electromagnetic waves and sound waves can have the same frequency. what is the wavelength of a 1.00kHz electromagnetic wave

Answers

Answer 1
Wavelength = 300 000 000 / 1000 = 300 000 m

Related Questions

Help please!!!!!!!!!!!!!

Answers

Answer:

The second choice

Explanation:

I think the answer is the second choice because if the surface is smooth, there is less friction. With a boat, it is easier to pull it on water than on the sand, because water has less friction, and thus, the answer is the second choice because rough surfaces have more friction.

Hopefully the explanation and answer helps!

How are gas giants similar to one another?

Answers

Answer:

they are all made of gass and they are all giants.

Explanation:

Answer:

How are the gas giants similar to one another? dont have solid surfaces and are much larger than earth. Why do all of the gas giants have thick atmospheres? Because they are so massive, the gas giants exert a much stronger gravitational force than the terrestrial planets

Explanation:

A boy and a girl are pulling a heavy crate at the same time with 7 units of firce each. What is the net force acts on the ibject? Is the object balanced or unbalanced?

Answers

Answer:

Net force= 14 units

The object is unbalanced

Explanation:

The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.

This means that the force is in the same direction, hence, the net force will be:

F(N) = 7 + 7 = 14 unit

However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED

3. An object with a mass of 3.2 kg has a force of 6.2 N applied to it. What is the resulting acceleration
of the object?

Answers

Answer:

The answer is 1.94 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

f is the force

m is the acceleration

From the question we have

[tex]a = \frac{6.2}{3.2} \\ = 1.9375[/tex]

We have the final answer as

1.94 m/s²

Hope this helps you

When there are equal forces from opposite directions acting on an object, the forces are said to be which of the following? (4 points)
A.Positive
B.Negative
C.Balanced
D.Gravitational

Answers

Balanced
Hope it helps!!!


Answer: C. Balanced

Explanation:

I took the test and got it right.

One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.

Answers

Answer:

a. the amount of work done on a system is dependent of pathway

Explanation:

The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.

ΔU = Q - W

Where;

Q, the net heat transfer into the system depends on the pathway

W, the net work done by the system also depends on the pathway

But, ΔU, the change in internal energy is independent of pathway

Therefore, the correct option is "A"

a. the amount of work done on a system is dependent of pathway

I will give you branilest!

Answers

Answer:

easy thats

13

Explanation:

A race car driver travelling at 15m*s^-1 accelerates at a constant value for 10.0s. She is now driving at a speed of 35 m*s^-1 What was her acceleration? Give your answer in m*s^-2 to one significant figure . Do not include units with your answer.

Answers

The driver speeds up with acceleration a so that

35 m/s = 15 m/s + a (10.0 s)

Solve for a :

20 m/s = a (10.0 s)

a = (20 m/s) / (10.0 s)

a = 2 m/s²

A rectangular loop with an area of 2 m2 is placed perpendicular to a uniform magnetic field of 1 Tesla. The field’s magnitude is increased to 6 Tesla in 4 seconds. The magnitude of the induced emf is equal to:

Answers

Answer:

Induced emf = 0

Explanation:

An emf can be induced due to the change in magnetic field. It can be given by :

[tex]\epsilon=\dfrac{d\phi}{dt}\\\\\because \phi=BA\cos\theta\\\\\epsilon=\dfrac{d(BA\cos\theta)}{dt}\\\\\epsilon=A\cos\theta\dfrac{dB}{dt}[/tex]

As the loop is placed perpendicular to a uniform magnetic field of 1 Tesla. It means that [tex]\theta=90^{\circ}[/tex] and cos(90) = 0. Hence, the induced emf is equal to 0.

If a pair of shoes weighs 0.3 N on Pluto what is the strength of gravity on Pluto

Answers

Answer:

0.6 m/s 2

Explanation:

Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.

Answers

Answer:

v_y = 10 - 10t

v_x = 10 m/s

Explanation:

This is a projectile launch where the x axis and y axis will be treated independently.

Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant

So, vₓ = v₀ₓ

Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.

