How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?

a. 45 mL of a 0.10 M solution:
mL

b. 330 mL of a 0.074 M solution:
mL

Answers

Answer 1

Answer:

a. Approximately [tex]1.3\; \rm mL[/tex].

b. Approximately [tex]7.2\; \rm mL[/tex].

Explanation:

The unit of concentration "[tex]\rm M[/tex]" is equivalent to "[tex]\rm mol \cdot L^{-1}[/tex]", which means "moles per liter."

However, the volume of both solutions were given in mililiters [tex]\rm mL[/tex]. Convert these volumes to liters:

[tex]\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L[/tex].

[tex]\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L[/tex].

In a solution of volume [tex]V[/tex] where the concentration of a solute is [tex]c[/tex], there would be [tex]c \cdot V[/tex] (moles of) formula units of this solute.

Calculate the number of moles of [tex]\rm NaCl[/tex] formula units in each of the two solutions:

Solution in a.:

[tex]n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol[/tex].

Solution in b.:

[tex]n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol[/tex].

What volume of that [tex]3.4\; \rm M[/tex] (same as [tex]3.4 \; \rm mol \cdot L^{-1}[/tex]) [tex]\rm NaCl[/tex] solution would contain that many

For the solution in a.:

[tex]\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L[/tex].

Convert the unit of that volume to milliliters:

[tex]\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL[/tex].

Similarly, for the solution in b.:

[tex]\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L[/tex].

Convert the unit of that volume to milliliters:

[tex]\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL[/tex].


Related Questions

How many milliliters of 2.00 M H2SO4 will react with 28.0 g of NaOH?

Answers

Taking into account the reaction stoichiometry and the definition of molarity, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

Reaction stoichiometry

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂SO₄: 1 moleNaOH: 2 moles  Na₂SO₄: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

H₂SO₄: 98 g/moleNaOH: 40 g/moleNa₂SO₄: 142 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂SO₄: 1 mole× 98 g/mole= 98 gramsNaOH: 2 moles× 40 g/mole= 80 gramsNa₂SO₄: 1 mole× 142 g/mole= 142 gramsH₂O: 2 moles× 18 g/mole= 36 grams

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity= \frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Moles of H₂SO₄ required

The following rule of three can be applied: If by reaction stoichiometry 80 grams of NaOH react with 1 mole of H₂SO₄, 28 grams of NaOH react with how many moles of H₂SO₄?

[tex]moles of H_{2}S O_{4} =\frac{28 grams of NaOHx1 mole ofH_{2}S O_{4} }{80 grams of NaOH}[/tex]

moles of H₂SO₄= 0.35 moles

Volume of H₂SO₄ required

In this case, you know:

Molarity= 2 M= 2 [tex]\frac{moles}{liter}[/tex]amount of moles= 0.35 moles

Replacing in the definition of molarity:

[tex]2 \frac{moles}{liter}= \frac{0.35 moles}{volume}[/tex]

Solving:

2 [tex]\frac{moles}{liter}[/tex] × volume= 0.35 moles

volume= 0.35 moles ÷ 2 [tex]\frac{moles}{liter}[/tex]

volume= 0.175 liters= 175 mL (being 1 L= 1000 mL)

Finally, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

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the reaction stoichiometry:

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Everything in outer space including stars, planets, and galaxies
O A. Solar System
B. Universe
OC. Galaxy
D. Biosphere
I

Answers

Answer:

Universe.

Explanation:

Biosphere is just a planet. Solar system contains planets and star. Galaxy holds multiple solar systems only. Universe hold everything, biospheres, solar systems, and galaxies. I hope this helps :D

Answer:

B.

Explanation:

A solar system is IN a galaxy. Its not A.

A Galaxy doesnt have other galaxies in it. Its not c

A biosphere is only referring to earth. its not D.

Therefore, it is B. A universe is everything in outer space including stars, planets, and galaxies.

