if a car has a mass of 1,000 kg that is evenly distributed to its four tires, how much force does each tire apply to the road?

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Answer 1

if a car has a mass of 1,000 kg that is evenly distributed to its four tires, force each tire apply to the road is 2450 N.

A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

To calculate the weight of the car.

Weight = Mass x Acceleration due to gravity

Weight = 1000 kg x 9.8 m/s2

Weight = 9800 N

Divide the weight of the car by 4, to get the force each tire applies to the road

Force = Weight ÷ 4

Force = 9800 N ÷ 4

Force = 2450N

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Related Questions

consider a 70-kg woman who has a total foot imprint area of 400 cm2. she wishes to walk on the snow, but the snow cannot withstand pressures greater than 0.5 kpa. determine the minimum size of the snowshoes needed (imprint area per shoe) to enable her to walk on the without sinking.

Answers

The minimum size of the snowshoes needed to enable her to walk without sinking will be 1.37 m².

Assumption:

(i) Her weight is uniformly distributed on the imprint area

(ii) the weight of the shoes is negligible

Now, given that mass of women, m = 70 kg

For a pressure of 0.5 kPa on the snow, the imprint area of one shoe must be:

A = W/P

here, W = mg = 70 kg . 9.81 m/s² = 70x9.81 N

P = 0.5 kPa = 0.5 x 1000 N/m²

so, A = [tex]\frac{70x9.81 N}{0.5(1000)N/m^2}[/tex]

or A = 1.37 m²

Therefore, the minimum size of the snowshoes needed to enable her to walk without sinking will be 1.37 m².

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g assume that there are no other targets between moon and earth, and therefore range aliasing can be tolerated. what is the maximum pulse repetition frequency that can be used for the purpose of mapping the (half-sphere) surface of the moon?

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Assuming that range aliasing can be tolerated and there are no other targets between the moon and Earth, a pulse repetition frequency of around 10-20 MHz would likely be sufficient for mapping the moon surface.

The maximum pulse repetition frequency (PRF) that can be used for mapping the surface of the moon is determined by the need to avoid range ambiguities and to achieve the desired resolution. The PRF is the number of pulses emitted per second. A high PRF allows for high resolution mapping but also increases the chance of range ambiguities.

If range ambiguities can be tolerated, a high PRF can be used to achieve a high resolution map. The altitude of the spacecraft, the size of the antenna, and the desired resolution of the map are also factors that determine the maximum PRF. A general estimate is that a PRF of around 10-20 MHz would be sufficient for mapping the surface of the moon with a high resolution.

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A blender is 70% efficient. It has a total input power of 600 W. Calculate the useful output power. Help meh. I has no idea ¯\_(ツ)_/¯

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The useful output power of the blender is 420 W.

How to calculate useful output power?

To calculate the useful output power of the blender, we can use the equation:

P_output = P_input * efficiency

Where P_output is the useful output power, P_input is the total input power, and efficiency is the percentage of input power that is converted to useful output power.

Given that the total input power is 600 W and the blender is 70% efficient, we can substitute these values into the equation to find the useful output power:

P_output = 600 W * 0.70

P_output = 420 W

Therefore, the useful output power of the blender is 420 W.

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write a hamiltonian function representing an electron in the presence of a stationary positive point charge

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A hamiltonian function representing an electron in the presence of a stationary positive point charge is

H = (p^2)/(2m) - (e^2)/(4πε_0r)

What is a hamiltonian function?

Generally, The Hamiltonian function representing an electron in the presence of a stationary positive point charge is given by:

H = kinetic energy + potential energy = (p^2)/(2m) - (e^2)/(4πε_0r)

where

p = momentum of the electron m = mass of the electron e = charge of the electron (assumed to be negative) ε_0 = vacuum permittivity r = distance between the electron and the positive point charge.

Note that the first term represents the kinetic energy of the electron, and the second term represents the potential energy of the electron due to the attractive electrostatic force from the positive point charge.