Thus, the equation is;

v_y  =  v_oy - gt

Now, the initial velocity component will be;

cos 45 = v₀ₓ/v₀

And sin 45 = v_₀y/v₀

Thus, we have;

v₀ₓ = v₀(cos 45)

Also, v_oy = v₀(sin 45)

Now, the initial velocity would be gotten from the equation of range which is;

R = (v₀² × sin 2θ)/g

Making v₀ the subject, we have;

v₀ = √(Rg/sin 2θ)

We are given;

R = 20 m

g = 10 m/s²

θ = 45°

Thus;

v₀ = √[20 × 10/(sin (2 × 45))]

v₀ = √200

v₀ = 14.14 m/s

Thus;

v₀ₓ = 14.14(cos 45) = 10 m/s

v_oy = 14.14(sin 45) = 10 m/s

Earlier we saw that;

v_y  =  v_oy - gt

Thus;

v_y = 10 - 10t

Also,we saw that;

vₓ = v₀ₓ

Thus;

v_x = 10 m/s

For the graph, we will use times of  t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2

Thus, for each of those values of t, we will have the following values of v_oy

t (s)       v_oy (m / s)

0           10

0.2         8

0.4          6

0.6         4

0.8          2

1.0         0

1.2          -2

Graph is attached

Helpppp guys plsss help !

Answers

Answer:

with what? I can help but with what

Answer:

2

Explanation:

The number of
• in the atom of an element determines its chemical properties.

Answers

Answer:

Yes, the number of electrons determines the chemical properties of the atom.

Explanation:

A boy pushes a box with a force of 150 N at an angle of 40 with a flat floor. What component of his force is directed downward , or into the floor . PLEASE ANSWER!!!!!

Answers

Answer:

[tex]F_y=96.4N[/tex]

Explanation:

Hello.

In this case, considering the force diagram shown on the attached picture, we can see that the component of his force is directed downwards is:

[tex]F_y=F\times sin (\theta)[/tex]

Because the other component is the horizontal one:

[tex]F_x=F\times cos(\theta)[/tex]

In this case, the y-component force turns out:

[tex]F_y=150N\times sin (40\°)\\\\F_y=96.4N[/tex]

Moreover, the x-component force is also computed if required:

[tex]F_x=150N\times cos(40\°)\\\\F_x=114.9N[/tex]

Best regards.

A planned high-speed train between Houston and Dallas will travel a distance of 386 kilometers in 5.40 × 103 seconds. What is the average speed of this train?

Answers

The answer to your question is


556.2

Consider the following debate between two students about their answer to the above question.
Student 1: I thought that whenever one object exerts a force on a second object, the second object also exerts a force that is equal in strength, but in the other direction. So even though Earth is bigger and more massive than the Moon, they still pull on each other with a gravitational force of the same strength, just in different directions.
Student 2: I disagree. I said that Earth exerts the stronger force because it is way bigger than the Moon. Because its mass is bigger, the gravitational force Earth exerts has to be bigger too. I think you are confusing Newton's third law with the law of gravity. Do you agree or disagree with either or both of the students?

Answers

Answer:

I agree with student 1

Explanation:

This is because, the magnitude of the gravitational force on both Earth and Moon depends on the product of their masses. Also, both Earth and Moon exert the same force but in opposite directions.

Student 2 is wrong because the gravitational force is the only force acting between the Earth and Moon, and from Newton's third law, it follows an action-reaction pair. But, student 2 got it wrong in the sense that the magnitude of the action and reaction forces are the same and are equal to the gravitational force.

So, the gravitational force acting on each object is the same and doesn't vary for each mass.  

We should agree with the student 1.

Gravitational force:

This is to be done due to the magnitude of the force since earth and moon should be based on the masses' product. Moreover, the earth and moon exert a similar force but that should be in inverse directions. Here student 2 should be wrong because the gravitational force is that force that acted between the earth and moon. Based on this, we can say that it should be acted on each object when it is the same also it should not be changed for every mass.

Learn more about newton here: https://brainly.com/question/14379797

What causes tides to occur in the ocean?

