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The interpret of P(0) is 0 and P(250) = 132.58. The domain of P is [0, ∞]

The population of Sasquatch in Portage County can be modeled by the function P(t) = 140t/(t + 14) where t represents the number of years since 1803.

We have to interpret P(0).

To interpret P(0) we put t = 0 in the function then solve the function.

The function is:

P(t) = 140t/(t + 14)

Putting t = 0

P(0) = (140 × 0)/(0 + 14)

P(0) = 0/14

P(0) = 0

Now we interpret P(250) by putting t = 250.

P(250) = (140 × 250)/(250 + 14)

P(250) = 35,000/264

P(250) = 132.58

The domain of the time cannot be negative. So the domain of P is [0, ∞].

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The complete question is:

The population of Sasquatch in Portage County can be modeled by the function P(t) = 140t/(t + 14) where t represents the number of years since 1803. Find and interpret P(0) and P(250). Discuss with your classmates what the applied domain and range of P should be.

From the graph, it looks like the tangent line at 20 minutes has a slope that is close to 0.55°C/minute. So, the estimate of the rate of change of the temperature of the cookies after 20 minutes is approximately 0.55°C/minute.

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Answer:

The dimensions are 3, 4 and 5 inches.

Step-by-step explanation:

Area = 1/2 * height * base

6 = 1/2 * h * b

h * b = 12.

As the hypotenuse is 5 inches long

H^2 + B^2 = 5^2

From the third line: h = 12/b, so we have
(12/b)^2 + b^2 = 25

144/b^2 + b^2 = 25

144 + b^4 = 25b^2

b^4 - 25b^2 + 144 = 0

Let B = b^2, so

B^2 - 25B + 144 = 0

(B - 16)(B - 9) = 0

B = 16, 9

So, b = 4, 3

h = 12/b

= 3 , 4.

The inequality that represents the minimum number of points he must score on the remaining tests in order to get an A is 320 + n ≥ 389, n ≥ 69, where n is the number of points.

When we use ≥ symbol, as at least means greater than or equal to.

320 + n ≥ 389

Subtracting 320 on both the sides,

n ≥ 69,

n represents the score he must receive on the remaining tests. Then n + 320 represents his total score for the semester.

Thus, the required inequality is n ≥ 69, which means that n is the minimum scored points to get A.

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The scale factor that takes quadrilateral T to quadrilateral U would be = 1.6

A scale factor is defined as the factor that is used to creat a similar shape of an object with a different dimension.

The formula that is used for the new object = original object × scale factor

The original object = quadrilateral T

The new object = quadrilateral U.

The scale factor the was used to form U using the length of the quadrilateral as 16;

16 = 10 * Scale factor

This gives

Scale factor = 16/10

Scale factor = 1.6

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The are of shade part of semi-circle is 75.36 cm^2.

What is a circle?

A circle is a special kind of ellipse in which the eccentricity is zero and the two foci are coincident. A circle is also termed as the locus of the points drawn at an equidistant from the center. The distance from the center of the circle to the outer line is its radius. Diameter is the line which divides the circle into two equal parts and is also equal to twice of the radius.

The equation of circle in the plane is given as:

(x-h)^2 + (y-k)^2 = r^2

where (x, y) are the coordinate points

(h, k) is the coordinate of the center of a circle

and r is the radius of a circle.

and Area of circle = πr²

Now,

Area of the shaded region=area of large semicircle-2*area of small semicircles

radius for large semicircle=7cm

radius for small semicircle=3.5cm

Therefore,

         Area of the shaded region=πR^2-2*πr^2

                                        =3.14(7^2-2*3.5^2)

                                         =3.14*(49-25)

                                         =3.14*24

                    Area of the shaded region =75.36 cm^2

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The trapezoid abcd median is 16 lengths long.

Regarding the query,

Considering that,

The trapezoid's area is equal to 80,

The trapezoid abcd is 5 inches tall.

Let a be the base of the trapezoid abcd.

So, b = a + 12 ,

In the formula Area of the trapezoid = A =(a+b)h/2, the value is substituted.

(a + a + 12)5/2 = 80

(2a + 12)5 = 160

2a + 12 = 160/5

2a + 12 = 32

2a =32 - 12

2a = 20

a = 20/2

a = 10 units

additional base is 10 + 12 = 22 units.