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a ball is dropped from the roof of a tall building. if the ball bounces back to a height of 34 m. what was the velocity with which it left the ground?

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The velocity with which the ball left the ground when it is dropped from a tall building is calculated to be 25.82 m/s.

Height to which a ball bounces back s = 34 m

From the equations of kinematics, we know, the relation connecting height, velocities and acceleration as,

v² - u² = 2 a s

where, v is the final velocity

u is the initial velocity

a is the acceleration

s is the height travelled

Here, u = 0 and a is the acceleration due to gravity

v² = 2 × 9.8 × 34

v² = 666.4

v = 25.82 m/s

Thus, the velocity with which the ball left the ground is calculated to be 25.82 m/s.

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the first practical peacetime use of airplanes was for

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The first time pirates used airplanes in peacetime was to transport letters. Considered to be the founding flight of what would become American Airlines, this flight was the first regularly scheduled flight.

What was the first sensible application of aircraft during peacetime? Airplanes were first used for postal delivery during a period of peace.The De Havilland DH-4 biplane that Charles Lindbergh, the chief pilot of Robertson Aircraft Corporation, flew from Chicago to St. Louis carrying a bag of mail, was built in 1926.Considered to be the founding flight of what would become American Airlines, this flight was the first regularly scheduled flight.Reconnaissance was the initial purpose of aviation in World War.The aircraft would soar over the battlefield, observing the enemy's actions and positions.The 1903 Wright Flyer, the first successful powered airplane, was the result of four years of study and development by Wilbur and Orville Wright.On December 17, 1903, Orville piloted it for its maiden flight over Kitty Hawk, North Carolina.

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A car that has a mass of 1,500 kg is turning in a horizontal circle that has a radius of 20 meters. If the coefficient of friction between the car and the ground is 0.6, what is the maximum speed the car can take the turn without skidding?

Answers

The maximum speed the car weighing 1500kg and turning in a horizontal circle which has a radius of 20 meters can take the turn without skidding at 10.84m/s.

What is Maximum speed?

Maximum speed is the highest rate of speed that can be attained. Acceleration is the velocity, and because velocity has both a magnitude and direction associated with it, the acceleration changes when an object change the magnitude of their motion, the direction of their motion, or both of these.

Radius of the circular path, r = 20 m

Mass of the car, M = 1500 kg

Maximum speed of the car = v

The coefficient of friction, μ = 0.6

The centrifugal force will balance the friction force so that the car does not slip.

Therefore, mv²/r = μmg

v²/r = μg

v² = μgr

v = √(μgr)

v = √(0.6 × 9.8 × 20)

v = √(117.6)

v = √(294,000)​

v = √(117.6)

v = 10.84m/s

Therefore, the maximum velocity of the car is 10.84 meter per second.

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A 2. 0 kg toy car is released at the top of a frictionless track on the left and rolls off of the track from its right

side ramp. The car starts at a height of 0. 80 m, goes through a 0. 50 m diameter loop, and exits the ramp at a

height of 0. 25 m.

what is the change in the cars gravitational potential energy form A to B?

Answers

The change in the car's gravitational potential energy from A to B is calculated as 4.90 J.

What is Gravitational potential energy?

Gravitational potential energy may be characterized as a type of energy that is typically possessed or acquired by an object due to an alteration in its position when it is present in a gravitational field. In more simple terms, it can be revealed that gravitational potential energy is an energy that is associated with gravitational force or gravity.

According to the question,

The formula for gravitational potential energy is as follows:

Gravitational potential energy = mgh.

where m is the mass (in kg) of the body. G is the magnitude of the gravitational field that the body is exposed to. H is the height at which the body is located.

First, you have to calculate the gravitational potential energy of the car on point A, i.e. U₁= (2.0 kg)(9.8 m/s²)(0 m)= 0 J.

Second, the Gravitational potential energy of the car on point B is found as, U₂= (2.0 kg)(9.8 m/s²)(0.25 m)= 4.90 J.

