can someone help please i am disintegrating by the second

Answer:

Range => y ≤ -2

Domain => All real numbers

Step-by-step explanation:

As it extends horizontally either way, domain can be any possible value.

Whereas it only extends from -2 towards the bottom, therefore the range will be less than or equal to -2.

Answer:

The slope is 11/5 or 2.2, gimme that brainliest

Answer:

The missing degree is 60, but the perimeter is 11 cm.

I hope this is correct, if it's incorrect, I'm sorry

Answer:

40x^2-68x+41

Step-by-step explanation:

Multiply both expressions

(-2x+5)^2=  4x^2-20x+25

(6x-4)^2=36x^2-48x+16

Then add

Use multiplication table if you have difficulty with multiplying

Ex

      -2x       5

-2x  4x^2  -10x

5     -10x    25

Then add them all to get the full expression

Answer:

6x+5 that's the answer what I have

The shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

The given equation for ball height

[tex]=6+30t-16t^{2}[/tex]

The equation for the blocker's height will be

[tex]=9+25t-16t^{2}[/tex]

But, the shot is made before two-tenths of a second or 0.2 seconds therefore modified equation for ball height is

[tex]=6+30(t-0.2)-16(t-0.2)^{2}[/tex]

Now for the shot to be blocked, the height of the shot-blocker must be greater than the height of the ball which is shot before 0.2 seconds :

[tex]9+25t-16t^{2} \geq 6+30(t-0.2)-16(t-0.2)^{2}[/tex]

[tex]9+25t-16t^{2} \geq6+30t-6-16(t^{2} -0.4t+0.04)[/tex]

[tex]9+25t-16t^{2} \geq30t-16t^{2} -6.4t+0.64[/tex]

[tex]9+25t\geq36.4t-0.64[/tex]

[tex]9.64\geq11.4t[/tex]

[tex]t \leq \dfrac{9.64}{11.4}=0.846[/tex]

Thus the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

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Answer:

C

shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

Step-by-step explanation:

On edge

Answer: D'(3, 6), E'(0, 12), F'(3, -3)

Step-by-step explanation:

Step-by-step explanation:

[tex] \sqrt{a {}^{2} } + 24 - 4 = a [/tex]

Answer:

See Explanation

Step-by-step explanation:

[tex]A+B= 45 \degree \\ \\ assuming \: \tan \: on \: both \: sides \\ \\\implies \: \tan( A+B)= \tan 45 \degree \\ \\ \implies \: \tan( A+B)= 1 \: \: \\ ( \because \: \tan 45 \degree = 1) \\ \\ \implies \: \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B } = 1 \\ \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\ \\ \purple{ \implies }\: \orange{ \bold{\tan \: A +\tan \: B + \tan \: A .\tan \: B= 1 }} \\ \\ thus \: proved[/tex]

Answer:

Distribute Property

Step-by-step explanation:

In the first expression, 7 is the only coefficient of i in the second term, and 5 is the only coefficient of i in the first term. The rewritten sum would simplify to -3i +7i +4i+5i.

Answer:

2x^2+7x and 8y+3x

Step-by-step explanation:

Okay for the first one when you combine like terms you are adding the ones with the same terms so the ones that have X in it you add, the one with Y you add so it would be

2x+6x=8x ----> 8x-5x=3x

5y+3y=8y so

8y+3x

same thing for the other one so the answer is:

2x^2+7x

A: The plane is going 525 miles per hour.

B: In 13 hours the plane will travel 6,825 miles.

Answer:

(a)  [tex]\sf 450 \ miles \ per \ hour[/tex]

(b) 675 miles in [tex]\sf 1\frac{1}{2} \ hours[/tex]

explanation:

(a)

unit rate:

[tex]\sf \dfrac{total \ distance}{total \ time}[/tex]

[tex]\sf \dfrac{2100}{\sf 4\frac{2}{3}}[/tex]

[tex]\sf \dfrac{2100}{\sf \dfrac{14}{3}}[/tex]

[tex]\sf 450 \ miles \ per \ hour[/tex]

(b)

distance: speed * time

distance: [tex]\sf 450 \\[/tex] * [tex]\sf 1\frac{1}{2}[/tex]

distance: 675 miles

Answer:

4x10=40

It will lose 40% pressure after four minutes

It will lose 40% pressure after four minutes

Consider the function:

[tex]y = a(1\pm r)^m[/tex]

where m is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

We have been given that a bike tire just ran over a nail, and it is losing pressure at a rate of 10% every minute. The tire pressure is currently 1,060 kilo-pascals. We are asked to find the tire pressure in 4 minutes.