Waves
Wind
Gravitational pull
Coriolis effect

Answers

Answer:

Gravitational pull

Explanation:

The moon pulls the tides

Answer: gravitational pull

Tides are caused by a gravitational pull from the Moon. Ocean/bay tides rise because of this pull for the gravity under the water. This can happen every day up to 6 times.

Type of tissue that helps with movement.Immersive Reader

a. Epithelial
b.Muscle
c.Connective
d.Nervous

Answers

the answer is b. muscle

The Newton unit obtained from

A)Kg.m/s2
B) Kg. m
C) kg/m
D) kg ml​

Answers

Answer:

Explanation:

The Newtons unit is kg. m/s2

Option A is the correct answer

The two main types of weathering are (4 points)
A. mechanical and physical
B. physical and kinetic
C. chemical and physical
D. chemical and acidic

Answers

Answer:

b

Explanation:

Answer:

its acually c

Explanation:

Part B
You should find that your Interpolated and extrapolated values are not even close to the actual recorded values for these
displacement and velocity readings. Describe the basic assumption behind Interpolation and extrapolation, then for at least
one of these values explain why the calculated value was significantly larger or smaller than the recorded value.
BI
x
Font Sizes
A- A-EIE 3
I
Characters used: 0 / 15000

Answers

Answer:

When ever we use interpolation and extrapolation in our case we use linear approximation but the displacement verses time graph as well as velocity verses time grph are not linear so that whenever we use interpolatio and extrapolation we did not get close readings to the actual recorded values.

Explanation:

1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?

TAD
Cochlear implant
Hearing aid
OBI
No treatment available


2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?

Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss

Answers

Answer:

For number 1 no treatment available , number 2 cochlear hearing loss

Explanation:

nerve damage is permanent

A 1.10-kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Figure a). The object has a speed of vi = 2.60 m/s when it makes contact with a light spring (Figure b) that has a force constant of 50.0 N/m. The object comes to rest after the spring has been compressed a distance d (Figure c). The object is then forced toward the left by the spring (Figure d) and continues to move in that direction beyond the spring's unstretched position. Finally, the object comes to rest a distance D to the left of the unstretched spring (Figure e).

The right end of a horizontal spring labeled k is attached to a wall. Five images show five configurations as a block labeled m approaches, compresses, and then moves away from the spring.
In figure a, the block is to the left of the spring, and an arrow above the block points to the right.
In figure b, the block is just touching the uncompressed spring, and an arrow labeled vector vi above the block points to the right.
In figure c, the block has compressed the spring by a distance d, and a label indicates vector vf = 0.
In figure d, the block is just touching the uncompressed spring, and an arrow labeled vector v above the block points to the left.
In figure e, the block is a distance D away from the spring, and a label indicates vector v = 0.
(a)
Find the distance of compression d (in m).
m
(b)
Find the speed v (in m/s) at the unstretched position when the object is moving to the left (Figure d).
m/s
(c)
Find the distance D (in m) where the object comes to rest.
m
(d)
What If? If the object becomes attached securely to the end of the spring when it makes contact, what is the new value of the distance D (in m) at which the object will come to rest after moving to the left?
m

Answers

Answer:

(a) Approximately [tex]0.335\; \rm m[/tex].

(b) Approximately [tex]1.86\; \rm m\cdot s^{-1}[/tex].

(c) Approximately [tex]0.707\; \rm m[/tex].

(d) Approximately [tex]0.228\; \rm m[/tex].

Explanation:

[tex]v_i[/tex] denotes the velocity of the object in the first diagram right before it came into contact with the spring. Let [tex]m[/tex] denote the mass of the block. Let [tex]\mu[/tex] denote the constant of kinetic friction between the object and the surface. Let [tex]g[/tex] denote the constant of gravitational acceleration.Let [tex]k[/tex] denote the spring constant of this spring.(a)

Consider the conversion of energy in this object-spring system.

First diagram: Right before the object came into contact with the spring, the object carries kinetic energy [tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^2[/tex].

Second diagram: As the object moves towards the position in the third diagram, the spring gains elastic potential energy. At the same time, the object loses energy due to friction.

Third diagram: After the velocity of the object becomes zero, it has moved a distance of [tex]D[/tex] and compressed the spring by the same distance.

Energy lost to friction: [tex]\underbrace{(\mu \cdot m \cdot g)}_{\text{friction}} \cdot D[/tex]. Elastic potential energy that the spring has gained: [tex]\displaystyle \frac{1}{2}\,k\, D^2[/tex].

The sum of these two energies should match the initial kinetic energy of the object (before it comes into contact with the spring.) That is:

[tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^{2} = (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].

Assume that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex]. In the equation above, all symbols other than [tex]D[/tex] have known values:

[tex]m =1.10\; \rm kg[/tex].[tex]v_i = 2.60\; \rm m \cdot s^{-1}[/tex].[tex]\mu = 0.250[/tex].[tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].[tex]k = 50.0\; \rm N \cdot m^{-1}[/tex].

Substitute in the known values to obtain an equation for [tex]D[/tex] (where the unit of [tex]D\![/tex] is [tex]m[/tex].)

[tex]3.178 = 2.69775\, D + 25\, D^2[/tex].

[tex]2.69775\, D + 25\, D^2 + 3.178 = 0[/tex].

Simplify and solve for [tex]D[/tex]. Note that [tex]D > 0[/tex] because the energy lost to friction should be greater than zero.

[tex]D \approx 0.335\; \rm m[/tex].

(b)

The energy of the object-spring system in the third diagram is the same as the elastic potential energy of the spring:

[tex]\displaystyle \frac{1}{2}\,k\, D^2 \approx 2.81\; \rm J[/tex].

As the object moves to the left, part of that energy will be lost to friction:

[tex](\mu \cdot m \cdot g) \, D \approx 0.905\; \rm J[/tex].

The rest will become the kinetic energy of that block by the time the block reaches the position in the fourth diagram:

[tex]2.81\; \rm J - 0.905\; \rm J \approx 1.91\; \rm J[/tex].

Calculate the velocity corresponding to that kinetic energy:

[tex]\displaystyle v =\sqrt{\frac{2\, (\text{Kinetic Energy})}{m}} \approx 1.86\; \rm m \cdot s^{-1}[/tex].

(c)

As the object moves from the position in the fourth diagram to the position in the fifth, all its kinetic energy ([tex]1.91\; \rm J[/tex]) would be lost to friction.

How far would the object need to move on the surface to lose that much energy to friction? Again, the size of the friction force is [tex]\mu \cdot m \cdot g[/tex].

[tex]\displaystyle (\text{Distance Travelled}) = \frac{\text{(Work Done by friction)}}{\text{(Size of the Friction Force)}} \approx0.707\; \rm m[/tex].

(d)

Similar to (a), solving (d) involves another quadratic equation about [tex]D[/tex].

Left-hand side of the equation: kinetic energy of the object (as in the fourth diagram,) [tex]1.91\; \rm J[/tex].

Right-hand side of the equation: energy lost to friction, plus the gain in the elastic potential energy of the spring.

[tex]\displaystyle {1.91\; \rm J} \approx (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].

[tex]25\, D^2 + 2.69775\, D - 1.90811\approx 0[/tex].

Again, [tex]D > 0[/tex] because the energy lost to friction is greater than zero.

[tex]D \approx 0.228\; \rm m[/tex].

The energy transferred between the object and the spring as a closed system, therefore, conserved are;

(a) The distance of compression, d ≈ 0.3354 meters

(b) The speed in the un-stretched position wen the object is sliding to the left, v ≈ 1.8623 m/s

(c) The distance where the object comes to rest, D ≈ 0.7071 m

(d) The distance the object will come to rest attached to the spring, D ≈ 0.2278 m

The reason the above values are correct are as follows;

The known parameters are;

Mass of the object, m₁ = 1.10 kg

Coefficient of friction, μ = 0.250

The initial speed of the object, [tex]v_i[/tex] = 2.60 m/s

Force constant of the spring, K = 50.0 N/m

Distance the spring is compressed by the object = d

(a) Conservation of energy principle

[tex]Kinetic \ energy = \dfrac{1}{2} \cdot m\cdot v^2[/tex]

Work done = Force × Distance

Friction force, [tex]F_f[/tex] = W × μ

Weight, W = m·g

Weight = Mass × Acceleration

Energy transferred by object = Work done by spring + Work done by friction

[tex]Energy \ transferred \ by \ object = Kinetic \ energy = \dfrac{1}{2} \times 1.10\times 2.60^2 = 3.718[/tex]

Energy transferred by object = 3.718 J

[tex]Work \ done \ by \ spring = \dfrac{1}{2} \cdot k\cdot x^2[/tex]

[tex]Work \ by \ spring \ to \ bring \ object \ to \ rest, \ W_{spring} = \dfrac{1}{2} \times 50\times d^2[/tex]

[tex]W_{spring}[/tex] = 25·d²

Work done by friction, [tex]W_{friction}[/tex] = 1.10×9.81×0.250×d = 2.69775·d

Therefore;

3.718 = 25·d² + 2.69775·d

25·d² + 2.69775·d - 3.718 = 0

Solving gives

The distance of the compression d ≈ 0.3354 m

(b) The energy given by the spring = 25·d²

The work done by friction, [tex]W_{friction}[/tex] = 2.69775·d

Kinetic energy given to object = 0.55·v²

0.55·v² = 25·d² - 2.69775·d

0.55·v² = 25×0.3354² - 2.69775×0.3354

∴ v = √(3.4682) = 1.8623

The velocity of the object at the un stretched position, v ≈ 1.8623 m/s

(c) The kinetic energy, K.E. of the object on the way left is given as follows;

K.E. = 0.5 × 1.10 kg × 3.4682 m²/s² = 1.90751 J

The work done by friction before object comes to rest = 2.69775·D

[tex]D = \dfrac{1.90751 \, J}{2.69775 \, N} \approx 0.7071 \, m[/tex]

The distance where the object comes to rest, D ≈ 0.7071 m

(d) The work done on spring, [tex]W_{spring}[/tex] = 25·D'²

Work done on friction, [tex]W_{friction}[/tex] = 2.69775·D'

Kinetic energy of object, K.E. ≈ 1.90751 J

K.E. = [tex]W_{spring}[/tex] + [tex]W_{friction}[/tex]

1.90751 ≈ 25·D'² + 2.6775·D'

25·D'² + 2.6775·D' - 1.90751 = 0

Solving with a graphing calculator gives;

D' ≈ 0.2278 m

The new value of the distance D = 0.2278 m

Learn more about the energy conservation principle here:

https://brainly.com/question/928985

why a dam is thicker at the bottom than it's top​

Answers

Answer: Due to water pressure.

Explanation:

As depth increases so does the pressure.

Two cars are traveling on a desert road between three consecutive poles, as shown in the
figure. After 5.1 s, they are side by side at the
next telephone pole. The distance between
the poles is 72.7 m.

1-Find the displacement of Car A after 5.1 s.(answer in units of m.)
2-Find the average velocity of Car A during 5.1
s. (answer in units of m/s.)

Answers

Answer:

SUGGGA

Explanation:

A cows mass is 401 kg and a trucks mass is 832 kg. What is the difference between their weights . Answer please!!!

Answers

Answer:

403 kg is the diffrence

MULTIPLE CHOICE QUESTION
What is the acceleration of the object?
(Remember a = Fnet/m and acceleration needs a
direction)
8 m/s/s
0.125 m/s/s to the right
8 m/s/s to the left
8 m/s/s to the right

Answers

Which object? More information is needed to answer this question

A helpful association method like remembering the Allies during World War II as BAR
(Britain, America, and Russia) is called
O an acronym
O the DAP flashcard method
O a visual image
O a mind map

Answers

Answer:

an acronym because it is shorted to remember like mvemjsun it's the planet

A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen when the spectacles hit the ground? Neglect the air resistance.