Now, you must have to calculate the change in the car’s gravitational potential energy: ΔU= U₂-U₁= 4.90 J - 0 J= 4.90 J.

Therefore, the change in the car's gravitational potential energy from A to B is calculated as 4.90 J.

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a ball is thrown upwards at 20.0 m/s from the top of a roof that is 10.0 meters above the ground. how long does it take before the ball hits the ground? take g

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A ball is thrown upwards at 20.0 m/s from the top of a roof that is 10.0 meters above the ground and t = 4.84 seconds

The equation used to solve this problem is

s = vt - (1/2)gt^2

where s = the distance travelled (in this case, 10.0 meters), v = the initial velocity (in this case, 20.0 m/s), g = the acceleration due to gravity (in this case, 9.81 m/s^2), and t = the time (in this case, the time it takes for the ball to hit the ground).

Rearrange the equation to solve for t:

t = (2s/g) + (v^2/g^2)

Substitute the given values into the equation:

t = (2(10.0)/(9.81)) + (20.0^2/(9.81^2))

Simplify the equation:

t = 0.811 + 4.03

t = 4.84 seconds

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8. (a) a spherical mirror is cut in half horizontally and the top half removed. will an image be formed by the bottom half of the mirror? how does the image formed by the half mirror compare to the image formed before cutting the mirror in half?

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As the radius of curvature and focal length of the mirror is bottom half of the mirror is same as earlier, so the image formation by this mirror will not change. As a result, the bottom half of the spherical mirror will reflect an image that is an exact replica of the image it projected prior to being chopped.

Only the aperture area will be cut in half when a mirror is cut in half horizontally; the radius of curvature remains unchanged.

The spherical mirror has a radius of curvature that is twice its focal length. Because the radius of curvature remains unchanged when the mirror is cut horizontally, the focal length of the bottom portion will be the same as in the initial situation.

The location of the image created by the lower portion of the mirror is therefore the same as in the preceding situation according to the mirror equation.

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Two barges full of salted toad guts have a collision. The red barge has a mass of 150 000 kg and is traveling Northwest at 0. 25 m/s. The blue barge has a mass of 100 000 kg and is traveling Southeast at 0. 1 m/s. After the collision the blue barge has a velocity of 0. 32 m/s to the Northwest. What is the final velocity of the red barge? Is this collision elastic?​

Answers

When the red barge collides with the blue barge, which has a mass of 1000000 kg, its final velocity with in collision elastic becomes 0.311 m/s.

Define the term collision elastic?A elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of a collision. In elastic collisions, momentum as well as kinetic energy are both conserved.

The given data:

m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s

Using the law of conservation of momentum.

Following the formula, the red barge's final velocity (v3) is determined.

m1×v1+ m2×v2= (m1+m2)v3

Put the values;

150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3

37500+ 320000= 1150000×v3

357500 = 1150000×v3

v3 = 0.311 m/s

Thus,

After one head-on elastic hit where the projectile is substantially more substantial than the target, the target particle's velocity will be nearly twice as fast as the projectile, but really the projectile's velocity will essentially be unaffected.

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a 90.0 kg astronaut receives a 30.0 n force from her jetpack. how much faster is she be moving after 2.00 seconds?

Answers

After 2.00 seconds, the astronaut is moving at the speed of 0.67 m/s. The result is obtained by using the concept of Newton's second law.

What is Newton's second law?

The Newton's second law states that "The acceleration is directly proportional to the net force acting on an object and inversely proportional to the object's mass." It can be expressed as

a = ∑F/m

or

∑F = ma

Where

∑F = net force (N)a = acceleration (m/s²)m = object's mass (kg)

An astronaut moves after receiving a force. We have

m = 90.0 kgF = 30.0 Nt = 2.00 s

Find the speed of the astronaut moving!

The force makes the astronaut moves from rest to a certain speed.

The speed can be calculated by the Newton's second law.

