The standard for chromium VI in a sample is 0.1 milligrams per liter (mg/l) or 100 parts per billion (ppb).
What is EPA?EPA is an acronym that stands for Environmental Protection Agency. The major concern of the agency is to ensure that the level of contaminants released into the environment does not exceed the set standards.
The standard for chromium VI in a sample is 0.1 milligrams per liter (mg/l) or 100 parts per billion (ppb), Since the question is incomplete, we can't ascertain if the chromium (VI) concentration exceeds this standard.
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on food webs can i get some help with that
Compare and contrast an endothermic and exothermic process.
Answer:
An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.”
Explanation:
hope this helps
i did this for hw
what does taking a neutral position about an issue mean?
It means to not favor either side of an argument, even if you believe one side may be right.
If you combine 390.0 mL of water at 25.00 ∘C and 100.0 mL of water at 95.00 ∘C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.
heat water 1 = heat water 2
mass of water = density x volume
because density = 1 g/ml then:
mass water 1 = 100 g
mass water 2= 390 g
Input the equation:
mcΔt 1 = mcΔt 2
100 . c . (95 - T) = 390 . c . (T - 25)
9500 - 100T = 390T - 9750
9500+9750 = 390T+100T
19250=490T
T=39.29 °C
Why was there a large increase in the human population after the Industrial Revolution?
Question 1 options:
advancements in science
improvements in nutrition
advancements in medicine
all of the above
Answer: improvements in nutrition
Explanation:
Answer:Look at the graph above. Human population increased dramatically at certain times. The graph begins 10,000 BC, although you can't really see the line. Population starts to rise perceptibly at around 1800 BC. The numbers begin to rise dramatically about 200 years ago. What causes these changes
Explanation:
Calculate the solubility (in g / L) of a generic salt with a formula of A2B, a Ksp of 4.30 × 10−11 and a molar mass of 274 g / mol.
With a Ksp of 4.30*10−11 and a molar mass of 274 g / mol the solubility (in g / L) of the generic salt is mathematically given as
S=0.0604g/l
What is the solubility (in g / L) of the generic salt?Generally, the Ksp is mathematically given as
Ksp=4s^3
Therefore
s=(\frac{4.30 × 10−11}{4})^{1/3}
s=2.207×10^{−4]
In conclusion, solubility is
S=2.207×10^{−4]*274
S=0.0604g/l
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PLEASE HELP!
If 0.00516 mols of HC2H302 are reacted with 0.00585 mols of NaHCO3, which is the limiting reactant?
Show your work.
NaHCO3(s) + HC2H302(aq) → C2H302Na(aq) +H2CO3(aq) H2CO3(aq) - H2O(1) +CO2(g)
Look at the reaction
More than 1mol of HC2H3O2 is required so the mols will be doubled atleast
0.00516(2)=0.01032molNow
NaHCO_3 is less
So Sodium bicarbonate is the limiting reagentIn the given query, the limiting reagent in provided chemical reaction is: [tex]\rm NaHCO_3(s) + HC_2H_3O_2(aq) \rightarrow C_2H_3O_2Na(aq) +H_2CO_3(aq)+ H_2O(l) +CO_2(g)[/tex] is [tex]\rm HC_2H_3O_2[/tex].
In a reaction, limiting reagent is a chemical substance that is completed used or is totally consumed resulting into limiting the formation of further products.
In the provided reaction:
[tex]\rm NaHCO_3(s) + HC_2H_3O_2(aq) \rightarrow C_2H_3O_2Na(aq) +H_2CO_3(aq)+ H_2O(l) +CO_2(g)[/tex]
Given: 0.00516 mol [tex]\rm HC_2H_3O_2[/tex] and 0.00585 mol [tex]\rm NaHCO_3[/tex].
Using balanced equation, the stoichiometric ratio of [tex]\rm HC_2H_3O_2[/tex] to [tex]\rm NaHCO_3[/tex] is 1:1. Meaning that, for every 1 mole of [tex]\rm HC_2H_3O_2[/tex], we need 1 mole of [tex]\rm NaHCO_3[/tex].
Therefore, the number of moles of [tex]\rm NaHCO_3[/tex] needed to react with 0.00516 mol of [tex]\rm HC_2H_3O_2[/tex] is:
0.00516 mol [tex]\rm HC_2H_3O_2[/tex] × (1 mol [tex]\rm NaHCO_3[/tex]/ 1 mol [tex]\rm HC_2H_3O_2[/tex])
= 0.00516 mol [tex]\rm NaHCO_3[/tex].
Since we have 0.00585 mol of [tex]\rm NaHCO_3[/tex], which is greater than the amount needed (0.00516 mol), [tex]\rm NaHCO_3[/tex] is not the limiting reactant.
Calculate the number of moles of [tex]\rm HC_2H_3O_2[/tex]needed to react with 0.00585 mol of [tex]\rm NaHCO_3[/tex]:
0.00585 mol [tex]\rm NaHCO_3[/tex] × (1 mol [tex]\rm HC_2H_3O_2[/tex]/ 1 mol [tex]\rm NaHCO_3[/tex]) = 0.00585 mol [tex]\rm HC_2H_3O_2[/tex]
As we see, only 0.00516 mol of [tex]\rm HC_2H_3O_2[/tex] are present, which is less than the amount needed (0.00585 mol), [tex]\rm HC_2H_3O_2[/tex] is the limiting reactant.
Therefore, [tex]\rm HC_2H_3O_2[/tex]is the limiting reactant in the provided chemical reaction.
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"A certain group one metal combines with Hydrogen, to form a molecule with the formula XH. The equilibrium bond length of this compound is 1.5957 Å. If this molecule exhibits a pure rotational spectrum with a rotational constant of 7.5131cm−1, calculate the molecular weight of metal X."
I thought that you would use a mix of the reduced mass and rotational constant formulas to get:
[tex]1.66e-27(\frac{(m1)(m2)}{m1+m2})=\frac{h/2\pi}{4\pi Bcr^{2} }[/tex]
However, that just gives a negative answer, and mass cannot be negative. I am confused and would appreciate any help
Based on the bond length, the molecular weight of the unknown metal X is 23.
What are ionic compounds?Ionic compounds are compounds which are formed between oppositely charged ions.
When hydrogen combines with the group 1 metals, they form ionic compounds.
The group one metals that combine with hydrogen to firm ionic bonds include:
Lithium to give Lithium hydride with equilibrium bond length of 0.239Å. Sodium to give sodium hydride with equilibrium bond length of 1.896Å.Potassium to give potassium hydride with equilibrium bond length of 2.321ÅThe molecular weight of lithium is 7 g
The molecularweight of sodium is 23
The molecular weight of Potassium is 39.
Therefore, based on the equilibrium bond length, the molecular weight of the unknown metal X is 23.
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How many grams of NH3 can be produced from 12.0g of H2?
Answer:
Balanced reaction:
3 H2 (g) + N2 (g) → 2 NH3 (g)
Use stoichiometry to convert g of H2 to g of NH3. The process would be:
g H2 → mol H2 → mol NH3 → g NH3
12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3
Explanation: See above
Hope this helps, friend.
Typically the role of the “masses” – the town’s people in this case – serve largely as an antagonist in a story. Either they initiate trouble or they latch on and carry it along. Analyze the characterization/role of the town’s people in the story and how they affect the outcome of the story
Answer:
i believe its the role of the antagonist
Explanation:
A constantly changing and developing resume means that you are always _______________ as a person and potential employee. A. changing and developing B. failing C. succeeding D. remaining the same
a. How many moles of CO2 are produced in 19.63 grams of CO2?
Answer:
0.44604005953260284 moles
Explanation:
or you could round it to 0.446 moles
mol CO₂ = mass : molar mass CO₂
mol CO₂ = 19.63 : 44 g/mol = 0.446
Consider this reaction:
Li3N (s) + 3H2O (l)→NH3 (g) + 3LiOH (l)
You need to make 24 g LiOH.
How many grams of Li3N must you react with excess water?
5.8 g
11.7 g
35.0 g
70.0 g
Please help!
How many grams of H_{2}*O can be produced from the reaction of 100. g of C_{3}*H_{8}
Answer: 163.6g H2O
Explanation:
The balanced chemical equation for the combustion of propane is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
This means 1 molecule of C3H8 react with 5 molecules of O2 to produce 3 molecules of CO2 and 4 molecules of H2O.
