if the speed of a car is increased by 50%, bywhat factor will its minimum braking distance be increased, assuming all else is the same?

Answers

Answer 1

When the speed of a car increases by a factor of 50%, the minimum braking distance will also be increased by a factor.

Braking distance will increase by a factor  2.25

Solution

From Newton's equation of motion, we can say that;

v² = u² + 2as

Where initial velocity is zero, we have;

v² = 2as

s = v²/2a

s is the distance and v is the final speed.

50% increase in speed means it has increased by a factor of 1.50

Hence we have

1.50²v² is directly proportional to the 1.50²d

Distance = 1.50²v² = 2.25d

Hence, breaking distance will increase by a factor 3.0625

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Related Questions


1. Which of the following types of energy is
potential energy? More than one answer is
possible,
A kinetic energy
B.thermal energy
C.sound energy
D.gravitational energy

Answers

Answer:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?

Answers

This question involves the concepts of the equations of motion in vertical direction.

The height of the bridge is "116.8 m".

We will use the second equation of motion in vertical direction to find out the height of the bridge.

[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]

where,

h = hieght = ?

vi = initial speed = 0 m/s

t = time taken = 4.88 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]

h = 116.8 m

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A 50 kg driver of a car is traveling at 35 m/s when she hits a large deer. She strikes the air bag/seatbelt combination that brings her body to a stop in 1.1s. What is the impulse imparted to the driver of the car?


Answers

Answer:1590 N

Explanation:

Impulse =  change in momentum/time

change in momentum = 0 - 50 x 35 = -1750

-1750/1.1 = 1590 (3s.f.) N

can someone explain please?​

Answers

Hi there!

We can begin by solving for the velocity in which the ball was thrown at using the following:

[tex]v_f^2 = v_i^2 + 2ad[/tex]

At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:

[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]

'a' = acceleration due to gravity and 'd' is the max height, so:

[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]

Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).

[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]

[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]

hi i need some help with this.....

Answers

Answer: D

Explanation: moogle helps lol.

the answer is C

Explanation:

In a plant cell, chloroplast makes sugar during the process of photosynthesis converting light energy into chemical energy stored in glucose. In mitochondria, through the process of cellular respiration breaks down sugar into energy that plant cells can use to live and grow.

SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.

Answers

Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

what has to increase in order for an object to accelerate?

Answers

Answer:

Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.

Explanation:

I do Accelerate to good luck

according to newton, doubling the distance between two interacting objects:

Answers

Answer:

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

Explanation:

hope his helps

The app claimed it has "Forbidden text"​

Answers

What??? I’m confused

Two hockey players are skating toward each other on a frictionless ice. One is moving at 1 m/s while the other is traveling at 2 m/s. The players collide and stick together. Find their combined speed.

Answers

Their combined speed will be 1m/s

Given the following parameters;

The velocity of the first hockey player is 1m/s.The velocity of the second hockey player is 2m/s.

If the player collides and stick together, the combined speed is expressed as;

Combined speed = differences in velocityCombined speed = 2m/s - 1m/sCombined speed = 1m/s.

Hence their combined speed will be 1m/s

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Classify the statement below as either Speed or Velocity?

A jeep was driving 40 mph
heading to the grocery store.

Answers

Answer:

Hello There!

It is Speed.

[tex]\Large\bold\red{Reason}[/tex]

Because in the question it is said that at which speed car is travelling.

Speed is a scalar quantity.

If it is velocity then first know this that it is a vector quantity.

It must include both magnitude and direction.

If it is velocity then it would be 40 mph east or west or north or south.

I hope it is helpful to you...Cheers!_____________

Two sections of genetic material from a fruit fly are shown in the diagram.
X
-Eye color
-Wing shape
What does the diagram reveal about the inherited traits of fruit flies?
А Inherited traits are controlled by tissues, which are found in organs.
B
Inherited traits are controlled by organs, which are found in tissues.
с
Inherited traits are controlled by genes, which are found in chromosomes.
OD
Inherited traits are controlled by chromosomes, which are found in genes.

Answers

the answer is c, inherited traits are controlled by genes, which are found in chromosomes

the maximum displacement of a particle by a wave is called

Answers

The answer is amplitude

Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?

-298 kg
-600 kg
-0.006 kg
-150 kg

Answers

F=300Na=2m/s^2

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow 300=2m[/tex]

[tex]\\ \sf\Rrightarrow m=150kg[/tex]

Hey there!

The formula of “mass” in physics is:

m = F/a

Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.

mass = 300 Net force/2 acceleration

300 Net force/2 acceleration = m

mass = 150

Therefore, your answer is: 150 kg

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 million electrons per second through an ohmic gas

Answers

the compare software

hope it's help

Answer:

you ask or answer?

Explanation:

thanks for point

if A and B are non zero vectors, is it possible for vector A×vector B and vector A.vector B both to be zero? Justify your answer​

Answers

Answer:

not able to understand the question


[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]


Calculate equivalent resistance of two resistors R1 and R2 in parallel where,

[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]

Answers

[tex]it \: was \: helpful \: to \: you[/tex]

# be careful#

A 0.15 kg baseball moving at 20 m/s is stopped by a player in 0.010 s. What is the average force of the ball?

Answers

Answer: 300N

Explanation:

Impulse= Mass * Velocity

F.T = M * V

F= MV/T

F= (0.15*20)/ 0.01

F= 300N

What is the boiling point of water?