∑F = ma

∑F = m (v₁ - v₀)/t

30.0 = 90.0 (v₁ - 0)/2.00

60.0 = 90.0v₁

60.0/90.0 = v₁

v₁ = 2/3

v₁ = 0.67 m/s

Hence, the astronaut is moving at the speed of 0.67 m/s.

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A 50kg student is climbing a rock face with a constant speed. Neglect any friction and drag impending her motion. What is the magnitude of the net force on the student? How much force is the student generating up the hill? What is the magnitude of the normal force?

Answers

The magnitude of the net force on the student is zero.

The force generated by the student is 500N.

The magnitude of the normal force is 500 N

What is the net force on the student?

The net force on the student is determined as follows:

The formula of the force of gravity is given by :

W = mass × acceleration due to gravity

The mass of the student is 50 kg

The magnitude of the net force in the student is:

Force = 50 * 10

W = 500 N

The force generated by the student is equal to the force of gravity acting o the student since the student is moving at a constant speed.

The force generated by the student = 500N

The net force = weight - force generated by the student

Net force = 500 N - 500 N

Net force = 0 N

The magnitude of the normal force is equal to the weight of the student.

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a doubly charged ion is accelerated to an energy of 36.0 kev by the electric field between two parallel conducting plates separated by 1.60 cm. what is the electric field strength (in v/m) between the plates?

Answers

The electric field strength between the conducting plates would be 3.6 x 10⁵ V/m.

What is electric field strength?

Electric field strength (E) is a measure of the force exerted on a charged particle by an electric field. It is measured in units of volts per meter (V/m) or newtons per coulomb (N/C). An electric field can be created by a static charge or by a changing magnetic field. The strength of the electric field is affected by the distance from the source of the field, the charge of the source, and the permittivity of the medium. Electric fields are used in many applications, including in electric motors, generators, and particle accelerators. It is also used in the study of charges and the behavior of conductors and insulators.

The electric field strength (E) can be determined by using the equation: E = W / qd

Where,

W = energy of the ion (36.0 keV)

q = charge of the ion (doubly charged ion, so 2e)

d = distance between the plates (1.60 cm)

To convert keV to J and cm to m:

1 keV = 1.602176634 x 10⁻¹⁶ J

1cm = 0.01m

Therefore,

E = (36.0 x 1.602176634 x 10⁻¹⁶ J) / (2e x 0.01m)

E = (57.634 x 10⁻¹⁶J/C) / (2 x 1.602176634 x 10⁻¹⁹ C x 0.01m)

E = 3.6 x 10⁵ V/m

So, the electric field strength between the plates is 3.6 x 10⁵ V/m.

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A ball is thrown horizontally from the roof of a building 85 m tall with a speed of 10.6 m/s.
a. How much later does the ball hit the ground?
b.
How far from the building will it land?
C. What is the velocity of the ball just before it hits the ground?

Answers

Answer:

1) [tex]t=4.16s[/tex]

2) [tex]s=44.10m[/tex]

3) [tex]v_{final}=40.84\frac{m}{s}[/tex]

Explanation:

a) How long till it hits the ground?

Since the person threw the ball perfectly horizontal, the ball has 0 vertical velocity at the start. In fact, it takes the same time for the ball to reach the ground if they dropped the ball instead of throwing. The acceleration in a vertical drop is gravity ([tex]a=9.81\frac{m}{s^2}[/tex])

Basically, we'll solve first part as if he just dropped the ball.

Use this linear motion formula:

[tex]s=v_{inital}(t_{final} -t_{initial})+1/2a(t_{final}-t_{inital})^2[/tex]

Since [tex]v_{initial} =0[/tex] we can remove that part from equation:

[tex]s=1/2a(t)^2[/tex]

[tex]85=1/2*9.81(t)^2[/tex] Plug and solve

[tex]170=9.81(t)^2[/tex]

[tex]17.33=t^2[/tex]

[tex]t=4.16s[/tex]

b) How far away does it land?

We will use the same formula above for horizontal motion.

