Complete Question
A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string, If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?
Answer:
The value is [tex]\theta = 4.41^o[/tex]
Explanation:
From the question we are told that
The mass of the rock is [tex]m_r = 940 \ g = 0.94 \ kg[/tex]
The length of the string is [tex]l = 1.30 \ m[/tex]
The breaking strength(i.e the maximum tension) on the string is [tex]T = 120 \ N[/tex]
Gnerally the vertical component of the tension experienced by the string is mathematically represented as
[tex]T_v = T sin(\theta)[/tex]
Generally this vertical component of tension is equivalent to the weight of the rock
So
[tex]Tsin (\theta) = mg[/tex]
=> [tex]\theta = sin^{-1} [\frac{mg}{ T} ][/tex]
=> [tex]\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ][/tex]
=> [tex]\theta = 4.41^o[/tex]
What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?
Answer:
4.1 m/s²
Explanation:
Net force in the x direction equals the mass times the acceleration.
∑F = ma
91 cos 35° = (18 kg) a
a = 4.1 m/s²
Answer:
Explanation:
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Which pair of factors affects the force of gravity between objects?
direction and distance
mass and distance
mass and shape
shape and time
Answer:
mass and distance
Explanation:
dont need to summary this
Answer:
B. mass and distance
Explanation:
What is the final velocity if you have an initial velocity of 4 m/s with an acceleration of 2 m/s2 over 5 second interval interval
Answer:
14m/s
Explanation:
A baseball's resultant velocity is 25.79 m/s, at 68.64° from the level ground.
Determine the vertical component of the baseball's velocity.
Answer:
Vy = 24.01 [m/s]
Explanation:
To solve this problem we must understand that velocity is a vector and therefore has magnitude and direction, in this way we can decompose the velocity in the components x & y, by means of the trigonometric functions of the sine and cosine of the angle.
For the vertical component, the sine of the angle is used.
Vy = 25.79*sin(68.64)
Vy = 24.01 [m/s]
15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)
A)
16°C
B)
30°C
C)
212°C
D)
190°C
Answer:
letter b
Explanation:
30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest
The student toses a ball into the air and then watches the ball fall back down to earth. When does the ball have the most potential energy
Answer:
when the ball is at its highest in the air.
Explanation:
I don't know for sure, but when the ball is in the air it has potential energy to fall(or something like that).
8. Using Newton's second law, solve the following problems using
GFFS.
a. A force of 35N is applied to a 25kg object, what is its
acceleration??
b. What force is required to accelerate a 14kg object at 4.5
m/s2?
c. Calculate the mass of an object that accelerated at a rate of
2.7 m/s2 by a force of 18N.
Answer:
a) 1.4 m/s2
b) 63N
c) 6.66kg
8. In explosives, potential energy is generally
stored in the form of
a thermal energy
b. electromagnetic energy
c. nuclear energy
d. chemical energy
Answer:
In explosives,potential energy is in the stored form of chemical energy.
which graph best demonstrates the general relationship between mass and temperature similar to the trend of thermal energy absorbed by your sand and water samples
Answer: the first one
Explanation: got it right on edg
Answer:
The first graph
Explanation:
Correct on Edge 2022! :]
PLEASE PLEASE HELP PICTURE INCLUDED
Answer:
a is the answer
Explanation:
5. Why should the free ends of a conduction tester not be connected for a long
time?
If the free ends of conduction tester are connected for long time , The cell of the battery will drain very quickly
A 70 kg student is riding on a skateboard at 4m/s. A 60 kg student is also riding a
skateboard at 4 m/s. Which statement below demonstrates an understanding of
Newton's 1st Law of Motion?
A. Since both students are traveling at the same speed they must have the same
inertia
B. Since both students are traveling at the same speed they must have the same
mass
C. One student has more mass and therefore more inertia
The particle model shows the image of the moving object.
TRUE OR FALSE
ANSWER AND I WILL GIVE YOU BRAINILIEST
Answer:
it does show the objects position
What is called mass per unit
volume of a substances? | ककसी पदाथष के
द्रव्यमान प्रतत इकाई आयतन को क्या कहते हैं?
A : Mass | द्रव्यमान
B : Weight | भार
C : Density | घनत्व
D : Volume | आयतन
Ans:
C : Density | घनत्व
Answer:
Density
Explanation:
The definition of density of a substance is the quotient between its mass and its volume. Such results in the mass per unit of volume.
a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5
Which describes the motion of the box based on the resulting free-body diagram?
