I need this quickly:)

Answer:

The maximum height (vertex) is at (0,256), which is also when it began (Y-Intercept). It will take 4 units for it to hit the ground.

Let us know how you do on the test.

Answer:

half

Step-by-step explanation:

Answer:

1/2 of the mango or half

Step-by-step explanation:

(-2,-4) , (-2, -3) , (-4, -3)

when you rotate 180° then the x and y of each point will become the opposite

Answer:

(x-2,y-4), (x-2,y-3) and (x-4,-y3)

Step-by-step explanation:

The rule is (x,y)-->(-x,-y) so

(x2,y4)=(x-2,y-4)

(x2,y3)=(x-2,y-3)

(x4,y3)=(x-4,-y3)

never mined rong center point It would not let me change any thange

Answer:

see explanation

Step-by-step explanation:

8(16) + 8(6) ← factor out 8 from each term

= 8(16 + 6)

= 8(22)

= 8 × 22

= 176

Answer:

square root graph

Step-by-step explanation:

this is the graph given by a square root function

Answer:

  14

Step-by-step explanation:

The triangle inequality is usually expressed as ...

  a +b > c

for any permutation of a, b, c.

Here, that would mean ...

  1 + 14 > c

  c < 15

The largest whole-number value that the third side (c) can have is 14.

_____

Additional comments

Some authors write the triangle inequality as ...

  a +b ≥ c

If you use that version, the longest side could be 15. Such a "triangle" would look like a line segment, and have zero area.

__

We can also check the shortest length:

  c +1 > 14

  c > 13

The smallest whole-number value for the shortest side is also 14. That is, the only triangle with whole-number side lengths of 1 and 14 will be an isosceles triangle with two sides of length 14.

That's possible when function tends to zero

[tex]\\ \rm\hookrightarrow 0.25x^2-x+9.5=0[/tex]

[tex]\\ \rm\hookrightarrow 1/4x^2-x+19/2=0[/tex]

[tex]\\ \rm\hookrightarrow x^2-x+38=0[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{1-152}}{2}[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{151}i}{2}[/tex]

Answer:

8.5 ft

Step-by-step explanation:

[tex]f(x) = 0.25x^2 - x + 9.5[/tex]

To find the minimum point of the function, differentiate:

[tex]f'(x) = 0.5x - 1[/tex]

set to zero and solve for x:

[tex]f'(x) =0\\ \implies0.5x - 1=0\\\implies x=2[/tex]

Substitute found value of x into function to find y (height):

[tex]f(2) = 0.25(2)^2 - 2 + 9.5=8.5[/tex]

Therefore, the lowest point on the bottom edge of the banner is 8.5 ft above the floor.

Answer:

The answer is B- 10h( h+3+5j) AND C- 2(5h+15+25j)

The equation of the sum of any two squares x and y is x^2 + y^2 = (x + y)^2 - 2xy

The question is incomplete, as there are no parameters to determine the last digit of the first number.

So, I will give a general explanation

The sum of squares of two numbers x and y is:

[tex]x^2 + y^2 = (x + y)^2 - 2xy[/tex]

Assume the numbers are 5 and 6, then the equation becomes

[tex]5^2 + 6^2 = (5 + 6)^2 - 2*5*6[/tex]

Evaluate

[tex]5^2 + 6^2 = 61[/tex]

Read more about sum of squares at:

https://brainly.com/question/52031

Answer:

1m=100cm

Step-by-step explanation:

do it correctly, sooo ya

Answer: 52 degrees

Step-by-step explanation:

Answer:

A: -6 + 2

Step-by-step explanation:

remember two negative signs makes a positive sign

Answer:

Step-by-step explanation:

Givens

Greeting Card = 3.79

Total Cost = 5.11

Post cards = x

Equation

Total Cost = Greeting Card + 4x

Solution

Substitute the gives into the equation

5.11 = 3.79 + 4x                       Subtract 3.79 from both sides

5.11 - 3.79 = 3.79 - 3.79 + 4x  Combine

1.32 = 4x                                  Divide by 4

1.32/4 = 4x/4

x = 33

Each post card costs 0.33 dollars

Answer:

the answer is C.