Sulfur has an electronegativity of 2.58, while Cesium has a value of 0.79. Based on this information, they would have what kind of chemical bond?

Answers

Answer:

Ionic

Explanation:

Because sulphur is a non-metal and cesium is part of the group 1 Alkali Metals, this creates an ionic bond

Ionic bonds are created from one metal and one non-metal element.

This still is declared as Ionic despite the balance of this is Cs2S

Why is Mg++ smaller than Mg atom?​

Answers

Answer:

The magnesium ion is much smaller than the magnesium atom because magnesium atom contains more electrons as compared to magnesium ion. Explanation: ... Whereas when an atom tends to lose an electron then it acquires a positive charge and size of the atom tends to increase.

Answer:

Because it looses it two electrons to form a stable octet Ionic form..........

A very new item just arrived in the market. It is very good for construction, and other things. Now, this item has chemicals, and in every drop, there are 400 grams of NaCI. If there are 10 drops in this item, how many grams of NaCI are in one bottle?

Answers

Answer: 4,000 grams of NaCI

Explanation:

We know that there are 400g of NaCI in one drop.

This bottle has 10 drops of this item.

So, we have to multiply the amount of NaCI in a drop by the amount of drops.

400 x 10 = 4,000.

The answer to the question is 4,000. Hope this helps!

As you move from N to Bi, the metallic properties of the element
A. increases.
C. remains the same.
B. decreases.
D. does not follow a trend.

Answers

Answer:

b. decreases

Explanation:

i just took a test on it

As you move from N to Bi, the metallic properties of the element decrease. The correct option is B.

What are nitrogen and bismuth?

Nitrogen is a chemical element, whose chemical element is N. Nitrogen is a gas and its atomic number is 7. It is a non-metal and is present in group 15 of the periodic table.

Bismuth is a chemical element, whose chemical element is Bi. It is a post-transition metal, and it is also present in group 15 of the periodic table near arsenic and antimony. Its atomic number is 83.

Now, nitrogen and bismuth are present in the same line and group. Nitrogen is the first element of the group and going down, there is bismuth present in the group last. So the metallic property decreases from going down the group.

Thus, the correct option is B. decreases.

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SO3 is a covalent compound with no lone pairs on the central S atom. What's the structure of a molecule of SO3? Is an SO3 molecule polar or non-polar?
Question 14 options:

A)

Trigonal planar, non-polar

B)

Trigonal pyramidal, polar

C)

Trigonal planar, polar

D)

Trigonal pyramidal, non-polar

Answers

Answer:

A

Explanation:

it has non polar molecule, because it has the equal sharing of electrons, so equal repulsion from all sides. atoms are equally represented.

Answer:

Trigonal planar, non-polar

Explanation:

The enthalpy change of reaction 1 is -114 kJ mol-1
reaction 1
2NaOH(aq) + H2SO4(aq)
→ Na2SO4(aq) + 2H2O(1)
By using this information, what is the most likely value for the enthalpy change of reaction 2?
reaction 2
Ba(OH)2(aq) + 2HCl(aq) → BaCl2(aq) + 2H2O(1)​

Answers

Answer:

-114kJ mol-1

Explanation:

Definition of the enthalpy change of neutralization: the energy released with the formation of 1 mole of water when neutralization takes place between an acid and a base.

Since both reactions yield the same number of moles of water, the answer should be -114kJ mol-1.

The statement for the enthalpy change of reaction 2 is "-114 kJ"

What is enthalpy change?

The change in enthalpy (ΔH) is a quantity of heat of a system. The enthalpy change is the amount of heat that enters or exits a system during a reaction.

One equivalent of hydrogen ions is neutralised with one equivalent of hydroxide ions in the reaction 1,

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

The change in enthalpy is given as -114 kJ.

