Answer:
Least to greatest: (D), 6/25, 0.243, 24.5%,
Step-by-step explanation:
6/25=0.240
0.243=0.243
24.5%=0.245
-3x+3=-7x-1 and you solve for x
Answer:x=-1
add 1 to 3 to get 4, add 3 to -7 to get -4, divide both sides by -4
Answer:
-1[tex] \: [/tex]
Step-by-step explanation:
Given Equation,
[tex] \\ {\longrightarrow \qquad{ \sf{-3x+3=-7x-1}}}\\ \\ [/tex]
Adding 7x to both sides we get,
[tex]{\longrightarrow \qquad{ \sf{-3x+3 + 7x=-7x-1 + 7x}}}\\ \\ [/tex]
[tex]{\longrightarrow \qquad{ \sf{4x+3=-1}}}\\ \\ [/tex]
Subracting -3 from sides we get,
[tex] \\ {\longrightarrow \qquad{ \sf{4x+3 - 3=-1 - 3}}}\\ \\ [/tex]
[tex]{\longrightarrow \qquad{ \sf{4x=-4}}}\\ \\ [/tex]
Dividing both sides by 4 we get,
[tex] \\ {\longrightarrow \qquad{ \sf{ \frac{4x}{4} = \frac{ - 4}{4} }}}\\ \\ [/tex]
[tex]{\longrightarrow \qquad{ \sf{x=-1}}}\\ \\ [/tex]
Write an equation to solve for x.
Answer:
3x - 35 = 130
Step-by-step explanation:
Vertically opposite angles are congruent.
3x - 35 = 130
hope it helps ~
Colton has watched 222 comedy movies for every 333 other movies. He has watched 303030 total movies.
Complete the table. will mark brainlyest
The total ratio is 5
The number of comedy movies watched is 12
The number of other movies watched is 18
What is a ratio?
Ratio is a comparison of two or more numbers that indicates their sizes in relation to each other. Therefore,
He has watched 2 comedy movies for every 3 other movies. The total movies he has watched is 30. Therefore,
2:3Ratio of comedy to total movies is as follows:
2 : 5number of comedy movies watched = 2 / 5 × 30 = 60 / 5 = 12
number of other movies watched = 3 / 5 × 30 = 90 / 5 = 18
Therefore,
total ratio = 5
number of comedy movies watched = 12
number of other movies watched = 18
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:)
Comedy movies- 2 (12)
Other movies- 3 (18)
Total movies- (5) 30
what 5 times 5 plus 4
Answer:
29
Step-by-step explanation:
5x5=25
25+4=29
First for 5 times 5 u do 5x5=25 and for (5x5) plus four u add 4 to the answer of 5 times five which makes 29.
Answer:
The answer is 29
Step-by-step explanation:
5 times 5 plus 4
5 × 5 + 4
Use BODMAS
(Bracket of Division, Multiplication, Addition and Subtraction)
(5 × 5) + 4 = 25 + 4 = 29
Thus, The answer is 29
-TheUnknownScientist 72
I honestly need the answers for this quickly, tri ends in a few days, and everything locks tomorrow.
Answer:1) 1/12 2)21/5 3) 9/25.
Step-by-step explanation:
5x1/12x5 is 5/60, which is 1/12. 4 2/3 is 14/3. 14x9/3x10 is 126/30, or 21/5. 36 percent is 36/100. Divide by 2. 18/50. Divide by two again, 9/25.
If m Greater-than-or-equal-to n, which inequalities must be true? Check all that apply. M 2. 1 Greater-than-or-equal-to n 2. 1 m - (-4) Greater-than-or-equal-to n -(-4) m - 3 Greater-than-or-equal-to n 3 16. 5 m Greater-than-or-equal-to 16. 5 n m Greater-than-or-equal-to n One-half 6 m Greater-than-or-equal-to 9 n.
The inequalities that must be true if m is greater-than-or-equal-to n are given as:
Option 1: [tex]m \times 2.1 \geq n \times 2.1[/tex]Option 2: [tex]m - (-4) \geq n - (-4)[/tex]Option 4: [tex]16.5m \geq 16.5n[/tex]What operations are allowed in inequalities?Only those operations are allowed which are sure to not modify the inequality between the expressions in the statement.
Some operations that are sure not to modify the inequalities are:
Addition, Subtraction, multiplication by positive real numbers, division by positive real numbers etc.
Example, if 5 > 2, then you can do whatever which keeps the term on the side of 5 bigger than the terms formed on side of 2.
