Explain How you get -8 whe solving -5+-3

Answer:

x²⁰y⁷

____

2

Step-by-step explanation:

multiply

combine exp

cancel terms

combine multiplied terms

combine exp

Answer:

ANSWER (A.

Step-by-step explanation:

HOPE IT HELP'S !

Answer:

Well my answer is high data set I took the test and got 100%

Step-by-step explanation:

Answer:

High

Step-by-step explanation: I took the test.

Answer: 6x² - 20x + 6

Step-by-step explanation:

x(6x - 2) -3(6x - 2)

= 6x² - 2x - 18x + 6

= 6x² - 20x + 6

Answer:

HOP IT HELPS

3/8=1.5/4

because when you divide

3÷2 and 8÷2

you get

1.5/ 4

Answer:

1/2

Step-by-step explanation:

3/8 to the nearest 1/2.

The question wants to know if you round 3/8 to the nearest half, what value would that be?  On a number line from 0 to 1, we could mark every 1/8 unit:

0/8==1/8==2/8==3/8==4/8==5/8==6/8==7/8==8/8

Note that 0/8 is 0, 4/8 is 1/4 and 8/8 is 1.

3/8 is one step from 4/8, or 1/2.  So the nearest half would be 1/2.

Answer:

2

Step-by-step explanation:

subtract 15 from 30 till u have 0 and count how many times u subtracted 15 from 30

Answer:

2

Step-by-step explanation:

30÷15=2

so 15 goes into 30 2times

Answer:

Approximately 1.6

Step-by-step explanation:

To graph. a function, let use desmos or graphing calculator.

Here the function.

The length of the pendulum as shown here when x=2, is 1.6

Given :

To Find :

Solution :

Area of the outer circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}} [/tex]

⠀

Area of the inner circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}} [/tex]

⠀

Therefore,

Area of the region inside the circular paths :

[tex]\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}[/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}[/tex]

Answer:

12

Step-by-step explanation:

[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]

[tex]\longrightarrow[/tex]Since angle X and Y have a sum of 159

[tex]\implies \bf Y + X= 159 \_\_\_\_(1) [/tex]

[tex]\longrightarrow[/tex]Since X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -

[tex]\implies \bf Y - X = 43 \_\_\_\_(2) [/tex]

Adding Equation (1) and (2)

[tex]\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered} [/tex]

Putting Y in eq (1)

[tex]\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf X = 153-101 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf{ X = 52 }}\\\end{gathered} [/tex]

Answer:

-6

Step-by-step explanation:

-1 * 2 * 3

= -2 * 3

= -6

Answer:

-1 x 2 = -2

-2 x 3 = -6

Answer:

-6

Answer: 360000m

Step-by-step explanation:

Okay, so since we know that this train’s speed is 200km/h, let’s find the time difference between 12 24 and 14 12.

14 12 - 2hrs = 12 12

12 12 + 12min = 12 24

2hrs -12min = 1hr 48 min

1hr 48 min also equals to 1.8hrs in decimals. So:

200km x 1.8 = 360km

Now we have to find the answer in meters. Since 1km is equal to 1000m,

That means 360km equals 360000m.

Therefore 360000m is the answer

Step-by-step explanation:

[tex]V = \frac{ER}{R + a} [/tex]

[tex]V(R+a)=ER[/tex]

[tex]VR + Va=ER[/tex]

[tex]Va= ER-VR[/tex]

[tex]Va=R(E-V)[/tex]

[tex]R = \frac{Va}{E-V} [/tex]

2x - 5y = 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.

[tex]\rm{2x - 5y = 1 }\\ [/tex]

[tex] \rm{2x - 5y + 5y = 1 + 5y}\\[/tex]

Subtract -5y from both sides of the equation

Simplify 2x - 5y + 5y = 1 + 5y

Cancel -5y with 5y

Reorder 1 + 5y so highest order terms are first

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Move factors not having X from the left side of equation 2x = 5y + 1

[tex] \rm{ \frac{2x}{2} = \frac{5y + 1}{2} } \\ [/tex]

Divide both sides of equation 2x = 5y + 1 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}x}{\cancel{2}} = \frac{5y + 1}{2} } \\ [/tex]

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Therefore, the x of 2x - 5y = 1 is [tex] \rm{ \frac{5y + 1}{2} } [/tex]

2x - 5y = 1

[tex]\rm{-5y + 2x = 1}\\ [/tex]

Reorder 2x -5y so highest order terms are first

-5y = -2x + 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1

[tex]\rm{-5y + 2x - 2x = 1 - 2x}\\[/tex]

Subtract 2x from both sides of the equation

Simply - 5y + 2x -2x = 1 - 2x

Cancel 2x with -2x

Reorder 1 - 2x so highest order terms are first

[tex] \rm{y = - \frac{2x + 1}{5} }\\[/tex]

Move factors not having y from the left side of equation -5y = -2x + 1

[tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} }\\ [/tex]

Divide both sides of equation -5y = -2x +1 by -5

Simplify [tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} } [/tex]