Two equivalents of hydrogen ions are neutralised with two equivalents of hydroxide ions in the reaction 2,

Ba(OH)2 + H2SO4 (aq) → BaSO4 (s) + 2H2O (l)

But, that primary ionic reaction is same for both the reaction in which hydrogen ion combines with hydroxide ion to generate a water molecule. So, the enthalpy change of reaction 1 would be exactly same as for reaction 2.

The neutralization enthalpy comes out to be -114 kJ.

Hence the correct answer is -114 kJ.

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When a metal reacts with hydrogen carbon dioxide gas is produced? True or False

Answers

Answer:

false

Explanation:

"When a metal reacts with hydrogen carbon dioxide gas is produced" statement is false.

What is a chemical equation?

A chemical reaction is a representation of symbols of the elements to indicate the amount of substance and moles of reactant and product.

Generally, metals do not react with hydrogen. But some metals like sodium, potassium, calcium and magnesium force the hydrogen atom to accept the electrons given by these elements and form salt-like ionic solid compounds called metal hydrides.

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Which statement accurate describes plate tectonics?

Answers

Answer:

the lithosphere is broken into sections called plates.

Answer:

The lithosphere is broken into sections called plates.

Explanation:

edge2020

Considering the patterns you have noticed in this activity, which statement best explains why a compound with the molecular formula CH3 doesn't exist in nature?
A. Hydrogen typically needs four bonds to reach a noble gas configuration.
B. Carbon needs more than just three bonds to reach a noble gas configuration. C. The chemical CH3 does not react with other substances because of its high stability.
D. CH3 has three double bonds, which fails to give it a noble gas configuration​

Answers

Answer:

The answer is B

Explanation:

I had the same question and I chose B and it was correct.

Answer:

B. Carbon needs more than just three bonds to reach a noble gas

Explanation:

PLATO ANSWER

PLATO EXPLANATION-

Each hydrogen atom can make only one bond, but a carbon atom needs four bonds to be stable. Therefore, three hydrogen atoms are not enough for the carbon atom to make four bonds.

You have two containers. The first container contains 22.99 grams of solid
sodium (Na). The second container contains 15.999 grams of Oxygen (O).
Which container has more moles of the indicated substance? *

Answers

Answer:

The sodium has more moles.

n(Na)=2.09 mole

n(O)=0.999 mole

2. Suppose 13.7 g of C2H2 reacts with 18.5 g O2 according to the reaction below. C2H2(g) + O2(g) → CO2(g) + H2O(ℓ) a. What is the mass of CO2 produced? b. What is the limiting reagent?

Answers

Answer:

Mass of CO₂ produced = 20.328 g

Oxygen is limiting reagent.

Explanation:

Given data:

Mass of C₂H₂ = 13.7 g

Mass of O₂ = 18.5 g

Mass of CO₂ produced = ?

What is limiting reagent = ?

Solution:

Chemical equation:

2C₂H₂ + 5O₂      →     4CO₂ + 2H₂O

Number of moles of C₂H₂:

Number of moles = mass /molar mass

Number of moles = 13.7 g/ 26.04 g/mol

Number of moles = 0.526 mol

Number of moles of O₂:

Number of moles = mass /molar mass

Number of moles = 18.5 g/ 32 g/mol

Number of moles = 0.578 mol

Now we will compare the moles of CO₂ with C₂H₂ and O₂

                      C₂H₂              :                CO₂

                           2                :                 4

                       0.526            :              4/2×0.526 = 1.052

                      O₂                  :                   CO₂

                        5                   :                     4

                      0.578             :                4/5×0.578 = 0.462

The number of moles of  CO₂ produced by O₂  are less thus oxygen will be limiting reactant.

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 0.462 mol × 44 g/mol

Mass = 20.328 g

Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Write the equation for the ionization of ammonia in water.


List all species present in the solution AND determine the concentrations of each.





Determine the pH of this solution.

Answers

The concentrations : 0.15 M

pH=11.21

Further explanation

The ionization of ammonia in water :

NH₃+H₂O⇒NH₄OH

NH₃+H₂O⇒NH₄⁺ + OH⁻

The concentrations of all species present in the solution = 0.15 M

Kb=1.8 x 10⁻⁵

M=0.15

[tex]\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}[/tex]

[tex]\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21[/tex]

what is the source of the force that moves the tectonic plates along this plate boundary

Answers

Answer:

Mantle convection

Explanation:

The source of the force that moves tectonic plates along plate boundaries is as a result of the mantle convection.

Heat energy produced in the mantle especially from radioactive decay is a very important source of internal heat that drives plate motion. Denser and cold materials close to the over-riding lithosphere above sinks deep into the mantle. Hotter and lighter materials rises to the surface. This sets up a convection cell by which the plates above are driven.

what are the reactants in a cheese sandwich

Answers

Answer:

cheese and bread

Explanation:

2 bread 1 cheese = cheese sandwich

Cheese and Bread
Explanation:

The internal energy of reaction is -855.1). The reaction has a change of
temperature of 63.20°C that consist of 8.85g of material. Assume the
heat capacity of 2.650J/g °C. What is the work energy of this process..

Answers

The work energy of this process : 2337.298 J

Further explanation  

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

ΔU=Q-W

Q=m.c.Δt

[tex]\tt Q=8.85\times 2.650\times 63.2=1482.198~J[/tex]

the work (W) :

[tex]\tt W=Q-\Delta U\\\\W=1482.198-(-855.1)=2337.298~J[/tex]

Alcohol is a
Depressant
Muscle relaxer
Both

Answers

Alcohol is both a Depressant and a Muscle Relaxer. Therefore the answer would be both!

Hope this helps :)

3. What is the pairing arrangement of the nitrogenous bases? _____________ pairs with __________ and ____________ pairs with ___________.

Answers

Answer:

Adenine pairs with thymine and guanine pairs with cytosine

What happens to the gravitational potential energy of an object if you bring it higher with respect to the ground? *

Answers

Answer:

Increases

Explanation:

The gravitational potential energy of an object increases as you bring it higher with respect to the ground.

Gravitational potential energy depends on the mass, height and gravity between two bodies;

   Gravitational potential energy  = mgh

m is the mass

g is the height

h is the height

We can clearly see that the higher the elevation, the more the value of the gravitational potential energy.

Brad pushed a shopping cart directly toward his car at a constant velocity for 6.0 seconds.
During that time, Brad's daughter jogged past him at 2.4 meters per second, and the cart
moved 6.6 meters. What was the cart's velocity?

Answers

Answer:

Watch Naruto that's the answer

Explanation:

What volume of a 0.181 M nitric acid solution is required to neutralize 25.1 mL of a 0.167 M calcium hydroxide solution

Answers

Answer:

46.32 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2HNO₃ + Ca(OH)₂ —> Ca(NO₃)₂ + 2H₂O

From the balanced equation above,

The following data were obtained:

Mole ratio of the acid, HNO₃ (nA) = 2

Mole ratio of the base, Ca(OH)₂ (nB) = 1

Next, we shall write out the data obtained from the question. This includes:

Molarity of the acid, HNO₃ (Ma) = 0.181 M

Volume of the base, Ca(OH)₂ (Vb) = 25.1 mL

Molarity of the base, Ca(OH)₂ (Mb) = 0.167 M

Volume of the acid, HNO₃ (Va) =?

Finally, we shall determine the volume of the acid, HNO₃ as shown below:

MaVa/ MbVb = nA/nB

0.181 × Va / 0.167 × 25.1 = 2/1

0.181 × Va / 4.1917 = 2

Cross multiply

0.181 × Va = 4.1917 × 2

0.181 × Va = 8.3834

Divide both side by 0.181

Va = 8.3834 / 0.181

Va = 46.32 mL

Therefore, the nitric acid, HNO₃ required for the reaction is 46.32 mL

Which determines the reactivity of an alkali metal?

a. it's boiling and melting points
b. the shininess of its surface
c. the number of protons it has
d. it's ability to lose electrons

Answers

Answer:

d. It's ability to lose electrons

how many moles of nitroge are there in 50.0 g of nitrogen?