[tex]s=v_{inital}(t_{final} -t_{initial})+1/2a(t_{final}-t_{inital})^2[/tex]

[tex]s=v(t)+0[/tex]  (Remove the last part since [tex]a=0[/tex])

[tex]s=10.6(4.16)[/tex]

[tex]s=44.096m[/tex]

c) How fast was it traveling vertically at the end?

Use this other linear motion formula for this step. s=85m (height of building).

[tex]v_{final} ^2-v_{initial} ^2=2as[/tex]

[tex]v_{final} ^2-0^2=2(9.81)*(85)[/tex] Started with 0 vertical velocity.

[tex]v_{final} ^2=1667.7[/tex]

[tex]v_{final}=40.837m/s[/tex]

According to the question of speed, a) 16.05 seconds does the ball hit the ground, b) 169.33 m far from the building will it land, c) 37.68 m/s is the velocity of the ball just before it hits the ground.

What is speed?
Speed is the rate at which something moves or an object's rate of motion. It can be measured in metres per second, kilometres per hour, and miles per hour, and is often used to describe the motion of objects, such as vehicles, animals, or natural phenomena.

a. The time it takes for the ball to hit the ground is given by the equation t = (2×h)/v, where h is the height of the building (85 m) and v is the initial velocity of the ball (10.6 m/s). Plugging in the given values, we get t = (2×85)/10.6 = 16.05 seconds.

b. The distance from the building at which the ball will land is found using the equation x = vt, where v is the initial velocity (10.6 m/s) and t is the time it takes for the ball to hit the ground (16.05 seconds). Plugging in the given values, we get x = 10.6×16.05 = 169.33 m.

c. The velocity of the ball just before it hits the ground is determined by the equation v = √(2gh), where g is the acceleration due to gravity (9.8 m/s2) and h is the height of the building (85 m). Plugging in the given values, we get v = √(2×9.8×85) = 37.68 m/s. This is the velocity of the ball just before it impacts the ground.

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does turning up the thermostat in the middle of the night for 15 minutes reduce the amount of time it takes it to reach temp in the morning?

Answers

Yes, turning up the thermostat in the middle of the night for 15 minutes reduce the amount of time it takes it to reach temp in the morning.

The United States Department of Energy suggests turning thermostats back 7 to 10 degrees from their normal settings for 8 hours per day in order to achieve annual savings of up to 10%. The Department of Energy estimates that savings of approximately 1 percent can be achieved for each degree of thermostat adjustment that is made every 8 hours. The amount of time it takes for the temperature to reach the desired level in the morning can be reduced by raising the thermostat for fifteen minutes in the middle of the night.

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What is the SI unit of K so that the equation Velocity = K x density is correct Give answer in terms of basic units. (Kg^-1m45^-1)

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The SI unit of K so that the equation Velocity = K x density is correct is given as

K=m^4/s-kgK= m4/s−kg

What is velocity?

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

The SI unit of velocity is m/s and the Si unit of density is kg/m^3kg/m3 .

Adding the SI units of both quantities, we have that  :

m/s=K\times kg/m^3m/s=K×kg/m3

In terms of dimensions,

[LT^{-1}]=K\times [ML^{-3}][LT−1]=K×[ML−3]

Dimension of K is :

[K]=[M^{-1}L^4T^{-1}][K]=[M−1L4T−1]

SI unit of K is :

K=m^4/s-kgK=m4/s−kg

Hence,  the required solution is  K=m^4/s-kgK=m4/s−kg

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how does the magnitude of the electric field at the origin for the quarter-circle arc you have just calculated comnpare to the electric field at the origin produced by a point charge q

Answers

although the electric field at the origin owing to the quarter-circle arc is zero, the electric field at the origin due to a point charge q is non-zero.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field. The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically. Electric charge or magnetic fields with variable amplitudes can produce an electric field. The area of space surrounding an electrically charged particle or object in which the charge body perceives force is known as the electric field.