Molar mass C3H8 = 44 g/mol
According to the stochiometric coefficients 1 mol C3H8 will form 4H2O
100g C3H8 to mol = 100 g / 44 g/mol = 2.273 mol
This will produce 2.273*4 H2O = 9.09 mol H2O
Molar mass H2O = 18 g/mol
Mass of 9.09 mol H2O = 9.09 mol * 18 g/mol = 163.6 g H2O
Therefore, 163.6g of H2O will be formed from the combustion of 100g of C3H8
When an ACID ionizes in water, the number of hydronium ions in the solution _____ and the value of the pH _?
decreases; increases
decreases; decreases
remains the same; cannot be predicted
increases; decreases
increases; increases
How many moles are in 59.6 grams of BaSO4
Answer:
0.2553669915026199 BaSO4
Explanation:
hi, give brainliest?
Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 78.8g of carbon dioxide is produced from the reaction of 83.39g of octane and 122.6g of oxygen gas, calculate the percent yield of carbon dioxide.
Answer:
get it back to me by tomorrow
Explanation:
I am currently in life generally but will be perfect
What is technology?
the process of designing and making tools
any device that contains electronic parts
the use of knowledge to solve practical problems
the study of the natural world
90 points
Answer:
Any device that contains electronic parts
I need help with Chemistry: Mole Conversion
It must be answered in complete detail
Answer:
As Per Given Information
Number of moles SO₂ ( Sulphur dioxide ) is 0.30
We 've been asked to find the number of atoms in given moles of Sulphur dioxide .
Value of Avogadro Number is 6.022 × 10²³ mol⁻¹
For finding the number of atoms we will use formale
[tex]\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \: = Given \: moles \: . Avogadro \: number}}}}[/tex]
Putting the given value we obtain
[tex] \sf \twoheadrightarrow \: Number \: of \: atoms \: = 0.30 \times 6.022 \times {10}^{ 23} \\ \\ \sf \twoheadrightarrow \: Number \: of \: atoms \: = \: 1.8066 \times {10}^{ 23} atoms[/tex]
So, the number of atoms in sulphur dioxide is 1.8066 × 10²³
No of atoms
No of moles ×Avagadro no0.3×6.023×10²³1.8066×10²³atoms(b) What will be the change in pH of the buffer of 7 if 5 mL of 5 N NaOH is added
to 1000 mL of the buffer?
What factors mechanical weathering ?.
Earth Science.
Answer:
-Growth of plants on the rock.
-Temperature and pressure changes in nature.
-Freezing and thawing of water in cracks of the rock.
-Formation of salt crystals within the rock.
-Burrowing by animals.
those are some factors I know
hope this helped you
A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2. What is (i) the molar mass of the element
The molar mass of the element M is mathematically given as
M=91.927g/mol
What is the molar mass of the element M?Question Parameters:
A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2.
Generally, the equation for the Chemical Reaction is mathematically given as
3M+N2=M3N2
Therefore
moles of N2 is given as
[tex]m=\frac{mass of N2}{molar mass}[/tex]
Where
mass of N2=43.5-35.3
mass of N2=8.2
Therefore
[tex]m=\frac{8.2}{32}[/tex]
m=0.25625mole
Since 2 moles of N2 reacts with 3mols of M
Hence, 0.25625 mole of N2 reacts with 3mole of M
x=3/2*0.256
x=0.384mol
In conclusion, the molar mass of M
[tex]M=\frac{mass of x}{moles of x}\\\\M=\frac{35.3}{0.384}[/tex]
M=91.927g/mol
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How many truck stop by the store on Wednesday
Answer:
More information so I can answer please.
Explanation:
Answer the following questions on your answer sheets to summarize what you have learned from this module: 1. What is the measure of the sum of the interior angles of a convex polygon with n sides? 2. What is the measure of the sum of the angles of a convex quadrilateral? A pentagon? A nonagon? 3. What is the measure of an interior angle of a regular polygon with n sides? 4. What is the measure of an interior angle of a regular octagon? 5. What is the sum of the measure of the exterior angles, one at each vertex of a convex polygon? You are now going to take the post-assessment to see how much you have learned about the topics. Write the letter of the correct answer on your answer sheets.whit it's part of your website is subject your company is looking to buy the tickets to buy the graphs for your website on top and a ate the tickets for your website on each event time position requires that you enjoyed each of these emails from this list update me with u part time job and even if the tickets email from your website is for your time job your friend in real estate request email from your ee
The measure of the sum of the interior angles of a convex polygon with n sides is given by [tex]S=(n-2)180[/tex]
What is a polygon?A polygon can be defined as a two-dimensional geometric figure that consists of straight line segments and finite number of sides.
What is a quadrilateral?A quadrilateral can be defined as a type of polygon that is made up of four (4) sides, four (4) vertices, four (4) edges and four (4) angles.
