Data
Table A
Record your data either in your lab notebook or in the tables below.
Cart Speed
Cart Speed
Elapsed Time
(s)
(Low fan speed) (Medium fan speed)
(cm/s)
(cm/s)
16.4
23
Cart Speed
(High fan speed)
(cm/s)
31.7
1
31.5
64.0
2
54
36
89.8
3
118.1
4
5
6
7

Answer:

Momentum change of the rock = 3835 kgm/s

Chane in earth's velocity = 6.4 x 10⁻²² m/s

Explanation:

m = 50.0 kg, M = 6.0 x 10²⁴ kg

d = 300.0 m

final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s

Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s

Inital momentum of the rock+earth system = 0

final momentum = 0 (momentum conservation)

momentum of rock and momentum of earth are same magnitude and opposite directions.

mv - MV = 0

Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s

Answer:

58600 = momentum answer

Answer:

B) parabolic

Explanation:

A parabolic path is defined as :-

"The angle of trajectory of a projectile", such as a cannon ball, which moves in such a path after being launched from a cannon.

The weight is equal to 'mg' where m is the mass and the g is the gravitational constant on that certain planet

In this case, the mass is 150 kg and the gravitational constant is about 9.8.

so the weight = 150 * 9.8 = 1470 Newtons.

Hope that helped!

The weight of the box with the given mass on Earth is 1470 Newtons.

Given the data in the question;

Weight is the force acting on the mass of a particular object or particle due to gravity. It is the gravitational force acting on an object with mass. It is measured in newtons. It is expressed as;

[tex]W = m * g[/tex]

Where m is mass of object and g is acceleration due to gravity on earth ( [tex]g = 9.8m/s^2[/tex] )

To find the weight of the box, we substitute our values into the expression above;

[tex]W = 150kg * 9.8m/s^2\\\\W = 1470kgm/s^2\\\\W = 1470N[/tex]

Therefore, the weight of the box with the given mass on Earth is 1470 Newtons.

Learn more about weight: https://brainly.com/question/19540959

Explanation:

the electrons that are the furthest from the nucleus

GPE=mgh

10³=60 x 9.8 x h

h=1.7 m

The value of her height will be 1.7 m. The formula for the gravitational potential energy is used in the given problem.

Gravitational potential energy is found as the product of the mass, gravity, and height attained by the object during a fall.

The given data in the problem is;

m is the mass of a girl =60 kg

E is the gravitational potential energy= 10 kJ

h is the height traveled during free fall.

The expression for the gravitational potential energy is;

[tex]\rm \ GPE(E) = mgh \\\\ h = \frac{E}{mg} \\\\ h = \frac{10\times 10^3 }{60 \times 9.81 } \\\\ h= 1.7 \ m[/tex]

Hence her height will be 1.7 m.

To learn more about gravitational potential energy refer to the link;

https://brainly.com/question/388485

how much pressure is created when a force of 55N is applied over an area of 8m²

We have been asked to determine the pressure exerted when given magnitude of force acting on given area.

[tex]☄\bf \qquad \mathcal{Pressure} = \mathcal{\dfrac{Force}{Area}}[/tex]

Put all given value we obtain

[tex]\qquad \sf \longrightarrow \:Pressure \: = \dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = \cancel\dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = 6.875 \: Pa.[/tex]

Therefore,

Answer:

C. Mass of object 1 = 12 kg

Mass of object 2 = 12 kg

Distance between objects = 1.5 m

Explanation:

From the universal gravitation equation

Force of gravity between two objects is directly proportional to the product of mass 1 and mass 2 and inversely proportional to the square of the distance apart

Option B is has the greatest factor

Force of gravity between the objects = (15 x 12)/(0.5)^2

Force of gravity between the objects = 720G

Option C has the least factor and the answer

Force of gravity between the objects = (12 x 12)/(1.5)^2

Force of gravity between the objects = 64G

G = The constant of proportionality = 6.673 x 10-11 N m^2/kg^2

What is the difference between the fourth harmonic and the nth harmonic?

The fourth harmonic has frequency f4= v/λ4= 4v/2L = 4f1, and, to generalise, The nthharmonic has frequency fn= v/λn= nv/2L = nf1. All waves in a string travel with the same speed, so these waves with different wavelengths have different frequencies as shown.

Answer:

bevz there may be a inward for acting upon to

cause inward acceleration