Given the balanced equation:
( Reaction type : double replacement)
CaF2 + H2SO4 → CaSO4 + 2HFI
We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.
This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.
For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.
For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.
Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.
The limiting reactant in the given balanced reaction is sulphuric acid. The mass of HF produced from 75 g of H₂SO₄ is 30 g.
What is limiting reactant?The limiting reactant in a species is the reactant which is fewer in amount and thus determine the yield of the product.
In the given reaction, one mole of calcium fluoride reacts with one mole of sulphuric acid to give two moles of HF. The molar mass of calcium fluoride CaF₂ is 78 g/mol the weight taken here is 63 g. Thus number of moles is 63/78 = 0.87 moles.
The molar mass of sulphuric acid H₂SO₄ is 100g/mol. The weight taken here is 75 g and thus, number of moles is 75/100 = 0.75 moles. One mole of calcium fluoride need one mole of H₂SO₄ . Thus 0.87 neede 0.87 moles of H₂SO₄ . But here we have only 0.75. Thus it is the limiting reactant.
As per the reaction, one mole or 100 g of H₂SO₄ produce 2 moles or 40 g of HF (molar mass = 20 g/mol). Thus mass of HF produced from 75 g is calculated as follows:
mass of HF = (75 × 40)/100
= 30 g.
Hence, mass of HF produced in this reaction is 30 g.
To find more about limiting reactant, refer the link below:
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In each case, state whether the forces are balanced or unbalanced. If unbalanced, calculate the net force and describe the direction of the resultant force.
Answer:
Check explanation section.
Explanation:
In order to understand balanced force and unbalanced forces the first law of Newton should be considered as a basic knowledge.
For Balanced forces, there is equal equality in the direction of the forces. In balanced forces, there is no acceleration.
For unbalanced forces, there is acceleration that is go say there is going to be movement. Therefore, net force is equal to unbalanced forces.
(i) Suitcase dropped from a height.
Answer: since there is movement that is acceleration, then the force here is unbalanced force. The resultant force is downwards.towards the greater force direction.
(ii) A bicycle moving with constant velocity on a straight road.
Answer: As the bicycle moves at constant velocity on the straight road the force here is Balanced. Frictional forces balances the forces from the cyclist.
(iii) The rope does not move in a tug of war on applying force at both ends.
Answer: Balanced force.
DESPERATE WILL GIVE BRAILIST AND THANKXS
Which statement is true about a rock layer deposited on top of another rock layer?
A- It is younger than the rock layer below.
B- It is older than the rock layer below.
C- It is the same age as the rock layer below.
D- It is no different than the rock layer below
Hello there!
Your answer is C.
Answer:
The right option is; A. It is younger than the rock layer below.
Explanation:
A rock layer deposited on top of another rock layer is younger than the rock layer below. This is based on the law of superposition which states that in any undeformed sequence of rocks that are laid down in layers, the youngest layer of rock will be on top of the sequence, while the oldest layer will be at the bottom of the sequence.
Which of the following elements would you expect to be ductile and
malleable?
Germanium (Ge)
Argon (Ar)
O O O O
Nitrogen (N)
O Zirconium (Zr)
Answer:
ductile - germanium
mellabe - zirconium
Which of the following is not an example of biased language?
a.
“You are too short to reach that.”
b.
“Are you deaf?”
c.
“Move along, grandpa!”
d.
“I think I’ve been gypped.”
Answer:
I think it is D.
Explanation:
Answer:
b
Explanation:
PLS PLS SOMEONE HELP ME ANSWER THESE QUESTIONS PLEEEAAASSSE!!
(press on the picture so you can see the questions better!)
Answer:
1)conduction
2) convection
3) conduction
4) radiation
5) radiation
6) radiation
7) conduction
8) conduction
9) radiation
10) convection
Explanation:
not 100% sure
Please hurry i really need it fast
The answers are here
In which figure does Colin do work?
A. Figure A
B. Figure B
C. Both figures
D. Neither figure
How many moles of acetaminophen are in a 0.8mL (0.0008L) dose of infants Tylenol
Answer:
0.007 mol
Explanation:
Step 1: Given data
Volume of acetaminophen: 0.8 mL
Step 2: Calculate the mass corresponding to 0.8 mL of acetaminophen
The density of acetaminophen is 1.26 g/mL.
0.8 mL × (1.26 g/mL) = 1 g
Step 3: Calculate the number of moles corresponding to 1 g of acetaminophen
The molar mass of acetaminophen is 151.16 g/mol.
1 g × (1 mol/151.16 g) = 0.007 mol
7. Which of the following is always true when a substance undergoes a
phase change? *
O A. The molecules keep moving at the same average speed.
B. The substance becomes a liquid as it heats up.
C. The melting point of the substance changes.
D. The substance is made up of the same type of molecules.
The following answered has been deleted due to multiple violations to our Terms of Service.
what is the half life of the element in the picture
HELP BRAINLIEST
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days