Hi! Please help me!
Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a
resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total
resistance in the
circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t =
1207
+ 120
Find the inverse of Janine's equation.
Look at photo below
Thank you have a nice day:)
Answers
Answer:
The answer is t^-1 (r)=120r/120-r
i hope this is right sry if im wrong have a good day :)
The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).
According to the question
Janine is building a circuit that contains two lightbulbs in parallel.
One of the lightbulbs has a resistance of 120 ohms.
R = 120ohms
r = resistance of the second lightbulb
t = total resistance in the circuit
[tex]t = \frac{120r}{r+120}[/tex]
Now,
The inverse of Janine's equation in which we will make r independent
[tex]t = \frac{120r}{r+120}[/tex]
[tex]t(r+120) = 120r[/tex]
[tex]tr + 120t = 120r[/tex]
[tex]120t = 120r - tr[/tex]
[tex]120t = r(120-t)[/tex]
[tex]r = \frac{120t}{120-t}[/tex]
Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
To know more about resistance here:
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Answer:
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Step-by-step explanation:
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