Step-by-step explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

Subtract the difference:

2690 - 284 = 2406

Divide by 2:

2406 / 2 = 1203

Ricky Had 1,203

Pedro had 1203 + 284 = 1,487

Answer:

See Below

Step-by-step explanation:

The left side of the equation HAS TO BE GREATER THAN 3

So we take each ordered pair (x,y), plug it into the expression of left side of inequality and see which one is GREATER THAN 3. That's our answer.

A:

0.5x - 2y

0.5(-2) -2(0.5) = -2

NO

B:

0.5x - 2y

0.5(2) -2(1) = -1

NO

C:

0.5x -2y

0.5(2) -2(-1) = 3

NO

D:

0.5x -2y

0.5(-2) -2(-0.5) = 0

NO

None of them are solutions. C would have been a solution if the inequality had an "EQUAL SIGN" -- but it doesn't. Maybe the question is wrong, but if the question is right, then there is no correct answer.

Answer:

The answer is 13.25 I'm so sorry if its incorrect please let me know so I can fix it

Answer:

The value of x round to the nearest tenth is 12.04

Step-by-step explanation:

We have used trigonometric ratios to calculate the required value.

Answer:

see explanation

Step-by-step explanation:

the 2 angles are on opposite sides of the transversal  and outside the parallel lines.

the 2 angles are alternate exterior angles

The mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Constants who are in multiplication with variables are called coefficients of those variables.

For example, in [tex]10x^2[/tex] we have 10 as coefficient of [tex]x^2[/tex]

Those variables who have got no visible coefficient has 1 as their coefficient. Thus, [tex]x^2[/tex] has got its coefficient as 1. It is true since 1 multiplied with any number is that number itself.( [tex]x^2 = 1 \times x^2[/tex] )

If we have [tex]a^b[/tex] then 'a' is called base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

[tex]a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\\\ a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\(ab)^c = a^c \times b^c[/tex]

For the considered situation, the expression that Anja is simplifying is:
[tex]\dfrac{10x^{-5}}{-5x^{10}}[/tex]

Anja simplified it to [tex]\dfrac{15}{x^{15}}[/tex]

She performed operations with variable 'x' correctly since

[tex]\dfrac{x^{-5}}{x^{10}} = \dfrac{1}{x^5} \times \dfrac{1}{x^{10}} = \dfrac{1}{x^{15}}[/tex]

But coefficients will also get divided. Instead of dividing 10 by -5, she subtracted them (as 10 - (-5) = 10 + 5 = 15)

This was her mistake.

The correct simplification would be: [tex]\dfrac{10x^{-5}}{-5x^{10}} = \dfrac{10}{-5} \times \dfrac{x^{-5}}{x^{10}} = -2 \times \dfrac{1}{x^{15}} = \dfrac{-2}{x^{15}} = -2x^{-15}[/tex]

Thus, the mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Learn more about exponent and bases here:

https://brainly.com/question/847241

Answer: c

Step-by-step explanation:

Answer:

0.0073

Step-by-step explanation:

<3

Answer:

0.0025

Step-by-step explanation:

This is because , you have the number 75, and dividing that by 3 is 25, but since our number is 0.75, that means we are adding the 2 zeros from our 300 and add it on to be to 0.0025, this won’t work in some situations.

Hope that helps!

Answer:

B

Step-by-step explanation:

among the following below which of these represents a plane screen of a cellphone .

Answer:The solution is in the attached file

Step-by-step explanation:

Answer:

the correct answer is : b

Solution :

Let,

We know that,

[tex]{ \longrightarrow \bf \qquad \: (AB) {}^{2} +( BC) {}^{2} = (AC) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} +( 4) {}^{2} = (5) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} = (5) {}^{2} - ( 4) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{(5) {}^{2} - ( 4) {}^{2}} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{25 - 16 }}[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{9 }}[/tex]

[tex]{ \longrightarrow {\pmb {\bf\qquad \: AB = 3}}}[/tex]

Therefore,