraunhofer
B. fresnel
C. far-field
D. single slit

Answers

Fresnel diffraction

What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?
0 1 = 0.01 A
0 1 = 0.8 A
0 1 = 80 A
O I = 0.08 A

Answers

Answer:

80 A

Explanation:

Hi there!

Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I

[tex]V=IR\\0.8=I(0.01)[/tex]

Divide both sides by  0.01 to isolate I

[tex]0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I[/tex]

Therefore, the current for this circuit would be 80 A.

I hope this helps!

A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.

Answers

Answer:

The thickness of the oil slick. t = 173.91 nm

Explanation:

Oil film thickness t is given by the equation

[tex]t = \frac{\lambda}{2n}[/tex]

where λ = wavelength of incident light in air = 400 nm

and n = index of refraction of oil

therefore,

[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]

The thickness of the oil slick. t = 173.91 nm

please answer this im not sure

Answers

Answer:

the answer is B

The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.

Calculate the decay constant of the radioisotope.​

Answers

Answer: [tex]0.0353\ s^{-1}[/tex]

Explanation:

Given

Radioactive material is found to decrease 40% of its original value in [tex]2.59\times 10\ s[/tex]

Sample at any time is given by

[tex]N=N_oe^{-\lambda t}[/tex]

where, [tex]\lambda=\text{decay constant}[/tex]

Put values

[tex]\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10[/tex]

Taking natural logarithm both side

[tex]\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}[/tex]

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