Therefore, the median's length will be equal to (10 + 22)/2.

= 32/2 = 16 units

As a result, the median's length is 16.

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Answer:The term glycol does not indicate a lack of glucose.

Step-by-step explanation:The term glycol does not indicate a lack of glucose, it refers to a specific class of organic compounds which are characterized by having two hydroxyl groups (-OH) on adjacent carbon atoms. Common examples include ethylene glycol and propylene glycol which are used in a variety of industrial and commercial applications such as antifreeze, coolants, and solvents.

Answer:

Glycopenia

Step-by-step explanation:

This is where the body lacks or shortage of glucose in the body which is properly needed.

Given that the reflex angle at G is x degrees, then x is equal to

A reflex angle is a type whose value falls within 180^o and 360^o. This implies that the value of the angle is greater than 180^o, but less than 360^o.

Considering the reflex angle given in the question, it can be deduced that;

m<AGE + m<GAE + m<GEA = 180^o

But,

i. m<GAB + m<GAE = 180^o    (sum of angles on a straight line)

120 + m<GAE = 180

m<GAE = 180 - 120

             = 60

m<GAE = 60^o

ii. m<GEA + m<GEL = 180^o

  m<GEA + 80 = 180

m<GEA = 180 - 80

             = 100

m<GEA = 100^o

Thus,

m<AGE + m<GAE + m<GEA = 180^o

m<AGE + 100 + 60 = 180

m<AGE = 180 - 160

            = 20

m<AGE = 20^o

Therefore,

x + m<AGE = 360  (sum of angles at a point)

x + 20 = 360

x = 360 - 20

  = 340

x = 340^o

x is equal to 340^o.

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Answer:

see explanation

Step-by-step explanation:

a translation [tex]T_{(-5,-4)}[/tex]

means subtract 5 from the original x- coordinate and subtract 4 from the original y- coordinate.

A (2, - 1 ) → A' (2 - 5, - 1 - 4 ) → A' (- 3, - 5 )

B (- 4, - 2 ) → B' (- 4 - 5, - 2 - 4 ) → B' (- 9, - 6 )

C (3, 2 ) → C' (3 - 5, 2 - 4 ) → C' (- 2, - 2 )

Sammy obtained a convenient sample.

The sampling method is biased because the students in the statistics class are not representative of the entire high school population. The sample only includes the students in one particular class and does not account for the experiences or characteristics of other students in the school.

68% is likely to be greater than the percent of all students at the high school who have a driver's license.

To avoid the bias, Sammy could use a more representative sample, such as a simple random sample or a stratified sample, to ensure that the sample includes a diverse group of students from various backgrounds, classes, and demographics. This would give a more accurate representation of the experiences and characteristics of the entire high school population.

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Answer: The doubling period is the time it takes for the population of bacteria to double. To find the doubling period in this case, we need to determine how often the population doubles during the 3-minute period.

We know that the initial population is 50 and the final population is 204800, which means that the population has grown by a factor of 204800/50 = 4096. Since this is a multiplication by a factor of 4096, this means that the population has doubled 4096 times in 3 minutes.

To find the doubling period, we need to divide the total time (3 minutes) by the number of doublings (4096).

So, the doubling period is:

3 minutes / 4096 = 3/4096 minutes ≈ 0.0007 minutes ≈ 0.042 seconds

So, the population of bacteria doubles every 0.042 seconds

Step-by-step explanation:

Answer: 19.56z - 9

Step-by-step explanation: Hello!  Here are the steps to solve this problem:

14.33z - 3 - (6 - 5.23z).  

Firstly, you have to use the distributive property and distribute -1 to the parentheses using PEMDAS, Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.

14.33z - 3 + -1(6 - 5.23z)
14.33z - 3 + (-6 + 5.23z)
14.33z + (-3) + (-6) + (5.23z)
14.33z + (5.23z) + (-3) + (-6)
(14.33z + 5.23z) + (-3 - 6)
19.56z + (-3 - 6)

19.56z + (-9)
19.56z - 9.

The time that it took to complete the race is the time it took for them to stop at the same position, hence it is of 16 hours.

For the Blue turtle, we have that:

The velocity is given by the change in position divided by the change in time, hence:

v = (10 - 10)/(13 - 6)

v = 0.

The red turtle maintained a consistent speed through the entire race, as the slope of her line is constant.

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Answer: A monomial is a polynomial with only one term. So 9p^3 and 4p are monomials.

9p^3 is a monomial with coefficient 9 and exponent 3 in the variable p.

4p is a monomial with coefficient 4 and exponent 1 in the variable p.

Step-by-step explanation:

The total area of the figure is 14.35 square inches

The six-sided figure is not given, however we can deduce the following parameters from the question:

The shape is made of a triangle and a trapezoid

The side lengths derived from the question are:

The triangle on top:

base: 4 inches and height: 2.3 inches

The trapezoid at the bottom:

Parallel sides: 2.5 inches and 4 inches with a height of 3 inches

So, we have the total area of the figure to be

Area of figure = 1/2 * 4 * 2.3 + 1/2 * (2.5 + 4) * 3

Area of figure = 14.35

Hence, the total area is 14.35 square inches

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Answer:

Step-by-step explanation:

dddcdcdcdc its d

Answer: its d

Step-by-step explanation:

Answer:

The answer is C:

y = -x + 2

add brainliest please.

Answer:

y- intercept = 12, x- intercept = 4

Step-by-step explanation:

to find the y- intercept, the point where the line crosses the y- axis.

let x = 0 in the equation and solve for y

y = - 3(0) + 12 = 0 + 12 = 12

then y- intercept = 12

to find the x- intercept, where the line crosses the x- axis.

let y = 0 in the equation and solve for x

0 = - 3x + 12 ( subtract 12 from both sides )

- 12 = - 3x ( divide both sides by - 3 )

4 = x

then x- intercept = 4

The polynomial in descending order is

[tex]x^7[/tex] - 4[tex]x^5[/tex] + 4x³  + 2[tex]x^4[/tex] - 10

Polynomial is an equation written as the sum of terms of the form kx^n.

where k and n are positive integers.

We have,

-4[tex]x^5[/tex] + 4x³ + [tex]x^7[/tex] - 10 + 2[tex]x^4[/tex]

Arranging in descending order means arranging the terms in their descending order of power.

Now,

[tex]x^7[/tex] > [tex]x^5[/tex] > [tex]x^4[/tex] > x³

So,

[tex]x^7[/tex] - 4[tex]x^5[/tex] + 4x³  + 2[tex]x^4[/tex] - 10

Thus,

The polynomial is:

[tex]x^7[/tex] - 4[tex]x^5[/tex] + 4x³  + 2[tex]x^4[/tex] - 10

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Answer: After doing the problem I got,  -4x-2

Therefore, the potential length of a triangle's third side is 17-11<x<17+11 is equals to 6 < x< 28.

A triangle's third side must always have a length that falls between (but not exactly equal to) the sum and difference of the other two sides. Consider the examples 2, 6, and 7 as an example. The third side length must therefore be larger than 4 and less than 8.

According to the Triangle Inequality Theorem, any two triangle sides must add up to more than the third side's length. To find the potential length of a triangle, multiply the sum of the two sides by the difference of the two sides.

Therefore, the potential length of a triangle's third side is 17-11<x<17+11.

= 6 < x< 28

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As a result, the third side of a triangle may be equal to 17-11<x<17+11 is equals to 6 < x< 28.

The third side of a triangle must always have a length that is between the sum and difference of the other two sides, but is not exactly equal to either. As an illustration, think about cases 2, 6, and 7. Therefore, the third side length must be more than 4 and lower than 8.

The Triangle Inequality Theorem states that any two triangle sides must add up to greater than the length of the third side. Multiply the sum of the two sides by the difference of the two sides to determine the potential length of a triangle.

Consequently, 17-11<x<17+11.= 6 < x< 28 is the possible length of the third side of a triangle.

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The probability that Sam's first upgrade will occur after the third flight = 0.729

Let m represents the number of flights Sam must take in order to receive his first upgrade.

To find the probability that Sam's first upgrade will occur after the third flight.

i.e., to find P(m ≥ 4)

Here,  0.10 probability that a coach-class ticket holder who flies frequently will be upgraded to first class on any flight.

p = 0.10

q = 1 - p

q = 0.90

P(m ≥ 4) = 1 - P(m ≤ 3)

P(m ≥ 4) = 1 - [P(m = 1) + P(m = 2) + P(m = 3)]

P(m ≥ 4) = 1 - [0.1 + (0.9 × 0.1) + (0.9² × 0.1)]

P(m ≥ 4) = 1 - (0.1 + 0.09 + 0.081)

P(m ≥ 4) = 0.729

therefore, the required probability = 0.729

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The complete question is:

An airline claims that there is a 0.10

probability that a coach-class ticket holder who flies frequently will be upgraded to first class on any flight. This outcome is independent from flight to flight. Sam is a frequent flier who always purchases coach-class tickets.

What is the probability that Sam's first upgrade will occur after the third flight?

The value of x in the figure is 3

Suppose that we've got two quantities with measurements as 'a' and 'b'

Then, their ratio(ratio of a to b) a:b

or [tex]\dfrac{a}{b}[/tex]

We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. Numerator is the upper quantity in the fraction and denominator is the lower quantity in the fraction).

Suppose that we've got a = 6, and b= 4, then:

[tex]a:b = 6:2 = \dfrac{6}{2} = \dfrac{2 \times 3}{2 \times 1} = \dfrac{3}{1} = 3\\or\\a : b = 3 : 1 = 3/1 = 3[/tex]

Remember that the ratio should always be taken of quantities with same unit of measurement. Also, ratio is a unitless(no units) quantity.

Given;

The ratio of line segment QP=2:6

The ratio of line segment RP=X:9

Now, to find x

2/6=x/9

x=9/3

x=3

Therefore, the value of x according to given ratio will be 3

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If the equation to model his altitude(y) in feet, in terms of the number of feet he bicycled(x) is y = 1/20x + 5000 , then the rate of change in altitude as he traveled is described by the fraction "1/20" .

The rate of change in altitude(y) as Zach traveled can be described as the slope of the line represented by the equation y = 1/20x + 5000. In this equation, the slope is 1/20.

The slope of a line is also called as the "rise over run", represents the change in y (altitude) per change in x (distance traveled). So in this case, the slope of 1/20 means that for every 20 feet Zach travels, his altitude changes by 1 foot.

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The original length is 250 meters and the scale drawing width is 0.67 cm

From the question (see attachment), we have the following parameters that can be used in our computation:

Scale length = 0.5 meters

So, we have

Original length = 0.5/(1/500)

Evaluate

Original length = 250

This means that the original length is 250 meters

Here, we have

Scale drawing width = 335 * 1/500

Scale drawing width = 0.67 cm

Hence, the scale drawing width is 0.67 cm

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The solution of the expression is 3m-5.

Basic Guidelines and Procedures for Condensing Any Algebraic Expression

step1:

(6m² -13m+5)/(2m-1): 3m-5

6m²  -13m+5/2m-1

factor 6m² -13m+5 : (2m-1) (3m-5)

=(2m-1) (3m-5)/2m-1

step2:

cancel the common factor 2m-1

=3m-5

The solution of the expression is 3m-5

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Answer:

y - 8 = -1 (x + 4)

Step-by-step explanation:

I don't know if your suppose to solve it but i'll do it anyway

y - 8 = -1 (x+4)

y - 8 = -1x - 4

y - 8 +8 = -1x -4 +8

y = -1x + 4

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{- 1}(x-\stackrel{x_1}{(-4)}) \implies y -8= -1 (x +4) \\\\\\ y-8=-x-4\implies {\Large \begin{array}{llll} y=-x+4 \end{array}}[/tex]

Answer: 25.90

Step-by-step explanation:

Answer:

y = 57.2 - 7.15x

Step-by-step explanation:

Let y represent the number of gigabytes left, and let x = number of games.

Originally, y = 57.2.

Each game will occupy 57.2/8 gigabytes = 7.15 gigabytes.

x games occupy 7.15x gigabytes, so for x games loaded on his computer,  the gigabytes left go down by 7.15x.

The equation is

y = 57.2 - 7.15x

This depends on the number of paths that exist between point a and point b. If there are more than one path, then the number of paths that avoid the point with the surrounding circle will be one less than the total number of paths.

The number of paths from point a to point b that avoid the point with the surrounding circle will depend on the total number of paths between the two points. If there are multiple paths between the two points, then the number of paths that avoid the point with the circle will be one less than the total number of paths.

For example, if there are three paths between a and b, then two of those paths will avoid the point with the circle.

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