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an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? the electric field points away from the electron and the proton. the electric field points toward the electron and the proton. the electric field is zero.

Answers

The electric field due to these charges at some point a great distance from them is zero.

What is electric field?

Electric field is a physical field created by a static electric charge or a changing electric charge. It is a vector field that exerts force on other charged particles. Electric fields are created when electric charges are separated, and the strength of the field is determined by the amount of charge and the distance from the charge.

This is because the electric field from an individual charge is inversely proportional to the square of the distance from it, and so the electric field from the two charges cancel each other out when the distance is greater than the separation between the electron and proton.

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what is the total displacement, in meters, of the ball going through its entire motion: traveling from the ground to the top and then falling back to the ground?

Answers

The total displacement, in meters, of the ball going through its entire motion: traveling from the ground to the top and then falling back to the ground is 0.

What do you mean by displacement?

 An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

The total displacement of an object is the distance and direction between its initial and final positions. If a ball is thrown upward, travels to the top and then falls back to the ground, its total displacement is zero.

This is because the ball travels upward and then downward, covering the same distance in opposite directions. The upward motion and the downward motion cancel each other out, resulting in a net displacement of zero.

So, the ball will be back to the ground where it was originally thrown.

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how much power is needed to move a person (mass 72 kg) up an escalator (angle 34 degrees with the horizontal) with a speed of 1.5 m/s (neglect friction)? 878w

Answers

878 Watts of power is needed to move a person (mass 72 kg) up an escalator (angle 34 degrees with the horizontal) with a speed of 1.5 m/s (neglect friction).

Moving sidewalks move people horizontally or at a little slope, elevators or lifts take people and cargo up and down, escalators are moving staircases from one story of a building to another. A really compact commercial elevator called a du.mb. waiter elevator is designed to convey things rather than humans.

The given data:

m = 72 kg

w = fd

w mgd

w = 72 kg × 9.8 × 1.5 m

w = 878w

The pressure preventing movement against one another of hard substrates, liquids layers, and material components is known as friction. There are many sorts of friction.

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you stand on a tall cliff and throw a ball so that it is initially moving purely horizontally. if we neglect the effect of air friction, what is the motion of the ball a short time later.?

Answers

If we neglect the effect of air friction, then the motion of the ball a short time later will be a combination of horizontal and vertical motion.

What is the motion of the ball after a short time?

If you stand on tall cliff and throw ball so that it is initially moving purely horizontally and neglecting the effect of air friction, motion of the ball a short time later will be combination of horizontal and vertical motion. This is because the only force acting on ball is gravity, which will pull the ball downwards. Therefore, ball will experience a vertical acceleration due to gravity, while continuing to move horizontally at constant velocity.

Motion of the ball is a parabolic path, which is the trajectory of projectile under the influence of gravity. Horizontal component of the motion will remain constant, while vertical component will be affected by gravity and will decrease until ball reaches maximum height and then it will increase again until the ball hit the ground.

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the ejected gases have a mass that is small compared to the mass of the spacecraft. you then continue coasting with the rocket engines turned off. what will be the components of your position vector an hour later? start by finding the x component, rf,x

Answers

The final position of the rocket after 1 hour is (2.64 × 10⁴, 3.5 × 10⁴, 0).

Initial velocity, = (0, 2× 10⁴, 0)

Initial location, = (1.2× 10⁴, 1.5 × 10⁴, 0)

Net force acting, F₁ = (6× 10⁴, 0, 0) N

Mass of the rocket, m₁ = 1.5 × 10⁴

Initial momentum, p₁ = mv₁ = (1.5 × 10⁴) × (0, 2× 10⁴, 0)

p₁ = (0, 3 × 10⁸, 0)

Final momentum after 1 hour(3600 sec), P₂ = p₁ + F₁×Δt

P₂ = (0, 3 × 10⁸, 0) + (6× 10⁴, 0, 0)×3600

P₂ = (2.16 × 10⁸, 3 × 10⁸, 0)