1. It is moving up with a net force of 20 N.
2. It is moving to the right with a net force of 10 N.
3. It is in dynamic equilibrium with a net force of 0 N.
4. It is in static equilibrium with a net force of 0 N.
Answer:
D. (static equilibrium)
Explanation:
I just took the test and made a 100 with that answer.
Answer:
4. It is in static equilibrium with a net force of 0 N.
Explanation:
Just got it right :)
when electric and _______ fields both exist, it is called an electromagentic
Answer:
the answer is magnetic
A series RLC circuit contains a 1,000 resistor, a 240 mH inductor, and a 0.04 uF capacitor. What is the circuit's resonant frequency?
A. 12,684 Hz
B. 48,194 Hz
C.51,393 Hz
D. 16.244 Hz
what is it called when I sound waves slowed buy a new medium
1.echo
2.transmission
3.absorption
4.reflection
Answer:
3
Explanation:
Which function has a graph that intersects the y-axis at the point (0-4)?
Plz help por favor
Answer:
I believe B. The picture is not completely clear
Explanation:
What is the main difference between the atoms in a solid versus atoms in a 1 point
liquid?
Answer:
Atoms in a solid are close and tightly packed.They vibrate about fixed positions .They are arranged in a regular LATTICE.They cannot be compressed nor can they change shape.They have strong forces of attraction between them so they cannot move in order to move they have to gain ENERGY. Whereas the atoms in a liquid are not that close compared to the ones in solid.They take the shape of the container but their volume remains fixed.They have weak forces of attraction between atoms and have more energy which enables them to move.
Explanation:
A force of 1000N is applied to push
a mass of 500kg. How quickly does
it accelerate?
Answer:
Explanation: use f= ma
we get 1000 ÷ 500 = a
∴ a = 2 m/s²
When a mass of 500 Kg with the force 1000N, the acceleration produced is equal to 2m/s².
What is Newton's second law of motion?According to Newton’s second law of motion, the force equals the mass of the object times acceleration when the object has constant mass.
This law states that acceleration depends on two variables. The first variable is the mass and the net force acting on the body. The acceleration is directly proportional to the net force acting and inversely proportional to the mass.
Newton’s second law can be represented in the equation as follows:
[tex]F= ma[/tex]
or, [tex]a =\frac{F}{m}[/tex]
Acceleration or gaining speed happens when a force acts on an object.
Given the mass of the object, m= 500 Kg
The force applied on the object, F = 1000N
The acceleration produced in the mass, a = F/m = 1000/500 = 2m/s².
Therefore, the mass accelerates at a rate of 2m/s².
Learn more about Newton's second law of motion, here:
brainly.com/question/13447525
#SPJ2
the graph below represents the relationship between velocity and time for an object moving along a straight line.
What is the magnitude of the object's acceleration?
1. 5.0 m/s^2
2. 8.0 m/s^2
3. 10. m/s^2
4. 20. m/s^2
Answer:
10. m/s^2
Explanation:
40-(-10)= 50
50/5 =10
This question can simply be answered by using the slope of the velocity-time graph.
The correct answer for the magnitude of the acceleration is "3. 10 m/s²".
Since the graph between the velocity and the time is in the form of a straight line. Hence, the acceleration can be calculated as the slope of this line. We will use the first and last point of the line to calculate the slope (acceleration):
[tex]Acceleration = Slope = \frac{v_2 - v_1}{t_2-t_1}[/tex]
where,
v₁ = initial velocity from the graph = - 10 m/s
v₂ = final velocity from the graph = 40 m/s
t₁ = initial time from the graph = 0 s
t₂ = final time from the graph = 5 s
Therefore,
[tex]Acceleration = \frac{40\ m/s\ -\ (-\ 10\ m/s)}{5\ s\ -\ 0\ s}[/tex]
Acceleration = 10 m/s²
The attached picture shows the types of a velocity-time graph.
Learn more about the velocity-time graph here:
https://brainly.com/question/11290682?referrer=searchResults
What is the final velocity of a running back that is moving with an initial velocity of 2 m/s and accelerates at a rate of 4 m/s$$ in 5 seconds as he moves toward the defensive line?
Answer:
Final velocity = 22
Explanation:
22-2/5= 4
20/5=4
so add to so it is not 18/5
Then you get your answer.
Answer:
4. A sound wave moves towards a building at 5 m/s for 22 seconds.
Explanation:
According to the kinetic theory, what happens when the temperature of water
increases?
The water molecules increase their speed.
The water molecules do not change speed.
The water molecules decrease their speed.
