Find the height of a rectangular prism
with surface area of 286 square inches and a
base measuring 7 x 9 inches

[tex]\qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ 9n^2-3n-8=-10\implies 9n^2-3n+2=0 \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{9}n^2\stackrel{\stackrel{b}{\downarrow }}{-3}n\stackrel{\stackrel{c}{\downarrow }}{+2}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases}[/tex]

[tex](-3)^2-4(9)(2)\implies 9-72\implies -63\leftarrow \stackrel{\textit{two \underline{imaginary} solutions}}{\textit{no real solution}} \\\\[-0.35em] ~\dotfill\\\\ -2x^2-8x-14=-6\implies -2x^2-8x-8=0 \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{-8}x\stackrel{\stackrel{-8}{\downarrow }}{-8}=0\qquad \qquad \qquad \qquad (-8)^2-4(-2)(-8) \\\\\\ 64-64\implies 0\leftarrow \textit{one \underline{real} solution}[/tex]

The perimeter of the figure, rounded to the nearest tenth is: 17.2 units.

Perimeter of a figure is the total length of all sides of the figure.

The distance formula, [tex]d = \sqrt{(x_2 - x_2)^2 + (y_2 - y_1)^2}[/tex], can be used to find the length of each segment of a figure on a coordinate plane.

Thus, we have:

A(0, 4)

B(4, 4)

C(1, 0)

D(4, 1)

Perimeter of the figure = AB + BC + CD + DA

AB = |4 - 0| = 4 units

BC = √[(1−4)² + (0−4)²]

BC = √25

BC = 5 units

CD = √[(1−4)² + (0−1)²]

CD = √10

CD = 3.2 units

DA = √[(0−4)²+ (4−1)²]

DA = √25

DA = 5 units

Therefore:

Perimeter of the figure = 4 + 5 + 3.2 + 5 = 17.2 units.

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Answer:

Wind. “The most common source or cause of damage is wind-related,” Scott Humphrey, second vice president of risk control at Travelers, told TODAY Home. ...

Nonweather-Related Water. ...

Hail. ...

Weather-Related Water.

Theft.

hope i correct

Answer:

4 feet wide because to find the perimeter you add all the numbers around

The value of d when h is 500m is approximately 1,813m

Give the heights above the ground (hm) after it has dropped expressed as:

h = 3/8(d-480),

If h = 500m, then;

500 = 3/8(d - 480)

Cross multiply

500*8 = 3(d - 480)

4000 = 3(d - 480)

Expand to have:

4000 = 3d - 1440

3d = 5440

d = 1,813.3m

Hence the value of d when h is 500m is approximately 1,813m

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Answer:

C

Step-by-step explanation:

D: {-3,0,1,3}

R: {-5,-4,1,5}

[tex]f(x) = (tan(5x)+2)^2\\\\f'(x) = 2(tan(5x) +2)*\frac{d}{dx}(tan(5x)+2) = 2(tan(5x)+2)*5sec^2(5x)\\ =(2tan(5x)+4)*5sec^2(5x)\\ =10tan(5x)*sec^2(5x)+20sec^2(5x)[/tex]

Hope that helps!

Answer:

  $17,922.55

Step-by-step explanation:

The future value of a one-time investment is calculated using the formula ...

  FV = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years.

__

You have FV = 44000, r = 0.05, n = 12, t = 18, and you want to find P.

  44000 = P(1 +0.05/12)^(12·18) ≈ 2.455008P

  P = 44000/2.455008 = 17,922.55

The couple must deposit $17,922.55 in order to have $44,000 in 18 years.

_____

Additional comment

Some calculators, all spreadsheets, and a number of apps can make this calculation for you. All you must do is fill in the numbers.

The width of the cloud is 12500 meters wide.

The situation forms a right angle triangle.

Right angle triangle are triangle that has one of its sides as 90 degrees. The sides can be found using trigonometric ratios.

Therefore, the altitude is the opposite side of the triangle formed. The width of the cloud is the adjacent side of the triangle formed.

tan 10 = opposite / adjacent

Therefore,

tan 10° = 2200 / a

cross multiply

a = 2200 / tan 10°

a = 2200 / 0.1763269807

a = 12500 meters

Therefore, the width of the cloud is 12500 meters .