Final position of this time,

r₂ = r₁ + (P₂)/m₁

r₂ = (1.2 × 10⁴, 1.5 × 10⁴, 0) + (2.16 × 10⁸, 3 × 10⁸, 0)/(1.5 × 10⁴)

r₂ = (2.64 × 10⁴, 3.5 × 10⁴, 0)

--The given question is incomplete, the complete question is:

"Suppose that you are navigating a spacecraft far from other objects. The mass of the spacecraft is 1.5 × 10⁴ kg. The rocket engines are shut off, and you're coasting along with a constant velocity of (0, 2× 10⁴, 0) m/s. As you pass the location (1.2× 10⁴, 1.5 × 10⁴, 0) you briefly fire side-thruster rockets, so that your spacecraft experiences a net force of (6× 10⁴, 0, 0) N for 1 hour. After turning off the thrusters, you then continue coasting with the rocket engines turned off. The ejected gases have a mass that is small compared to the mass of the spacecraft. you then continue coasting with the rocket engines turned off. what will be the components of your position vector an hour later? start by finding the x component, rf,x?"

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calculate the amgnitued of the cetripetal force acting on earth as it orbits the sun, assuming a circular orbit and an orital speed of 3.00 times 10^4 meters per second

Answers

Answer:

Approximately [tex]3.59\times 10^{22}\; {\rm N}[/tex] (assuming that the orbit is circular.)

Explanation:

When an object is in a circular orbit of radius [tex]r[/tex] with a (linear) speed of [tex]v[/tex], the centripetal acceleration of this object would be [tex]a = (v^{2} / r)[/tex]. If the mass of the object is [tex]m[/tex], magnitude of the net force on this object would be [tex]F = m\, a = (m\, v^{2} / r)[/tex].

Look up the mass of the Earth: [tex]m \approx 5.9722\times 10^{24}\; {\rm kg}[/tex].

Look up the radius of the orbit (mean distance between the Earth and the Sun): [tex]r \approx 1.4960\times 10^{11}\; {\rm m}[/tex] (one Astronomical Unit.)

It is given that the linear orbital speed is [tex]v = 3.00 \times 10^{4}\; {\rm m\cdot s^{-1}}[/tex].

Therefore, magnitude of the centripetal force (net force) on the Earth would be:

[tex]\begin{aligned}F &= m\, a = \frac{m\, v^{2}}{r} \\ &\approx \frac{(5.9722 \times 10^{24}\; {\rm kg})\, (3.00 \times 10^{4}\; {\rm m\cdot s^{-1}})^{2}}{1.4960 \times 10^{11}\; {\rm m}} \\ &\approx 3.59 \times 10^{22}\; {\rm N} \end{aligned}[/tex].

If you go to the moon, which force is greater? The force of gravity that you exert on the moon or the force of gravity the moon exerts on you?



The force you exert on the moon



The force the moon exerts on you



The force of gravity you exert on the moon equals the force of gravity the moon exerts on you



WILL GIVE BRAINLIEST AWARD

Answers

The force of gravity the moon exerts on you is greater than the force of gravity you exert on the moon.

What is the force of gravity?

The force of gravity is a fundamental pressure of nature that acts between two gadgets with mass. It's miles the pressure that attracts  objects toward every other, and its energy is proportional to the mass of the gadgets and the space among them. The pressure of gravity is liable for the motion of planets and different celestial gadgets, as well as for maintaining items on the floor. It turned into first described by way of Sir Isaac Newton in his laws of motion and normal gravitation, which stated that every item inside the universe attracts each different item with a pressure proportional to the product of their masses and inversely proportional to the rectangular of the distance between them.

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The force the moon exerts on you is greater.

What do you mean by gravity?

Gravity is a force of attraction between two objects in space that is proportional to the masses of the objects and inversely proportional to the square of the distance between them. It is the force that holds planets in orbit around stars and is what causes objects to fall to the ground when dropped. On Earth, the force of gravity is what gives weight to objects and what keeps us anchored to the surface. The strength of the gravitational force is determined by the mass of the objects and the distance between them, with more massive objects having a stronger gravitational pull.