Answers

Answer:

[tex]h_p = 30.46\ m[/tex]

Explanation:

Free Fall Motion

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

[tex]v_f=g\cdot t[/tex]

Where [tex]g = 9.8 m/s^2[/tex]

Similarly, the distance y the object has traveled is calculated as follows:

[tex]\displaystyle y=\frac{g\cdot t^2}{2}[/tex]

If we know the height h from which the object was dropped, we can solve the above equation for t:

[tex]\displaystyle t=\sqrt{\frac{2\cdot y}{g}}[/tex]

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

[tex]\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec[/tex]

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

[tex]t_2=2.56 - 2 = 0.56\ sec[/tex]

Therefore, it has traveled down a distance:

[tex]\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m[/tex]

Thus, the height of the pen is:

[tex]h_p = 32 - 1.54\Rightarrow h_p=30.46\ m[/tex]

The pen is 30.52 m above the ground.

Given that the height of the stadium is h = 32m

The initial velocity of the glasses will be 0.

[tex]h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s[/tex]is the time taken for the glasses to hit the ground.

Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:

[tex]t^{'}=2.55-2\\t^{'}=0.55s[/tex]in the air

distance traveled by the pen:

[tex]d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m[/tex]

So the pen is  [tex]h-d=32-1.48=30.52m[/tex]  above the ground.

Learn More:

https://brainly.com/question/24018491

Which of the following does not discribe a mineral

Answers

Answer:

give us some further context to answer your question as well

Explanation:

Other Questions
It refers to the ability of an individual to explain things Read the excerpt from chapter 2 of Night.We tried to reason with her, more to calm ourselves, to catch our breath, than to soothe her:"She is hallucinating because she is thirsty, poor woman . . . That's why she speaks of flames devouring her . . .But it was all in vain. Our terror could no longer be contained. Our nerves had reached a breaking point. Our very skin was aching. It was as though madness had infected all of us. We gave up. A few young men forced her to sit down, then bound and gagged her.What quotation indicates that the authors purpose is to justify actions in an intolerable situation?We tried to reason with her, more to calm ourselves, to catch our breath, than to soothe her.But it was all in vain.It was as though madness had infected all of us.A few young men forced her to sit down, then bound and gagged her. Rewrite this phrase using algebraic symbols eight times a number is decreased by 12 (a) It takes 37 pounds of seed to completely plant a 6-acre field.How many acres can be planted per pound of seed?Can yall answer both 4. State in words how acceleration is calculated. A block of wood has a mass of 8 g and occupies a volume of 10 cm3. What is its density? pls I need help understanding How to identify a maps scale?What would this map be considered? Are microscopic and macroscopic ecosystems affected by limiting factors differently? A color-blind woman marries a man who is not color-blind. All of their sons are color-blind, but none of their daughters are color-blind. Color-blindness is likely A. the result of having too few chromosomes. B. the result of having an extra chromosome. C. a sex-linked trait. D. a recessive trait. How can you promote the interest of young people like you to read comics specially in the present generation where everything it's already internet dependent? Do you think it would be useful to determine the chemical properties of any of the evidence? Why or why not? plz! give me brainliest? i give u some if u give me some! HaEeiiekekekekekek HELP PLEASS Refer to Table 9.2. (Data are expressed in billions of dollars).Full Employment Income (Output) Consumers Desire to Spend Investors Desire to Spend Total Private Spending Total Saving$500 $300 $250 $___ $___600 375 250 $___ $___700 450 250 $___ $___800 525 250 $___ $___If the full-employment level of income (YF) in Table 9.2 is $800 billionA. There is a recessionary gap of $25 billion.B. The economy is in equilibrium.C. There is an inflationary gap of $250 billion.D. There is a recessionary gap of $275 billion. BRAINLIEST WILL BE AWARDED!!!!!!!!!!!!!!!!! What did the British government offer to get people to grow crops such as indigo and rice? The British government offered a subsidy to farmers to grow indigo and rice The British government offered free slaves to farmers willing to grow indigo and rice The British government offered free land to farmers willing to grow indigo and rice The British government offered office positions to farmers willing to grow indigo and rice Eddie's recipe for bagels makes 18 bagels per batch. Eddie makes 2/3 batch of bagels. How many bagels does Eddie make In the diagram, quadrilateral LMNO is a parallelogram. What is the length of ?A. 6B. 5.66C. 5.39D. 2.24 True or False: The Catholic Church expanded the work of the Inquisition to target Protestant Reformers.