Jack is buying a subscription to a magazine club. The function c=45+3.75m
c
=
45
+
3
.
75
m
describes the cost of the yearly subscription, c
c
, in terms of the number of magazines, m
m
, he orders.
What is the appropriate domain for the function?
the set of integers
the set of whole numbers
the set of all real numbers
the set of rational numbers
Answer:
the set of all real numbers
Explanation:
Given the cost of the magazine expressed as:
c=45+3.75m where:
c describes the cost of the yearly subscription.
m is the amount of order.
You must understand that domain are the values of the input variable m that will make the function exist.
The value of m that will produce a positive output since we can only have a positive value of the cost. According to the option, we can say that the domain is on the set of all real numbers (some are negative but all positive real numbers)
A trebuchet launches a pumpkin at an angle of 27 degrees at an initial velocity of 32 m/ s from the ground. What is the apogee of the pumpkin?
Answer:
10.77 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 32 m/s
Angle of projection (θ) = 27°
Acceleration due to gravity (g) = 9.8 m/s²
Apogee i.e maximum height (H) =?
Thus, the apogee i.e the maximum height of the pumpkin can be obtained as follow:
H = u² Sine² θ /2g
H = 32² × (Sine 27)² / 2 × 9.8
H = 1024 × (0.454)² / 19.6
H = (1024 × 0.206116) / 19.6
H = 10.77 m
Thus, the apogee i.e the maximum height of the pumpkin is 10.77 m.
If the maximum linear velocity her center of mass reaches is 2.3 m/s, what is her maximum angular velocity
Like linear velocity, angular velocity is the relationship between the variation of angular space at a given time.
It was agreed that the trajectory of the movement is clockwise. Thus, the movement that follows this orientation will be positive and the opposite, negative.
For the formula relating the linear velocity, it is necessary to take into consideration the following formula
[tex]v = \omega \times R[/tex]
For example, for a R = 0.738 m
[tex]2.3 m/s = \omega \times R \therefore\\ R = 0.738m \therefore\\\omega = 3.12 \frac{rad}{s}[/tex]
How would natural cycles (day/night, moon phases) change if gravity did not
exist?
Answer: Eh, we would be dead...
Explanation: First off, the moon is orbiting us for one reason, gravity. and if the switch for gravity just flicked off, poof! The moon would be speeding away at 1,000-2,000 hours! And the reason that we orbit the sun is gravity too. So every planet would fling into space. Everything in the UNIVERSE would fling into space. That much flying debris would eventually smash into earth. Well, if we did survive that, then we would freeze instantly because when we travel too far away from the star that we orbit, the planet would become very life-threateningly cold. And in this case, we are traveling away from the sun, which is the star we orbit. If we still manage to survive THAT, then we...would actually die from the start, cuz what holds our planet together? You guessed it-gravity.
A metal wire has a circular cross section with radius 0.800 mm. You measure the resistivity of the wire in the following way: you connect one end of the wire to one terminal of a battery that has emf 12.0 V and negligible internal resistance. To the other terminal of the battery you connect a point along the wire so that the length of wire between the battery terminals is d. You measure the current in the wire as a function of d. The currents are small, so the temperature change of the wire is very small. You plot your results as I versus 1/d and find that the data lie close to a straight line that has slope 600 A⋅m.
Required:
What is the resistivity of the material of which the wire is made?
Answer:
The value is [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 0.800 mm = 0.0008 \ m[/tex]
The voltage of the battery is [tex]emf = 12.0 V[/tex]
The slope is [tex]s = 600 \ A \cdot m[/tex]
Generally the resistance is mathematically represented as
[tex]R = \frac{\rho * d }{A }[/tex]
Generally the current is mathematically represented as
[tex]I = \frac{V}{R}[/tex]
=> [tex]I = \frac{V}{\frac{\rho * d }{A }}[/tex]
=> [tex]I = \frac{V * A }{\rho} * \frac{1}{d}[/tex]
Comparing this equation to that of a straight line we see that the slope is
[tex]s = \frac{V * A }{\rho}[/tex]
So [tex] 600 = \frac{V * A }{\rho}[/tex]
Here A is the cross-sectional area of the wire which is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.0008 )^2[/tex]
=> [tex]A = 2.011*10^{-6} \ m^2[/tex]
So
[tex] 600 = \frac{12.0 * (2.011*10^{-6}) }{\rho}[/tex]
=> [tex]\rho = \frac{12 * 2.011*10^{-6} }{600}[/tex]
=> [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]