Mathematically, the measure of the sum of the interior angles of a convex polygon with n sides is given by:
[tex]S=(n-2)180[/tex]
In Geometry, the measure of the sum of the angles of a convex quadrilateral, pentagon, and a nonagon is equal to 360 degrees.
For a regular polygon:
Mathematically, the measure of an interior angle with n sides is given by;
[tex]A=(2n-4)90[/tex]
For a regular octagon:
Mathematically, the measure of an interior angle is equal to 135 degrees.
Lastly, the sum of the measure of the exterior angles, one at each vertex of a convex polygon is equal to 360 degrees.
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If there are 1652 kJ of bond energy in methane, how much energy is there in a single Carbon - Hydrogen bond?
The energy in a single Carbon - Hydrogen (C-H) bond of methane is 413 kJ
Bond energyFrom the question, we are to determine the Carbon - Hydrogen bond energy in methane
From the given information,
The total bond energy in a molecule of methane is 1652 kJ
C-H bond energy = [tex]\frac{Total\ bond\ energy\ in\ methane}{number\ of \ C-H \ bonds}[/tex]
Number of C-H bonds in methane = 4
Therefore,
C-H bond energy = [tex]\frac{1652}{4}[/tex]
C-H bond energy = 413 kJ
Hence, the energy in a single Carbon - Hydrogen (C-H) bond of methane is 413 kJ
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List the following alcohols in the order of increasing boiling points (BP). A)
glycerol, B) ethylene glycol, C) n-hexyl alcohol, D) n-propyl alcohol, E)
isopropyl alcohol, F) n-butyl alcohol (Hint: You don't need to look up the BP
values, since the order can be predicted from the structures.)
*
A. ABDEFC
B. BADEFC
C. DEFCBA
D. ABCFED
E. EDFCBA
Answer:
A.
Explanation:
because it is the only logical answer
What is the coefficient for O2SF2 once the reaction is balanced
Answer:
3
Explanation:
Important concept! The little number after an element represents the number of atoms in the substance. Eg. SF6. The 6 after the F tell us that there are 6 atoms of Fluorine in SF6. The coefficient or big number before a substance tells us how many of that substance there is in the equation. TO find the number of atoms in a substance with a coefficient we simply multiply the coefficient by the subscript or small number. Eg. 4SF6. The number of fluorine atoms in 4SF6 can be found my multiplying 4 and 6. 4 * 6 = 24 so there are 24 atoms of fluorine in 4SF6
Balancing the equation!
First lets list the number of atoms of each element on each side so we can see what we need to balance
SF6 + SO3 --> O2SF2
2 S 1
6 F 2
3 O 2
First lets balance the number of oxygen atoms. We can do this by adding a coefficient of 2 to SO3 and a 3 to O2SF2. After doing so lets count the number of atoms of each element again as some of them may have changed.
SF6 + 2SO3 --> 3O2SF2
3 S 3
6 F 6
6 O 6
It appears that the each element in the reaction is now balanced after adding a 2 to SO3 and a 3 to O2SF2 so the equation is now balanced.
The answer would be 3 as 3 was added to O2SF2 to balance the reaction.
4 Al (s) + 302(8)
-
2Al2O3(s)
How many grams of Al2O3 can be formed from 77.58 g of Al and 33.92 g of O2?
(Hint: You need to determine which one is the limiting reactant).
Explanation 2Al2O3(s)-->4Al(s)+302(g)What is the total number of moles of O2 that are produced when 8.0 mol of Al2O3(s)are totally decomposed ?
i need help with this question
Answer:
the difference between model A and model B is the fact that model A has more atoms in it, and they are smaller and all the same type while model B has less atoms, they are bigger and there are different types of atoms.
Explanation:
mr clean
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[tex]\Large \text{1)}[/tex]
[tex]\textbf{Use the formula and substitute the values}[/tex]
[tex]\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}[/tex]
[tex]\textbf{Solve for the number of moles}[/tex]
[tex]n = 0.003\ mol[/tex]
[tex]\textbf{Calculate final volume }[/tex]
[tex]40+10=50\ mL[/tex]
[tex]\textbf{Number of moles remains same. Solve for concentration}[/tex]
[tex]\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L[/tex]
[tex]\Large \text{2)}[/tex]
[tex]\displaystyle DF=\frac{V_f}{V_i}[/tex]
[tex]\displaystyle DF=\frac{50}{10}=5[/tex]