Thus, 5 + 1 > 2 + 1 is correct, (it was addition of 1, a real number).
For the considered case, we're given that:
[tex]m \geq n[/tex]
Checking all the options sequentially, we get:
Case 1: [tex]m \times 2.1 \geq n \times 2.1[/tex]It must be true, since the multiplication is done by 2.1, which is > 0
Case 2: [tex]m - (-4) \geq n - (-4)[/tex]It must be true since -4 is a real number, and addition or subtraction of any real number (if done on all the sides of the statement) doesn't change the inequality
Case 3: [tex]m - 3 \geq n + 3[/tex]From [tex]m \geq n[/tex], addition or subtraction is guaranteed to not change the inequality only if they are of same quantity on all the sides of the inequality. Thus, this inequality is not necessary to be true.
Example, if we take m = 5, n =3, then,
[tex]5 \geq 3[/tex] but [tex]5 - 3=0 \: \rm and \: 3 + 3= 6 \implies 5-3 < 3 + 3[/tex]
Case 4: [tex]16.5m \geq 16.5n[/tex]It must be true if given that [tex]m \geq n[/tex] since multiplication of equal positive real number on both the sides of [tex]m \geq n[/tex] was done.
Case 5: [tex]\dfrac{1}{2} 6m \geq 9m[/tex]one-half of 6 = 3, thus, this inequality means [tex]3m \geq 9m[/tex]
Dividing both the sides by 3, we get:
[tex]m \geq 3n[/tex]
It is not necessary to be true if [tex]m \geq n[/tex]. Example
[tex]3 \geq 2\\but\\ 3 < 3 \times 2 = 6[/tex]
Thus, the inequalities that must be true if m is greater-than-or-equal-to n are given as:
Option 1: [tex]m \times 2.1 \geq n \times 2.1[/tex]Option 2: [tex]m - (-4) \geq n - (-4)[/tex]Option 4: [tex]16.5m \geq 16.5n[/tex]Learn more about inequality here:
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The solutions to the equation (IMG) are (IMG) or (IMG)
.
Answer:
Step-by-step explanation:
First of all, you have to set up the equation
2x^2 + x -1 = 2 Subtract 2 from both sides
2x^2 + x - 1 - 2 = -2+2 Combine
2x^2 + x - 3 = 0 This factors.
(2x + 3)(x -1 ) = 0
Either
2x + 3 = 0 Subtract 3 from both sides
2x = - 3 Divide by 2
2x/2 = - 3/2
x = - 3/2 which you already know
or
x - 1 = 0 Add 1
x - 1 + 1 = 1
x = 1
the other answer is x = 1
3. A rock is thrown from the top of a tall
building. The distance, in feet, between the
rock and the ground t seconds after it is
thrown is given by
d(t) =
4t + 382.
- 16t²
a. How long after the rock is thrown is it
370 feet from the ground?
b. After how many seconds will the rock
reach the ground?
c. What is the height of the rock when it
is halfway to the ground?
Answer:
Step-by-step explanation:
d(t) = 4t + 382 - 16t²
where d is the distance (in feet) between the rock and ground t seconds after thrown. Ground is 0 feet. As a note, I'm not clear why the "4t" term is in this equation. It has the effect of adding an increase in height at the rate of 4 feet/sec. I'll assume this is to accommodate any increase in height due to the throw, but it is a bit curious.
a. How long after the rock is thrown is it 370 feet from the ground?
The 382 in the equation represents the starting height of the rock (382 feet). To find the time to reach 370 feet:
370 = 4t + 382 - 16t²
Solve using the quadratic equation. There will be two answers, one negative, which we'll discard until we can go backwards in time. The positive value is 1, which would mean the rock will be at 370 feet in 1 second after throwing.
b. After how many seconds will the rock reach the ground?
Ground is 0 feet:
0 = 4t + 382 - 16t²
t = 5 seconds
c. What is the height of the rock when it is halfway to the ground?
The initial height is 382 feet, as per the equation, since when t = o (initial), d(t) is 382 feet. Halfway to the ground would be (382/2) or 191 feet.
2 sin x cos x = tan x
Answer:
If [tex]sin x = 0[/tex] we get [tex]2 (0) (\pm1) = 0[/tex] which is true. so we have a first set of solutions given by
[tex]x= 0; x = \pi[/tex];
Else, if [tex]sin x \ne 0[/tex] we can divide both sides by it and we get
[tex]2 cos x = \frac 1 {cos x} \rightarrow 2cos^2x =1 \rightarrow cos^2x =\frac12\\cos x= \pm \frac{\sqrt2}2[/tex]
Which gives us a second set of solutions given by [tex]x= \frac{\pi}4;x= \frac{3\pi}4; x= \frac{5\pi}4;x= \frac{7\pi}4[/tex];
We can group all solutions (doesn't matter, but it's more elegant!) by writing
[tex]x= k\frac{\pi}4; k\in \{0,1,3,4,5,7\}[/tex]
How many minutes are in 3 hours and
25 minutes?