Answers

1.785714286 moles

The number of moles (n) for nitrogen is: [ n=50.0÷28.0 ] = 1.785714286 moles.

Can someone please help me quick !!!

Answers

2 and 4 is the answer. Because (NO3)2 means you multiply the o3 by 2 giving you 6 oxygen. And then number 2 has O6 which equals 6 oxygen.

Is steel wool and vinegar an exothermic reaction? Explain.

Answers

Answer:

Vinegar contains acetic acid which removes this coating. When the protective coating is removed, oxygen in the atmosphere can reach the iron in the steel wool and a chemical reaction called oxidation occurs. ... This reaction is also an exothermic reaction. It creates heat energy

Explanation:

hope this helps u

Vinegar incorporates acetic acid which gets rid of this coating. When the defensive coating is removed, oxygen in the environment can reach the iron in the metal wool and a chemical reaction called oxidation occurs. This reaction is additionally an exothermic reaction. It creates warmth energy.  

Hope it helped! Have a nice day! <3

state Graham's law diffusion of gas mathematical expression ?​

Answers

Answer:

Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight

Explanation:

A sample of compound contains 5.65x10 21 molecules molar mass of the compound is 89.06g/ mol determine the mass of the sample in grams

Answers

Answer:

Explanation:

no of molecules=5.65*10^21

NA=6.23*10^23

no of moles=no of molecules/avogadro number

no of moles=5.65*10^21/6.23*10^23

no of moles=9.07*10^-3

now we know that

no of moles=mass/molar mass

mass=no of moles*molar mass

mass=9.07*10^-3*89.06

mass=0.808 g

9. What are the advantages of using an indicator to inform pH measurements? What are the advantages of using a pH meter?

Answers

Answer:

The advantages of using an indicator to inform pH measurements:

It gives a mathematically result of the pH, in addition, it gives the precise pH of solvent, and it also gives an idea of the straight of the solution also.

Now, the advantage of using a pH meter:

It is a rapid method to characterize between acids, bases. However, this method does not show how strong acid or base actually are, plus it tends to gives a range of acidity or basicity not quite accurate as a result.

A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine if each addition would exceed the capacity of the buffer to neutralize it.

a. 250 mg NaOH
b. 350 mg KOH
c. 125 g HBr
d. 1.35g Hl

Answers

Answer:

no one additions exceed the capacity of the buffer

Explanation:

given

Volume buffer = 500.0 mL = 0.5 L

mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂

mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻

solution

we know when any base more than 0.05 (HNO2) than exceed buffer capacity

and when any base more than 0.075 (KNO2) than exceed buffer capacity

when we add 250 mg NaOH (0.250 g)

than molar mass NaOH =40 g/mol

and mol NaOH = 0.250 g ÷ 40g/mol

mol NaOH  = 0.00625 mol

0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂

so it would not exceed the capacity of the buffer.

and

when we add 350 mg KOH (0.350 g)

than molar mass KOH =56.10 g

and mol KOH = 0.350 g ÷ 56.10 g/mol

mol KOH = 0.0062 mol

here also capacity of the buffer will not be exceeded

and

now we  add 1.25 g HBr

than molar mass HBr = 80.91 g/mol

and mol HBr = 1.25 g  ÷ 80.91 g/mol

mol HBr = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻  

so the capacity will not be exceeded.

and

we add 1.35 g HI  

molar mass HI = 127.91 g/mol

so mol HI = 1.35 g ÷ 127.91 g/mol

mol HI = 0.011 mol

capacity of the buffer will not be exceed

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