Group of answer choices

373.15 degrees Fahrenheit

373.15 degrees Celsius

373.15 Kelvin

Answers

Answer:

373.15 Kelvin

Explanation:

Boiling Point of water

= 100 degree Celsius

= (100 + 273.15) Kelvin

= 373.15 Kelvin

the purpose of many scientific investigations is to test a {n}

Answers

Hypothesis , I believe the answer is hypothesis

Answer:

Scientific investigation is a quest to find the answer to a question using the scientific method.

Explanation:

the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s

Answers

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

Velocity = 30 m/sAngle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

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how to solve for time given distance and velocity

Answers

Answer:

Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:

S = Vt + S0

With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).

From this you can calculate t, if that's what you want.

With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Answers

initial velocity=u=20km/h=5.5m/sAcceleration=a=8m/s^2Time=t=10s

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

4 What type of circuit is described by each of the following statements?
Answer series or parallel
a All components are connected end-to-end.
b. The current in the circuit divides so that some flows through one component
and the rest through another component
Two lamps are connected side by side so that each lights brightly
d The current has the same valur everywhere in the circuit
C

Answers

b. the current in the circuit divides so that some flows through one component

What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.

Answers

Answer:

6 kg.m/s

Explanation:

Momentum is the product of mass and velocity. So,

p = mv

Here,

p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]

→ p = 5 kg × 1.2 m/s

→ p = (5 × 1.2) kg.m/s

→ p = (5 × 12/10) kg.m/s

→ p = 12/2 kg.m/s

p = 6 kg.m/s

Therefore, momentum of the object is 6 kg.m/s.

The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

MOMENTUM:

Momentum of a substance is the product of its mass and velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:

Momentum = 5kg × 1.2m/s

Momentum = 6kgm/s.

Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

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The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.

If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?

Answers

Answer:

1.1x10¹⁶ kg

Explanation:

Let m =  mass of asteroid y.

Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.

Given:

F = 6.2x10⁸ N

d = 2100 km = 2.1x10⁶ m

Note that

G = 6.67408x10⁻¹¹ m³/(kg-s²)

The gravitational force between the asteroids is

F = (G*m*(m/3))/d² = (Gm²)/(3d²)

or

m² = (3Fd²)/G

    = [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))

   = 1.229x10³² kg²

m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)

A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.

Answers

The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge [tex]q[/tex] =  [tex]5\times 10^{-7}[/tex] C,

the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex]  m/sec,

the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,

angle between the direction of v and B [tex]\theta[/tex] = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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A certain satellite is in circular orbit about the earth at an altitude of 550km. If the satellite makes a revolution in 110minutes, calculate its orbital speed ​

Answers

Answer:

Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].

Explanation:

Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].

The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:

[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].

Convert the units of both distance and time to standard units:

Orbital radius:

[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].

Orbital period:

[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].

Calculate the circumference of this orbit:

[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].

Calculate the orbital speed (tangential) of this satellite:

[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].

Plz help!

A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?

Answers

The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:

The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º

The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:

Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.

Indicate in  the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.

Vector A.

         Aₓ = 100.0 m  

Vector B.

         B_y = -300.0 m  

The negative sign indicates that it goes in the negative direction of the y-axis

Vector C.

We use trigonometry.

The angle measured from the positive side of the x-axis counterclockwise is

        θ = 180 + 30 = 210

       

        sin 210 = [tex]\frac{C_y}{C}[/tex]

        cos 210 = [tex]\frac{C_x}{C}[/tex]

        C_y = C sin 210

        Cₓ = C cos 210

         C_y = 150.0 sin 210 = -75.0 m

         Cₓ = 150.0 cos 210 = -129.9 m

Vector D.

The angle from the positive side of the x-axis counterclockwise.

        θ = 180-60 = 120º

       sin 120 = [tex]\frac{D_y}{D}[/tex]  

       cos 120 = [tex]\frac{D_x}{D}[/tex]  

       D_y = D sin 120

       Dₓ = D cos 120

       D_y = 200.0 sin 120 = 173.2 m

       Dₓ = 200.0 cos 120 = -100.0 m

we add the component with algebraic sum.

       x = Aₓ + Cₓ + Dₓ

       y = B_y + C_y + D_y

       x = 100 - 129.9 -100 = -129.9 m

       y = -300 - 75.0 + 173.2 = -201.8 m

We construct the resulting vector.

We use the Pythagorean theorem for the Modulus.

       [tex]R+ \sqrt{x^2 +y^2}[/tex]  

       R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]  

       R = 239.99 m

We use trigonometry for the angle.

      tan  θ = [tex]\frac{y}{x}[/tex]

       θ = [tex]tan^{-1} \frac{y}{x}[/tex]  

       θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)

       θ = 57.2º

Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.

          θ = 270 - θ'

          θ = 270 - 57.2

          θ = 212.8º

In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:

The resulting vector has a modulus of R = 239.99 m and an angle of  θ= 212.8º

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The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
I need the Formula,Known,Substitute & Solve Answer with Units

Answers

Answer:

1.67m

5m/s

Explanation:

Wavelength of the wave = 3m

Speed of the wave  = 5m/s

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

 To find the frequency ;

        V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

  Insert the parameters and find the frequency;

        f  = V/ ∧   = 5 / 3  = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s

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