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Answer:

x=14

Step-by-step explanation:

subtract 2 from both of the sides

70=5x

divide each side by 5

x=14

Answer:

Physical activy used for pleasure.

Step-by-step explanation:

It's just a meaning so I can't provide an explanation.

Answer:

30

Step-by-step explanation:

5% of 600 is 30 so that should be ur answer

Answer:

20b

Step-by-step explanation:

3+8+9

3+8=11

9+11=20

3b+8b+9b

3b+8b=11b

11b+9b=20b

Answer:

Since they all have the same variable, you add them all together. so it would be 20b !!

Step-by-step explanation:

Answer:

(1, 15), (2, 30), (3, 45), (4, 60)

Step-by-step explanation:

So the values are already given to you in the table, it's just a matter of turning them into ordered pairs. Ordered pairs are a set of numbers that represent a point on the coordinate plane. On the graph, the x-axis (horizontal) is for time and the y-axis (vertical) is for the amount of push-ups. An ordered pair is (x, y) so you put (amount of minutes, amount of push-ups). For how they're related, how many push-ups he did increases by 15 for every minute. So, the y-value increases by 15 when the x-value increases by 1.

Answer:

(32,92) and (−1,2)

Step-by-step explanation:

You have to equal the two Ys, meaning their values as well or you can find the value of the first x and then plug it in the second equation. There are many ways to solve this to.

Answer:

1.3n + 9.6

Step-by-step explanation:

3.4n + 9.6 - 2.1n

So you can rearrange it to make it visually easier (but it's not needed)

3.4n - 2.1n + 9.6

Subtract like terms

1.3n + 9.6

Answer:

It's 96%

Step-by-step explanation:

Just took the test

The profit from the store in town B compared with the profit from the store in town A is the ratio represented by 96%.

The ratio is the simplest form of a fraction involving two quantities determining each other. It is written as a:b, read as "a is to b", and functions as a/b.

In the question, we are given that a business owner opens one store in town A. The equation p(x)= 10,000(1.075)^t represents the anticipated profit after t years. The business owner opens a store in town B six months later and predicts the profit from that store to increase at the same rate.

We are asked to assume that the initial profit from the store in town B is the same as the initial profit from the store in town A and find the comparison between the profits from the store in town B to the store in town A.

We take the time for the store in town A as t1.

Then the time for the store in town B is t1 - 0.5, as store in town B is opened 6 months after the store in town A.

To compare the profits, we take the ratio of the profits from the stores.

= Profit from the store in town B/Profit from the store in town BA

= 10,000(1.075)^(t1 - 0.5)/10,000(1.075)^t1

= (1.075)^(t1 - 0.5 - t1)

= 1.075^(-0.5)

= 1/(1.075)^0.5

= 0.96448

= 96% (approx.)

Therefore, the profit from the store in town B compared with the profit from the store in town A is the ratio represented by 96%.

Refer to the attachment for the proper question.

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Answer:

y=(5/8)x+2

Step-by-step explanation:

Equation of Line in Slope-Intercept Form is y=mx+c

where m is the Slope and c is the y-intercept

so for our Problem

m=5/8 and c=2

y=(5/8)x+2

Answer:

Step-by-step explanation:

The general equation is y = mx + b

The slope is m

and b is the y intercept.

Now all you need do is substitute the values given for m and b

m = 5/8 = 0.625

b = 2

Answer

Answer:

8. B.

9. B.

10. B.

11. No answer choices.

Step-by-step explanation:

Yes, they are all actually B. Hope this helps!

Answer: B, B, B

Step-by-step explanation: The last question has no answer choices shown.

Answer:

thought they were to hard

get them correct il give brainlist

Answer:

4.) 15

Step-by-step explanation:

90 - 75 = 15 which would be the answer.