A recipe for rice pudding calls for 2 1/2 cups of milk. The recipe makes 5 servings. How many cups of milk are needed to make 8 servings?
Find the missing number so that the equation has infinitely many solutions.
3x + 20 = 4x + __ - x
A circle has a central angle measuring StartFraction 7 pi Over 10 EndFraction radians that intersects an arc of length 33 cm. What is the length of the radius of the circle? Round your answer to the nearest whole cm. Use 3. 14 for Pi. 11 cm 15 cm 22 cm 41 cm.
The radius of the given circle with a central angle of 7π/10 and arc length of 33cm is 15cm.
It is given that
The central angle of the given circle = 7π/10 radians
Length of arc = 33cm
What is the formula for arc length?Arc length = central angle* radius
From the above formula
Radius = Arc length/Central Angle
Radius = [tex]\frac{33}{(7\pi)/10 }[/tex]
Radius = 15cm
Therefore, radius of the given circle is 15cm.
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Answer:
15 cm or B on egde
Step-by-step explanation:
Using the net below, find the surface area of the triangular prism.
160 i believe. to find the area of a triangle act like its a square and divide in half. for squares multiply base by height.
take the area of each shape and add it up
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP
Answer:
A. (-3,1)
Explanation:
if you invert the point over the Y-axis, then it will switch the x point to negative.
I need these answers please
Solve for n n/3 - 2 = 2
n/3-2 = 2
n/3 = 4
n = 12
The solution to the algebraic equation, n/3 - 2 = 2, is: n = 12.
How to Solve an Algebraic Equation?If given an algebraic equation, such as n/3 - 2 = 2, to solve for n, you have to isolate n as shown below:
n/3 - 2 = 2
Add 4 to both sides of the equation
n/3 = 2 + 2
n/3 = 4
Multiply both sides by 3
n = (4)(2)
n = 12
Therefore, the solution to the algebraic equation, n/3 - 2 = 2, is: n = 12.
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Help me pleaseee !!!!!!
please help me first right get breainlest
Answer:
Tm = 6 - Ts
Step-by-step explanation:
We are given an equation and the variables that go with each part of the equation.If the equation is RmTm + RsTs = 170...And Rm is 20, Rs is 30, and Tm is Ts + 1...Then we can plug those variables in and solve algebraically.Currently we have 20 • (Tm + 1) + 30 • Ts = 170Subtract 30 from both sides.Now we have 20 • (Tm + 1) • Ts = 140Distribute 20.Now we have 20Tm + 20 • Ts = 140Subtract 20 from both sides.Now we have 20Tm • Ts = 120Divide 20Tm by 20, then divide 120 by 20.Tm • Ts = 6.Subtract Ts from both sides.Tm = 6 - Ts.If I am incorrect in my reasoning, please let me know so that I can plan better for my future answers. Have an amazing day.
the ratio of boys and girls at a school is 7:3 if there are 350 learners in the school,how many boys are there
Find the area.
5 cm
5 cm
16 cm---
7 cm
14 cm
Answer:
if it is area of triangle it would be 49
Step-by-step explanation:
(please help!) Find the surface area of the prism.
Answer:
42 sq ft
Step-by-step explanation:
L x W x H
3 x 7 x 2
21 x 2
42 sq ft
To solve a linear equations in one variable we use elimination method or
Answer:
[tex]\displaystyle Substitution[/tex]
Explanation:
Elimination and Substitution are two methods to use when solving systems of equations in two and three variables [tex]\displaystyle [z, y, and\:x].[/tex]With Elimination, you decide on which pair of variables you want to eradicate so they are set to zero, whereas Substitution is mainly used when one variable is automatically isolated. If not, then you must manually decide on which variable to isolate as well as the equation you want to wourk.
I am joyous to assist you at any time.