The force of gravity is the force with which a celestial body attracts objects toward its center. The force of gravity is proportional to the mass of the object and inversely proportional to the square of the distance between the objects. The force of gravity acts as the source of the weight of objects. The force of gravity is responsible for holding objects in orbit around the earth and other celestial bodies. The most well-known example of the force of gravity is the attraction between the earth and moon, which causes the tides.

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how fast does the earth rotate near the equator persona 3

Answers

Roughly 1,700 km/h. The Earth rotates faster than sound near the equator.

How quickly rotates the Earth close to the equator?

The Earth's circumference is around 40,075 kilometres at the equator; multiplying this by the length of the day yields a spin speed of approximately 1670 kilometres per hour.

How many times does the equator revolve in a day?

Each 24-hour day, the Earth rotates once around its axis. The speed of Earth's spin at its equator is around 1,000 miles per hour (1,600 km per hour). Every day of your existence, this day-night spin has taken you outside and under the sun and stars.

Can people feel the Earth's spin?

The speed of Earth is rapid. It orbits the Sun at a speed of roughly 67,000 miles (107,000 kilometres per hour), spinning (rotating) at about 1,000 miles (1600 kilometres) per hour. Due to the consistent speeds, we are not aware of any motion.

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Around 1,700 km/h.Correct!. Its circumference is approximately 40,075 kilometers at the equator; multiplying this by the length of the day yields a value of 1670 kilometers per hour for the equator-bound speed of rotation.

How quickly rotates the Earth close to the equator? Around 1,700 km/h.Correct!. With players trying their hardest to finish quickly, the game can be completed in as little as 44 hours.Between 65 and 66 hours are typically needed to finish the main game alone.Shinjiro is ultimately kept alive on October 4 by his pocket watch.He is thrown in a coma rather than killed by the bullet because it hits the pocket watch instead of piercing him.Players who save Shinjiro at the end of the story have the option to spend time with him thanks to New Game+. Despite the fact that Persona 3 is a good game, it has many gloomy themes that are inappropriate for young players.

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If an astronaut weighs 981 N on Earth and only 160 N on the
Moon, then what is his mass on Earth?

Answers

Answer: The mass on Moon will be 98. 1 kg.

Explanation:

As per the known fact, the mass is independent of acceleration due to gravity of planet.

A ball is attached by a tether to a stake in the ground. The ball travels in a circle at the full length of the tether. The pull of the tether acts in a direction ____________ to the ball's velocity, and changes its ____________.

Answers

Answer:A ball is attached by a tether to a stake in the ground. The ball travels in a circle at the full length of the tether. The pull of the tether acts in a direction perpendicular to the ball's velocity, and changes its direction.

Explanation: i big brained thats y

Why should a person warm up before exercising?

To gradually increase blood flow to the body
To spend extra time thinking about exercise
To keep from getting too tired after the activity
To help increase muscle strength

Answers

Answer:

To gradually increase blood flow to the body

The answer to your question is A

IM CONFUSEDDDD!

i have to turn in this project for an online balloon car thing, can someone do the calculating at least please!

Answers

To design a race car with a balloon engine for the best possible performance. must take into consideration Newton's laws of motion. the formula Velocity (speed) = Distance / Time (v = d / t).

What was the average velocity of your balloon car?3.753968254 metres per second was the car's average speed.According to the law of conservation of energy, as you fill up the balloon more, it stores more potential energy, which is then transformed into more kinetic energy, causing the balloon to expand faster and the car to move forward.Using f=ma, calculate thrust.By averaging the positive acceleration readings or measuring the time it takes to reach maximum velocity, average acceleration may be obtained.The balloon will travel with greater force and accelerate more quickly as compressed air content increases. The force of the balloon is reduced and its speed is slowed down if the number of pumps is reduced (air pressure is decreased).

The Complete Question.

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