Answer:

answer is 2.8 im not sure so check with another person mark me as brainliest

Step-by-step explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

Answer:

A= 19 1/4

Step-by-step explanation:

to find the area of a rectangle, it would be LxW

so you would take 5 1/2 x 3 1/2. this would give you 19 1/4

Answer:

81 inches is 6.75 feet

Step-by-step explanation:

hope this helps

Answer:

6.75

Step-by-step explanation:

Given;

81 Inches to Feet

Note;

Formula of Inches to Feet : divide the length value by 12

Solve;

81/12 = 6.75

Thus, Result of converting 81 inches to feet is 6.75

[RevyBreeze]

Answer: z = 3

Step-by-step explanation: 1 centimeter = 1 month so 3 centimeter = 3 months

The series you had provided is generally the Maclaurin's series , and we want to prove the series , this series is very very much useful in calculus , especially when you have to substitute a function by it's series . So now let's start !

Consider the function f(x) as series of a polynomials of nth (n ≥ 1) degree as

[tex]{\boxed{\bf{f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}}}[/tex]

Now , at x = 0

[tex]{:\implies \quad \sf f(0)=a_{0}+a_{1}(0)+a_{2}(0)^{2}+a_{3}(0)^{3}+a_{4}(0)^{4}+\cdots \cdots \infty}[/tex]

[tex]{\boxed{:\implies \quad \sf f(0)=a_{0}}}[/tex]

Now , again consider the function that we assumed

[tex]{:\implies \quad \sf f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}[/tex]

Differentiating both sides w.r.t.x will yield

[tex]{:\implies \quad \sf f^{\prime}(x)=0+a_{1}\times 1+a_{2}\times 2\times x+a_{3}\times 3\times x^{2}+a_{4}\times 4\times x^{3}+\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime}(x)=a_{1}+2a_{2}x+3a_{3}x^{2}+4a_{4}x^{3}\cdots \cdots \infty}[/tex]

Now , put x = 0 ;

[tex]{:\implies \quad \sf f^{\prime}(0)=a_{1}+2a_{2}(0)+3a_{3}(0)^{2}+4a_{4}(0)^{3}\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime}(0)=a_{1}}[/tex]

[tex]{\boxed{:\implies \quad \sf a_{1}=\dfrac{f^{\prime}(0)}{1!}}}[/tex]

Now , consider ;

[tex]{:\implies \quad \sf f^{\prime}(x)=a_{1}+2a_{2}x+3a_{3}x^{2}+4a_{4}x^{3}\cdots \cdots \infty}[/tex]

Differentiating both sides w.r.t.x now ;

[tex]{:\implies \quad \sf f^{\prime \prime}(x)=0+2\times a_{2}\times 1+3\times a_{3}\times 2\times x+4\times a_{4}\times 3\times x^{2}\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime \prime}(x)=2a_{2}+6a_{3}x+12a_{4}x^{2}+\cdots \cdots \infty}[/tex]

Now , putting x = 0 will yield ;

[tex]{:\implies \quad \sf f^{\prime \prime}(0)=2a_{2}+6a_{3}(0)+12a_{4}(0)^{2}+\cdots \cdots \infty}[/tex]

[tex]{:\implies \quad \sf f^{\prime \prime}(0)=2a_{2}}[/tex]

[tex]{\boxed{:\implies \quad \sf a_{2}=\dfrac{f^{\prime \prime}(0)}{2!}}}[/tex]

Now , similarly we can prove that ;

[tex]{\boxed{:\implies \quad \sf a_{n}=\dfrac{f^{n}(0)}{n!}}}[/tex]

Now , as we had considered ;

[tex]{:\implies \quad \sf f(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}+\cdots \cdots \infty}[/tex]

Now , putting the values we obtained above ;

[tex]{:\implies \quad \sf f(x)=f(0)+\dfrac{x}{1!}f^{\prime}(0)+\dfrac{x^2}{2!}f^{\prime \prime}(0)+\dfrac{x^3}{3!}f^{\prime \prime \prime}(0)+\dfrac{x^4}{4!}f^{\prime \prime \prime \prime}(0)+\cdots \cdots \dfrac{x^n}{n!}f^{n}(0)+\cdots \cdots \infty}[/tex]

Hence , Proved