I really need help quick
y = x² -4x
find values of x when y=2
with explanation please
Answer:
[tex]\sf x=2+\sqrt{6},\:x=2-\sqrt{6}[/tex]
Explanation:
[tex]\sf y = x^2 -4x[/tex]
given that y = 2
[tex]\sf x^2 -4x = 2[/tex]
[tex]\sf x^2 -4x -2 = 0[/tex]
using quadratic formula:
[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ \ when \ ax^2 + bx + c = 0[/tex]
[tex]\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}[/tex]
[tex]\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}[/tex]
[tex]\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}[/tex]
in decimals:
[tex]\rightarrow \sf x=4.45 , \ -0.45[/tex]
Guys please help!!
If you have exponents in your answer use ^ for example:
2^3 = two to the power of three
Answer:
5x^2 - 8x - 32
Step-by-step explanation:
Area of rectangle = base x height
Area of larger rectangle = (3x - 8)(2x + 4)
= 6x^2 - 4x - 32
Area of smaller rectangle = (x + 4)x
= x^2 + 4x
Area of shaded region = area of larger rectangle - area of smaller rectangle
= (6x^2 - 4x - 32) - (x^2 + 4x)
= 5x^2 - 8x - 32
help please bestie :,)
Answer:
C. 1200 yds
Step-by-step explanation:
Each cm equals 10 yards, so start by multiplying the 3cm and 8 cm by 10. Then all you do is insert those numbers into the equation for the area of a triangle which is 1/2BH
1/2*80*30=1200
Answer:
C. 1,200 yds
Step-by-step explanation:
To find the area of a triangle, you must use the triangle area formula, [tex]A = \frac{1}{2}(b*h)[/tex].
Since 1 cm = 10 yards, then 8 cm = 80 yards and 3 cm = 30 yards. You can use 80 yards as your base and 30 yards as your height to find the area:
[tex]A=\frac{1}{2} (80*30)[/tex]
[tex]A=\frac{1}{2} (2400)[/tex]
[tex]A=1200[/tex]
Therefore, the answer is C. 1,200 yards.
I hope this helps!
Help!! Irrelevant answers will be deleted. Thank you so much!!
Answer:
k = 30; y = 30/xy = 9; y = 36/xx = 5/2; k = 50y = 2; k = 24Step-by-step explanation:
When we say "y varies inversely as x", we mean that y is proportional to the inverse of x: y = k·(1/x). This relation is usually written ...
y = k/x
It can be solved for the other values:
xy = k . . . . multiply by x
x = k/y . . . divide by y
If you are given the equation, the value of k can be read directly from it: it is the constant in the numerator.
__
a)k = xy = 5·6 = 30; the equation is y = 30/x
b)y = k/x = 36/4 = 9; the equation is y = 36/x
c)k = 50 (read from the equation); x = k/y = 50/20 = 5/2
d)k = 24 (read from the equation); y = k/x = 24/12 = 2
An incident ray strikes a piece of diamond at an angle of 40. 5 degrees. The index of refraction of air is 1. 0003 and the index of the refraction of diamond is 2. 42. What is the angle of refraction? degrees.
The angle of refraction is 15.6 deg.
We have given that An incident ray strikes a piece of diamond at an angle of 40. 5 degrees.
What happen when light passes through one medium to another medium?When a ray of light passes from medium 1 to medium 2, the refractive index of medium 2 with respect to 1 is the ratio of the absolute refractive index of medium 2 and medium 1
[tex]1n_{2}=\frac{^{n_{1}}}{n_{2}}[/tex]
When light passes from air into diamond, with the given values of refractive indices,
[tex]an_{d}=\frac{^{n_{d}}}{n_{a}}=\frac{2.42}{1.0003} =2.4193[/tex]
According to Snell's law,
[tex]an_{d}=\frac{^{sini}}{sin r}[/tex]
[tex]< br/ > sinr=an_{d}=\frac{^{sini}}{sin r}=\frac{sin(40.5)}{2.41930} =0.2684[/tex]
[tex]< br/ > r=arcsin(0.2684)=15.57 deg[/tex]
The angle of refraction is 15.6 deg
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b. a cylinder with radius 3 inches and height 4 inches
What is the volume in cubic inches?
The volume of the cylinder is [tex]\pi r^{2}h[/tex]
r: radius --> 3 inchesh: height --> 4 inchesVolume = [tex]\pi 3^{2} * 4=113.097[/tex] cubic inches (approximated)
Hope that helped!
Please help. I don’t know the answer.
Answer:
y^12/5 aka the first option
Step-by-step explanation:
(9x^5y^16)/(45x^5y^4)
rules of exponents say youll do 5-5 because when dividing with exponents you subtract them
you get x^0 which is equal to 1 due to another rule of exponents
youll do 16-4 next and get 12 so y^12
now 9/45=5
the answer is (y^12)/5 (the first option)