We will use exponential decay formula to solve our given problem.

[tex]y = a(1\pm r)^m[/tex]

Let us convert 10% into decimal.

0.01

Initial value is 1,060 . Upon substituting our given values in above formula, we will get:

y = 1,060 (1 - 0.01)^4

Therefore, the tire pressure will be approximately 40% kilo-pascals in 4 minutes.

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Answer:

D

Step-by-step explanation:

First of, let's make a table for y = cos(x)

(x , y): (0 , 1) (π/2 , 0) (π , -1) (3π/2 , 0) (2π , 1)

Now, making a table for y = 2cos(x) is simple. We just have to multiply all the y-values from the previous table by 2.

(x , y): (0 , 2) (π/2 , 0) (π , -2) (3π/2 , 0) (2π , 2)

Graphing these coordinates, we find that the answer is D.

Hello.

There are really 2 ways to think about the given problem.

First, we can use the slope formula:

[tex]\displaystyle\frac{y2-y1}{x2-x1}[/tex]

[tex]\displaystyle\frac{-6-(-2)}{-9-(-9)} =\frac{-6+2}{-9+9} =\frac{-4}{0} =[/tex]

Slope = undefined

The second way is to just take a look at the points.

You should notice that the x-coordinates are the same.'

If the x-coordinates are the same, then the slope is

[tex]\Large\boxed{Und.efined}}[/tex]

I hope it helps.

Have a nice day.

[tex]\boxed{imperturbability}[/tex]

Answer:

undefined

Step-by-step explanation:

the x-coordinates are the same look

The mode of the given data is equal to bowls of spaghetti.

Given the following data:

In Mathematics, a mode can be defined as a statistical terminology that is used to denote the value that appears most often or repeatedly occurring in a given data set.

This ultimately implies that, a mode represents the value (number) with the highest frequency. In this exercise, the bowls of spaghetti represents the mode of the given data.

Read more on mode here: https://brainly.com/question/542771

Answer:

your answer is

180-(51+39)=

180 - 90=90°

BC =90°

Answer:

48

Step-by-step explanation:

Reverse solve for a perfect Square

(b/2a)^2=36

(b/2(4))^2=36

(b/8)^2=36

b/8=6

b=48

48 makes the trinomial a perfect square trinomial.

Answer:

12i

Step-by-step explanation:

2i×2i=4i

4i×3i=12i

Answer:

4 and 3/5

Step-by-step explanation:

Answer:

Step-by-step explanation:

The area of a rectangle is given by the formula:

Area=width×height

The perimeter of a rectangle is given by the formula

Perimeter=2(width+height)

Area

(x + 6) × (x+2) =

x² + 2x + 6x + 12

x² + 8x + 12

------------------

Perimeter

2 × (x + 6 + x + 2) =

2 × (2x + 8) =

4x + 16

Answer: 70%

Step-by-step explanation:

Answer:

70%

Step-by-step explanation:

Answer: Isaac Newton and Gottfried Leibniz.

Isaac Newton and Gottfried Leibniz

Answer:

Step-by-step explanation:

then simplify

Step-by-step explanation:

first, get a piece of tracing paper. then, place it on the grid and copy the shape and the point of rotation. then, place your pen on the point of rotation and rotate the paper 180°. then copy the shape to its new position on the grid. then move the shape 4 units left by counting 4 squares on each vertex and moving it. lastly, find the coordinates of point

Hey there!

Is 4/3 greater than 9/9?”

Well…
4/3

= 4 ÷ 3

= 1.333333333333333

9/9

= 9 ÷ 9

= 1

4/3 > 9/9

Thus, your answer: YES 4/3 is GREATER THAN 9/9

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

circumference 69.08 area 379.94

Step-by-step explanation:

After 3 years of depreciation at a rate of 16% per year, the computer will be worth $886.93.

To determine the value of Cleo's computer after depreciating for 3 years at a rate of 16% per year, we need to calculate the depreciation amount for each year and subtract it from the original value.

First, let's calculate the depreciation for one year. The depreciation amount is obtained by multiplying the original value by the depreciation rate: $1,495 * 0.16 = $239.20.

After the first year, the value of the computer would be $1,495 - $239.20 = $1,255.80.

Now, we need to repeat this process for the next two years. For the second year, the depreciation amount would be $1,255.80 * 0.16 = $200.93. Subtracting this from the value after the first year gives us $1,055.87.

For the third year, the depreciation amount would be $1,055.87 * 0.16 = $168.94. Subtracting this from the value after the second year gives us $886.93.

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