Cancel 5 with -5

Resolve sign on fraction [tex] \rm{\frac{ - 2x + 1}{ - 5} }[/tex]

Therefore, the y of 2x-5y = 1 is [tex]\rm{\frac{ - 2x + 1}{ - 5} } [/tex]

3x + 2y = 11

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y

Subtract 2y from the both sides of the equation

Simplify 3x + 2y - 2y = 11 - 2y

Cancel 2y with 2y

Reorder 11 - 2y so highest order terms are first

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Move the factors not having x from the left side of equation 3x = -2y +11

[tex] \rm{ \frac{3x}{3} = \frac{-2y + 11}{3} } \\ [/tex]

Divide both sides of equation 3x = 2y + 11 by 3

Cancel 3 with 3

[tex] \rm{ \frac{\cancel{3}x}{\cancel{3}} = \frac{-2y + 11}{3} } \\ [/tex]

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Therefore, the x for 3x + 2y = 11 is [tex] \rm{ \frac{2y + 11}{3} } [/tex]

2y + 3x = 11

Reorder 3x + 2y so highest order terms are first

[tex]\rm{2y + 3x = 11}\\[/tex]

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11

[tex]\rm{2y + 3x - 3x = 11 - 3x}[/tex]

Subtract 3y from the both sides of the equation

Simplify 2y + 3x - 3x = 11 - 3x

Cancel 3x with - 3x

Reorder 11 - 3x so highest order terms are first

[tex] \rm{y= - \frac{3x + 11}{3} } \\ [/tex]

Move factors not having y from the left side of equation 2y = -3x + 11

[tex] \rm{ \frac{2y}{2} = \frac{-3x + 11}{3} } \\ [/tex]

Divide both sides of equation 2y = -3x + 11 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}y}{\cancel{2}} = \frac{-3x + 11}{3} } \\ [/tex]

[tex] \rm{y = \frac{-3x + 11}{3} } \\ [/tex]

Therefore, the y for 2y + 3x = 11 is [tex] \rm{ \frac{-3x + 11}{3} } [/tex]

Answer:

A, C, E

Step-by-step explanation:

You would want to graph the points an if the line goes through them then that would be the answer

Answer:

30ft2. (C.)

I did this question once.

Sorry for my Lack of explanation.-

Answer:

C

Step-by-step explanation:

Draw a line to make 2 separate shapes and find the area of each them then add the 2 areas together

18+12=30

Answer:

-x + 5y = 15

Step-by-step explanation:

Hello! This question simply asks us to rearrange the equation.

So we have this:

y - 2 = 5(x + 5)

Okay, so we need to get an answer with integers for x and y, but no brackets. This means we can start by expanding them:

5y - 10 = x + 5

now, let's put y and x on the same side of the equation, and numbers on the other side:

5y - x = 5 + 10

5y - x = 15

we can put x first, but it's not necessary:

-x + 5y = 15

A = -1

B = 5

C = 15

And that's it!

I hope this makes sense :))

Answer:

5x - y = - 27

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y - 2 = 5(x + 5) ← distribute parenthesis

y - 2 = 5x + 25 ( add 2 to both sides )

y = 5x + 27 ( subtract 5x from both sides )

- 5x + y = 25 ( multiply through by - 1 )

5x - y = - 27 ← in standard form

Answer:

the answer for d question is 10

Solution (1):

Note that:

This means that...

Finding the value of x.

Solution (2):

Note that:

This means that...

Finding the value of x.

Answer:

The first one is: -2xy+7x

The second one is: 12x+9y

Number one is a little weird in how you put it, but I hope this helps!

Answer:

4

Step-by-step explanation:

Answer:

[tex]2x = 53 - 3y \\ x = \frac{53 - 3y}{2} \\ y = \frac{53 - 2x}{3} [/tex]

Answer:

64°

.

.........................

Answer:

Step-by-step explanation:

Given : points 4  , 1 ,25  , opposite of 3 ,  -1/2

To Find : draw on Number Line

Solution :

Numbers with a negative sign are less than zero

Right of zero represented by ‘+’ sign and to the left of zero represented by ‘–’ sign.

+ sign numbers can be denoted as simply numbers  

On a number line the number increases as we move to the right and decreases as we move to the left.  

1 : Draw a line and mark some points at equal distance on it as shown in the figure below  Mark a point as zero on it. Points to the right of zero are positive integers and are marked simply 1, 2, 3  and so on , while points to the left of zero are negative integers and are marked – 1, – 2, – 3 and so on

2.  Go 4 unit on right sides from Zero   to show  4

3.  Go 3 units on Left from zero to show opposite of 3

4.  Divide number line between 1 & 2 in 4 Equal parts and go 1 part right of 1

5.  Divide number line between  0 & -1  in 2 Equal parts and go 1 part left of 0

give brainliest.

Answer:

The bottle with 1.25quarts is the better bargain because a quart is the same thing as 2pints

50 times; 40% A

2/5(50) = A

A = 20

Answer:

50 times; 40% A

2/5(50) = A

A = 20

Step-by-step explanation: